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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 32551. |
What is the solution of this equation 1x square-9x+18 |
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| 32552. |
8u square+16u+1 |
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| 32553. |
If d the HCF of 45 and 27 find x y satisfying d= 27x + 45y. |
| Answer» 45 = 27 {tex} \\times {/tex}\xa01 + 1827 =18 {tex} \\times {/tex}\xa01 + 918 = 9 {tex} \\times {/tex}\xa02 + 0So H.C.F. = 9Now 9 = 27 – 18 {tex} \\times {/tex}\xa01{tex}\\style{font-family:Arial}{\\begin{array}{l}9=27-18\\\\=27-(45-27\\times1)\\times1\\\\=27-45+27\\\\=2\\times27-(1)\\times45=27x+45y\\end{array}}{/tex}⇒ x = 2, y = – 1. | |
| 32554. |
Using prime factorization, find the HCFand LCMof 144.and 198 |
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Answer» 144=2×2×2×2×3×3198=2×3×3×11HCF=9LCM=2×2×2×2×2×11×9=3168LCM×HCF=144×19828512=28512 HCF=9;LCM=4,752 $¥$ |
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| 32555. |
If 1 is a zero of p(x)=ax square- 3(a-1)x-1 then find the value of a |
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| 32556. |
Cos A=4÷5 prove that SinA-4Sin3A÷4Cos3 A-3CosA=3TanA-Tan3A÷1-3Tan2A |
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| 32557. |
Irrational no. between root 3 and root 5 |
| Answer» Infinite numbers | |
| 32558. |
What is the point lie on x-axis |
| Answer» Positive or negative | |
| 32559. |
3x+y=1(2k-1)x+(k+1)y=2k+1How to solve. |
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| 32560. |
___________+___________+_____________=30(1,3,5,7,9,11,13,15) |
| Answer» 11+13+3!=30 | |
| 32561. |
If LCM of 12 & 42 is 10m+4 find the value of m |
| Answer» 8 | |
| 32562. |
What is elimination method in this chapter |
| Answer» Elimination method means that eliminating the first term to get an perfect equation | |
| 32563. |
Whai is a linear equation |
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| 32564. |
How to solve equations |
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| 32565. |
M =3m + 1 |
| Answer» Let n be an arbitrary positive integer.On dividing n by 3, let m be the quotient and r be the remainder.The positive integer is in the form of 3m or (3m + 1) or (3m + 2)Then, by Euclid\'s division lemma, we haven = 3m + r, where {tex}0 \\leq r < 3{/tex}.{tex}\\therefore{/tex}\xa0n = 3m or (3m +1) or (3m + 2), for some integer m.Thus, any positive integer is of the form 3m or (3m + 1) or (3m + 2) for some integer m. | |
| 32566. |
What are prime number? |
| Answer» A prime number can be divided by evenly only be 1 or itself and it must be whole no. greater than 1Example., 5 can only divisible by 1 or 5 therefore it is a prime no. | |
| 32567. |
What is contradiction method in chapter 1 real number |
| Answer» Contradiction means to assume something | |
| 32568. |
Real numder 4m+1 |
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Answer» This is imaginary number No |
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| 32569. |
4m +1 |
| Answer» Let a be the positive integer and b = 4.Then, by Euclid’s algorithm, a = 4q + r for some integer q ≥ 0 and r = 0, 1, 2, 3 because 0 ≤ r < 4.So, a = 4q or 4q + 1 or 4q + 2 or 4q + 3.{tex}(4q)^3\\;=\\;64q^3\\;=\\;4(16q^3){/tex}= 4m, where m is some integer.{tex}(4q+1)^3\\;=\\;64q^3+48q^2+12q+1=4(\\;16q^3+12q^2+3q)+1{/tex}= 4m + 1, where m is some integer.{tex}(4q+2)^3\\;=\\;64q^3+96q^2+48q+8=4(\\;16q^3+24q^2+12q+2){/tex}= 4m, where m is some integer.{tex}(4q+3)^3\\;=\\;64q^3+144q^2+108q+27{/tex}=4×(16q3+36q2+27q+6)+3= 4m + 3, where m is some integer.Hence, The cube of any positive integer is of the form 4m, 4m + 1 or 4m + 3 for some integer m. | |
| 32570. |
Is 75/80 good in maths |
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Answer» Yaa Time nahi puura nahi to 80 hote the.joking invigilator YES |
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| 32571. |
Solve: 43x + 67y =-24 and 67x + 43y = 24 from chap 3 of NCERT |
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| 32572. |
by applying Euclid\'s division of lemma to find HCF of 650&1170 |
| Answer» The largest number which divides 650 and 1170 = HCF (650,1170)By Euclid’s division algorithm,1170 = 650 {tex}\\times{/tex} 1 + 520650 = 520 {tex}\\times{/tex} 1 + 130520 = 130 {tex}\\times{/tex} 4 + 0So, HCF = 130So 130 is the largest number which divides 650 and 1170 | |
| 32573. |
find the sum of the product in this order of the zero of the polynomial 8x^2-18x-5 |
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| 32574. |
So that the square of any positive integers is of the form 3m,3m+1 for some integers m |
| Answer» Let a be any positive integer and b = 3.Then a = 3q + r for some integer q ≥ 0And r = 0, 1, 2 because 0 ≤ r < 3Therefore, a = 3q or 3q + 1 or 3q + 2Or,a2 = (3q)2 or (3q + 1)2 or (3q + 2)2a2=9q2 or 9q2 +6q + 1 or 9q2 + 12q + 4=3 \u200b×\u200b (3q2) or 3(3q2+2q) +1 or 3(3q2+4q)+1=3k1 or 3k2+1 or 3k3+1Where k1 , k2 , and k3 are some positive integers | |
