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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 35301. |
(Alpha)(beta)=? |
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Answer» C/A.✅ (Alpha) (beta) =c/a c/a c/a |
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| 35302. |
Draw a line segment of length 7cm . Find a point p on it which divide it in the ratio 3:5 |
| Answer» We have to draw a line segment of length 7 cm.Then,we have to find a point P on it, which divides it in the ratio 3 : 5.Steps of construction:\tDraw a line segment {tex}AB=7{/tex} cm.\tDraw a ray AX, making an acute {tex}\\angle BAX{/tex} with AB.\tMark {tex}3+5=8{/tex} points, i.e, {tex}A_1, A_2, A_3, A_4 ...A_8{/tex} on AX, such that {tex}AA_1 = A_1A_2 = A_2A_3 = A_3A_4 ... = A_7A_8{/tex}\tJoin A{tex}_8{/tex}B\tFrom A3, draw {tex}A_3P || A_8B{/tex} which intersects AB at point P [ by making an angle at A3 equal to {tex}\\angle AA_8B{/tex}\xa0\tThen, P is the point on AB which divides it in the ratio 3:5. So, {tex}AP : PB = 3:5{/tex}Justification: In {tex}\\triangle ABA_8{/tex}, we have {tex}A_3P || A_8B{/tex}\xa0{tex}\\therefore \\frac{AP}{PB}=\\frac{AA_3}{A_3A_8}{/tex} [ by basic proportionality theorem]By construction, {tex}\\frac{AA_3}{A_3A_8}=\\frac{3}{5}{/tex}\xa0Hence, {tex}\\frac{AP}{PB}=\\frac{3}{5}{/tex} | |
| 35303. |
What is the volume of triangular prism |
| Answer» 1/2 • a(base side) • c (base side) • h (height) | |
| 35304. |
How to draw more than type ogive |
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| 35305. |
What is quadrant |
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Answer» 1/4 part of the circle is a quadrant The cartesian plane is divided by the axis of refrence into four part is known as quadrant . |
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| 35306. |
What is corresponding chord |
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| 35307. |
Hcf by algorithm of 135 and 225 |
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Answer» 135 and 225225=135×1+90135=90×1+4590 =45×2+0So HCF of135 and 225 is 45. Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45. |
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| 35308. |
In these app anyone is geneous.if you are so why you are used these app ? |
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Answer» What is the proof.proof me u r a geneous. Yes ,I m geneous and, I use this app because I want to always be a geneous . |
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| 35309. |
Find the median of following table |
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Answer» Table? Where is table |
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| 35310. |
A line is drawn pll to ( 5,3) to y axis what is the distance |
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| 35311. |
tangent and secant defference |
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Answer» Tangent: A tangent is a line that touches a circle at only one point. A tangent is perpendicular to the radius at the point of contact. The point of tangency is where a tangent line touches the circle.Secant: When the line touches the circle at two points: It is called a secant. A secant line intersects the circle in two points. A line which intersect a circle in two distinct points is called a secant and a line meeting a circle only in one point is called tangent. |
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| 35312. |
[ A³ + 3A² + 9A = 1 ] then find [ A³ + 3/A] |
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| 35313. |
Write general form of euclid division algorithum |
| Answer» a=bq+r | |
| 35314. |
Determine k in which 3k-2 ,4k-6 and k+2 are consecutive term of ap |
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Answer» 4k-6-(3k-2)=k+2-(4k+6). {Common difference is equal coz its an Ap}4k-6-3k+2=k+2-4k-6k-4=3k-44k=0k=0 O 4k-6-(3k-2)=k+2-(4k-6) |
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| 35315. |
Ex 12.3 quation 2 |
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| 35316. |
Resources |
