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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 33001. |
3x+5x=0 |
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Answer» 3x+5x=08x=0X=0/8 0X=0 ans 3x + 5x =0 Then , 8x=0 x=0/8So x =0 X = 0 |
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| 33002. |
Value of sin45 geometricaly |
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Answer» But how to find it ? one by root 2 |
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| 33003. |
xsquare +5/6=√45/24 |
| Answer» | |
| 33004. |
Prove root 2 is irrational number |
| Answer» refer to examples given in ncert book | |
| 33005. |
Find two cnsecutive positsve integer sum of whose s CBSE class 10th exercise 4.2 |
| Answer» Vikas | |
| 33006. |
Guy wisdom |
| Answer» Awful | |
| 33007. |
How can you prove theorm |
| Answer» which theorem | |
| 33008. |
By splitting the middle term what do we get in this question : 4x raise to 2 - 12x + 9 |
| Answer» 4x^2-6x-6x+92X(2x+3) -3(2x+3)(2x+3)(2x-3) it is zero when 2x+3=0 & 2x-3=0X=-3/2 & X=3/2 | |
| 33009. |
Find the value of (-1)+(-1)2n+(-1)2n+1+(-1)4n-1where n is postive odd integer |
| Answer» Answer | |
| 33010. |
If sin A =3_4 CALCULATE COS A AND TANA |
| Answer» | |
| 33011. |
How many 3digit number leaves the remainder 2. When divided by 4 |
| Answer» | |
| 33012. |
(87)+(89)=87% |
| Answer» | |
| 33013. |
8x²-22x-21 |
| Answer» 8x^2-(28-6)x-21=8x^2-28x+6x-21=4x(2x-7)+3(2x-7)=(4x+3)(2x-7)Ans | |
| 33014. |
Complete squaring method?? |
| Answer» | |
| 33015. |
can cbse pass students in compartment |
| Answer» | |
| 33016. |
Obtain all roots of polynomial x^4-3x^3-x^2+9x-6 if 2 of its Zeros are √3 and -√3 |
| Answer» Answer | |
| 33017. |
How many numbers of two digits are divisible by 8. Of ch- Arithmetic progressions |
| Answer» a=16d=8n=?SoTn=a+(n-1)d=9616+(n-1)8=96n=11 | |
| 33018. |
Find x if sin 3x =√3÷2 |
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Answer» 20 degree 20 ഡിഗ്രി 20 degree |
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| 33019. |
Irrational |
| Answer» The numbers that are not rational.or the numbers that are non terminating and non repeating | |
| 33020. |
4+3 (5-2)=4+(3*3)= |
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Answer» 13 13 13 13 |
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| 33021. |
4x+3y=122x+2y=5 |
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Answer» What do you mean to do? ??? 4x+3y=122x+2y=5It has only one solution.Ab iske aage kya karna hai Question kya hai Kya karna hai |
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| 33022. |
Chapter 3 mai puri equation nhi hai |
| Answer» | |
| 33023. |
Determine algabrically whether the pair of linear equations 3x-5y=-1 2x-y=-3 |
| Answer» You will tell me | |
| 33024. |
Perimeter theorem |
| Answer» | |
| 33025. |
Conversion from binary number to decimal number |
| Answer» 0and1 | |
| 33026. |
If the equations 4x +py=12 and px +3y =6 are dependent,the value of p is |
| Answer» Given linear equation is 4x + py + 8 = 0 and 2x + 2y + 2 = 0.So, 4x + py + 8 = 0 ...(1)and 2x + 2y + 2 = 0 ...(2)a1 = 4, b1 = p, c1 = 8, a2= 2 , b2 = 2 and c2 = 2The condition of unique solution,\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } \\neq \\frac { b _ { 1 } } { b _ { 2 } }{/tex}Hence,{tex}\\frac { 4 } { 2 } \\neq \\frac { p } { 2 } \\text { or } \\frac { 2 } { 1 } \\neq \\frac { p } { 2 }{/tex}{tex}p \\neq 4{/tex}The value of p is other than 4 it may be 1,2,3, - 4 ,.... etc. | |
| 33027. |
Find 2 irrational no. Btween 2 and 3 |
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Answer» 2.443565785 /2.987654321 2.12345678934562.......2.76589032467........ |
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| 33028. |
Find-sec^2 37-cot^2 53.tan21.tan 69-sin 51.cos49-cos51.sin49 |
| Answer» | |
| 33029. |
Compartment ka exam easy hoga ya hard |
| Answer» The will depend on how you prepare for it? | |
| 33030. |
5 different methods of proving pythagoras theorem |
