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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34751. |
2cos•cos60 +3sin•sin45 -3sin•sin30 + 2cos•cos90 |
| Answer» 3root2-1 whole divided by 2 | |
| 34752. |
If m times the nth term of a.p is equal to n times its nth term than show m+nth term -0 |
| Answer» Let a be the first term and d be the common difference of the given AP. Then, in general the mth and nth terms can be written as\xa0Tm = a + (m - 1) d and Tn = a + (n - 1)d respectively.According to the question,we are given that,\xa0(m.Tm) = (n.Tn){tex}\\Rightarrow{/tex}\xa0m.{a + (m - 1)d} = n.{a + (n - 1)d}{tex}\\Rightarrow{/tex}\xa0a.(m - n) + {(m2 - n2) - (m - n)} . d = 0{tex}\\Rightarrow{/tex}\xa0(m - n).{a + (m + n - 1)}d.{tex}\\Rightarrow{/tex}\xa0(m - n).Tm+n = 0{tex}\\Rightarrow{/tex}Tm+n = 0 [{tex}\\because{/tex}\xa0(m-n){tex}\\neq{/tex}0].Hence, the (m + n)th term is zero. | |
| 34753. |
If the sum of three no. is 24 and their product is 440 but these are in AP find these three numbers |
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Answer» Let the numbers be a,a+d,a+2d .a+a+d+a+2d=24a+d=8,which is the second termNow,a(a+d)(a+2d)=440a(a+2d)8=440a(a+2d)=55a(a+2d)=5×11So a=5,a+d=8,a+2d=11? Kaise solve kiye 5,8,11 Please solve it step by step 24 42 34 |
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| 34754. |
What is circumscribe of circle by equilateral triangle |
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Answer» A circle inside the equilateral triangle It means the inside a equi. triangle there is a circle .... |
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| 34755. |
Example 4 of chapter area related to circle of class 10 |
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| 34756. |
3+2under root 5 is irrational |
| Answer» Let 3+2√5 be rational in the form of a/b and then derive two common factor of 3+2√5 and then prove | |
| 34757. |
Minus 2 root 5 the whole square equala |
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Answer» 20 (-2√5)²=-2×-2×√5×√5=4×5=20This is the correct answer i am very much sure do this 20 50 |
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| 34758. |
Very very very easy way to do top in maths |
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Answer» yes why not Hi Neha Practice makes a man perfect Practise , practise and practise the most easiest way. |
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| 34759. |
How to proof area therome of chaoter triangles |
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| 34760. |
Find the quadratic polynomial whose zeros are - 3 and 4 |
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Answer» x^2-x-12 X^2-x-12 |
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| 34761. |
I do lots of practise but i dont understand chaptr 13 of class 10 maths |
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Answer» Not only you have to do practice but also u have to see that how it is solved and by which formula and do that question again and ahain Learn all the formulas and then read the question and translate it in hindi u will understand what the question is asking to find. Revise this chapter just before the exam. Pls tell n |
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| 34762. |
Sec thita+Tan thita=p then find the value of cosec thita |
| Answer» Brainly.inWhat is your question?1Secondary SchoolMath 8 pointsIf sec theta + tan theta = p, then find the value of cosec thetaAsk for details Follow Report by Imhanmerincess 18.08.2016AnswersARoyARoy ExpertSecθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) Ans. | |
| 34763. |
2nd |
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| 34764. |
How to score ? in mathematics |
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Answer» Just solve NCERT book of maths as it is vry important for boards First clear the concept of chapter and practice as more as you can. And don\'t fotget to practice ncert questions as they are most important from examination point of view. Simple technique Jo kar sako vo kar lo bas......? Keeps practice and practice..... Learn all formulaes ...... Solve all sample paper from last 10 years ..... |
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| 34765. |
Sum and product of zeroes of quadratic polynomial p(x) are 7 and 10 respectively then find p(x) |
| Answer» X2-7x+10 | |
| 34766. |
Prove that tangents drawn at the end of diameter are parallel |