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Answer» Which is available, affordable, feasible and acceptable by the society a supply of something, a piece of equipment, etc. that is available for somebody to use |
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| 35317. |
How many marks do ap have? |
| Answer» 5to 8 | |
| 35318. |
The side if square is 10 cm.find the area of circumscribed and inscribed circle. |
| Answer» Side of square = 10cmFor incirclediameter of circle = side of square{tex}\\Rightarrow r = \\frac{{10}}{2} = 5cm{/tex}{tex} \\therefore {/tex}\xa0Area of incircle\xa0{tex}= \\pi {r^2}{/tex}{tex}= 3.14 \\times 5 \\times 5{/tex}78.50 cm2For circumcircleAC will be the diameter because\xa0{tex} \\angle B = 90^\\circ {/tex}Now, In\xa0{tex} \\triangle ABC{/tex}, by pythagoras theoremAC2 = AB2 + BC2{tex}\\Rightarrow {/tex}\xa0AC2 = 102 + 102{tex}\\Rightarrow {/tex}\xa0AC2 = 200{tex}\\Rightarrow AC = \\sqrt {200} = 10\\sqrt 2 cm{/tex}{tex} \\therefore {/tex}\xa0Area of circumcircle\xa0{tex}= \\pi {r^2}{/tex}{tex}= 3.14 \\times {\\left( {5\\sqrt 2 } \\right)^2}{/tex}{tex}= 3.14 \\times 50{/tex}= 157cm2 | |
| 35319. |
What do u mean by cross section and how to find the cross section area of any figure |
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| 35320. |
X3+1/x3=52, then x+1/x=? |
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| 35321. |
Find area of triangle with vertices (a, be), (b, na) and (c, an) |
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| 35322. |
SecA + tanA=p then find the value of cosecA |
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| 35323. |
What is measure of central tendency.? |
| Answer» Often in statistics, we tend to represent a set of data by a representative value which would approximately define the entire collection. This representative value is called as the measures of central tendency. The name itself suggests that it is a value around which the data is centered.The measures of central tendency are given by various parameters but the most commonly used are mean, median and mode | |
| 35324. |
TEN =72, MEN =65, HAT =? |
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Answer» 58 60 |
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| 35325. |
How to make maths easy....it is very hard |
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Answer» Practice regularly you will get??? +.-.main galati mt kro.formule yad krlo.confident .and maths is very easy Do regular practice and make it easy Regular practice make maths easy Command on formula |
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| 35326. |
What is the easy way to understand trignometry |
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Answer» Learn the values Only to comand on tringle (angles sides) remember formula And also you remember all formulaa. focus on basics..? To know consept |
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| 35327. |
Hcf of 25 and35 |
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Answer» HCF of 25&35 is 5 25=5×535=5×7HCF OF 25 & 35=5 |
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| 35328. |
Mere dost ka name sec^2 h to mera name kya h |
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Answer» Tera naam ajax shrimali 1+tan^2 hoga |
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| 35329. |
if a fraction p/q is a terminating decimal,then q can be |
| Answer» q is a product of 2&5 or 2 and sirf 5. | |
| 35330. |
P(6,-6),Q(3,-7),and R(3,3) are collinear or not explain that |
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Answer» if pq=qr=pr=0 then it will be collinear?????????????????????????????????????????????? You should do by yourself Check if sum of any 2 of them is equal to the 3rd Eg PQ+QR=PR or else I don\'t know ?? |
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| 35331. |
What is the assume mean method, with example |
