Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3351. |
Describe the formula of A. P |
| Answer» | |
| 3352. |
sinπ+cosβ=0 |
| Answer» | |
| 3353. |
find the roots of quadratic equation 2xx-4x+3=0 |
| Answer» D = (-4)² - 4×2×3 = 16-24 = -8 ....its impossible to find as itbis imaginary !! This can be found bg iota ckncept which is in 12th | |
| 3354. |
Kya Hua sahil Ji no reply |
| Answer» | |
| 3355. |
Ex 10.2 Q13 |
|
Answer» Thanks In quadrilateral ABCD circumscribes a circle with centre O. Join OP,OQ, OR and OS.In tri. OPB and tri OQB. Angle OPB= Angle OQB = 90PB =QB (Theorem 10.2)OB=OB (common )Tri.OPB=tri.OQB ( by RHS congruency rule)ang.POB=ang.BOQ (1=2)(by CPCT)similarly ang.QOC=ang.COR (3=4) ang.ROD= ang.DOS (5=6) ang.SOA=ang.AOP (7=8)therefore , Sum of angles of a quadrilateral is 360.angle 1+2+3+4+5+6+7+8=360 2 (ang.2+3)+2 (6+7)=360 (because ang.1=2,3=4,5=6,7=8) and similarly, 2 (ang.1+8)+2 (4+5)=360(2+3)+(6+7)=180 and (1+8)+(4+5)=180ang.BOC+ ang.AOD=180 and ang.AOB+ang.COD=180 H.P. |
|
| 3356. |
Sahil slept what |
| Answer» | |
| 3357. |
The vertices of a triangle are (0,0) (3,0) and (0,4) the centroid of the triangle is ? |
| Answer» | |
| 3358. |
If cos x =1|2 and sin y = 1|2 then find the value of x+y |
|
Answer» 90° Siny+cosx =1 because sin+cos=1 |
|
| 3359. |
(Sin 45°+cos 45°)find value |
|
Answer» 1....because sinsquaretheta + cossquaretheta = 1 1 |
|
| 3360. |
tan(40+theata)-cot(40-theata) find value. |
| Answer» | |
| 3361. |
Sahil please Na bolo Na Jane ko niinii ar hi hai |
| Answer» | |
| 3362. |
Sahil me jaati Na niinii aa rhi hai zorse |
| Answer» | |
| 3363. |
√x+y=14,x+√y=28 ,solve x and y |
| Answer» | |
| 3364. |
Sahil good night so jao |
| Answer» | |
| 3365. |
Sahil bolo Kaun sa kaam |
| Answer» | |
| 3366. |
Eva u wrote zyada hogaya kya zyada ho gaya |
| Answer» | |
| 3367. |
Kya hua eva |
| Answer» | |
| 3368. |
Kya hua sahil bro |
| Answer» | |
| 3369. |
Eva u r Awsome girl |
| Answer» | |
| 3370. |
Eva for you pagal nhi hum jo teri har baat mante hai bas teri khushi se zyada kuch acha nhi lgat hai |
| Answer» | |
| 3371. |
Different between csa & volume |
| Answer» | |
| 3372. |
ए eva तेरा पढाई लिखाई साढे 22 है क्या? |
| Answer» | |
| 3373. |
Eva i am your shayr are wah |
| Answer» | |
| 3374. |
Sahil u r my good freind chill mar bro |
| Answer» | |
| 3375. |
what is your favourite song? |
| Answer» | |
| 3376. |
Eva u r intresting???? |
| Answer» | |
| 3377. |
Eva u know gauri sharma |
| Answer» | |
| 3378. |
mujhe friends banana hai kaun banega |
| Answer» | |
| 3379. |
How to find eighth negative term from last. |
| Answer» | |
| 3380. |
2x/x-3+1/2x+3+3x+9/(x+3)(2x+3) |
