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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 33401. |
555/543 |
| Answer» 1. 022099 | |
| 33402. |
ax + by = cBx + ay = 1 + cSolve it value of x and y? |
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Answer» You can see it, in this in ncrt solution Please guys try it quickly ✍️✍️✍️✍️ |
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| 33403. |
Explan theEx 1.1 Quc .no1 &2 |
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Answer» In second question u have to show postive odd integer in 6q+1..... So u use (a=bq+r where r=0,1,2,3,4,5) Sorry bro i dont know why its not comingBut u can refer page 3, theorem 1.1 0 Solution dekh ke samajh lo |
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| 33404. |
In a given AP if Pth term is q and the qth term is p then show that the nth term is ( p+q-n) |
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| 33405. |
If x =(a+b)/2 where a and b are rational numbers,then x is? |
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| 33406. |
x²-3²=? |
| Answer» X2=9X=+-3 | |
| 33407. |
Please give me all answers of worksheet of Army Public School Mathura Cantt of all subject |
| Answer» Me from Army Public school Gorakhpur... Anyone also their???? | |
| 33408. |
Find the vakue of k if (x-2) is a factor of 2x-6x+5x+k |
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Answer» Value of k = -2 K=-2 Value of k= -2 0 |
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| 33409. |
Chechk whether x=3 zero of polynomial x³-3x+x-3!!! Plz ans it fastly..... |
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Answer» 3^3-3*3+3-3=27-9+0=18 Yes,x=3 is a zero of polynomial x³-3x+x-3.. .. by putting value of x=3,we get....................... 3³-3(3)+3-3--->9-9+3-3=0 . Zero aa rha h solve krke dekhlo U borh r wrong....ans yes hoga No it\'s not No it is not |
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| 33410. |
Kx(x-2√5)+10 |
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| 33411. |
Prove that cube root of 2 is irrational. |
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| 33412. |
Elimination methad 2x+2y=10 2x-3y=4 |
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Answer» X=3.8Y=1.2 y=6 is answer Im Aditi remember? Hi ritik Chaudhary |
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| 33413. |
To know whether 13÷3125 will have terminating decimal expansion or not |
| Answer» No it is non terminating | |
| 33414. |
i want to take maths tuison plZ HELP ME |
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Answer» nowgong mp Ya ri8 u can go ur nearest or best coaching center..... Go to near by institute or center Where you live |
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| 33415. |
Find a quadratic polynomial whose zeros are (3+√5) and (3-√5) |
| Answer» Let, alpha =3+√5 & Bitta =3-√5Sum of the zeros (alpha+bitta) = 3+√5 + 3-√5 = 3+3 =6Product of the zeros (alpha×bitta) = 3+√5 × 3-√5 = (3)^2 - (√5)^2 = 9 - 5 = 4So, the required quadratic polynomial is (x^2 -(alpha+bitta)x + (alpha ×Bitta)x^2 - (6)x + (4)x^2 - 6x + 4 | |
| 33416. |
Rd sharma class 10th exercise 1.1 question no. 1 |
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| 33417. |
Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case |
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| 33418. |
The sum of two numbers is 1000 and the difference their squares is 256000. Find the numbers. |
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| 33419. |
Express 0.36 in the form of p by q |
| Answer» 9/25 | |
| 33420. |
7429 its prime factor can any one tell me plzzz |
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Answer» 17 * 19 * 23 7429 itself or 1 |
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| 33421. |
Make me clear of triangles theorem |
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| 33422. |
The area of square is 7056 m2. Find the perimeter of the square |
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Answer» Ar.=side sq. =7056 sq mt =√7056 =84Hence, side is 84Perimete = 4 * side =4 * 84 =336 m Firstly we find side by the formulla of .Area of square=sidesquare.7056squareroot=Side.84=side .Then,Perimeter of square=4×side.Perimeter=336m Area = 7056 m^2a^2 = 7056a= /7056a =84 mPerimeter = 4a= 4×84=336m |
