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32651.

What is the purpose of learning an equation?

Answer» Equations are useful to solve our daily life problem. Most of the times we take pre algebra help to resolve real life problems.
32652.

2+2+32+32+65*3+699/633--336//+3++-+3*3

Answer»
32653.

He Tu i

Answer»
32654.

22222222÷333333333

Answer» 0.06666666606
32655.

(2√2+3√3)(2√2-3√3)

Answer» -19
-19
-19
32656.

Find the least which as divisible by all the no. 1 to 10.

Answer» Correct ans is 2520 guaranteed
ans is 360
32657.

Find k if (4,k)is 10 units away from (-2,6)

Answer» Find the distance between (2,6),(-3,6)
32658.

62779

Answer» ??
32659.

Find the quadratic polynomial whose zeros are 2and_6

Answer»
32660.

I67 19 21lI39 13 14lI81 24 26l. Evaluate

Answer»
32661.

What is the difference between whole and natural

Answer» Numbers which are starting with 0are called whole numbers and the numbers which are starting with 1are called natural number.
32662.

Hcf of 256

Answer»
32663.

Class 6

Answer»
32664.

what is parallel line

Answer» Those lines that can never intersect each other at any point.
Two line that never intersect that lines is called parallel line
32665.

Find the coordinates of point on yaxis 13 units from the point (12,10)

Answer»
32666.

In trigonometry hw to solve sin square 36+sin square 72 /cos square 17+cos square 73

Answer»
32667.

What is consistent line and what is in consistent line?

Answer» The consistent line has a unique solution whereas inconsistent line has no solution
32668.

√3x+√4x is a irrational no. Prove

Answer»
32669.

4y×y-15 find the zeroes of the polynomial

Answer» We have to find the zeroes of the quadratic polynomial 4y2 – 15 and verify the relationship between the zeroes and coefficient of polynomial.Let {tex}f(y)\\;=\\;4y^2\\;–\\;15{/tex}Compare it with the quadratic {tex}ay^2\\;+\\;by\\;+\\;c{/tex}.Here, coefficient of{tex}\\;y^2\\;=\\;4{/tex}, coefficient of y = 0 and constant term = - 15.Now {tex}4y^2\\;–\\;15\\;=\\;(2y)^2\\;–\\;(\\;\\sqrt{15})^2{/tex}= {tex}(2y\\;+\\;\\;\\sqrt{15})(2y\\;-\\;\\sqrt{15}){/tex}The zeroes of f(y) are given by {tex}f(y) = 0{/tex}⇒{tex}(2y)\\;+\\;\\;\\sqrt{15})(2y\\;-\\;\\sqrt{15}){/tex} = 0⇒ {tex}(2y)\\;+\\;\\;\\sqrt{15}){/tex} = 0 or {tex}(2y\\;-\\;\\;\\sqrt{15}){/tex} = 0⇒ {tex}2y\\;=\\;-\\;\\;\\sqrt{15}{/tex} or {tex}2y\\;=\\; \\;\\;\\sqrt{15}{/tex}⇒ {tex}\\;y\\;=\\;-\\frac{\\;\\;\\sqrt{15}}2{/tex} or {tex}\\;y\\;=\\;\\frac{\\;\\;\\sqrt{15}}2{/tex}Hence, the zeroes of the given quadratic polynomial are {tex}-\\frac{\\;\\;\\sqrt{15}}2{/tex}, {tex} \\frac{\\;\\;\\sqrt{15}}2{/tex}
32670.

Why 1/4×(-1) =-1

Answer»
32671.

Write the HCF of the smallest composite number and the smallest prime number

Answer» Smallest composite number =4 smallest prime number =2 hcf of 2and 4=2 ans =2*
32672.

23*6

Answer» 138
32673.

Obtain a factor of y^2-13y +12 by factor theorem .and factorise the polynomial

Answer»
32674.

2x+9y+10=0 find the value x

Answer» (-10-9Y )÷2
Y=10/9
32675.

