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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3301. |
Prove that nth term of an A.P. cannot be n2+1. |
| Answer» | |
| 3302. |
Gyss koi bta skta h What is Brisk effervescence?? |
| Answer» Brisk effervescence is defined as the rapid or vigorous evolution of a gas in a chemical reaction. | |
| 3303. |
What is the meeting point of a circle and tangent called?? |
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Answer» Secant to jo circle me se pass hota hai vo hota hai Point of contact Nhi Secant |
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| 3304. |
Sahil sorry bye get lost |
| Answer» | |
| 3305. |
Elimination of trigonometric identity is included in syllabus or not? |
| Answer» Include in syllabus. | |
| 3306. |
Sin60ki value |
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Answer» Under root 3/2 Under root 3by 2 |
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| 3307. |
2+3+4_24&_46-$4 |
| Answer» | |
| 3308. |
prime number |
| Answer» Which is divisible by 1 and itself only. | |
| 3309. |
The answer of question 3 of exercise 14.2 |
| Answer» Mode =1847.83,mean=-0.175 | |
| 3310. |
2/x+2/3y=1/6;3/x+2/y=0 |
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| 3311. |
Since the CBSE Class 10th Model exams have been |
| Answer» | |
| 3312. |
Shviangi app na kbi Gand marvi ha |
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| 3313. |
I want excitement |
| Answer» | |
| 3314. |
Prove theorem of triangles |
| Answer» Without figure !! impossible | |
| 3315. |
For what values of k, are the roots of the equation 3x^2+2kx+27=0 real ang equal |
| Answer» We have the following equation,3x2\xa0- 2kx + 27\xa0= 0a = 3, b = -2k\xa0and c = 27{tex}\\therefore{/tex}\xa0D = b2\xa0- 4ac= (-2k)2\xa0- 4(3)(27)= 4k2 - 324Roots are real and equal if D = 0{tex}\\Rightarrow{/tex}\xa04k2\xa0- 324 = 0k\u200b\u200b\u200b\u200b\u200b\u200b2=\xa0{tex}\\frac { 324 } { 4 }{/tex} = 81{tex}\\therefore k = \\pm 9{/tex} | |
| 3316. |
what is your aim in board exam |
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| 3317. |
exam datesheet has been declared. |
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| 3318. |
what is scale factor? |
| Answer» | |
| 3319. |
If x+a is a factor of polynomial 2x²+2ax+5x+10 find the value of a |
| Answer» Here the given polynomial f(x)=2x2 + 2ax + 5x +10If x+a is a factor of f(x) then x+a=0 or x = -a{tex}\\Rightarrow{/tex}f(-a) = 0{tex}\\Rightarrow{/tex}2(-a)2 + 2a.(-a) + 5(-a) + 10 =0{tex}\\Rightarrow{/tex}2a2 - 2a2 -5a +10 =0{tex}\\Rightarrow{/tex}-5a = -10{tex}\\Rightarrow{/tex}a=2. | |
| 3320. |
Area of rohmbus |
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Answer» 1/2×product of its diagonals 1/2 × d1× d2 1/2(d1)(d2) |
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| 3321. |
If the mode of following frequency is10 |
| Answer» | |
| 3322. |
Vhufcvh |
| Answer» | |
| 3323. |
Sin3035 |
| Answer» | |
| 3324. |
10² |
| Answer» 100 | |
| 3325. |
My CBSE have selected dj as best student 2017 |
| Answer» | |
| 3326. |
The 7th term of an A.P. is 0 ...then prove tht 25th term is twice the 16 th term... |
| Answer» Nhi ata | |
| 3327. |
When will be our pre board |
| Answer» | |
| 3328. |
Which is the best dual camera phone under 17k |
| Answer» | |
| 3329. |
Koi fb pe hai |
| Answer» | |
| 3330. |
When 10th date sheet will be uploaded |
| Answer» | |
| 3331. |
How to get pass in maths?? |
| Answer» | |
| 3332. |
Who play con here |
| Answer» | |
| 3333. |
