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33351.

Determine graphically the cordinates of the vertices of a triangle whose equation is 2x-3y+c=0

Answer»
33352.

If p and q are two prime numbers then what is the hcf and lcm of p and q.

Answer» H.C.F.= 1LCM= pq
33353.

What is the HCF of smallest prime number and smallest complete number?

Answer» smallest prime no is2 and composite no is 4 and hcf of 2 4 is 2
33354.

how to change sign in elimination methord sometimes it become (-) (+)=+ how???

Answer» yes
swati tum ya kahna cahati ho ki agar upper (-) ha aur neecha (-) toh change nhii hoga sirf + and - change hoga
but agar unka sign same h to sign nahi change hota
Niche jo sab number honge unko dekhna......... Jo positive jonge.... Wahan - hoge..... Aur negative hoge to +
33355.

If alpha and beta are zeros of polynomial f(x)=x^2-p(x+1)-c then find alpha + 1into beta +1

Answer»
33356.

General bterm of a p

Answer»
33357.

Poduram

Answer»
33358.

Give to me the question of linear equation so that I can solve

Answer» Buy rd sharma book or rs aggrawal or s.chand......There are thousands of questions which u can solve ?
33359.

Express 1001 as a product of its prime factor

Answer» 7×11×13
7×11×13
33360.

Prove that Cosec2A-Tan2A(90-A)=Sin2A+Sin(90+A)

Answer»
33361.

Formula of (a+b) ³

Answer» acube+bcube+3ab(a+b)
a3+b3+3ab(a+b).....
Assistance
33362.

Find the value of K for which the equation x²+K(2x+k-1)+2=0 has equal and real roots.

Answer» k = 2
33363.

prove that 3 root 5 is irrational

Answer» let 3 and root 5 is irratonal no and 1 upon 3 is also irratonal no then multiply it to 3 root 5 then root 5 is required tand we know that root five is irrational mo
33364.

3x4-16x3+26x2-16x+3=0

Answer»
33365.

Application of mathematics in other fields

Answer» PhysicsChemistry
33366.

Middle term sipliting of 6x+10x+12

Answer» Ans. is(16x+12)
Thers should be square on first term
I think you should once check the question.
33367.

A square + b square ka equal to

Answer» a^2+b^2= (a+b)^2- 2ab
No, priyanka you are wrong it is a2+b2+2ab
A Plus b ka whole square minus 2 a.b
a2+b2+2ab*
A2+b2 become (a+b)2=a2+b2+ab
33368.

Cbse syllabus for10 math

Answer» all chapters of ncert book ? in syllabus.
All the chapters in the ncert booj
33369.

If one zero of the polynomial 5z

Answer»
33370.

Prove that :(1-sin०+cos०)sq=2(1+cos०)(1-sin०)

Answer»
33371.

Draw the stars of cubic and cube holiday the different sources with colours with clear vision

Answer»
33372.

what is co - prime number

Answer» Two no.s having HCF as 1.eg. 5,6;2,3;17,15 etc.
please give any example
Two natural numbers having no common factors other than1
33373.

if x = 3 is one root of the quadratic equation x2 -2kx -6= 0,then find the value of x.

Answer» 1/2
33374.

Find the 10th term from the end of A.P 8,10,12-----------------126

Answer» Here the common difference is 2.It\'s first term is 8.Therefore, 10th term = First term + {(10-1)× common difference}=8+{9×2}=8+18=26
26
33375.

If 9 sec^2-9 tan^2=. Then solve it

Answer» 9
33376.

If 3x + 5 is a factor of a polynomial 6 X square + 16 X cube+ 3x-5 then find the value of p

Answer» What a question
Where is p in question
Sakshi Rai, please check your question.??
33377.

2 root 3x ^2-5x+root 3

Answer» Hello This is only test purpose you remove it from answer√ 4√ 5
Hello
First Step: Multiplication of first and Last Number (2root 3* root 3 = 2*3 = 6)(2) Step: if last sign is Plus (+) Multiplication Start Before the Middle Number (4*1 = 4, then 3*2 = 6)so Our Factor is 3*2now2root3 x^2- 3x - 2x + root 32 root 3 x^2- root 3* root 3 x - 2x + root 3root 3x (2x - root 3) - 1 (2x - root 3)(2x - root 3) (root 3x -1)p(x) = 00 = (2x - root 3) (root 3x - 1)x= root 3/2 or x= 1/root 3
33378.

X+ 11 y= 1 ,8 x+13 y = 2 solve by elimination and subsitituon method

Answer» Mark x+11y=1 as eq.1 and 8x+13y=2 as eq.2 . Now multiply eq1 by eq2 and then subtract the results. After subtraction x=9/75. Put x=9/75 in eq 1. It will give y=66/825 . Hence x=9/75 and y=66/825
33379.

1+2=5 how\'s that possible justify?

Answer» Galti se it is possible
Don\'t waste our time.??
33380.

Given sec tetha is equal to 13/12 calculate all other trigonometric ratios.