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| 33423. |
(a-b)x+(a+b)y=2a2-2b2 (a+b)(x+y)=4ab Solve this by cross multiplication |
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Answer» The given system of equations are:(a - b)x + (a + b)y = 2a2 - 2b2So, (a - b)x + (a + b)y - 2a2 - 2b2 = 0\xa0(a - b)x + (a + b)y - 2(a2 - b2) = 0 ........(i)And (a + b)(x + y) = 4abSo, (a +b)x + (a + b)y - 4ab = 0 ..........(ii)The given system of equation is in the form ofa1x + b1y - c1 = 0and a2x + b2y - c2 = 0Compare (i) and (ii) , we geta1 = a - b, b1 = a + b, c1 = -2(a2 + b2)a2 = a + b, b2 = a + b, c2 = -4abBy cross-multiplication method{tex}\\frac{x}{{2(a + b)({a^2} - {b^2} + 2ab)}}{/tex}\xa0{tex} = \\frac{{ - y}}{{2(a - b)({a^2} + {b^2})}}{/tex}\xa0{tex} = \\frac{1}{{ - 2b(a + b)}}{/tex}Now, {tex}\\frac{x}{{2(a + b)({a^2} - {b^2} + 2ab)}} = \\frac{1}{{ - 2b(a + b)}}{/tex}\xa0{tex}{/tex}{tex}⇒ x = \\frac{{2ab - {a^2} + {b^2}}}{b}{/tex}And, {tex}\\frac{{ - y}}{{2(a - b)({a^2} + {b^2})}} = \\frac{1}{{ - 2b(a + b)}} {/tex}\xa0{tex}⇒ y = \\frac{{(a - b)({a^2} - {b^2})}}{{b(a + b)}}{/tex}The solution of the system of equations are\xa0{tex}\\frac{{2ab - {a^2} + {b^2}}}{b}{/tex}\xa0and {tex}\\frac{{(a - b)({a^2} - {b^2})}}{{b(a + b)}}{/tex}\xa0respectively. thanks |
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| 33424. |
From what all books should I prepare for boards |
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Answer» S chand book is the best book for you prachi ? For maths u should go for RD Sharma and for science S Chand |
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| 33425. |
what is a math |
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Answer» Maths is very Interesting subject?? Calculation of 1234567890?☺️???????????️?️?️✨??️♥️?? Interesting subject |
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| 33426. |
What is angular elevation of sum? |
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| 33427. |
If A= 2n+3 and B=n+7 where n is a natural number than HCF of A and B will Be??? |
| Answer» Taking different values of n, we find that A and B are co-prime.When {tex}n = 1, A = 5, B = 8{/tex}When {tex}n = 2, A = 7, B = 9{/tex}When {tex}n = 3, A = 9, B = 10{/tex} and so on....Therefore, {tex}HCF = 1{/tex} | |
| 33428. |
10/x+y+2/x-y=4 15÷x+y-15/x-y=-2 |
| Answer» {tex}\\frac { 10 } { x + y } + \\frac { 2 } { x - y } = 4{/tex}{tex}\\frac { 15 } { x + y } - \\frac { 9 } { x - y } = - 2{/tex}.Putting\xa0{tex}\\frac 1{x+y}{/tex}=u and\xa0{tex}\\frac 1{x-y}{/tex}= v\xa0,the given equations{tex}10u +\xa02v= 4{/tex}........(i){tex}15u -\xa09v = -2{/tex}.......(ii)Multiplying (i) by 9\xa0and (ii) by 2 and adding them,{tex}\\Rightarrow{/tex}\xa0{tex}90 u + 18 v = 36\\ and\\ 30u - 18v = -4{/tex}{tex}\\Rightarrow 120u = 32{/tex}{tex}\\Rightarrow u = \\frac{4}{15}{/tex}Substituting u =\xa0{tex}\\frac{4}{15}{/tex} in (i), we get v =\xa0{tex}\\frac { 2 } { 3 }{/tex}{tex}\\Rightarrow \\frac { 1 } { x + y } = \\frac { 4 } { 15 } \\text { and } \\frac { 1 } { x - y } = \\frac { 2 } { 3 }{/tex}{tex}\\Rightarrow x + y = \\frac { 15 } { 4 }{/tex}\xa0.......(iii)and\xa0{tex}x - y = \\frac { 3 } { 2 }{/tex}\xa0......(iv)Adding (iii) and (iv),\xa0{tex}\\Rightarrow 2 x = \\frac { 21 } { 4 } \\Rightarrow x = \\frac { 21 } { 8 }{/tex}Substituting x ={tex}\\frac { 21 } { 8}{/tex}\xa0in (iii), we get\xa0{tex}y = \\frac { 9 } { 8 }{/tex}Hence, the solution is\xa0{tex}x = \\frac { 21 } { 8 } \\text { and } v = \\frac { 9 } { 8 }{/tex} | |
| 33429. |
If the hcf of 657 and 963 is expressible in the form 657x + 963*(-15) find x |
| Answer» Given numbers are 657 and 963 .Here, 657 < 963\xa0By using Euclid\'s Division algorithmm , we get963 = (657 × 1) + 306Here , remainder = 306 .So, On taking 657 as new dividend and 306 as the new divisor and then apply Euclid\'s Division lemma, we get657 = (306 × 2) + 45Here, remainder = 45\xa0So, On taking 306\xa0as new dividend and 45\xa0as the new divisor and then apply Euclid\'s Division lemma, we get306 = (45 × 6) + 36Here, remainder = 36So, On taking 45\xa0as new dividend and 36\xa0as the new divisor and then apply Euclid\'s Division lemma, we get45 = (36 × 1) + 9Here, remainder = 9So, On taking 36\xa0as new dividend and 9\xa0as the new divisor and then apply Euclid\'s Division lemma, we get36 = (9 × 4) + 0Here , remainder = 0 and last divisor is 9.\xa0Hence, HCF of 657 and 963 = 9.∴ 9 = 657x + 963(-15)⇒ 9 = 657x - 14445⇒ 657x = 9 + 14445⇒ 657x = 14454⇒x = 14454/657⇒ x =22 | |
