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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 32601. |
Vidya publication book solution |
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Answer» What is the find the sum of the following AP 1 - 1 upon 1 + 1 minus 2 upon 10 + 1 minus 3 upon and + upon and term If the sum of first 7 terms of an ap is 49 and that of the first 17 terms is 289 find the sum of first |
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| 32602. |
if alpha and beta are the zeroes of x2+px +q,find the value of (α/ β +2)(β/α+2) |
| Answer» q/q-2p+4 | |
| 32603. |
Find the largest positive integer,that will divide 398 , 436 , 542 leaving remainder 7 , 11 , 15 |
| Answer» The largest positive integer that will divide 398, 436 and 542 leaving reminders 7, 11 and 15 respectively is the HCF of the numbers (398 – 7), (436 – 11) and (542 – 15) i.e. 391, 425 and 527.HCF of 391,425 and 527:HCF of 425 and 391:425 = 391 × 1 + 34391 = 34 × 11 + 1734 = 17 ×2 + 0HCF of 425 and 391 = 17527 = 17 × 31Similarly, HCF of 17 and 527 = 17So, HCF of (391,425 ,527) = 17∴ Required number is 17. | |
| 32604. |
4+10 |
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Answer» 14 my friend. Off course 14 |
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| 32605. |
1×1 |
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Answer» 1 Affcourse 1 1 |
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| 32606. |
in right triangle ABC,right-angled at B,if tanA=1(2sinA cosA=1 |
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| 32607. |
Find the LCM of 1320 and 540 |
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| 32608. |
What is contradiction Method?? |
| Answer» Assuming or assumption | |
| 32609. |
EX.8.2 Q.NO.4 2 WHY |
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| 32610. |
Find the cubic polynomial whose zeroes are 2-7 and -14 respectively |
| Answer» Let the cubic polynomial be ax3 + bx2 +cx + dand its zeroes be\xa0{tex}\\alpha ,\\beta {/tex}\xa0and\xa0{tex}\\gamma{/tex}.Then,\xa0{tex}\\alpha + \\beta + \\gamma= 2 = \\frac { - b } { a }{/tex}{tex}\\alpha \\beta + \\beta \\gamma + \\gamma \\alpha = - 7 = \\frac { C } { a }{/tex}and\xa0{tex}\\alpha \\beta \\gamma = - 14 = \\frac { - d } { a }{/tex}If a = 1, then b = -2, c = -7, d = 14So, one cubic polynomial which fits the givenconditions is x3 - 2x2 - 7x + 14. | |
| 32611. |
Theoerm 200.5 |
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| 32612. |
Theorem6.1 |
| Answer» Good | |
| 32613. |
If one zero of the polynomial 2x^2-(3k+1)z-9=0 ia negative of thw other , find the value of k |
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| 32614. |
Even numbers |
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| 32615. |
Find factors of (x-y)3+(y-z)3+(z-x)3 |
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| 32616. |
What is gamma |
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| 32617. |
Solution of example no. 5 by using completing the square and quadratic formula |
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| 32618. |
Prove that square of an off positive Integer is of form 8q+1, for some Integer q |
| Answer» Since, any odd positive integer n is of the form 4m\xa0+ 1 or 4m + 3.if n = 4m + 1n2 = (4m + 1)2= 16m2 + 8m + 1= 8(2m2 + m) + 1So n2 = 8q + 1 ........... (i)) (where q = 2m2 + m is a positive integer)If n = (4m + 3)n2 = (4m + 3)2= 16m2 + 24m + 9= 8(2m2 + 3m + 1) + 1So n2 = 8q + 1 ...... (ii) (where q = 2m2 + 3m + 1 is a positive integer)From (i) and (ii) we conclude that the square of an odd positive integer is of the form 8q + 1, for some integer q. | |
| 32619. |
For the following ap write first term and the common difference |
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| 32620. |
Tancube thita ÷ 1+tan square thita +cot cube thita ÷1+cot square thita |
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| 32621. |
X2-7x-12. Factorise it |
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| 32622. |
Show that sum of two irrational number is rational number~ |
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Answer» Let R and I are rational number and irrational number respectively.Assume that sum of R and I is a rational number and equal to P |
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| 32623. |
If 21x2-x-20find the quadratic polynomial whose zeroes are 2alpha and 2 beta |
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| 32624. |
25x^-30x-10=0 |
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| 32625. |
How to factories any equation |
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| 32626. |
If cosA = 5/13 then find the value of :- sin2A - cos2A / 2sinA . cosA * 1/tanA |
