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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34101. |
If a & b are odd positive &a>b then show out of (a+b)/2 & (a-b)/2 one is odd & one is even |
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Answer» Explain Both will be even |
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| 34102. |
Find 2 consective positive odd integers ,sum of whose squares is 290 |
| Answer» 11 square+13 square=121+169=290Hope it helps u... | |
| 34103. |
If tan2¥ =1-a2 ,prove that sec¥+ tan3¥ × cosec¥=(2-a2)3/2 |
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| 34104. |
What is difference between algorithm and lemma |
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Answer» Lemma are the proven statemets that ae used to prove other statements while algorithems are are the steps to provestatements. Algorithm means to Solve anything step by step and lemma means a prove statement |
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| 34105. |
Find the largest number which divides 245 , 1037 leaving remainder 5 on each case ? |
| Answer» When the number divides 245 and 1037 , leave remainder 5.So, the number must divide 245-5 =240 and 1037-5 =1032.The required number is the HCF of 240 and 1032.By Euclid division lemma 240=2*2*2*2*3*51032=2*2*2*3*43HCF of 240 and1032 = 2*2*2*3 =24So, the required number is 24. | |
| 34106. |
a² + b² = ? |
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Answer» (a+b)(a+b)-2ab ur answer is... a square+2ab+b squareHope it helps u The question is wrong if we try to solve this it will come (a) sqr+(b) sqr Wrong question |
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| 34107. |
2×45+1002 |
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Answer» 1092 Answer is 1092 1092 1092 1092 Hii its answer is 1092 1092 |
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| 34108. |
Find the zeroes of the polynomial x³-3x²-2x+6 |
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| 34109. |
If [x+1] is a factor of 2x^3+ax^2+2bx+1 then find the value of a and b and given that 2a- 3b=4 |
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Answer» You can also find the answer by factor theriwm Put -1 in the polynomial p(x) , you will get another equation then solve it |
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| 34110. |
Prove that -3+7=6 |
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Answer» Is this possible or not ???????? I can\'t cool one |
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| 34111. |
Ex. 3.1 ka qs. No. Second kaise bne GA |
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| 34112. |
find the number of points on x-axis which are at a distance of 2 units from (2,4). |
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| 34113. |
2^(x)-2^(x-1)=4 |
| Answer» X=3 | |
| 34114. |
Pl mmnn |
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Answer» Sorry 2016-18\'s bach What do you want to ask ?? |
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| 34115. |
Laplas law |
| Answer» 2or2 | |
| 34116. |
Prime numbers on a dice |
| Answer» 2 3 5 | |
| 34117. |
Explain quadratic formula |
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| 34118. |
Find the largest number which divides 62,132, 237 leaving same remainder in each case. |
| Answer» ? | |
| 34119. |
Give me some substitution example |
| Answer» | |
| 34120. |
What are twin prime numbers? |
| Answer» A twin prime is a prime number that is either 2 less or 2 more than another prime number—for example, either member of the twin prime pair (41, 43). | |
| 34121. |
The center of a circle is (x+2),(x-1).find x if circle passes through (2,2)and(8,-2). |
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| 34122. |
1+cot2A/1+cosecA=cosecA prove it |
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| 34123. |
Find hcf of 3192,14280 by applying euclid\'s division algorithm |
