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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 36551. |
Can a quadratic equation be of degree 3?? |
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Answer» No Never be 3 No No because quadratic means degree 2 |
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| 36552. |
Upper limit define |
| Answer» The highest frequency has 2 limit one is upper and anotherbis lower limit LHS is lower limit and RHS is upper limit | |
| 36553. |
CosecA +cotA=1 find the value of cosecA -cotA |
| Answer» -1 | |
| 36554. |
1/2a+b+2x = 1/2a+1/b+1/Solve for x |
| Answer» Answer= x=-1-4a²b/4a²+4a | |
| 36555. |
An ap consists of 50 terms of which 3rd term is 12 and last term is 106 . Find the 20 th term |
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Answer» n=50a+2d=12an=106a+19d=???Its very easy quesan=a+(n-1)d106=a+49da+49d=106 46 46 |
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| 36556. |
Prove:- (sinA+cosecA) square + (cosA+sec) square = 7+tan square A + cot square A |
| Answer» L.H.S =(sin²A + cosec²A + 2sinAcosecA) + (cos²A + sec²A + 2cosAsecA) = Sin²A + cos²A + 2sinAcosecA + 2cosAsecA + cosec²A + sec²A = 1 + 2 × 1 + 2×1 + cosec²A + sec²A = 5 + ( 1+ cot²A ) + ( 1+ tan²A) = 7 + tan²A + cot²A | |
| 36557. |
A tower AB is 20m high and BC its shadow on the ground is 20 3m long. Find sun\'s altitude |
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Answer» Tan 30° 20√3 hoga question me ..... |
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| 36558. |
What do you mean by conjecture and contradiction |
| Answer» Conjecture means to predict something While contradiction means to oppose | |
| 36559. |
In triangle ABC, angle B=135o how would you prove that AC2=AB2+BC2+4[ABC] |
| Answer» Wrong question | |
| 36560. |
if isosceles triangle pqr pq=pr=5cm is inscribed in a circle of radius 15cm find area of triangle |
| Answer» | |
| 36561. |
Can two number have 18 as their HCF and 380 as their LCM |
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Answer» Because the LCM must be a multiple if the HCF. And in this case it\'s not No |
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| 36562. |
Find the product of the zeroes of -2x^2+kx+6 |
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Answer» Product of zeros=c÷a6÷-2-3 By factorisation 2 |
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| 36563. |
What is thita |
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Answer» It\'s same as x,y,a,b ..that we use in algebraic expression General referral for any of the angles Name of angle |
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| 36564. |
How to draw graph of chapter 2 |
| Answer» With pencil | |
| 36565. |
All the theories of triangle with solutions |
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Answer» Is given in ncert book You not write this on your notebook |
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| 36566. |
mean formula based on step deviation and assumed mean |
| Answer» Step Deviation Method - Mean= a+(f×u/f)×hWhere,a=arbitrary value chosen somewhre in middle of xih=class sizeu=xi-a/hAssumed mean-Mean=a+f×d/fWhere,a=refer to aboved=xi-a | |
| 36567. |
How we will come to know that we have to calculate an or sn in ap?????? |
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Answer» Is u have to find with the sum of numbers then u will calculate Sn but when u have to calculate the Nth term then u have to find An Ya by reading the question By reading the question |
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| 36568. |
Find the area of minor segment of a radius 42cm if length of the corresponding arc is 44cm |
| Answer» 924-441 root 3..may be.. | |
| 36569. |
Prove that root 5is a irrational no. |
| Answer» Let us prove {tex}\\sqrt 5 {/tex} irrational by contradiction.Let us suppose that {tex}\\sqrt 5 {/tex} is rational. It means that we have co-prime integers a and b (b ≠ 0)Such that{tex}\\sqrt 5 = \\frac{a}{b}{/tex}{tex}\\Rightarrow {/tex}b{tex}\\sqrt 5 {/tex}=aSquaring both sides, we get{tex}\\Rightarrow {/tex} 5b 2 =a 2 ... (1)It means that 5 is factor of a2Hence, 5 is also factor of a by Theorem. ... (2)If, 5 is factor of a , it means that we can write a = 5c for some integer c .Substituting value of a in (1) ,5b2 = 25c2⇒ b2 =5c2It means that 5 is factor of b2 .Hence, 5 is also factor of b by Theorem. ... (3)From (2) and (3) , we can say that 5 is factor of both a and b .But, a and b are co-prime .Therefore, our assumption was wrong. {tex}\\sqrt 5 {/tex} cannot be rational. Hence, it is irrational. | |
| 36570. |
What is Co prime no |
| Answer» Co prime numbers r the numbers which do not have factors other than 1 nd itself.. | |
| 36571. |
If p(x,y) is any point on the line joining points A(a,0) and B(0,b) then show that x/a+y/b=1 |
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Answer» Dusra, hai ki let tge ratio in which p divides ab be k:1 then....x or y coordinates nikalo, by section formula and put it in lhs..... yu will get the answer....... Ho gya solve....ise ap 2 trike se solve kr skte ho, pehla using the slope formula i.e. y1-y2/x1-x2.... by putting slope of AP = slope of AB........ |
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| 36572. |
In the figure, find the length of the tangent CD if AP =3cm and PC=8cm. |
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Answer» Incomplete question... Where is the figure?? where is figure??????? Fig??? |
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| 36573. |
√cosecA - 1/√cosecA + 1 + √cosecA+1/√cosecA-1 = 2secA |
