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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34051. |
700*90 |
| Answer» 63000 | |
| 34052. |
Prove that 2+3√3 is irrational number |
| Answer» Let 2+3√3 be rational no ,So 2+3√3=p/q,3√3=p/q-2,√3=p-2q/3q,p-2q/3q is rational but, We know that √3 is irrational so2+3√3 is irrational | |
| 34053. |
Find all the zeroes of the polynomial 2x |
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Answer» 2x is not a polynomial it is a monomial And 0/2 is also a solution of 2x It has two solutions 1. (0) and 2.(-2).. It has only 1 zero that is 0 |
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| 34054. |
What is the quaratic formula? |
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Answer» You can check also and thia formula is diacovered by me K(xsquare-(sum of zeros)x +product of zeros ax2+bx+c |
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| 34055. |
Is optional exercise type questions comes in board exam ? |
| Answer» Well they don\'t use to come earlier but now on the new examination pattern has started and also if you see the last year board class 10 maths question paper and ask some good students about the same, you will find that the paper was very tough so it\'s better if you do the optional expertise.It will only improve your knowledge and understanding of that chapter.Also do solve all the questions from R.D.Sharma ...it will help a lot and I\'m sure you will get good marks.... | |
| 34056. |
Find the quadratic polynomial whose one zero is -8 and the sum of the zero is 0 |
| Answer» K(xsquare-64) | |
| 34057. |
Integers number |
| Answer» FsBBC | |
| 34058. |
Formula chapter wise |
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Answer» you see the formula of your reference book as well as text book See in book |
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| 34059. |
Method of completing square |
| Answer» take common among all of the no. then hair the middle term then square it and in +and- then you will get a-b whole square formula then after add or subtract it | |
| 34060. |
Result kab aa rha hai cbse ka |
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Answer» 26 may May last or june first Nhi malum |
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| 34061. |
Obtain all the zeroes of polynomial p(x)=3x4-15x3+17x2+5x-6 if two zeroes are -1/root 3 and 1/root3 |
| Answer» | |
| 34062. |
Find the polynomial whoes are 5+√19and 5_√19 |
| Answer» , okkkk.. Thank u | |
| 34063. |
Find the polynomial whose zeros √3/2 & -√3/2 |
| Answer» | |
| 34064. |
Show that 10 of every among 3 consecutive positive integer is divisible by 3 |
| Answer» | |
| 34065. |
x+y=5and2x_3y=4 |
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Answer» 2x+2y= 10 (by multiplying by 2 both side in eqn (1)) x+y=5 ........... (i)2x_3y=4 ........... (ii)now ,We use elimination method to solve itSo,multiply by 3 in eqn (i)3x+3y=152x_3y=4 {adding both eqn}...............5x =19x =19 5now,Put the value of x in eqn (i)x+y=519+y=5 519+5y=255y=25_195y= 6y= 6 5 Hence x=19 5And y = 6 5 |
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| 34066. |
D is the hcf of 210 and 55.find the value of x and y where d= 210x + 55y |
| Answer» Please open the RD Sharma of class 10th and locate the chapter number 1 the examples and the questions of the exercise that is given to us or you can also download the app or you can search on the Internet to the related topic because today Technologies so advance | |
| 34067. |
What is the sum of first 10 natural number |
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Answer» 1+2+3+4+5+6+7+8+9+10=55The sum of first 10 natural numbers = 55...... Hope this help u..... ??? 55 |