| Answer» by euclids algorithm method:hcf of 14280 & 319214280 is equal to 3192 *4+15123192 is equal to 1512 *2+1681512 is equal to 168 * 9+0hence , the hcf is 9 | |
| 34124. |
Solve the pair of linear equations , 41x +53y = 135 |
| Answer» Gove a more eqation or relation to solve it | |
| 34125. |
Sin 60 is = x |
| Answer» Syed root3 /2 | |
| 34126. |
If one root of the x square-x-k=0 be the square of other than k is equal to the |
| Answer» The given equation is:x2\xa0- x + k = 0\xa0As it is given that\xa03 is root of the equation x2\xa0- x + k = 0, therefore we have:(3)2\xa0- 3 + k = 0{tex}\\Rightarrow{/tex}\xa09 - 3 + k = 0{tex}\\Rightarrow{/tex}\xa06 + k = 0{tex}\\Rightarrow{/tex}\xa0k = - 6For p = - 6 the other given equation becomes:x2\xa0- 6(2x - 6 + 2) + p = 0{tex}\\Rightarrow{/tex}\xa0x2\xa0-12x + 24 + p = 0This is the form of ax2\xa0+ bx + c = 0,where a = -1, b = -12 and c = 24 + pSince the given equation has equal roots, therefore D = 0.i.e., b2\xa0- 4ac = 0{tex}\\Rightarrow{/tex}\xa0(-12)2\xa0- 4(1)(24 + p) = 0{tex}\\Rightarrow{/tex}\xa0144 - 96 - 4p = 0{tex}\\Rightarrow{/tex}\xa048 - 4p = 0{tex}\\Rightarrow{/tex}\xa04p = 48{tex}\\Rightarrow{/tex} p = 12Hence, the value of p is 12. | |
| 34127. |
Class 10 chapter 1 EXERCISE 1.3 1. Prove that √5 is irrational |
| Answer» Solution - let us assume on the contrary that √5 is a rational number . Then there exist co - prime positive integers a and b such that √5 = a/b 5b^ 2 = a^2 5 | a^2 [ 5 | 5b^2 ] 5 | a. ( see theorem 2) (i)......a = 5c for some positive integer c a^2 = 25c^2 5b^2 = 25c^2 [ a^2 = 5b^2 ]b^2 = 5c^2 5 | b^2 [ 5 | 5c^2 ] 5 | b [ see theorem 2 ] (i) .......From (i)and (i) we find that a and b have at least 5 as a common factor . This contradicts the fact that a and b are co- prime Hence , √5 is an irrational number . | |
| 34128. |
Find the zeroes of the given polynomial: x square+2root2 x -6 |
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| 34129. |
If p(e)-0.05 what is the probability of not e |
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| 34130. |
A line AB is 8 cm in length . AB is produced to P such that BP^2 = AB + AP find the length of BP |
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| 34131. |
Find the zeros of polynomial x²+1/6x-2 |
| Answer» Let f(x) = x2 + {tex} \\frac 16{/tex}x - 2.Then, f(x) = {tex} \\frac 16{/tex}(6x2+ x -12) = {tex} \\frac 16{/tex}(6x2 + 9x - 8x - 12){tex} \\Rightarrow{/tex}\xa0f(x) = {tex} \\frac 16{/tex}{(6x2 + 9x) - (8x + 12)}= {tex} \\frac 16{/tex}{3x (2x + 3) - 4 (2x + 3)}= {tex} \\frac 16{/tex}(2x + 3) (3x - 4)Now f(x)=0 if{tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\begin{array}{l}i.e.\\;x=-\\frac32\\;or\\;x=\\frac43\\\\\\end{array}}}{/tex}Hence, {tex} \u200b\u200b\\alpha = \\frac { - 3 } { 2 } \\text { and } \\beta = \\frac { 4 } { 3 }{/tex}\xa0are the zeros of the given polynomial.{tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\begin{array}{l}Now\\;\\alpha+\\beta=\\frac{-3}2+\\frac43=\\frac{-9+8}6=-\\frac16\\\\\\end{array}}}{/tex}and\xa0{tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\begin{array}{l}\\alpha\\beta=\\frac{-3}2\\times\\frac43=-2\\\\\\end{array}}}{/tex}The given polynomial is f(x) =x2 + {tex} \\frac 16{/tex}x - 2.so a=1 b={tex}\\frac16{/tex}\xa0c=-2{tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\begin{array}{l}\\alpha+\\beta=\\frac ba=\\frac{-{\\displaystyle\\frac16}}1=-\\frac16\\\\\\end{array}}}{/tex}\xa0and {tex}\\style{font-family:Arial}{\\style{font-size:12px}{\\begin{array}{l}\\alpha\\beta=\\frac ca=\\frac{-2}1=-2\\\\\\end{array}}}{/tex}Hence, the relation between the coefficients and zeros is verified. | |
| 34132. |
Evaluate the following using aisuemative property -39*99 |
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| 34133. |
Ratio |
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| 34134. |
2x+7=67¶ + 3487[{65}] |
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| 34135. |