| Answer» | |
| 33031. |
Rohan mother is 26years older than him.the product of their ages |
| Answer» Rohan=x and Rohan\'s mother =26-x So, the product of their ages =x(26-x) | |
| 33032. |
Whats the need to study ncert and exempler of class 9 in board!!!? |
| Answer» | |
| 33033. |
Is there any proof for sin theta = perpenducular / height |
| Answer» | |
| 33034. |
2÷x_5÷x+2=0 |
| Answer» | |
| 33035. |
Solve by elimination method. 2x+y=3,3x+4y=5 |
| Answer» (2x + y= 3) × 3. ----1(3x + 4y=5) × 2. ----2From 1 & 2 we get;6x + 3y = 96x + 8y =10--------------------- -5y= -1So, y = 1/5Then, 2x= 3-1/5 2x =14/5X= 14/10 | |
| 33036. |
Find HCF of 196 and 38220 by using Euclid division algorithm. |
| Answer» | |
| 33037. |
2x(x)+x-528=0 |
| Answer» | |
| 33038. |
If the zeros of polynomial ax³–ax²+bx–c are in AP. Prove that 2a³–9ab+c=0. |
| Answer» | |
| 33039. |
2015 cbsc maths paper |
| Answer» | |
| 33040. |
What is the value of (cos²67°-sin²23°) |
| Answer» | |
| 33041. |
Find the value of x for which 8x plus 4,6x-2 and 2xplus7 are in A.p. |
| Answer» X = 15/2 ....... is it correct? | |
| 33042. |
root-2x to the power 0.Is it a polynomial? |
| Answer» Yes | |
| 33043. |
A+C =3π/4 than (1+cotA)(1+cotC) equals |
| Answer» (1+cot(3π/4-C)(1+cotC)(1+cot(π-π/4-C)(1+cotC)(1+cot(π/4+C)(1+cotC)1+1/tan(π/4+C))(1+1/tanC)(1+1-tanC/1+tanC)(1+1/tanC)(2cotC)(1+cotC) | |
| 33044. |
Smallest co prime no |
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Answer» 2 2,3 2 |
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| 33045. |
find the distance of a point p(x,y) form the origin |
| Answer» {tex}\\sqrt {{x^2} + {y^2}} {/tex} | |
| 33046. |
If x=2 & y=3are roots of the equation 3xsqure-2kx+2m find the value of k&m |
| Answer» It is given that x = 2 and x = 3 are roots of the equation 3x2 - 2kx + 2m = 0.{tex}\\therefore{/tex} 3 {tex}\\times{/tex}\xa022 - 2k {tex}\\times{/tex}\xa02 + 2m = 0 and 3 {tex}\\times{/tex}\xa032 - 2k {tex}\\times{/tex}\xa03 + 2m = 0{tex}\\Rightarrow{/tex}\xa012 - 4k\xa0+ 2m = 0 and 27 - 6k\xa0+ 2m = 0{tex}\\Rightarrow{/tex}\xa012 = 4k\xa0- 2m...(i) and 27 = 6k - 2m...(ii)Solving i and ii equation, we get k =\xa0{tex}\\frac { 15 } { 2 }{/tex}\xa0and m = 9 | |
| 33047. |
Sin(1+tan)+cos (1+cot)=(sec+cosec) |
| Answer» | |
| 33048. |
_39. _33. _29 |
| Answer» | |
| 33049. |
If sin +cos=a prove sin6+cos6=4-3(a²-1)²/4 |
| Answer» LHS{tex} = {\\sin ^6}\\theta + {\\cos ^6}\\theta {/tex}{tex} = {\\left( {{{\\sin }^2}\\theta } \\right)^3} + {\\left( {{{\\cos }^2}\\theta } \\right)^3}{/tex}{tex} = {\\left( {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta } \\right)^3} - 3{\\sin ^2}\\theta {\\cos ^2}\\theta \\left( {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta } \\right){/tex}{tex}\\left[ {\\because {a^3} + {b^3} = {{(a + b)}^3} - 3ab(a + b)} \\right]{/tex}{tex} = {(1)^3} - 3{\\sin ^2}\\theta {\\cos ^2}\\theta \\times 1{/tex}\xa0{tex}\\left[ {\\because {{\\sin }^2}\\theta + {{\\cos }^2}\\theta = 1} \\right]{/tex}{tex} = 1 - 3{\\sin ^2}\\theta {\\cos ^2}\\theta {/tex}RHS\xa0{tex} = \\frac{{4 - 3{{({x^2} - 1)}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {{{\\left( {\\sin \\theta + \\cos \\theta } \\right)}^2} - 1} \\right\\}}^2}}}{4}{/tex}\xa0{tex}\\left[ {given\\;x = \\sin \\theta + \\cos \\theta } \\right]{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {{{\\sin }^2}\\theta + {{\\cos }^2}\\theta + 2\\sin \\theta \\cos \\theta - 1} \\right\\}}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3{{\\left\\{ {1 + 2\\sin \\theta \\cos \\theta - 1} \\right\\}}^2}}}{4}{/tex}\xa0{tex}\\left[ {\\because {{\\sin }^2}\\theta + {{\\cos }^2}\\theta = 1} \\right]{/tex}{tex} = \\frac{{4 - 3{{\\left( {2\\sin \\theta \\cos \\theta } \\right)}^2}}}{4}{/tex}{tex} = \\frac{{4 - 3 \\times 4{{\\sin }^2}\\theta {{\\cos }^2}\\theta }}{4}{/tex}{tex} = \\frac{{4\\left( {1 - 3{{\\sin }^2}\\theta {{\\cos }^2}\\theta } \\right)}}{4}{/tex}LHS = RHSHence proved. | |
| 33050. |
Sin 36 =2 sin 18 cos18 |
| Answer» | |