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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 32501. |
LCM of (6,72,120) |
| Answer» 360 | |
| 32502. |
Rectangles |
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| 32503. |
-3/4 standard form |
| Answer» | |
| 32504. |
Find the hcf of 960 and 1575 and expression it in the form of 960m+1575n |
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| 32505. |
Koun si month me 11th class ke form bharne hote hai Plzzzzzzzz tell me??? |
| Answer» | |
| 32506. |
Q) Rational or Irrational ?? (root 5 - root 2)^10 |
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Answer» real number Irrational |
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| 32507. |
Define terminating and non terminating number...... |
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Answer» Pavan partu is wrongThe answer is a number which is stop is called terminating A number which is not stop is called non terminating number the numbers which r not repeating called terminatingthe num which r repeating called non terminating |
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| 32508. |
What are trigometry |
| Answer» | |
| 32509. |
find the largest no which divide 224, 250 and 302 and least remainder =3 in each case |
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| 32510. |
Prove that root 6 is a irrational number |
| Answer» If possible, let {tex}\\sqrt { 6 }{/tex} be rational and let its simplest form be {tex}\\frac { a } { b }{/tex} then, a and b are integers having no common factor other than 1, and {tex}b \\neq 0{/tex}.Now, {tex}\\sqrt { 6 } = \\frac { a } { b } {/tex}{tex}\\Rightarrow 6 = \\frac { a ^ { 2 } } { b ^ { 2 } }{/tex} [on squaring both sides]{tex}\\Rightarrow 6b^2 = a^2{/tex} .................(i){tex}\\Rightarrow{/tex} 6 divides {tex}a^2{/tex} [{tex}\\because{/tex} 6 divides {tex}6b^2{/tex}]{tex}\\Rightarrow{/tex} 6 divides {tex}a{/tex}Let {tex}a = 6c{/tex} for some integer {tex}c{/tex}putting {tex} a = 6c{/tex} in (i), we get{tex}a^2 = 36c^2{/tex}{tex}6b^2 = 36c^2 \\;\\;\\;[6b^2 = a^2] {/tex}{tex}\\Rightarrow b^2 = 6c^2{/tex}{tex}\\Rightarrow{/tex} 6 divides {tex}b^2{/tex} [{tex}\\because{/tex} 6 divides {tex}6c^2{/tex}]{tex}\\Rightarrow{/tex} 6 divides {tex}b{/tex} [{tex}\\because{/tex} 6 divides {tex}b^2 = 6{/tex} divides {tex}b{/tex}]Thus, 6 is a common factors of {tex}a{/tex} and {tex}b{/tex}But, this contradicts the fact that {tex}a{/tex} and {tex}b{/tex} have no common factor other than 1The contradiction arises by assuming that {tex}\\sqrt { 6 }{/tex} is rational.Hence {tex}\\sqrt { 6 }{/tex} is irrational. | |
| 32511. |
If p,qare zeroes of 2xsquare-7x+3,find p square+q square |
| Answer» 37/4 | |
| 32512. |
What is irrational |
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Answer» A number which is neither terminates nor repeat or which is not a perfect square Numbers that cannot be expressed in the form of p/q |
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| 32513. |
2y -4a-(-4) - (-9y+7a-34 |
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| 32514. |
Prove that root 3+3/7root 3 is an irrational number? |
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| 32515. |
1~ How we proof that 2+2= 52~ How we proof that 2× 2 =5 |
| Answer» 2 + 2 = 514 = 14 10 + 4 = 10 + 44 - 4 = 10 - 102^2 - 2^- 2 = 5 ( 2 - 2 )Then we apply identity( 2 + 2 ) ( 2 - 2) = 5 ( 2 - 2)Then we will cancel 2 - 2 by 2 - 2Then it will be2 + 2 = 5# proved# | |
| 32516. |
Prove under root 3 is itrational |
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| 32517. |
What is co-prime and composite number |
| Answer» Which come in others table | |
| 32518. |
Find hot of 256,678 |
