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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34201. |
Divide Xpower4-3xsquare+2x+1 by x-1 |
| Answer» Remainder=1 and ans is Xpower3+Xsquare-2x | |
| 34202. |
Simplify x+2y=3÷4;2x+y=3÷4 |
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Answer» give me thanks plz x=y=1/4 |
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| 34203. |
How to write a linear equation of the given statement? |
| Answer» But where is given statement | |
| 34204. |
Show that tha squre of an odd positive intrger is of the form 8m+1 for whole number m |
| Answer» Since, any odd positive integer n is of the form 4m\xa0+ 1 or 4m + 3.if n = 4m + 1n2 = (4m + 1)2= 16m2 + 8m + 1= 8(2m2 + m) + 1So n2 = 8q + 1 ........... (i)) (where q = 2m2 + m is a positive integer)If n = (4m + 3)n2 = (4m + 3)2= 16m2 + 24m + 9= 8(2m2 + 3m + 1) + 1So n2 = 8q + 1 ...... (ii) (where q = 2m2 + 3m + 1 is a positive integer)From (i) and (ii) we conclude that the square of an odd positive integer is of the form 8q + 1, for some integer q. | |
| 34205. |
Can two number have16 as their hcf 380 as their LCM? Give reason |
| Answer» Noo because 380 is not divisible by16 but every lcm is divisible by hcf | |
| 34206. |
Find the smallest number which when increased by 75 is exactly divisible by 325 and 315 |
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| 34207. |
Show that x^4 + x^2 +3 has no zeros? |
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| 34208. |
Why cos A = √1-sin^2 A not - √1-sin^2 A |
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| 34209. |
How cot A = cos A ÷ sin A? ??? |
| Answer» how to draw an insect | |
| 34210. |
If the hcf of 210 and 55 is expressible in the form of 210×5+55y , find y |
| Answer» First find H.C.F of 210 and 55 and them put 210×5+55y equal to H.C.F of 210 and 55 | |
| 34211. |
The sum of the squares of two consecutive natural numbers is 313.find the numbers. |
| Answer» Let one number be x then another consecutive number will be x+1 Therefore, (x)^2 + (x+1)^2 = 313 X^2 + x^2 +1 + 2x = 313 . Now solve it. | |
| 34212. |
Sllybus of 2018-2019 of all chapter |
| Answer» Check Syllabus here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 34213. |
Find zeros of 2x^2-9 and verify relation between zeros and co efficents |
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Answer» 2x^2 - 9 can be written as (Root2x)^2 - (3)^2Now with identity of a^2-b^2 = (a+b)(a-b) Solve it . Rgh4ķf |
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| 34214. |
Find the least number which when divided by 35,56 and 91 leaves the same remainder 7 in each case. |
| Answer» Required number= 28, 49, 84According to questionHcf of given number because a number whic is divisible by all is the factor Hcf of given numbers is 7 | |
| 34215. |
Tell me plz.. Shreedharacharya formula and 1 example |
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| 34216. |
ob |
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Answer» What does it mean? What ?????? |
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| 34217. |
Find sum and product of px^2+qx+pq |
| Answer» | |
| 34218. |
Prove that √2 is irrational |
| Answer» Hi | |
| 34219. |
Use euclid division algorithm to find the hcf of 196 & 38220 |
| Answer» 196 and 38220We have 38220 > 196,So, we apply the division lemma to 38220 and 196 to obtain38220 = 196 × 195 + 0Since we get the remainder is zero, the process stops.The divisor at this stage is 196,Therefore, HCF of 196 and 38220 is 196. | |
| 34220. |
Find the largest number that divides 245 and 1029 leaving remainder 5 in each case |
| Answer» The required number is the HCF of (245 - 5) and (1029 - 5) i.e., 240 and 1024.{tex}1024 = 240 \\times 4 + 64{/tex}{tex}240 = 64 \\times 3 + 48{/tex}{tex}64 = 48 \\times 1 + 16{/tex}{tex}48 = 16 \\times 3 + 0{/tex}{tex}\\therefore H C F \\text { is } 16{/tex}. | |
| 34221. |
How to prove a number is either irrational not |
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| 34222. |
X2 +4x_91 |
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| 34223. |
Hello friends i am new on this aap |
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Answer» hmm And you I am fine Hey how are you |
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| 34224. |
Exercise 5.3 |
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| 34225. |
I want class 10th textbook pdf 2018-19 where i can found that please tell me |
| Answer» U can\'t find PDF book but u can get digital book from e-pathsala application from Google play store | |
| 34226. |
What is difference between coprime and composite number |
| Answer» Coprime numbers those which have a common factor as one. Composite numbers those which have more than two factors. | |
| 34227. |
If k is a non zero constant then the polynomial whose zero are -1 and-2 is |
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| 34228. |