Answer» This is the step wise answer-First draw a right triangleGiven,sec theta=13/12.So,sec theta=h/bHence,h=13 and b=12Now finding p by Pythagoras theorem we get p=5Now,Sin theta=p/h=5/13Cos theta=b/h=12/13Tan theta=p/b=5/12Cot theta=b/p=12/5Cosec theta=h/p=13/5.
Sin theta=5/13 , cos theta=12/13 , tan theta=5/12 , cosec theta=13/5 , cot theta= 12/5
Sec theeta =13/12 , Cos theeta =12/13 , Sin theeta =5/13 , Cosec theeta =13/5 , Tan theeta =5/12 , Cot theeta =12/5
Sec theta =13/12 means hypotenuse=13 nd base 12 by Pythagoras theorem perpendicular 5 and we can calculate other ratios
33381.

Write the importance of zero in maths

Answer» 0 (zero) is both a number and the numerical digit used to represent that number in numerals. The number 0 fulfills a central role in mathematics as the additive identity of the integers, real numbers, and many other algebraic structures. As a digit, 0 is used as a placeholder in place value systems.
33382.

Square root of 161415

Answer» 401.764856601
33383.

Solution of a quadratic eqn by completing the square. How to find it

Answer» We have, 2x2 + x + 4 = 0Dividing both sides by 2, we get{tex}x^2 +{1 \\over 2}x + 2 = 0 {/tex}{tex}\\implies (x)^2 + {1 \\over 2}x + {1 \\over 16} = -2 + {1 \\over 16}{/tex}{tex}\\implies (x)^2 + 2(x) ({1 \\over 4})+ ({1 \\over4})^2= {- 32 +1 \\over 16}{/tex}{tex}\\implies (x + {1 \\over4})^2 = -{31 \\over 16} <0{/tex}Which is not possible, as square cannot be negative.So, there is no real value of x which satisfy the given equation.Therefore, the given equation has no real roots.
33384.

Find tha value of root 2

Answer» 1.414
33385.

X= 1+ 5 to the power 1/3+5 to the power 2/3Find the value of\tx cube - 3 square - 12x+6

Answer»
33386.

152x-378y=-74-378x+152y=-604Solve this by elimination method

Answer» 152x-378y=-74 .....(1)-378x+152y=-604 .....(2)Adding (1) and (2), we get-226x-226y=-678x+y=3 ....(3)Subtracting (2) from (1), we get530x-530y=530x-y=1 ....(4)Adding (3) and (4),we get2x=4=x=2x+y=3=2+y=3y=1
33387.

It is in the ap 3,4,5

Answer» Yes
33388.

In a ∆ABC, right angled at B, if AB=5,AC=12and BC=13, find the value of cosC and tanB.

Answer» 13/12 is the value of cos c
I think the question is wrong....
33389.

What is a scalar quantity

Answer»
33390.

Kaun kaun konsa sub loge

Answer» Science
PCB
Science
33391.

Find the value of k for which a system equation 3x+y=1 and (2k-1)x + (k-1)y=2k-1

Answer» Question is incomplete
33392.

Find the value of k for which a system equation 3x+y=1 and (2k-1)x+(k-1)y=2k+1

Answer» The given pair of linear equation is3x + y = 1, (2k - 1) x + (k - 1) y = 2k + 1{tex}\\Rightarrow{/tex} 3x + y - 1 = 0Here, (2k - 1)x + (k - 1) y - (2k + 1) = 0a1 = 3, b1 = 1, c1 = -1a2 = 2k - 1, b2 = k - 1, c2 = -(2k + 1)for having no solution, we must have {tex}\\frac{{{a_1}}}{{{a_2}}} = \\frac{{{b_1}}}{{{b_2}}} \\ne \\frac{{{c_1}}}{{{c_2}}}{/tex}{tex}\\Rightarrow \\frac{3}{{2k - 1}} = \\frac{1}{{k - 1}} \\ne \\frac{{ - 1}}{{ - (2k + 1)}}{/tex}From above we have\xa0{tex}\\frac{3}{{2k - 1}} = \\frac{1}{{k - 1}}{/tex}{tex}\\Rightarrow{/tex} 3(k - 1) = 2k - 1{tex}\\Rightarrow{/tex} 3k - 3 = 2k - 1{tex}\\Rightarrow{/tex} 3k - 2k = 3 - 1{tex}\\Rightarrow{/tex} k = 2Hence, the required value of k is 2.
33393.

Rdvhhghu

Answer» What do you mean by Rdvhhghu ?
33394.

Prove that sin^2theeta + cos^2theeta=1

Answer»
33395.

What are trigonometric identities

Answer»
33396.

How to define volume of frustum

Answer» {tex}\\frac{1}{3}\\pi h({r_1}^2 + {r_2}^2 + {r_1}{r_2}){\\text{ }}c{m^3}{/tex}
33397.

x+y=a+bax+by=a2+b2

Answer» X=a and y =b
33398.

Least prime number

Answer» 2
2
2
33399.

( sec2 teta- 1)(cosec2 teta- 1)=1

Answer»
33400.

Graphical and geometrical interpration of linear equation in two variable .plz give me good wnswera

Answer» Exercise kon sa h