| Answer» | |
| 32519. |
Find a quadratic polynomial, the sum of whose zeroes is 0 and one zero is 5 |
| Answer» Let α=5Given α+β=05+β=0,β=-5So the polynomial f(x)=(x-5)[x-(-5)]=(x-5)(x+5)=x2-25 | |
| 32520. |
How chapters to be read for sa1 |
| Answer» | |
| 32521. |
(X+5)(x+6)=25/24×24 |
| Answer» According to the question,{tex}(x - 5)(x - 6) = \\frac{{25}}{{{{\\left( {24} \\right)}^2}}}{/tex}{tex}\\Rightarrow x(x - 6) - 5(x - 6) = \\frac{{25}}{{{{(24)}^2}}}{/tex}{tex}\\Rightarrow {x^2} - 6x - 5x + 30 - \\frac{{25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - 11x + 30 - \\frac{{25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - 11x + \\frac{{30 \\times {{24}^2} - 25}}{{{{(24)}^2}}} = 0{/tex}{tex} \\Rightarrow {x^2} - 11x + \\frac{{30 \\times 576 - 25}}{{{{(24)}^2}}} = 0{/tex}{tex} \\Rightarrow {x^2} - 11x + \\frac{{17280 - 25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\frac{{264x}}{{24}} + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\left( {\\frac{{145}}{{24}} + \\frac{{119}}{{24}}} \\right)x + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\frac{{145}}{{24}}x - \\frac{{119}}{{24}}x + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow x\\left( {x - \\frac{{145}}{{24}}} \\right) - \\frac{{119}}{{24}}\\left( {x - \\frac{{145}}{{24}}} \\right) = 0{/tex}{tex}\\Rightarrow \\left( {x - \\frac{{145}}{{24}}} \\right)\\left( {x - \\frac{{119}}{{24}}} \\right) = 0{/tex}{tex}\\Rightarrow x - \\frac{{145}}{{24}} = 0{/tex} or {tex}x - \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow x = \\frac{{145}}{{24}}{/tex} or {tex}x = \\frac{{119}}{{24}}{/tex} | |
| 32522. |
Give an example of two irrational whose sum is rational |
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Answer» Sorry...√3and -√3. Are two irrational no. Which sum is rational no. 2root3 - root3 |
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| 32523. |
1.4 |
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| 32524. |
Short solutions ncert exercise |
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| 32525. |
Find the series of the polynomial 8x² - 22x - 21 |
| Answer» We have,{tex}8 x ^ { 2 } - 22 x - 21 = 0{/tex}{tex}\\Rightarrow{/tex}\xa08x2 - 28x + 6x - 21 = 0{tex}\\Rightarrow{/tex}\xa04x(2x - 7) + 3 (2x - 7) = 0{tex}\\Rightarrow{/tex}\xa0(2x - 7) (4x + 3) = 0 {tex}\\Rightarrow{/tex}\xa02x - 7 = 0 or,\xa04x + 3 = 0\xa0{tex}\\Rightarrow{/tex}\xa0{tex}x = \\frac { 7 } { 2 } \\text { or } x = - \\frac { 3 } { 4 }{/tex}Thus,\xa0{tex}x = \\frac { 7 } { 2 } \\text { and } x = - \\frac { 3 } { 4 }{/tex} are two roots of the equation 8x2 - 22x - 21 = 0 | |
| 32526. |
Prove that the product of three consecutive positive integer is divisibel by 6. |
| Answer» Let three consecutive numbers be x, (x + 1) and (x + 2)Let x = 6q + r 0 {tex}\\leq r < 6{/tex}{tex}\\therefore x = 6 q , 6 q + 1,6 q + 2,6 q + 3,6 q + 4,6 q + 5{/tex}{tex}\\text { product of } x ( x + 1 ) ( x + 2 ) = 6 q ( 6 q + 1 ) ( 6 q + 2 ){/tex}if x = 6q then which is divisible by 6{tex}\\text { if } x = 6 q + 1{/tex}{tex}= ( 6 q + 1 ) ( 6 q + 2 ) ( 6 q + 3 ){/tex}{tex}= 2 ( 3 q + 1 ) .3 ( 2 q + 1 ) ( 6 q + 1 ){/tex}{tex}= 6 ( 3 q + 1 ) \\cdot ( 2 q + 1 ) ( 6 q + 1 ){/tex}which is divisible by 6if x = 6q + 2{tex}= ( 6 q + 2 ) ( 6 q + 3 ) ( 6 q + 4 ){/tex}{tex}= 3 ( 2 q + 1 ) .2 ( 3 q + 1 ) ( 6 q + 4 ){/tex}{tex}= 6 ( 2 q + 1 ) \\cdot ( 3 q + 1 ) ( 6 q + 1 ){/tex}Which is divisible by 6{tex}\\text { if } x = 6 q + 3{/tex}{tex}= ( 6 q + 3 ) ( 6 q + 4 ) ( 6 q + 5 ){/tex}{tex}= 6 ( 2 q + 1 ) ( 3 q + 2 ) ( 6 q + 5 ){/tex}which is divisible by 6{tex}\\text { if } x = 6 q + 4{/tex}{tex}= ( 6 q + 4 ) ( 6 q + 5 ) ( 6 q + 6 ){/tex}{tex}= 6 ( 6 q + 4 ) ( 6 q + 5 ) ( q + 1 ){/tex}which is divisible by 6if x = 6q + 5{tex}= ( 6 q + 5 ) ( 6 q + 6 ) ( 6 q + 7 ){/tex}{tex}= 6 ( 6 q + 5 ) ( q + 1 ) ( 6 q + 7 ){/tex}which is divisible by 6{tex}\\therefore {/tex}\xa0the product of any three natural numbers is divisible by 6. | |