Is NCERT is sufficient to score 95% in board exam or there is a need of reference book |
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Answer» No need because the whole paper comes from NCERT only we should read each and every part of NCERT books even example to score 98% Our first priority should me NCERT book but for proper practice of physics numericals and maths sum we need a refrence book . |
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| 34229. |
When will be result for class 10 |
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Answer» No it wiil not be in mid of mayTt wiil be on end of may Mid of may |
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| 34230. |
Sum of the n term of the series under root 2,root8. Root 18. Root 32 , , , , , , , is |
| Answer» {tex}\\frac{{n(n + 1)}}{{\\sqrt 2 }}{/tex} | |
| 34231. |
If the point (2,3) (4,k) (6,-3) are collinear then find the value of k |
| Answer» Let the points A (2, 3), B{tex}\\left( {4,k} \\right){/tex} and C{tex}\\left( {6, - 3} \\right){/tex} be collinear.If the points are collinear then area of triangle ABC formed by these three points is 0.{tex}\\therefore {/tex}{tex}{\\text{ar}}\\left( {\\Delta {\\text{ABC}}} \\right) = \\frac{1}{2}\\left[ {{x_1}\\left( {{y_2} - {y_3}} \\right) + {x_2}\\left( {{y_3} - {y_1}} \\right) + {x_3}\\left( {{y_1} - {y_2}} \\right)} \\right]{/tex}= 0{tex} \\Rightarrow {/tex}{tex}\\frac{1}{2}\\left[ {2\\left( {k + 3} \\right) + 4\\left( { - 3 - 3} \\right) + 6\\left( {3 - k} \\right)} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}\\left[ {2k + 6 - 24 + 18 - 6k} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}\\left[ { - 4k} \\right] = 0{/tex}{tex} \\Rightarrow {/tex}{tex}k = 0{/tex} | |
| 34232. |
If angle A and angle B are acute angle such that cosA =cosB , then show that ang. A =ang. B |
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Answer» Draw a triangle ABC in which BC should be Base and triangle is at right angle at ang.CNow in triangle ABCCos A= side adjacent A/Hypotenuse= AC/ABSimilarly,COS B = side adjacent B/Hypotenuse= BC/ABGiven thatCOS A= COS BAC/AB=BC/ABAC=BCIN A TRIANGLE OPPOSITE SIDES ARE EQUALANG B= ANG APROVED..\xa0 |
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| 34233. |
Exercise 3.2 Q 6 |
| Answer» Of which book | |
| 34234. |
2x sqaure minus 50 |
| Answer» 2(x^2 - 25) | |
| 34235. |
Prove that the product of two consecutive posetive integers is divisible by two |
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Answer» Let two consecutive + ve integer r n and n+1n*n+1=n2+ nLet n=2q so (2q)2 + 2qThen we take common from it 2 then we have2(2q2+q)Divide by 2 then we have2q2+qRemainder is 0 so it is completely divisibleHence prooved... Take a example2*1=2and then divive by 2 so 2/2=1So it is completely devisible |
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| 34236. |
Rout in 2,1apond 3 write the method of sum of zero and product of zero |
| Answer» Alpha+beta and product of zero =alpha*beta | |
| 34237. |
Which help book is best for maths?? |
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Answer» Motivasional math R.D Sharma R.D.sharma |
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| 34238. |
If 2 and 3 are zeroes of polynomial 3x square -2kx+2m then fund the value of k and m |
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Answer» Sorry i haven\'t read the ques carefully. Since 2 and 3 are 0s of polynomial then (x-2) and (x-3) are factors.Then, (x-2)×(x-3) is also a factor.X^2-5x+6 is also a factor.Now divide the given polynomial px by the new factor.U\'ll get some quotient.Now do middle term split of the quotient and u will get other 0s |
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| 34239. |
Find the quadratic polynomial where sum and product of the zeros one and 1/a |
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| 34240. |
Is -2 a prime number? If yes,so why and if no so,why not? |
| Answer» No,\xa0By the usual definition of prime for integers, negative integers can not be prime. | |
| 34241. |
X=6+3y then y=? |
| Answer» x = 6 + 3yx - 6 = 3yy = x - 6/3 | |
| 34242. |
Ch 8 ncert |
| Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 34243. |
X=3y |
| Answer» | |
| 34244. |
Replace*by the smallest number take it divisible by 9 (65*5) |
| Answer» Hlo muskan | |
| 34245. |
What is goldbech\'s conjecture |
| Answer» Every even integer greater than 2 can be expressed as the sum of two primes. | |
| 34246. |
Smallest composite number |
| Answer» 4 | |
| 34247. |
In which percentage we get commerce without mathematics |
| Answer» 70 | |
| 34248. |
What is Algebraic Expression ? |
| Answer» Algebraic expression are those expression or variable which don\'t have defined values | |
| 34249. |
Sec theta×cos theta=? |
| Answer» Cos theta ×sec thetaB/H×H/B=1 | |
| 34250. |
Sin theta ×cosec theta=? |
| Answer» Sin theta =P/HCosec theta=H/PA.T.QP/H×H/P=1 | |