| Answer» Given, {tex}\\frac{2x}{x-3}+\\frac{1}{2x+3}+\\frac{3x+9}{(x-3)(2x+3)}=0{/tex}{tex}\\Rightarrow\\frac{{2x(2x + 3) + x - 3 + 3x + 9}}{{(x - 3)(2x + 3)}} = 0{/tex}{tex} \\Rightarrow \\frac{{4{x^2} + 6x + x - 3 + 3x + 9}}{{2{x^2} + 3x - 6x - 9}} = 0{/tex}{tex} \\Rightarrow \\frac{4{x^2} + 10x +6 }{{2{x^2} - 3x - 9}} = 0{/tex}Cross multiplying equation , we get ,{tex} \\Rightarrow 4{x^2} + 10x +6 = 0{/tex}{tex} \\Rightarrow 4{x^2} + 6x+4x +6 = 0{/tex}{tex} \\Rightarrow x(4{x} + 6)+1(4x +6) = 0{/tex}{tex}\\Rightarrow(x+1)=0{/tex} or {tex} (4x+6)=0{/tex}{tex}\\Rightarrow x=-1{/tex}{tex}\\Rightarrow x=-\\frac{3}{2}{/tex}Hence , the roots of the given quadratic equation are -1 and {tex}-\\frac{3}{2}{/tex} | |
| 3381. |
Good night frnds |
| Answer» | |
| 3382. |
Any one girl?who is single ?? |
| Answer» | |
| 3383. |
What are circles |
|
Answer» A collection of point A collection of which are equidistant from a certain point |
|
| 3384. |
What are prime nos |
| Answer» A prime number is a whole number greater than 1 whose only factors are 1 and itself. | |
| 3385. |
Prime no is what |
|
Answer» If a no. Has is divisible by 1and itself If no. Divides itself and 1 then it is a prime no. Ex-3,5,7,11 |
|
| 3386. |
Completing sq Method |
| Answer» | |
| 3387. |
I am not able to understand height and distance |
| Answer» First of all learn trigonometry and then try to solve the problem | |
| 3388. |
types of triangle |
|
Answer» Right angle triangle Scalene, isosceles, equilateral |
|
| 3389. |
Divide23485 answer |
| Answer» 23485 | |
| 3390. |
Board ka exam date ? |
|
Answer» It will be in March March |
|
| 3391. |
Please call me how many marks ch |
| Answer» | |
| 3392. |
What are co-prime numbers |
| Answer» Numbers are called coprime if the only positive integer that divides both of them is 1. | |
| 3393. |
Arya tu sota nhi h bhai kal 3 baje tak online tha tu jab tak hum the |
| Answer» | |
| 3394. |
Find the value of the middle term of the following A.P. -6 , -2 , 2 , . . . . . , 58 |
| Answer» According to question the given arithmetic progression: - 6, - 2, 2, ...,58.Here, a = -6, d\xa0= - 2 + 6 = 4 and an\xa0= 58 where a is first term and d is common difference{tex}\\Rightarrow{/tex}\xa0a + (n\xa0- 1)d = 58 {tex}\\Rightarrow{/tex}\xa0- 6 + (n - 1)4 = 58{tex}\\Rightarrow{/tex}\xa0(n - 1)4 = 64 {tex}\\Rightarrow{/tex}\xa0n\xa0- 1 = 16 {tex}\\Rightarrow{/tex}\xa0n\xa0= 17 (odd){tex}\\therefore{/tex}\xa0MIddle term =\xa0{tex}\\frac { 17 + 1 } { 2 } = \\frac { 18 } { 2 }{/tex} = 9th term{tex}\\therefore{/tex}\xa09th term is the middle term.Now, a9\xa0= a + 8d = -6 + 8\xa0{tex}\\times{/tex} 4 = -6 + 32 = 26 | |
| 3395. |
Oswaal sample papers with solutions kase nikale |
| Answer» | |
| 3396. |
Oswaal sample papers ke solutions kase nikale |
| Answer» | |
| 3397. |
Solve the equation x |
| Answer» | |
| 3398. |
Step mean a = 18 , h= 2 , fiui = k - 8 , fi = 40+ k find mean? |
| Answer» | |
| 3399. |
If 7sinA+3cosA =4 prove that tan A=1/3 |
| Answer» 7sinA+3cosA=47{cos(90-A)}+3cosA=47cos(90-A) | |
| 3400. |
Byeeeee frnds... |
| Answer» | |