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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34451. |
What must be added or subtracted from the polynomial is exactly divisible by x squared +2x-3. |
| Answer» f(x) = x4 + 2x3 - 2x2 + x - 1Remainder = -x + 2Therefore, we should add –(–x+ 2) to make it divisible exactly by x2 + 2x – 3.Thus, we should add x – 2 to x4 + 2x3 – 2x2 + x – 1 . | |
| 34452. |
Detrmine wheather the value of x is zero of given polynomial or not x2+x+1,x=-1 |
| Answer» Xsquare+x+1Substitute -1in place of x(-1)square +(-1)+11-1+1=1No the value of x is not zero of the given polynomial | |
| 34453. |
Paper kitne no ka aayenga 70 ya 80 |
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Answer» Last year, it was 80. 80 ka I also think 80 marks but I think it will come 70 marks because this marks is on examination master hands so anything can come. 80 marks ka 80 |
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| 34454. |
If x^y + y^x =2xyAnd (1/x) ^1/y+(1/y)^1/x =2underrot x /yFind x and y |
| Answer» {tex}\\huge Do \\space you\\space think\\space this \\space is\\space valid\\space \\space :x^y\\:+\\:y^x\\:=2xy,\\:x^{\\left(-1/y\\right)}\\:+\\:y^{\\left(-1/x\\right)}=2\\cdot \\:sqrt\\left(x/y\\right){/tex} | |
| 34455. |
6x+3y=6xy----(1)2x+4y=5xy----(2)Slove it ? |
| Answer» 6x+3y=6xy------(1)2x+4y=5xy------(2) | |
| 34456. |
if x×x+x+1=0 then x×x×x=? |
| Answer» 3x | |
| 34457. |
Find the hcf of 960 and 1575 by using Euclid algorithm |
| Answer» It is very long process | |
| 34458. |
What do people say about the ending of the world? |
| Answer» Ask these kinds of question\xa0on quora.com , not here | |
| 34459. |
Exercise 6.2 2nd question of triangles lesson |
| Answer» This app has all the NCERT solutions of Mathematics. So, you can see the solution of your question in this app.? | |
| 34460. |
Best book for science,math,sst,english,hindi ...? Plz tell me .. |
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Answer» U like is the best book of all subjects U like is the best book |
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| 34461. |
Splitting middle term 2×^+4×-16=0 |
| Answer» 2x square +8x-4x -16 2x(x-4)+4(x-4)(2x+4)(x-4)X=-2,X=4 | |
| 34462. |
When will improvement exam forum be filled |
| Answer» | |
| 34463. |
X3-3 x+5 x-3 |
| Answer» | |
| 34464. |
9(secA)²–9(tanA)²= |
| Answer» | |
| 34465. |
What is the difference between sinA and cosA. |
| Answer» | |
| 34466. |
2 year |
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Answer» What 2 year What |
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| 34467. |
Prove that square root 3 + square root 5 is irrational |
| Answer» | |
| 34468. |
Chapter 2 polonomials give the notes |
| Answer» Yess | |
| 34469. |
Find the sum of the 40 positive integer divisible by 6 |