2+2×2=? |
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Answer» its 6 6 as multiplication will be first. 8 Use BODMAS rule and try to find ? Ok so, 2+2*2= 6 |
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| 34136. |
How to solve alpha/beeta+beeta/alpha |
| Answer» First take LCM of alpha and beta in denoninators and then add alpha square and beta square and -2 alpha beta in numerator. Now put the values which are alpha+beta=-b/a and alpha×beta=c/a. Then you will get (b square + c )/a. | |
| 34137. |
One day equal to how many second |
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Answer» One day= 24 x 60 x 60 seconds. Or 86400 seconds. 86400seconds |
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| 34138. |
What is Square A+B |
| Answer» a²+b²+2ab | |
| 34139. |
for any positive integer n , prove that n^3_n is divisible by 6 |
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Answer» Please see answer in RD Sharma, shrishty no |
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| 34140. |
NCERT solutions exercise 3.6 question no. 6 |
| Answer» Get NCERT solutions here:\xa0https://mycbseguide.com/ncert-solutions.html | |
| 34141. |
SWATI ROW A BOAT IN A STILL WATER AT SPEED OF 5 KM/HR |
| Answer» Let the speed of the stream be x km/hr.\xa0Speed of\xa0boat upstream = (5 - x) km/hr.Speed of\xa0boat downstream = (5 + x) km/hr.Time taken to\xa0go\xa0upstream = {tex} \\frac { 5.25 } { 5 - x }{/tex}\xa0hours.Time taken to go\xa0downstream = {tex} \\frac { 5.25 } { 5 + x }{/tex} hours.According to question,{tex} \\therefore \\quad \\frac { 5.25 } { 5 - x } - \\frac { 5.25 } { 5 + x } = 1{/tex}{tex} \\Rightarrow \\quad 5.25 [ \\frac { 1 } { 5 - x } - \\frac { 1 } { 5 + x } ] = 1{/tex}{tex} \\Rightarrow \\quad \\frac { 21 } { 4 } [ \\frac { 5 + x - 5 + x } { ( 5 - x ) ( 5 + x ) } ] = 1{/tex}{tex} \\Rightarrow \\quad \\frac { 21 } { 4 } \\times \\frac { 2 x } { 25 - x ^ { 2 } } = 1{/tex}{tex} \\Rightarrow \\quad 21 x = 50 - 2 x ^ { 2 }{/tex}{tex} \\Rightarrow{/tex}\xa02x2 + 21x - 50 = 0{tex}\\Rightarrow{/tex}\xa02x2 + 25x - 4x - 50 = 0{tex} \\Rightarrow \\quad x ( 2 x + 25 ) - 2 ( 2 x + 25 ) = 0{/tex}{tex} \\Rightarrow{/tex}\xa0(2x + 25) (x - 2) = 0{tex} \\Rightarrow{/tex}\xa0x - 2 = 0, 2x + 25 = 0\xa0{tex} \\Rightarrow{/tex}\xa0x = 2\xa0{tex} \\left[ \\because x \\neq - \\frac { 25 } { 2 } \\text { as } x > 0 \\right]{/tex}Hence, the speed of the stream is 2 km/hr. | |
| 34142. |
Sin & = |
| Answer» 1/cosec& | |
| 34143. |
Cos^[email\xa0protected]^[email\xa0protected] |
| Answer» | |
| 34144. |
Exercise 3.6 question no. 1 i ii iii iv v |
| Answer» Get NCERT solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 34145. |
Ex3.2 ques no 4 i need more than 3 solutions |
| Answer» Get NCERT solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 34146. |
X^2+3x-10-(1+2√2)5+√2 |
| Answer» | |
| 34147. |
Locate the points (5,0)(0,5)(2,5)(5,2)(-3,-5)(5,-3)(6,1)in the cartesian plane |
| Answer» Locate the points are 1st ,1st, 1st, 1st, 3rd, 4th, 1st cartedian plane | |
| 34148. |
How to prove composite no. |
| Answer» Plzz give me one ques then I tell u | |
| 34149. |
Solve Qno.18 of Rs Agarwal ex-2B plzz |
| Answer» Write your ques. | |
| 34150. |
Pair of linear equationsX/2+y=0.87/x+y/2=10 |
| Answer» Given equations are{tex}\\frac{x}{2} + y = 0.8{/tex}{tex}\\frac{x + 2y}{2} = 0.8{/tex}.x + 2y = 1.6 ........ (i)and{tex}\\frac{7}{{x + \\frac{y}{2}}} = 10{/tex}\xa0{tex}\\frac{{7 \\times 2}}{{2x + y}} = 10{/tex}{tex}\\frac{{7}}{{2x + y}} = 5{/tex} 7 = 10x + 5y10x + 5y = 7 .......... (ii)Multiply first equation by 1010x + 20y = 16............ (iii)Subtracting the equations (ii) from (iii) , we get15y = 9{tex}y = \\frac{9}{{15}} = \\frac{3}{5}{/tex}Put value of y in (i){tex}x = 1.6 - 2\\left( {\\frac{3}{5}} \\right) = 1.6 - \\frac{6}{5} = \\frac{2}{5}{/tex}Solution is\xa0{tex}\\left( {\\frac{2}{5},\\;\\frac{3}{5}} \\right){/tex} | |