| 33430. |
find the value of 4/(216)-2/3 +1/(256)-3/4+2/(243)-1/5 |
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Answer» 1 0 |
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| 33431. |
4 sin A sin 2 A + 1-2 sin 2 A = 2 sin A ?? |
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| 33432. |
find the sum of first 51 terms of ap whose second and thired terms are14 &18 respectively |
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Answer» The ans.is 5610 notes of kings farmers and towns - class 12 history chapter |
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| 33433. |
25x2-64y2 |
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| 33434. |
Find the 11th term from the last term (towards the first term) of the ap : 10,7,4.....-62. |
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| 33435. |
Draw the graph of the polynomial f(x)equal to 3-2x-xsquare |
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Answer» Pagal hai kya But how I made in mobile yarr |
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| 33436. |
Show that there is no value of n for which 2^m*5^n ends in maths. |
| Answer» It is wrong qyes | |
| 33437. |
divide p[x] 5x4 subtract4x3 add 3x2 subtract 7x subtract 6 by g[x]x2subtract2 |
| Answer» can anyone solve my problem | |
| 33438. |
Cos^2theta÷1-tantheta+sin^3theta÷sintheta-costheta=1+sinthetacostheta |
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| 33439. |
How to solve chapter 5 |
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Answer» We have completed upto 1,2,3,4,7,8,9 You can solve chapter 5 by doing hard work and always focus on this chapter As being a NAVODAYAN I have completed all syllabus previous week ???????????✌????? Wow your syllabus is so fast ....i,m completed ch.1,2,3,4,8 |
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| 33440. |
Did anyone had buy the test paper of maths chapter 5 APIf yes then plz snd the screenshot |
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Answer» U r from which city???? I don\'t know how screen shot send in this app please tell? Dost yarr jann |
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| 33441. |
Find the point on x axis which is equidistant from (-2,5) and (2,3) |
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| 33442. |
What is tignametry |
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Answer» Tri means 3Gon means. SidesMetron means measure okkkk We divide this word in threee parts okk TRI. GON. METRON. 3. Sides. Measure I hope your confusion was cleared ☺☺☺☺☺ You mean trigonomatery????? |
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| 33443. |
Solve for x and y where x + y = a+ b and ax+ by= a^2 + b^2 |
| Answer» x + y = a + b multiply both sides with a we getax + ay = a^2 + ab ...(1)ax + by =a^2 + b^2 ...(2)(1) - (2) givesy(a+b) = b(a+b)So y =b (a+b)/(a+b)ie. y = bSubstitute y = b in the equation x+y=a+bx+b = a+bx = a+b-b. ie x= aSo x=a and y = b | |
| 33444. |
Solve this equation 3x^2+2√5x-5 by quadratic formula |
| Answer» 3x^2+2√5.x - 5 = 0Here a=3, b = 2√5 and c=-5x= {-b+or-√(b^2-4ac)}/2a={-2√5+or-√(20-4×3×(-5)}/6={-2√5 +or-√80}/6={-2√5 +or- 4√5}/6x=(-2√5+4√5)/6or (-2√5-4√5)/6x =2√5/6 or x= -6√5/6x=√5/3 or x = -√5 | |
| 33445. |
Prove that if x and are both odd positive integers then x* |
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| 33446. |
A juice seller was serving...... |
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| 33447. |
Find the simplest form of 561 upon 748 |
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| 33448. |
The decimal form of root 5 is repeating .Is it true give reason . |
| Answer» Because It is an irrational number. | |
| 33449. |
2+2×7÷49+8 |
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Answer» 24 10.28 10.28 2+2*7+82+14+824 |
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| 33450. |
Find the greatest number of 6 digits exactly divisible by 24, 15, 36 |
| Answer» First you take LCM of 24,15,36 =360 Then greatest no. Of 6digit 999999Divide 999999/360 You got some remainder Then you subtract 999999- remainder | |