RIMSHA r u online plzz reply |
| Answer» | |
| 3334. |
prove that tangents from an external point to a circle are equal in length |
| Answer» Given: P is an external point to the circle C(O,r).PQ and PR are two tangents from P to the circle.To Prove: PQ = PRConstruction: Join OPProof:{tex}\\because{/tex}\xa0A tangent to a circle is perpendicular to the radius through the point of contact{tex}\\therefore{/tex}{tex}\\angle{/tex}OQP = 90o = {tex}\\angle{/tex}ORPNow in right triangles POQ and POR,OQ = OR [Each radius r]Hypotenuse. OP = Hypotenuse. OP [common]{tex}\\therefore{/tex}{tex}\\triangle{/tex}POQ\xa0{tex}\\cong{/tex}{tex}\\triangle{/tex}POR\xa0[By RHS rule]{tex}\\therefore{/tex} PQ = PR | |
| 3335. |
If 7sin^2 a - 3cos^2 =4 then prove tan a = 1\\√3 |
| Answer» | |
| 3336. |
Introduction to trignomentry |
| Answer» Tri = three , gono = sides , metry = study !! The study of three sides of a triangle ( only right triangle ) and theis correspondiang angles is knkwn as trigonometry | |
| 3337. |
who knows देहाती भाषा? |
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| 3338. |
Who is robert hook |
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Answer» Robert Hooke was the one who discovered cell Tnx Robert Hooke was the person who discovered cell.. |
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| 3339. |
Oo ho jii aaj kisiko mood Alag hai |
| Answer» Kon | |
| 3340. |
what is the formuales for hollow solids |
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| 3341. |
Solve cuve Root of 25 by divisional method |
| Answer» | |
| 3342. |
RIMSHA where r u plzz come |
| Answer» | |
| 3343. |
Any one having instagram account |
| Answer» | |
| 3344. |
if PS is the bisector of |
| Answer» Given: In figure. PS is the bisector of\xa0{tex}\\angle QPR{/tex} of\xa0{tex}\\triangle PQR{/tex}To prove :{tex}\\frac { Q S } { S R } = \\frac { P Q } { P R }{/tex}Construction: Draw RT || SP to meet QP produced in T.Proof:\xa0{tex}\\because {/tex}\xa0RT||SP and transversal PR intersects them{tex}\\therefore \\angle 1 = \\angle 2{/tex}\xa0(1) ..... Alt. Int.\xa0{tex}\\angle s{/tex}{tex}\\because {/tex}\xa0RT||SP and transversal QT intersects them{tex}\\therefore \\angle 3 = \\angle 4{/tex} (2), ..... corres.\xa0{tex}\\angle s{/tex}But\xa0{tex}\\angle 1 = \\angle 3{/tex}\xa0...... Given{tex}\\therefore \\angle 2 = \\angle 4{/tex}\xa0......From (1) and (2){tex}\\therefore P T = P R{/tex}\xa0(3) ......{tex}\\because {/tex}\xa0Sides opposite to equal angles of a triangle are equal\xa0Now in\xa0{tex}\\Delta \\mathrm { QRT }{/tex}PS = RT .......By construction{tex}\\therefore \\frac { Q S } { S R } = \\frac { P Q } { P T }{/tex}\xa0....... By basic proportionally theorem\xa0{tex}\\Rightarrow \\frac { Q S } { S R } = \\frac { P Q } { P R }{/tex}\xa0......From (3) | |
| 3345. |
Manganese dioxide is heated with alumiñumpowder |
| Answer» 3MnO2(s) + 2Al (s) → 2Al2O3 (s) + 3Mn (s)Aluminium powder is a reducing agent. These displacement reactions are so exothermic that the metals are produced in the molten state. | |
| 3346. |
Exercise 7.2 7th question |
| Answer» Using section formula | |
| 3347. |
I want good marks in 12so what i do i am not making consantration in study |
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| 3348. |
Find the value of tan 1°.tan 2°.tan 3°........tan 89° |
| Answer» 1 | |
| 3349. |
Kuch to hai tuhjhase rabaata |
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| 3350. |
RIMSHA r u here plzz reply |
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