| Answer» We know that the first 40 positive integers divisible by 6 are 6,12,18,....This is an AP with a = 6 and d = 6S40 = n/2 [2a + (n - 1)d]S40 = 20[2(6) +(40-1)6]= 20[12+234]= 4920 | |
| 34470. |
If a and B are zeroes of the polynomial x2-7x+10.find a quadratic polynomial whose zeros are |
| Answer» x2-7x+10=x2-5x-2x+10=x(x-5)-2(x-5)=(x-2)(x-5)=> x=2/5 | |
| 34471. |
Find five rational no between 6/5 and 7/3 |
| Answer» 19/15,20/15,21/15,22/15,23/15 | |
| 34472. |
State wether it is terminating or non terminating6/15 |
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Answer» It is terminating Hlo This one is terminating Divide numerator and denomintor both by 3, we get 2/5. Denominator is in the form of 5^m, so the given no. is terminating.? |
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| 34473. |
Find the zero of the quadratic polynomials 7yy-11/3y-2/3 |
| Answer» p(y) = 7y2 -\xa0{tex}\\frac{11}{3}{/tex}y -\xa0{tex}\\frac{2}{3}{/tex}\xa0=\xa0{tex}\\frac{1}{3}{/tex}\xa0(21y2 - 11y - 2)=\xa0{tex}\\frac{1}{3}{/tex}[(7y + 1)(3y - 2)]{tex}\\therefore{/tex}\xa0Zeroes are\xa0{tex}\\frac{2}{3}{/tex}, -\xa0{tex}\\frac{1}{7}{/tex}Sum of Zeroes =\xa0{tex}\\frac{2}{3}{/tex}\xa0-\xa0{tex}\\frac{1}{7}{/tex}\xa0=\xa0{tex}\\frac{11}{21}{/tex}{tex}\\frac{-b}{a}{/tex}\xa0=\xa0{tex}\\frac{11}{21}{/tex}\xa0{tex}\\therefore{/tex}\xa0sum of zeroes =\xa0{tex}\\frac{-b}{a}{/tex}Product of Zeroes = ({tex}\\frac{2}{3}{/tex})(-{tex}\\frac{-1}{7}{/tex}) = -{tex}\\frac{2}{21}{/tex}{tex}\\frac{c}{a}{/tex}\xa0= -\xa0{tex}\\frac{2}{3}{/tex}({tex}\\frac{1}{7}{/tex}) = -{tex}\\frac{2}{21}{/tex}{tex}\\therefore{/tex}\xa0Product =\xa0{tex}\\frac{c}{a}{/tex} | |
| 34474. |
100÷5 |
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Answer» Can you use your sense of humor please. Its answer is 20 20 20 ans Ask question of sense pl 20 20 20 |
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| 34475. |
Find the value of k for which the system3x+y=1Kx+y=1Has (1) unique solution and (2) no solution |
| Answer» For no solution k=3 | |
| 34476. |
Find the HCF of the polynomials 2x²-x-1and 4x²+8x+3. |
| Answer» 2x²-x-1=2x²-2x+x-1=2x(x-1)+(x-1)=(x-1)((2x+1)and 4x²+8x+3.=4x²+6x+2x+3=2x(2x+3)+(2x+3)=(2x+3)(2x+1)Here common factor=2x+1hence\xa0HCF=2x+1\xa0 | |
| 34477. |
in the given figure De parallel to OQ and DE parallel to OR prove that EF parallel to OQ |
| Answer» In {tex}\\triangle {/tex}OQP,DE || OQ{tex}\\frac{{PE}}{{EQ}} = \\frac{{PD}}{{DO}}{/tex} .....(i)In {tex}\\triangle {/tex}OPR,DF {tex} \\bot {/tex} OR{tex}\\frac{{PD}}{{DO}} = \\frac{{PF}}{{FR}}{/tex} .....(ii)From (i) and (ii) , we get{tex}\\frac{{PE}}{{EQ}} = \\frac{{PF}}{{FR}}{/tex}{tex}\\therefore {/tex} From {tex}\\triangle {/tex}PQREF {tex} \\bot {/tex} OR | |
| 34478. |
Check whether the given equation is quadratic equation:(2x-1) (x-3)=(x+5) |
| Answer» (2x-1) (x-3)=(x+5)2x2-x-6x+3=x+52x2-8x-2=0x2-4x-1=0this is a quadratic equation | |
| 34479. |
Convert maths all chapter in hindi medium |