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| 34068. |
Find the roots of following equation1÷x+4 _ 1÷x_7= 11÷30 |
| Answer» {tex}\\frac { 1 } { x + 4 } - \\frac { 1 } { x - 7 } = \\frac { 11 } { 30 }{/tex} where {tex}x \\neq - 4,7{/tex}{tex}\\Rightarrow \\frac { ( x - 7 ) - ( x + 4 ) } { ( x + 4 ) ( x - 7 ) } = \\frac { 11 } { 30 }{/tex}{tex}\\Rightarrow \\frac { - 11 } { ( x + 4 ) ( x - 7 ) } = \\frac { 11 } { 30 }{/tex}{tex}\\Rightarrow{/tex}x2 - 7x + 4x - 28 = -30{tex}\\Rightarrow{/tex}x2 - 3x + 2= 0Comparing equation x2 - 3x + 2 = 0 with general form ax2 + bx + c = 0,We get\xa0a = 1, b = -3 and c = 2Using quadratic formula {tex}x = {-b \\pm \\sqrt{b^2-4ac} \\over 2a}{/tex}to solve equation,{tex}x = \\frac { 3 \\pm \\sqrt { ( - 3 ) ^ { 2 } - 4 ( 1 ) ( 2 ) } } { 2 \\times 1 }{/tex}{tex}\\Rightarrow x = \\frac { 3 \\pm \\sqrt { 1 } } { 2 }{/tex}\xa0{tex}\\Rightarrow x = \\frac { 3 + \\sqrt { 1 } } { 2 } , \\frac { 3 - \\sqrt { 1 } } { 2 }{/tex}{tex}\\Rightarrow{/tex}x = 2, 1 | |
| 34069. |
X+y=72x-3y=1 |
| Answer» | |
| 34070. |
When is 10th results |
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Answer» May 20may |
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| 34071. |
a² +b²-2ab and a=5 find the value of b |
| Answer» Formula for a^2+b^-2ab=(a-b)^2 so substitute a=5. (5-b)^2=0 now ,5-b=0 result is b=5 | |
| 34072. |
Solve equation by eliminationx +y=(a+b)ax+by=(a²+b²) |
| Answer» X=a | |
| 34073. |
Find the hcf of 392 and 267540 by Euclid division lemma |
| Answer» Its HCF is one hundred ninty six l96 | |
| 34074. |
The exponent of Z in the prime factorization of 144 is |
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Answer» I2 12 |
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| 34075. |
What is tha solution of this question √2n-√3y=0 And √5n-√2y=0 solve this by elimination method |
| Answer» | |
| 34076. |
Root under 1+ sin theta by root under 1_ sin theta |
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Answer» Please solve this question Read science ok Sec theta +tan theta |
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| 34077. |
Syllabus is half from 2018-1019 session |
| Answer» No not half | |
| 34078. |
Show that square of any positive integer cannot be of form 6m+2 or 6m+5 for any integer m. |
| Answer» Let a be the positive integer and b = 6.Then, by Euclid’s algorithm, a = 6q + r for some integer q ≥ 0 and r = 0, 1, 2, 3, 4, 5 because 0 ≤ r < 5.So,\xa0a = 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4 or 6q + 5.(6q)2 = 36q2 = 6(6q2)= 6m, where m is any integer.(6q + 1)2 = 36q2 + 12q + 1= 6(6q2 + 2q) + 1= 6m + 1, where m is any integer.(6q + 2)2 = 36q2 + 24q + 4= 6(6q2 + 4q) + 4= 6m + 4, where m is any integer.(6q + 3)2 = 36q2 + 36q + 9= 6(6q2 + 6q + 1) + 3= 6m + 3, where m is any integer.(6q + 4)2 = 36q2 + 48q + 16= 6(6q2 + 7q + 2) + 4= 6m + 4, where m is any integer.(6q + 5)2 = 36q2 + 60q + 25= 6(6q2 + 10q + 4) + 1= 6m + 1, where m is any integer.Hence, The square of any positive integer is of the form 6m, 6m + 1, 6m + 3, 6m + 4 and cannot be of the form 6m + 2 or 6m + 5 for any integer m. | |
| 34079. |
x+2 =-1 , 2x -3y = 12 solve this with elimination method |
| Answer» Value of y = Ten lo and value of x= 9 | |
| 34080. |
Find hcf 196 and 38220 using euclid division algorithm |
| Answer» 4 is hcf | |
| 34081. |
10th class ke result kab niklega yar.... |
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Answer» Okay... June mai |
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| 34082. |
Extra question of linear equations |
| Answer» | |
| 34083. |
3root2x^2-5x-root2=0 |
| Answer» | |
| 34084. |
Guys passing skim kya hay bta do ...80 may say kitnay laker anne hay boards may... |
