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3301.

Prove that nth term of an A.P. cannot be n2+1.

Answer»
3302.

Gyss koi bta skta h What is Brisk effervescence??

Answer» Brisk effervescence is defined as the rapid or vigorous evolution of a gas in a chemical reaction.
3303.

What is the meeting point of a circle and tangent called??

Answer» Secant to jo circle me se pass hota hai vo hota hai
Point of contact
Nhi
Secant
3304.

Sahil sorry bye get lost

Answer»
3305.

Elimination of trigonometric identity is included in syllabus or not?

Answer» Include in syllabus.
3306.

Sin60ki value

Answer» Under root 3/2
Under root 3by 2
3307.

2+3+4_24&_46-$4

Answer»
3308.

prime number

Answer» Which is divisible by 1 and itself only.
3309.

The answer of question 3 of exercise 14.2

Answer» Mode =1847.83,mean=-0.175
3310.

2/x+2/3y=1/6;3/x+2/y=0

Answer»
3311.

Since the CBSE Class 10th Model exams have been

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3312.

Shviangi app na kbi Gand marvi ha

Answer»
3313.

I want excitement

Answer»
3314.

Prove theorem of triangles

Answer» Without figure !! impossible
3315.

For what values of k, are the roots of the equation 3x^2+2kx+27=0 real ang equal

Answer» We have the following equation,3x2\xa0- 2kx + 27\xa0= 0a = 3, b = -2k\xa0and c = 27{tex}\\therefore{/tex}\xa0D = b2\xa0- 4ac= (-2k)2\xa0- 4(3)(27)= 4k2 - 324Roots are real and equal if D = 0{tex}\\Rightarrow{/tex}\xa04k2\xa0- 324 = 0k\u200b\u200b\u200b\u200b\u200b\u200b2=\xa0{tex}\\frac { 324 } { 4 }{/tex} = 81{tex}\\therefore k = \\pm 9{/tex}
3316.

what is your aim in board exam

Answer»
3317.

exam datesheet has been declared.

Answer»
3318.

what is scale factor?

Answer»
3319.

If x+a is a factor of polynomial 2x²+2ax+5x+10 find the value of a

Answer» Here the given polynomial f(x)=2x2 + 2ax + 5x +10If x+a is a factor of f(x) then x+a=0 or x = -a{tex}\\Rightarrow{/tex}f(-a) = 0{tex}\\Rightarrow{/tex}2(-a)2 + 2a.(-a) + 5(-a) + 10 =0{tex}\\Rightarrow{/tex}2a2 - 2a2 -5a +10 =0{tex}\\Rightarrow{/tex}-5a = -10{tex}\\Rightarrow{/tex}a=2.
3320.

Area of rohmbus

Answer» 1/2×product of its diagonals
1/2 × d1× d2
1/2(d1)(d2)
3321.

If the mode of following frequency is10

Answer»
3322.

Vhufcvh

Answer»
3323.

Sin3035

Answer»
3324.

10²

Answer» 100
3325.

My CBSE have selected dj as best student 2017

Answer»
3326.

The 7th term of an A.P. is 0 ...then prove tht 25th term is twice the 16 th term...

Answer» Nhi ata
3327.

When will be our pre board

Answer»
3328.

Which is the best dual camera phone under 17k

Answer»
3329.

Koi fb pe hai

Answer»
3330.

When 10th date sheet will be uploaded

Answer»
3331.

How to get pass in maths??

Answer»
3332.

Who play con here

Answer»
3333.

RIMSHA r u online plzz reply

Answer»
3334.

prove that tangents from an external point to a circle are equal in length

Answer» Given: P is an external point to the circle C(O,r).PQ and PR are two tangents from P to the circle.To Prove: PQ = PRConstruction: Join OPProof:{tex}\\because{/tex}\xa0A tangent to a circle is perpendicular to the radius through the point of contact{tex}\\therefore{/tex}{tex}\\angle{/tex}OQP = 90o = {tex}\\angle{/tex}ORPNow in right triangles POQ and POR,OQ = OR [Each radius r]Hypotenuse. OP = Hypotenuse. OP [common]{tex}\\therefore{/tex}{tex}\\triangle{/tex}POQ\xa0{tex}\\cong{/tex}{tex}\\triangle{/tex}POR\xa0[By RHS rule]{tex}\\therefore{/tex} PQ = PR
3335.

If 7sin^2 a - 3cos^2 =4 then prove tan a = 1\\√3

Answer»
3336.

Introduction to trignomentry

Answer» Tri = three , gono = sides , metry = study !! The study of three sides of a triangle ( only right triangle ) and theis correspondiang angles is knkwn as trigonometry
3337.

who knows देहाती भाषा?

Answer»
3338.

Who is robert hook

Answer» Robert Hooke was the one who discovered cell
Tnx
Robert Hooke was the person who discovered cell..
3339.

Oo ho jii aaj kisiko mood Alag hai

Answer» Kon
3340.

what is the formuales for hollow solids

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3341.

Solve cuve Root of 25 by divisional method

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3342.

RIMSHA where r u plzz come

Answer»
3343.

Any one having instagram account

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3344.

if PS is the bisector of

Answer» Given: In figure. PS is the bisector of\xa0{tex}\\angle QPR{/tex} of\xa0{tex}\\triangle PQR{/tex}To prove :{tex}\\frac { Q S } { S R } = \\frac { P Q } { P R }{/tex}Construction: Draw RT || SP to meet QP produced in T.Proof:\xa0{tex}\\because {/tex}\xa0RT||SP and transversal PR intersects them{tex}\\therefore \\angle 1 = \\angle 2{/tex}\xa0(1) ..... Alt. Int.\xa0{tex}\\angle s{/tex}{tex}\\because {/tex}\xa0RT||SP and transversal QT intersects them{tex}\\therefore \\angle 3 = \\angle 4{/tex} (2), ..... corres.\xa0{tex}\\angle s{/tex}But\xa0{tex}\\angle 1 = \\angle 3{/tex}\xa0...... Given{tex}\\therefore \\angle 2 = \\angle 4{/tex}\xa0......From (1) and (2){tex}\\therefore P T = P R{/tex}\xa0(3) ......{tex}\\because {/tex}\xa0Sides opposite to equal angles of a triangle are equal\xa0Now in\xa0{tex}\\Delta \\mathrm { QRT }{/tex}PS = RT .......By construction{tex}\\therefore \\frac { Q S } { S R } = \\frac { P Q } { P T }{/tex}\xa0....... By basic proportionally theorem\xa0{tex}\\Rightarrow \\frac { Q S } { S R } = \\frac { P Q } { P R }{/tex}\xa0......From (3)
3345.

Manganese dioxide is heated with alumiñumpowder

Answer» 3MnO2(s) + 2Al (s) → 2Al2O3 (s) + 3Mn (s)Aluminium powder is a reducing agent. These displacement reactions are so exothermic that the metals are produced in the molten state.
3346.

Exercise 7.2 7th question

Answer» Using section formula
3347.

I want good marks in 12so what i do i am not making consantration in study

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3348.

Find the value of tan 1°.tan 2°.tan 3°........tan 89°

Answer» 1
3349.

Kuch to hai tuhjhase rabaata

Answer»
3350.

RIMSHA r u here plzz reply

Answer»