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| 32627. |
23+23 |
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Answer» It\'s 2323 And your answer is 46 Don\'t ask such silly questions please |
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| 32628. |
Use Euclid algorithm find the hcf of 1180 and 1445 and find the value of 1180m and 1445n |
| Answer» Here we have to find HCF of 1190 and 1445 and express the HCF in the form 1190m + 1445n.1445 = 1190 ×\xa01 + 2551190 = 255 ×\xa04 + 170255 = 170 ×\xa01 + 85170 = 85 ×\xa02 + 0So, now the remainder is 0, then HCF is 85Now,85 = 255 - 170= (1445 - 1190) - (1190 - 255 ×\xa04)= 1445 - 1190 - 1190 + 255 ×\xa04= 1445 - 1190 ×\xa02 + (1445 - 1190) ×\xa04= 1445 - 1190 ×\xa02 + 1445 × 4 - 1190 ×\xa04= 1445 ×\xa05 - 1190 ×\xa06= 1190 ×\xa0(- 6) + 1445 ×\xa05= 1190m + 1445n , where m = - 6 and n = 5 | |
| 32629. |
x*x +24x-3456 |
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| 32630. |
Express it in simplest form 0.24 |
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Answer» 24/100 6/25 |
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| 32631. |
255 and 455 find hcf |
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Answer» HCF is 5 455= 255×1+200255=200×1+55200=55×3+3555=35×1+2035=20×1+1520=15×1+515=5×3+0HCF () |
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| 32632. |
ax/b-by/a=a+b, ax-by=2ab |
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| 32633. |
if HCF of 210 and 55 is expressible in the form 210*5-55x find the value of x |
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| 32634. |
5+2 |
| Answer» 7 dumbo | |
| 32635. |
Sin a ÷ 1- cot a + cos a÷1-tan a |
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| 32636. |
The 4th and 8th term is 1 and 2 find the 10th term |
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| 32637. |
The 7th and 3rd term is an ap is 12 and 5 find the 13th term |
| Answer» 7th term of ap = a+6d .. (1),3rd term of ap=a+2d .. (2),Subtracting (2) from (1), a + 6d =12-a - 2d = -5--------------------4d =7d=7÷4,a=12-6d, 12-6×7÷4,a=3÷2 Now, 13th term of ap=45÷2 | |
| 32638. |
Sum of the ages of Roza and her mother is 40. Mother\'s age is thrice Roza\'s age find their ages |
| Answer» Let roza\'s age be x So, mother\'s age will be 3xAccording to the question, 3x+x=404x=40X=10 Therefore, roza\'s age is 10 and mother\'s age is 30 | |
| 32639. |
The product of -1/3 and-1/4 is ? |
| Answer» 1/12 | |
| 32640. |
Mathmatics |
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| 32641. |
0/0=2 Prove that |
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Answer» It is possible it is not possible it is not possoble 16-16/8-8=8(2-2) /4(2-2)=8/4=2 I don\'t think it is possible |
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| 32642. |
A+B2+80+90=100 |
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| 32643. |
What is meant by alpha |
| Answer» Alpha also stands for thermal expansion coefficient of a compound in physical chemistry. It is also commonly used in mathematics in algebraic solutions representing quantities such as angles. | |
| 32644. |
Wgfagh |
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| 32645. |
In exercise 3.4 O1 part 3 why did we multiplied eqation1 with 3 |
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| 32646. |
If A,Bal and C are interior angles of a triangle ABC then show that sin[B+C ÷2] =cos A÷2 |
| Answer» 180-(B+C)=ACos(90-(B+C)÷2=Cos (A÷2)Sin (B+C÷2)=Cos (A÷2) | |
| 32647. |
Define co prime |
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Answer» Pair of two prime numbers are called to prime Co prime are those pair of numbers which have a common factor as 1 ex-15=3×5×116=4×3×1 |
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| 32648. |
What is an equation |
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Answer» The chemical equation represented by the name of reactant and product then it is called as equation . These are called balanced equation L. H. S. = R. H. S. A statement in which many variables along with numerous numbers gives out the terms of rhs.. Such that LHS=RHS... |
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| 32649. |
Why is small intestine in herbivores large than carnivorous |
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Answer» Because herbivores eats grass with contain cellulose and cellulose takes much time to be digest while carnivorous eat meat which contains Protein and protein can be easily digested.Thus herbivores have larger intestine than carnivorous. Because herbivores eat food that offs rich in starch. And starch is mainly digested on small intestine. |
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| 32650. |
12345 |
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