| Answer» 33 percent | |
| 34085. |
Where i get important questions for iit foundation for class 10 |
| Answer» | |
| 34086. |
If a rational number a/b has aterminating decimal expension what is the condition to be satisfy b |
| Answer» 1234 | |
| 34087. |
Obtain relationship between zeroes and coefficients of a polynomial |
| Answer» Alpha + Beta = - b/aAlpha×Beta= c/a | |
| 34088. |
956,13 how solve this que in lemma |
| Answer» | |
| 34089. |
X³-6x²+11x-6:3 find the zeros of Polynomial |
| Answer» The given polynomial f(x)={tex}\\text{x}^3-\\text{6x}^2+\\text{11x-6}{/tex}Since 3 is a zero of p(x), so (x - 3) is a factor of f(x).On dividing f(x) by (x - 3), we get{tex}\\therefore{/tex}\xa0f(x) = (x2\xa0- 3x + 2)(x - 3)= ( x2\xa0- 2x - x + 2)( x - 3)= [x(x - 2) -1(x - 2)](x - 3)= (x - 1)(x - 2)(x - 3)Now f(x)=0 if x - 1 = 0 or x - 2 = 0 or x - 3 = 0{tex}\\Rightarrow{/tex}\xa0x = 1 or x = 2 or x = 3{tex}\\mathrm{Hence}\\;\\mathrm{the}\\;\\mathrm{remainig}\\;\\mathrm{roots}\\;\\;\\mathrm{of}\\;\\mathrm f(\\mathrm x)\\;\\mathrm{are}\\;1\\;\\mathrm{and}\\;2\\;{/tex} | |
| 34090. |
How many solution we get in parallel lines?? |
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Answer» There is 0 number of solutions between 2 parallel lines As the lines don\'t meet there is no solution There are no solutions in parallel lines. Sorry I think no solution I think yes There are no solutions in parallel lines |
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| 34091. |
Show that square of any positive integer cannot be of the form 5q+2or 5q+3for any integer q |
| Answer» Hdujwjdjejsownydyhw | |
| 34092. |
Find the value of k in polynomial x2 -8x+k if Alpha square + B tech square equal to 40 |
| Answer» Let {tex}\\alpha,\\beta{/tex}\xa0be the zeros of the polynomial {tex}f(x)=x^2-8x+k{/tex}.Sum of zeroes =\xa0{tex} \\alpha + \\beta = - \\left( \\frac { - 8 } { 1 } \\right) = 8{/tex}\xa0and, Product of zeroes =\xa0{tex} \\alpha \\beta = \\frac { k } { 1 } = k{/tex}Now,\xa0{tex} \\alpha ^ { 2 } + \\beta ^ { 2 } = 40{/tex}{tex} \\Rightarrow \\alpha ^ { 2 } + \\beta ^ { 2 }+2 \\alpha\\beta-2 \\alpha\\beta= 40{/tex}{tex} \\Rightarrow \\quad ( \\alpha + \\beta ) ^ { 2 } - 2 \\alpha \\beta = 40{/tex}{tex} \\Rightarrow \\quad 8 ^ { 2 } - 2 k = 40{/tex}{tex} \\Rightarrow \\quad 2 k = 64 - 40 {/tex}{tex}\\Rightarrow 2 k = 24 {/tex}{tex}\\Rightarrow k = 12{/tex} | |
| 34093. |
root 2 is irrational |
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Answer» Yes ;by contadication fact Yes root 2 is irrational Yes |
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| 34094. |
If the number is divided by same number what is quotient |
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Answer» Always 1 1 |
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| 34095. |
find the largest 4 digit no which when divided by 4 , 7 ,13 leaves a remainder of 3 in each case |
| Answer» \xa0LCM of ( 4,7,13) = 364Largest 4 digit number = 9999On dividing 9999 by 364 we get remainder as 171Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828Hence, required number = (9828 + 3) = 9831Therefore 9831 is the number. | |
| 34096. |
Find the value of k in x2 |
| Answer» | |
| 34097. |
2x+4y } =0 |
| Answer» | |
| 34098. |
solve 3x+2y=14 and -x+4y=7 and hence find the value of k for which 3x=2ky+6 |
| Answer» I am not sure i think -1/9 | |
| 34099. |
Prime numbers from 2 to 100 |
| Answer» 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97, | |
| 34100. |
Express 135 and 225 in linear form |
| Answer» By Euclid\'s division algorithm225 = 135 {tex}\\times{/tex} 1 + 90135 = 90 {tex}\\times{/tex} 1 + 4590 = 45 {tex}\\times{/tex} 2 + 0hence the HCF is 45 | |