Find all the zeroes f (x)=2x^3-7x^2+3x+6 if two of its zeroes are 3÷2×3÷2 and 3÷2×3÷2

Answer»
32676.

If the product of two zeroes of the polynomial 2x^3+3x^2-5x+6 is 3,then find its third zero.

Answer»
32677.

Linear combination

Answer» Linear
32678.

(234+4655)(24564)(4545%)

Answer»
32679.

what is the zeroes of the given polynomial 2x2-3x-4

Answer»
32680.

Hlooooooooooooo

Answer»
32681.

6x5+5x4+11x3-6x2-16x+18 divide by 3x2-15x+13

Answer»
32682.

Hlo guys am back anyone know me

Answer»
32683.

Prove that √p+√q is an irrational no.

Answer» Let
32684.

prove that √10 is irrational

Answer»
32685.

Vedic maths

Answer»
32686.

Prove root 6 is irrational

Answer» Ya but it is process for such type of guestion but I want whole solution
By assuming root 6 as a rational number
32687.

Find the radio of circle when the area of a circle is 256

Answer» Circle no radio kem kadhvo
I think yur question is wrong
32688.

Is pie a rational?

Answer» No pie is not rational but its values are rational like 3.14,22/7 because they are not in their complete form so pie is irrational
Ya ri8 pie is not rational....
No
No pie is irrational
32689.

Show that the cube of any positive integer is either of the form 4m ,4m+1 or 4m+3 for some integer

Answer» Let a be the positive integer and b = 4.Then, by Euclid’s algorithm, a = 4q + r for some integer q ≥ 0 and r = 0, 1, 2, 3 because 0 ≤ r < 4.So, a = 4q or 4q + 1 or 4q + 2 or 4q + 3.{tex}(4q)^3\\;=\\;64q^3\\;=\\;4(16q^3){/tex}= 4m, where m is some integer.{tex}(4q+1)^3\\;=\\;64q^3+48q^2+12q+1=4(\\;16q^3+12q^2+3q)+1{/tex}= 4m + 1, where m is some integer.{tex}(4q+2)^3\\;=\\;64q^3+96q^2+48q+8=4(\\;16q^3+24q^2+12q+2){/tex}= 4m, where m is some integer.{tex}(4q+3)^3\\;=\\;64q^3+144q^2+108q+27{/tex}=4×(16q3+36q2+27q+6)+3= 4m + 3, where m is some integer.Hence, The cube of any positive integer is of the form 4m, 4m + 1 or 4m + 3 for some integer m.
32690.

64x²-25y²

Answer» (8x)^2 - (5y)^2 A^2 - B^2=(a+b)(a-b)=> (8x+5y)(8x-5y).
32691.

4+4 ka half kitna hota hai

Answer» How 6
How 6
4
6
32692.

Best practice books for secondary classes

Answer» NCERT
Ncert also use it\'s really help in board
RS or RD
32693.

5x+7y=3 nd 2x+3y=5 by substitution method

Answer»
32694.

How to prove root 3 is irrational

Answer» By using contradict method
32695.

If tanA=x/y,then cosA is equal to

Answer» Cos A = y/ x^2+y^2
32696.

NCRT book exercise 3.2 Q6

Answer» https://youtu.be/ecQKmwvij58You can see the answer by clicking this above link
32697.

Find k 2k+3=56

Answer» Thanks to all but
The answer is 53/2
2k + 3 = 562k = 56 - 32k = 53k = 53/2
2k+3=562k=56-32k=53K=53/2 Ans
53/2
32698.

Find the volume of largest cone which can be cut out from the sphere of 6 cm

Answer»
32699.

state any four methods to find the solution of a system of linear equation in two variables .

Answer» reply quickly plźz
sorry but please one more method
Another method is comparison method
please give me one more method
Elimination method,Substitution method,Cross multiplication method ,Graphical method
32700.

255555000999+522222222222-6333333

Answer» 307,770,889,888
777770889888..is correct ans.yaar kanj.is right
777770889888
547771389888