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32851.

Therom lesson exercise 6.1 questions and answers I want

Answer» But here it is not possible ?
32852.

If d= HCF(48,72)then find the value of d

Answer» d=24
32853.

Find a quadratic polynomial each with the given no.as the sum and product of it\'s zeros respected

Answer» f(x)=x square - (sum of zeroes)x + (product of zeroes)
P(x) = x^2-(sum of its zeros)x + product of its zeros
32854.

Mathematics compartment class. Tenth

Answer»
32855.

factorize 3x^2-2×√(6)+2

Answer»
32856.

Find the number of term in the AP 17, 14 1/2, 12.........-38.

Answer» Here , a=17, d=-3, and anth term =-38. So we can easily find n
Use :Anth term =a+(n-1)d
Hey u are here
Easy question.. Just use formula
32857.

Please tell me formulas of maths how to pass in compartment

Answer» Keep practicing and hardworking is only that the formula to pass in maths
32858.

In mode what we let f0 if the f1 is first frequency

Answer»
32859.

cos A - sin A +1/cos A + sin A - 1 = cosecA + cot A

Answer» Ya me too
Any help related to study then msg me ?????
Good morning
Good morning
It\'s to easy ?????
Ya me
Is anyone online here
32860.

Anyone need my th12 ? with experience 125.?

Answer» Meet me in coc take my code of th9- y8cvo9qjr
Ok give it to me
X minus 3 X 3 Y - 3 is equal to zero 3x - 9 by minus 2 is equal to zero
32861.

Find the mean of assume method of question no 4 of exercise 4.1

Answer» 4
32862.

If the mth term of an A.P be 1/n and nt term be 1/m , then show that its (mn)th term is 1

Answer» Let a and d be the first term and common difference respectively of the given A.P. Thenan = a + (n - 1)d{tex}\\frac { 1 } { n } ={/tex}\xa0mth term\xa0{tex}\\Rightarrow \\frac { 1 } { n } {/tex}= a + ( m - 1 ) d\xa0...(i){tex}\\frac { 1 } { m }{/tex}= nth term{tex}\\Rightarrow \\frac { 1 } { m } {/tex}= a + ( n - 1 ) d\xa0...(ii)On subtracting equation (ii) from equation (i), we get{tex}\\frac { 1 } { n } - \\frac { 1 } { m } = {/tex} [a+ (m-1) d] -[ a+ (n -1)d]= a + md - d - a - nd + d{tex}= ( m - n ) d{/tex}{tex} \\Rightarrow \\frac { m - n } { m n } = ( m - n ) d {/tex}{tex}\\Rightarrow d = \\frac { 1 } { m n }{/tex}Putting d = {tex}\\frac { 1 } { m n }{/tex}\xa0in equation (i), we get{tex}\\frac { 1 } { n } = a + \\frac { ( m - 1 ) } { m n } {/tex}{tex}\\Rightarrow \\frac { 1 } { n } = a + \\frac { 1 } { n } - \\frac { 1 } { m n } {/tex}{tex}\\Rightarrow a = \\frac { 1 } { m n }{/tex}{tex}\\therefore{/tex}\xa0(mn)th term = a + (mn - 1) d=\xa0{tex}\\frac { 1 } { m n } + ( m n - 1 ) \\frac { 1 } { m n } {/tex}{tex}\\left[ \\because a = \\frac { 1 } { m n } = d \\right]{/tex}= {tex}\\frac { 1 } { m n } + \\frac { mn } { m n } - \\frac { 1 } { m n }{/tex}= 1
32863.

How to see all subject in off line mode when we downloading the pdf

Answer» In offline content!!
32864.

The sum of 5th and 7th terms of an A.P is 52 and its nth term is 46.Find the A.P.

Answer»
32865.

Which publication practice papers would be the best for boards ????

Answer»
32866.

Hlo friends !

Answer» Anyone online here??????????
From where are you???
Hiiii
32867.

Hlo friends,

Answer» ok
Hello Aarohi
Good?☺
Hlo
I am new in my cbse guide
32868.

Theedvjt dr456 7y4 ghdr

Answer» What do you want to say??????Write properly please?
32869.

Find "x" if 6x^2+5x+1

Answer» Because after 5x., - 1is comeThen the answer is 1/6&-1
!your questions is wrong
32870.

Who invented zero???

Answer» Ji, vahi aryabhatta Jiski phle kisi ne ni suniPhir marne ke baad nobel prize diya
0 was invented by the indian mathematician Aryabhatta.
0 WAS INVENTED BY A MATHEMATICIAN ARYABHATTA
Aryabhatta
Aryabhatta
Aryabhatta
Aryabhatta
Aryabhatt
32871.

Divide 123 rupees A and B. So that B will get as many as many 25 praise coins as 50 coins gets.

Answer»
32872.

1+2=4 proove this

Answer» But 1+2=3 not 4
The question seems to be wrong
32873.

Solve graphically the system of linear equation: x+ y= 3,3x-2y=4

Answer» X+y=3X=5In place of x we can take 5then5+y=3Y=3-5Y=-2
32874.