| 32527. |
RS AGGRAWAL |
| Answer» | |
| 32528. |
Rd sharma exercise 5.3 and number 8 solutions |
| Answer» | |
| 32529. |
Rat |
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| 32530. |
X2- 2x-8 |
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| 32531. |
Find all zeroes of the polynomial p (x)=x^4+x^3-2x-10x^2+4. |
| Answer» | |
| 32532. |
Eliminate the following - 4/x+3y=14 3/x-4y=2 |
| Answer» 4/x+3y=14 3/x-4y=2 | |
| 32533. |
Plzz put last year means 2018 question paperPlzz.....Plz............. |
| Answer» No it is cheating | |
| 32534. |
What is definition of irrationals |
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Answer» The numbers that are non terminating and non recurring The numbers which cannot be written in the form of p÷q where p and q are integers and q is not equal to 0. |
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| 32535. |
Prove that (n)2-1 is divisible by 8 where n is an odd positive integer |
| Answer» No | |
| 32536. |
I am expecting 75 maths, is it good |
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Answer» Yes it is good but u can score more if u want and1 important thing never compare yourself with others I got 80 marks out of 80 I have scored 80out of 80in my ninety class and hoping to maintain the position I got 79 marks out of 80 in class 9th and I think I will do my very best now due to encouragement I would have scored 80 but due to less time I scored 75 No u should score more. I have scored 76 in class 9 in maths so i can score above 90 and u can also score. Maths of class 10 is very easy as compared to class 9. |
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| 32537. |
88888888 and 77777777 find the hcf with euclidean division |
| Answer» 11111111 is the answer | |
| 32538. |
In chapter 1 find HCF by using Euclid\'s lemma. 1(300,540,890) |
| Answer» | |
| 32539. |
For what value of n ,2^n× 5^m ends with digits 5 |
| Answer» {tex}\\begin{array}{l}(2\\times5)^{\\mathrm n}=2^{\\mathrm n}\\times5^{\\mathrm n}\\end{array}{/tex}{tex}\\text{=10}^n{/tex}{tex}\\text{If n=0 then 10}^0\\text{=1}{/tex}{tex}\\text{If n>0 then 10}^n\\text{ will end with 0 }{/tex}{tex}\\mathrm{If}\\;\\mathrm n<0\\;\\mathrm{then}\\;10^{\\mathrm n}\\;\\mathrm{ends}\\;\\mathrm{with}1\\;(\\mathrm e.\\mathrm g.\\;0.1,0.01,0.001){/tex}Hence for all values of n, {tex}2^n\\times 5^n{/tex} can never end with 5. | |
| 32540. |
2 chapter in hindi |
| Answer» | |
| 32541. |
1/4 -1 |
| Answer» Math answer in hindi | |
| 32542. |
I want the relible of 2018 both termd |
| Answer» | |
| 32543. |
3x+4y=18,6x+5y=35 |
| Answer» | |
| 32544. |
Value of (a – c) [(a – b)2 + (b – c)2 – (a – b)(b – c)] + (c – a)3 is equal to |
| Answer» | |
| 32545. |
Find lcm if 12 |
| Answer» The LCM of 12 is 12 itself | |
| 32546. |
7tm |
| Answer» | |
| 32547. |
Example of real number |
| Answer» 2,1/6, -1and irrational number | |
| 32548. |
How to solve X3 - 2x2 |
| Answer» | |
| 32549. |
Write whether 2√45+3√20÷2√5 |
| Answer» {tex}\\frac{2\\sqrt{45\\;\\;}+3\\sqrt{20}}{2\\sqrt5}{/tex}{tex}\\text{=}\\frac{\\displaystyle2\\sqrt{5\\times9}+3\\sqrt{5\\times4}}{2\\sqrt5}{/tex}{tex}=\\frac{6\\sqrt5+6\\sqrt5}{2\\sqrt5}{/tex}{tex}=\\frac{\\displaystyle12\\sqrt5}{2\\sqrt5}{/tex}{tex}=6=\\frac61{/tex}Hence the given number can be written in the form of {tex}\\frac pq{/tex} where p and q are integers.So the given expression is a rational number. | |
| 32550. |
What is the solution of this equation 6x square-x-8 |
| Answer» | |