| 32575. |
Ex 2.3. Q5 |
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| 32576. |
X+y=17 |
| Answer» Here x and y can be any no. Ex-13+4=17 | |
| 32577. |
Pls say what is contradiction |
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| 32578. |
HCF of 4052 and 12576 equal to 4052 X Plus 12576y .find X and Y |
| Answer» {tex}12576 = 4052 \\times 3 + 420{/tex}{tex}4052 = 420 \\times 9 + 272{/tex}{tex}420 = 272 \\times 1 + 148{/tex}{tex}272 = 148 \\times 1 + 124{/tex}{tex}148 = 124 \\times 1 + 24{/tex}{tex}124 = 24 \\times 5 + 4{/tex}{tex}24 = 4 \\times 6 + 0{/tex}HCF of 12576 and 4052 is \'4\'. | |
| 32579. |
Using prime factorization,find LCM and HCF of 96,404 |
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Answer» HCF=4,LCM=9696 HCF=4 ,LCM=9686 |
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| 32580. |
Solve 4x |
| Answer» The given equation is 4x2 - 4x + 1 = 0Here a = 4, b = - 4, c= 1{tex}\\therefore D=b^2-4ac = (-4)^2-4(4)(1) = 16-16=0{/tex}So, the given equation has equal roots{tex}x = {-b \\pm \\sqrt{D} \\over 2a} = {-(-4) \\pm0 \\over 2(4)}{/tex}{tex}\\implies x={4 \\over 8}= {1 \\over2}{/tex}{tex}Hence,\\, x={1 \\over 2}, \\,{1 \\over 2}{/tex}are the required roots. | |
| 32581. |
3x-y+7/11+2=102y+x+11/7=10 |
| Answer» Given,\xa0{tex}3x -{/tex}{tex}\\frac{y+7}{11}{/tex}\xa0{tex}+ 2 = 10{/tex}{tex}\\Rightarrow \\frac{33 x-(y+7)+22}{11}=10{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}33x - y - 7 + 22 = 110{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}33x - y = 95{/tex} ..(i)Also,\xa0{tex}2 y+\\frac{x+11}{7}{/tex}\xa0= 10{tex}\\Rightarrow \\quad \\frac{14 y+x+11}{7}{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}14y + x + 11 = 70{/tex}{tex}14y + x = 59{/tex}{tex}14y = 59 - x{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0y =\xa0{tex}\\frac{59-x}{14}{/tex}eq. (i) becomes33x -\xa0{tex}\\left(\\frac{59-x}{14}\\right){/tex}\xa0= 95{tex}\\Rightarrow \\quad \\frac{462 x-59+x}{14}{/tex}\xa0= 95{tex}\\Rightarrow{/tex}\xa0463x - 59 = 1330{tex}\\Rightarrow{/tex}\xa0x = 3When x = 3 eq. (i) becomes33(3) - y = 95{tex}\\Rightarrow{/tex}\xa0y =4 | |
| 32582. |
What we choose after 10th science or commerce ?And on what basis ?What are different Fields in both |
| Answer» I think science because commerce is easy in only class 11 and12 but if we face competitive exam we find difficulty in commerceThat is not possible To learn properly about commerce in 2 years only and we are familiar with science so we can do best | |
| 32583. |
F(x) |
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| 32584. |
Average |
| Answer» The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count. | |
| 32585. |
Is zero a even number |
| Answer» 0is nir even nir odd no. | |
| 32586. |
Find the remainder when 55 *347 *90 is divided by 7 without actually multiplying 55,347and 90 |
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| 32587. |
Explain term MATHEMATICS |
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Answer» Maha tricks subject but interesting He..he??? Meri aatma tumhe hamesha sataegi...maths fullform Mentally unstable tension |
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| 32588. |
How to get my lost class x original pass and marksheet. |
| Answer» In school | |
| 32589. |
Find the common zeroes of the polynomials xcube +5xsquare+ 9x- 45 and xcube+ 8xsquare+15x |
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| 32590. |
The difference between 2 numbers is 26 ,and one no. is 3 times the other then find them |
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Answer» Let one number be x and other be 3x . According to question 3x - x =26. 2x = 26 x = 26/2 x = 13 And 3x = 13 × 3 = 39 Therefore the number are 39 and 13 x-3x=26 |
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| 32591. |
(-1)×(-1)=+1 proved this question |
| Answer» -1x-1We know that - - is +So -1*-1=+1 | |
| 32592. |
What is formula of acetic acid |
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Answer» CH3COOH Ch3cooh C2H4O2 |
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| 32593. |
What is formula of algebra |
| Answer» Algebra | |
| 32594. |
RD sarrma book |
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| 32595. |
Prove 1+1= 0 |
| Answer» (-1)(-1)+1=0(-1)+1=0-1+1=0 | |
| 32596. |
tanQ+secQ=l than secQ is equal to |
| Answer» SecQ=1-tanQ | |
| 32597. |
2×root45+3×root20 ÷2root5 |
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| 32598. |
Find the √(1) |
| Answer» 1 | |
| 32599. |
Can anyone tell me about exercise 2.3 last question plzz |
| Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 32600. |
find the number of square shaped tile to paved a floor having it\'s dimension 15m17cm and 9m2cm |
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