Solve the following equation:4/x +5y=7 and 3/x + +4 y=5

Answer» The given system of equations is{tex}\\frac{4}{x} + 5y = 7{/tex} ....(1){tex}\\frac{3}{x} + 4y = 5{/tex} .....(2)Put {tex}\\frac{1}{x} = X{/tex} ....(3)Then equations (1) and (2) can be rewritten as4X + 5y = 7 ....(4)3X + 4y = 5 .....(5){tex}\\Rightarrow{/tex} 4X + 5y - 7 = 0 ....(6)3X + 4y - 5 = 0 .....(7)Then,{tex}\\frac{X}{{(5)( - 5) - ( 4)( - 7)}} = \\frac{y}{{( - 7)(3) - ( - 5)(4)}}{/tex}{tex}= \\frac{1}{{(4)(4) - (3)(5)}}{/tex}{tex}\\Rightarrow \\;\\frac{X}{{ - 25 + 28}} = \\frac{y}{{ - 21 + 20}} = \\frac{1}{{16 - 15}}{/tex}{tex}\\Rightarrow \\;\\frac{X}{3} = \\frac{y}{-1} = \\frac{1}{1}{/tex}{tex}\\Rightarrow{/tex} X = 3 and y = -1{tex} \\Rightarrow \\;\\frac{1}{x} = 3{/tex} and y = -1 ....using (3){tex}\\Rightarrow \\;x = \\frac{1}{3}{/tex} and y = -1Hence, the solution of the given system of equations is{tex}x = \\frac{1}{3}{/tex}, y = -1Verification : Substituting {tex}x = \\frac{1}{3}{/tex}, y = -1,We find that both the equations (1) and (2) are satisfied as shown below{tex}\\frac{4}{x} + 5y = \\frac{4}{{\\left( {\\frac{1}{3}} \\right)}} + 5( - 1) = 12 - 5 = 7{/tex}{tex}\\frac{3}{x} + 4y = \\frac{3}{{\\left( {\\frac{1}{3}} \\right)}} + 4( - 1) = 9 - 4 = 5{/tex}Hence, the solution of the given system of equations is {tex}x = \\frac{1}{3}{/tex}, y = -1
32875.

Are coincident lines consistent?

Answer» Yes
s
Yes buddy?
Yes
32876.

Solve:-4x^2-10x(a+b)+6a^2+13ab+6b^2=0

Answer»
32877.

what is the HCF of small composit and prime number

Answer» The HCF is two
Smallest prime no.is2Smallest composite no. Is 4Now find the HCF
32878.

CosQ=what?

Answer» B/H (Base/ height)
1/secQ
Base/height
CosQ=B/H
32879.

best refrence book for maths

Answer» NCERT. Rd sharma. Rsaggrawal etc and for question bank is pk garg
32880.

best refrence bool for maths

Answer» Ncert is must .{ you should read the given theory too}After ncert solve ncert exampler.complete sample paper and last years paperBy this you confidence level would increase For further practise do RS AGARWAL and RD SHARMA
32881.

What is the Use of solving last 5 years paperin board exam

Answer» Solving previous years paper will give you a very good experience of the questions asked in board exams
helps in experincing for board exam...nothing more
32882.

Find the quadratic polynomial for for given sum and product i.0,√5

Answer» x^2+√5
X^2+5
xx-0+5
32883.

tan(a+b-c)=1, sec(b+c-a)=2

Answer»
32884.

2x+y=52x+3x=8 By substitution method

Answer» Y = 23/5 and X=5/1
32885.

Will any optional questions from any chapter will come in matriculation exam...

Answer» Yes.....
32886.

2+√5 is ______no

Answer» Irrational no.
Irrational
32887.

Prove that if x and y are both odd positive integers the x^2+y^2 is even but not divisible by 4

Answer» As we know that every positive odd integer is in the form of 2m+1. So, let. X=2m+1. And. Y=2n+1. And then solve accordingly
32888.

if the product of zeroes of the polynomial ax2-6x-6 is 4 find the value of a

Answer» -3/2
2
32889.

Theurms of triangle chapter

Answer»
32890.

There\'s of triangle chapter

Answer»
32891.

How we score good marks in mathematics

Answer» Practice makes a man perfect
Solve the paper last question to upper question
32892.

What and how basically trignometery applied

Answer»
32893.

Find the value of a

Answer» GC
32894.

x+3-y=wvt find k

Answer» K is not k=0
32895.

Find the co ordinates of the point on x axis

Answer» Find. The distance between the point 2,3 and 4,3
32896.

Circle chapter me sare formula batho

Answer» Math book se Nahi padte
32897.

Thales theroer

Answer»
32898.

split 13 to get 18

Answer» It can be 6×3,9×2 and 18×1 only.but in all the three cases sum is not coming 13. So another method should be applied-you should try completing the square method.
32899.

2x+3y+5=0

Answer»
32900.

What is a prime number

Answer» A number that is divisible only by itself and 1!!!!(ex:-2,3,5,7)
A prime number is a number that has no other factor except 1 or itself