| Answer» Angles made by the tangents on The point of contact on both sides are equal 90\' so by alternative angle property both tangent are parallel | |
| 34767. |
If sec A=p ,prove that sin A=(p^2 -1)/(p^2 +1 |
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| 34768. |
Prove that the tangent drawn a circle at a diameter are parallel |
| Answer» Given: PQ is a diameter of a circle with centre O. The lines AB and CD are the tangents at P and Q respectively.\xa0To prove: AB\xa0{tex}\\parallel{/tex} CDProof: AB is a tangent to the circle at P and Op is the radius through the point of contact{tex}\\because{/tex}{tex}\\angle{/tex}OPA = 90o .......(1) [The tangent at any point of a circle is perpendicular to the radius through the point of contact]{tex}\\because{/tex}\xa0CD is a tangent to the circle at Q and OQ is the radius through the point of contact.{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}OQD = 90o ........(2) [The tangent at any point of a circle is perpendicular to the radius through the point of contact]From (1) and (2),{tex}\\angle{/tex}OPA = {tex}\\angle{/tex}OQDBut these form a pair of equal alternate angles.{tex}\\because{/tex}\xa0AB\xa0{tex}\\parallel{/tex} CD | |
| 34769. |
Prove that the parallelogram of service centre in the Rhombus |
| Answer» Given : ABCD is a parallelogram circumscribing a circle.To prove: ABCD is a rhombus\xa0Proof:\xa0{tex}\\because{/tex} The tangent segments from an external point to a circle are equal{tex}\\therefore{/tex}\xa0AP = ASBP = BQCR = CQand DR = DS{tex}\\Rightarrow{/tex}\xa0(AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ){tex}\\Rightarrow{/tex}\xa0AB + CD = AD + BC{tex}\\Rightarrow{/tex}\xa0AB + AB = AD + AD[{tex}\\because{/tex} Opposite sides of parallelogram are equal]{tex}\\Rightarrow{/tex}\xa02AB = 2AD{tex}\\Rightarrow{/tex}\xa0AB = ADBut\xa0AB = CD And AD = BC [Opposite sides of parallelogram]{tex}\\therefore{/tex}\xa0AB = BC = CD = AD{tex}\\therefore{/tex}\xa0Parallelogram ABCD is a rhombus. | |
| 34770. |
Prove that the tangent drawn a point at the diameter are parallel |
| Answer» see the example of rs aggrawal | |
| 34771. |
How to learn formulas of chapter 12 and 13 |
| Answer» Raata mar | |
| 34772. |
What is mean by two consecutive positive integers |
| Answer» Consecutive numbers are numbers that follow each other in order. They have a difference of 1 between every two numbers. In a set of consecutive numbers,the mean and the median are Equal.If n is a number, then n can be equal to n+1 and n+2ExamplesConsecutive: numbers that follow each other in order1, 2, 3, 4, 5 | |
| 34773. |
4758 ka HCF |
| Answer» Hey what\'s the second no. | |
| 34774. |
What is the nature of roots of qudratic equation 5x square -7x+2=0 |
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Answer» It has real roots but not equal D= bsqare - 4ac = 49 - 40 = 9 hence the equation have real and eqal roots |
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| 34775. |
If nth term of an A.P. is (2n+1),what is the sum of its first third number |
| Answer» If nth term of an A.P = 2n+1then, first term of A.P = 2(1)+1= 2+1= 3then, second term = 2 (2) + 1》4+1》5third term = 2 (3) +1》6+1》7sum of terms = 3+5+7sum of terms = 15 | |
| 34776. |
If surface area of 2 sphere are in ratio 9:16 then find the ratio of their raddi |
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Answer» The ratio of radii is 3:4 3:4 Its very easy |
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| 34777. |
(a+b)2=(a-b)2+4ab |
| Answer» How to solve | |
| 34778. |
Sample paper 2 pre borad |
| Answer» Check Sample Papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 34779. |
How to prove theorem 10.1 |
| Answer» Herw is the solution of yours MAN IF YOU ARE INTERESTED THIS GO FOR IT https://youtu.be/0tGCThUMGXQ | |
| 34780. |
What is the probability that a leap year, selected at random will contain 53 thursdays? |
| Answer» 1 year = 365 days A leap year has 366 days A year has 52 weeks. Hence there will be 52 Sundays for sure. 52 weeks = days 366 – 364 =2 days In a leap year there will be 52 Sundays and 2 days will be left. These 2 days can be: Sunday, Monday Monday, Tuesday Tuesday, Wednesday Wednesday, Thursday Thursday, Friday Friday, Saturday Saturday, Sunday Of these total 7 outcomes, the favourable outcomes are 2. Hence the probability of getting 53 days =2/3Visit www.ethicalabhishek.tk for my website | |
| 34781. |