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| Answer» For calculating arithmetic mean from this data, We have to first take the midpoint of each class interval, represented by \'m\' in the table. Then decide on anyone midpoint as assumed mean and find out the deviations.Calculation of Arithmetic Mean | Marks | Number of Students (f) | Mid-Value (m) | dm (m-A) A=45 | fdm | \xa0 | \t\t\t10-20215-30-60-30020-30725-20-14030-401035-10-10040-50154500\xa050-602055+10+200+70060-701665+20+32070-80675+30+180\xa0{tex}\\Sigma f = 76{/tex}\xa0\xa0\xa0{tex}\\Sigma f d m = + 400{/tex}\tAfter multiplying fd with m for all the values and finding the total of fdm, we apply the values to the formula of mean given below:Now,\xa0{tex}\\overline { X } = A + \\frac { \\Sigma f d m } { \\Sigma f } \\Rightarrow \\overline { X } = 45 + \\frac { 400 } { 76 }{/tex}{tex}\\Rightarrow \\quad \\overline { X } = 45 + 5.26 = 50.26{/tex}|
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| 35332. |
Ex 11.1 |
| Answer» Get NCERT solutions from here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 35333. |
a^x=bc, b^y=ac and c^z=ac . Then show that Xyz= x+y+z+2 |
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| 35334. |
Anybody have sample question paper of math and science 2018-19 |
| Answer» It will be on net 19 november | |
| 35335. |
At x axis.find the point which are equidistant for (2,-5) and(-2,9). |
| Answer» -8,0 | |
| 35336. |
Which book shout we prefer for board in matha and science |
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Answer» I think best book for 10th.....Science-book of lakhmir singh and manjeet kaur----S-chand And math - R d sharma....Hope u understood please text me My frnd I can suggest u that plzz surely go through the NCERT books thoroughly and for reference u can use R.D SHARMA for maths ans S.CHAND for science.I THINK IT WOULD SURELY HELP U!!!!?❤ Math is best Ncert Should* maths* |
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| 35337. |
(X)+5-4+5 |
| Answer» I am not sure that this answer be correctX+5-4+5,X+1+5,X+6,X=-6 | |
| 35338. |
Solve graphical x_y=8 ; 3x_3y=16 |
| Answer» 3x-3y=243x-3y=16Ans=8 The ans is 8 | |
| 35339. |
Quadrilateral lesson is not there? Sorry |
| Answer» What?? | |
| 35340. |
Find the digit at unit place of 3n if n is 9 |
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Answer» 27 N=9 3*9=27 |
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| 35341. |
Vdjdbdkdf |
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| 35342. |
If sin=a/b then show that (sec+tan)=√b+a/b—a. |
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| 35343. |
Yarr half yearly maths paper me kis lesson se zada questions aaya tha ?please batana jarur |
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Answer» Linear equation and quadratic equation triangles Shayad Triangles chapter 6 coordinate geometry |
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| 35344. |
Prove all the identities of trigonometry. |
| Answer» aise ques. nhi aate | |
| 35345. |
The maths model paper in come 2018-2019 |
| Answer» Yes Cbse upload model paper | |
| 35346. |
In ncert pg no 245 que no 8,why cant we subtract tsa of cone from tsa of cylinder? |
| Answer» Because we are finding total surface area and surface increases by mixing cone with cylinder in case of volume it may decrease but tsa it is not possible | |
| 35347. |
If,1=52=103=154=10then,5=? |
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Answer» 1 20 correct 1 1 Obviously 1 1 |
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| 35348. |
If tan A =1\\3 and tanB=1/3 and tan(A+B)=tanA+tanB/1-tanA tanB show that A+B=45° |
| Answer» Given\xa0{tex} \\tan A = \\frac{1}{2},\\tan B = \\frac{1}{3}{/tex}and\xa0{tex}\\tan (A + B) = \\frac{{\\tan A + \\tan B}}{{1 - \\tan A\\tan B}}{/tex}{tex}\\Rightarrow \\tan (A + B) = \\frac{{\\frac{1}{2} + \\frac{1}{3}}}{{1 - \\frac{1}{2} \\times \\frac{1}{3}}}{/tex}{tex}\\Rightarrow \\tan (A + B) = \\frac{{\\frac{5}{6}}}{{\\frac{5}{6}}}{/tex}{tex}\\Rightarrow \\tan (A + B) = 1{/tex}{tex}\\Rightarrow \\tan (A + B) = \\tan 45^\\circ {/tex}{tex}\\Rightarrow A + B = 45^\\circ {/tex} | |
| 35349. |
2√2*2 |
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Answer» 4 root 2 4 4√2 |
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| 35350. |
Value of sin square theata |
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Answer» 1-cos square theta cos square thetha _1 |
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