| Answer» Buy hindi medium book | |
| 34480. |
5/x - 3/y= 2 |
| Answer» 5/x - 3/y = 2(5y - 3x)/xy = 25y - 3x = 2xy | |
| 34481. |
Using Euclid\'s algorithm. Find the HCF of 144 and 198 |
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Answer» Prime factorization:{tex}144 = 2 ^ { 4 } \\times 3 ^ { 2 }{/tex}{tex}198 = 2 \\times 3 ^ { 2 } \\times 11{/tex}HCF = product of smallest power of each common prime factor in the numbers {tex}= 2 \\times 3 ^ { 2 } = 18{/tex} HCF(144,198) 198 = 144×1+54144 = 54×2+3654 = 36 ×1 + 18 36 = 18 ×2 +0Therefore HCF (144,198) =18 |
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| 34482. |
If p(x)=3 x^ -2x`+6x-5,find p(2) |
| Answer» Hahaha, oh my god!!!, don\'t you think this is too much, you are not studying properly{tex}\\large p(x):x^3 -x^2+6x-5\\\\putting, \\space x=2\\\\p(2):(2)^3-(2)^2+6\\times2-5\\\\p(2):8-4+12-5\\\\p(2):\\boxed {11}{/tex}You just only have to replace \'{tex}\\large x{/tex}\' by the value given and perform the arithmetic operations.Now, after seeing this, don\'t forget it.\xa0And please write your qeustions properly while asking. | |
| 34483. |
a+) |
| Answer» What is this bro type the question first | |
| 34484. |
If one zero of the polynomial (a² - 9) x² + 13x + 6a is reciprocal of the other, find the value of a |
| Answer» Let {tex} \\alpha{/tex}\xa0and\xa0{tex} \\frac { 1 } { \\alpha }{/tex} be the zeros of\xa0(a2\xa0+ 9)x2\xa0+ 13x\xa0+ 6a.Then, we have{tex} \\alpha \\times \\frac { 1 } { \\alpha } = \\frac { 6 a } { a ^ { 2 } + 9 }{/tex}⇒\xa01 =\xa0{tex} \\frac { 6 a } { a ^ { 2 } + 9 }{/tex}⇒\xa0a2\xa0+ 9 = 6a⇒ a2 - 6a + 9 = 0⇒\xa0a2\xa0- 3a - 3a + 9 = 0⇒\xa0a(a - 3) - 3(a - 3) = 0⇒\xa0(a - 3) (a - 3) = 0⇒\xa0(a - 3)2\xa0= 0⇒\xa0a - 3 = 0⇒ a = 3So, the value of a in given polynomial is 3. | |
| 34485. |
Pythagoras theorum 9.1 |
| Answer» | |
| 34486. |
Why the( √2) in square under root cut |
| Answer» {tex}\\begin{array}{l}\\sqrt2=2^{1/2}\\\\(\\sqrt2)^2=(2^\\frac12)^2\\\\=2^{\\frac12\\times2}\\\\=2^1\\\\=2\\\\Hence\\;the\\;root\\;is\\;removed\\;\\end{array}{/tex}\xa0 | |
| 34487. |
Ap questions |
| Answer» | |
| 34488. |
ABCD is a trapezium with ABparallel DC |
| Answer» What we have to do now we all know that one pair of trapeziym is parallel abd other one is non parallel | |
| 34489. |
X_y ka factorise |
| Answer» Question dhaag se bhj bhai | |
| 34490. |
1/cosecA-cotA-1/sinA=1/sinA-1/cosecA-citA |
| Answer» | |
| 34491. |
Solve equation0.2x+0.3y=1.30.4x+0.5y=2.3 |