What is difference between height and slant height |
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Answer» Height is alwasy perpendicular ....But slant height is hypotenuse And its formula is UNDERROOT H SQUARE + R SQUARE Bhai height perpendicular hoti hai aur slant height hypotenuse hota hai |
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| 34782. |
Use euclid divison algorithm 135 and 225 |
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Answer» a=bq + r225=135×1+90135=90×1+4590=45×2+0 What find 45 |
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| 34783. |
Bhjkv |
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Answer» Hello Hii |
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| 34784. |
Cost A =7/5 prove it |
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| 34785. |
How to score good marks in maths without tution |
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Answer» Do lot of practice solve the questions from differant books and of differant type.Atleast you have to solve RD sharma examples Do alot of practice solve the whole ncert as well as ncert exemplar ? u will score good Solve ncert with all example First read question carefully and understand it and read that certain formula and start practising by thinking logically you can gain it Solve ncert question answers and try to solve every examples of rs aggrawal |
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| 34786. |
2 3 4 5 .......................9 9 is it an ap |
| Answer» Yes T2-T1=3-2=1 its common difference is same. | |
| 34787. |
What is the value of (cos2 67°-sin2 73°) |
| Answer» {tex}\\because{/tex}\xa0cos 67o = sin 23o\xa0{tex}\\because{/tex}\xa0cos2 67o - sin2 23o = 0 | |
| 34788. |
If sinA +cosB = under root 2 |
| Answer» Plz post full ques | |
| 34789. |
Prove that 2+5√7 is an irrational number. |
| Answer» Let 2+5√7 is a rational numberHere,2+5√7=p÷q (q≠0) 5√7=p÷q-2 5√7=p-2q÷q P-2q÷q are rational numberSo,5√7 is rational number but this contradiction is incorrectHence,2+5√7 is an irrational number (proved) | |
| 34790. |
Which references are best for board examination preparation?? |
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Answer» NCERT exemplar R.D sharma and ncert exampler Rd sharma |
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| 34791. |
Who am i? Billa? |
| Answer» Yess..u r billa | |
| 34792. |
Write the value of cot2θ–1sin2θ. |
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Answer» question is wrong bro Apne se banao na |
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| 34793. |
Probability of red card and a king |
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Answer» 28upon52 Simple |
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| 34794. |
Can the diagnols of the rectangle bisect to form 45 degree to the adjacent side |
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Answer» As we can say that square is also a type of square... so I mean to say that its only possible in a square Rectangle in the form of square ⬜ .... I am not getting it... Please explain Only possible when the rectangle is in the form of a square... |
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| 34795. |
Find the value of k for which one root of quadratic equation kx2_14x+8=0is2 |
| Answer» K=5 | |
| 34796. |
Find the ratio in which the line segment joining P(x1,y1) and Q(x2,y2) is divided by x-axis |
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| 34797. |
Is class 10 board exam will be on February or March |
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Answer» Hamra to n pta hau Yaar good luck for the future board exam????? It depends on your subjects, vocational subjects will occur in feb whereas main subjects will occur in march Bhie phale school ke exam to de Possibly it may be 6march It will be in last week of february or in starting of march. I think so it would be on 7 march |
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| 34798. |
10^2y=2^5Find the value of 10^-y |
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| 34799. |
FIND THE VALUE OF 3 power 3+ 3 power 3 +3 power 3 |
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Answer» 81 81 We dont know b✊✊✊ |
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| 34800. |
What is marking scheme of maths class x |
| Answer» You can check the marking scheme in the syllabus here :\xa0https://mycbseguide.com/cbse-syllabus.html | |