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Answer» 0.2 x + 0.3 y = 1.3 ; 0.4 x + 0.5 y = 2.3The given system of linear equations is:0.2 x + 0.3 y = 1.3..............(1)0.4 x + 0.5 y = 2.3...................(2)From equation (1),\xa00.3 y = 1.3 - 0.2 x{tex}\\Rightarrow \\quad y = \\frac { 1.3 - 0.2 x } { 0.3 }{/tex}.........................(3)Substituting this value of y in equation(2), we get{tex}0.4 x + 0.5 \\left( \\frac { 1.3 - 0.2 x } { 0.3 } \\right) = 2.3{/tex}{tex}\\Rightarrow{/tex}0.12 x + 0.65 - 0.1 x = 0.69{tex}\\Rightarrow{/tex}0.12 x - 0.1 x = 0.69 - 0.65{tex}\\Rightarrow{/tex}0.02 x = 0.04{tex}\\Rightarrow{/tex}{tex}\\mathrm { x } = \\frac { 0.04 } { 0.02 } = 2{/tex}Substituting this value of x in equation(3), we get{tex}y = \\frac { 1.3 - 0.2 ( 2 ) } { 0.3 } = \\frac { 1.3 - 0.4 } { 0.3 } = \\frac { 0.9 } { 0.3 } = 3{/tex}Therefore, the solution is x = 2, y = 3, we find that both equation (1) and (2) are satisfied as shown below:0.2 x + 0.3 y = ( 0.2 )( 2 )+( 0.3)( 3 ) =\xa00.4 + 0.9 = 1.30.4 x + 0.5 y= ( 0.4 )( 2 ) + ( 0.5 )( 3 ) }\xa0= 0.8 + 1.5 = 2.3This verifies the solution.\u200b\u200b\u200b\u200b\u200b\u200b\u200b 0.2x+0.3y = 1.3 ....... (i)eq (i) ×102x+3y=130.4x+0.5y=2.3 ...... (ii)eq(ii) ×104x+5y=23from eq (i)x =13-3y/2putting value of x in eq (ii)4(13-3y/2)+5y=2326-6y+5y=2326-y=23y= 3putting value of y in eq (i)2x+3(3)=132x=13-9x=4/2x=2\xa0 |
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| 34492. |
Show that the polynomial x^2-6x+12 has no zeroes |
| Answer» x2\xa0- 6x + 12Here, a = 1, b = -6 and c = 12D = b2\xa0- 4acD = (-6)2\xa0- 4(1)(12)D = 36 - 48D = -12Hence, D < 0Therefore, there exists no real root of the equation. | |
| 34493. |
RD YA DESK WORK SE QUESTIONS AATE HA KY |
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Answer» Ha aate hai... WHAT SAY.?? YES.. Board exam me?? |
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| 34494. |
If 5cos theta=7sin theta find 7sin theta+ 5cos theta÷ 5sin theta + 7 cos theta |
| Answer» {tex}\\begin{array}{l}\\frac{7\\sin\\;\\theta+\\;5\\cos\\theta}{\\;5\\sin\\theta\\;+\\;7\\;\\cos\\;\\theta}=\\frac{7\\sin\\;\\theta+7\\sin\\;\\theta}{7\\sin\\;\\theta+{\\displaystyle\\frac{\\;7\\times5}5}\\cos\\theta}\\\\=\\frac{\\displaystyle14\\sin\\;\\theta}{7\\sin\\;\\theta+{\\displaystyle\\frac75}\\times7\\sin\\;\\theta}=\\frac{70\\sin\\;\\theta}{7\\sin\\;\\theta+49\\sin\\;\\theta}\\\\=\\frac{\\displaystyle70\\sin\\;\\theta}{\\displaystyle56\\sin\\;\\theta}=\\frac{70}{56}=\\frac54\\end{array}{/tex} | |
| 34495. |
Find factor tree on 874944 |
| Answer» | |
| 34496. |
Find all the zeroes of polynomial 5x^2-15x^2-3x+9, if two of its zeroes are √3/5 and -√3/5 |
| Answer» | |
| 34497. |
Compartment exam paper 2019 cbse |
| Answer» Please send me the details of the compartment exam paper 2019 cbse | |
| 34498. |
How can we consider this examination pattern 2020 as per previous years questions or or the latest |
| Answer» | |
| 34499. |
Write the relationship between zeros of polynomial ax^3+bx^2+cx+d if zreoes are alpha,beta, gamma. |
| Answer» {tex}\\begin{array}{l}\\alpha+\\beta+\\gamma=-\\frac ba\\\\\\alpha\\beta\\gamma=-\\frac ca\\\\\\alpha\\beta+\\beta\\gamma+\\gamma\\alpha=\\frac da\\\\\\\\\\end{array}{/tex} | |
| 34500. |
Sin power 4 theta minus Cos square theta |
| Answer» Question is incomplete | |