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Answer» *LCM First take the pcm and that will help you to remove the roots and then put the value of cosec A-1 as cotA then simpify it by taking cot A = CosA/Sin A that at last you will get 2/cosA that is equal to 2secA |
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| 36574. |
2x-3y=56y-4x=3Show graphically that the system of linear equation |
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Answer» Dono equation mein ek ek karke value dalo aur x,y ka value nikalo aur usko graph pe plot karo ,dono lines mein ya toh 1 jagah intersect krega, ya parallel hoga ya phir coinciding hoga bas uskr baad graph dekh ke likh dena jo bhi hoga Its is not possible to post graphi |
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| 36575. |
Find the distance of point P(x,y) from the origin |
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Answer» √x sq. + y sq. √x^2+y^2 |
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| 36576. |
10th maths all chapters formulas |
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Answer» Refer to yur ncert book..... Hey mate you can get it on the last page of each unit as summary NCERT book m dekho 3+1 |
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| 36577. |
Proof The pythagoras theorem:-AC²=AB²+BC² |
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Answer» Yes you are right we cannot type so much It\'s too long Refer ncert book |
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| 36578. |
The probability that it will rain today is 0.84.what is the probability that it will not rain today? |
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Answer» 1- 0.84 =0.16 0.16 |
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| 36579. |
Write the next 2 terms of the pattern 1,1/4,1/9,,,,,,,, |
| Answer» 1/16,1/25 | |
| 36580. |
write the nature of the roots of the quadratic equation 4x²+4√3+3=0 |
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Answer» Two equal real roots 2 equal real roots |
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| 36581. |
Solve equation (3x)(x)-5x+2=0 by complete square method |
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Answer» Value of x is 1 X=1 |
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| 36582. |
Prove that /3 is irrational |
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Answer» Check exercise 1.3 Ncert |
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| 36583. |
Stressed out!! |
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Answer» Lakin exam to nahi hue na Maths!!!!.... Vo kasse |
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| 36584. |
SinA/1-CosA + TanA/1+CosA=CotA+SecA×CosecA |
| Answer» When dava | |
| 36585. |
Colliner formula |
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Answer» Not sure I think so Area of ?=0Means co ordinate geometry wala area of triangle Area of triangle ka jo formula hota h coordinate m whi h |
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| 36586. |
Khy last 5 years ke board question paper mil sakate h |
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Answer» I think Google pr mil jayenge..bt pichle saal hi to board pattern chnge hua h to nxt year k sample paper hi bst choice h Yes |
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| 36587. |
If SecQ + TanQ=pFind the value of CosecQ |
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Answer» This is wrong Sec + tan=p1/cos+sin/cos=p Sin=pcos-1We know that cosec =1/sin Therefore,cosec=1/pcos-1 |
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| 36588. |
What is 0 |
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Answer» Mid no. Of all integers Natural number Integer Whole number |
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| 36589. |
What is difference between roots and zeros |
| Answer» Both r same | |
| 36590. |
If2x=secAand2/x=tanA then2(x2-1/x2)=? |
| Answer» | |
| 36591. |
is it compulsory to attempt questions in serial wise manner? |
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Answer» No....but if yu attempt in serial wise manner..then it will b easy for d examiner 2 check yur sheet...so better 2 do in series Actually if we do answer in series to checker ko acha lagta h au unhe copy check ke rs bhi milte hn to wo chahte hn ki jyada se jyada copy check kren aur series m krne se sir thodi loose checking bhi krte hn. Noo |
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| 36592. |
find the zeros of polynomial 4 root 3 X square + 4 root 3 x minus 3 root 3 |
| Answer» | |
| 36593. |
If sinA + cosA= √2 cos(90-A), then find cotA. |
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Answer» √2-1 Root2-1 |
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| 36594. |
Formula to find area of minor segment |
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Answer» Area of sector - area of triangle Consult to ncert textbook. Area of the corresponding sector- Area of the corresponding triangle |
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| 36595. |
Does ASs criteria exist for triangles |
| Answer» No ass is not a criteria exist for a triangle | |
| 36596. |
1÷sec-tan- 1÷cas= 1÷cos-1 sec+tan Prove that |
| Answer» No | |
| 36597. |
(a3+ b3) formula |
| Answer» (A+b)(a2+b2-ab) | |
| 36598. |
2cubes each of volume 64 cm^3 are joining end to end. Find the surface area of resulting cuboid. |
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Answer» You forget to divide by 2 also Wrong answer 160 is correct Volume of one cube-a^3^3_/64=4Side of 1Cube=4cmLength=4+4=8cmBredth=4CmHieght=4cmTSA of resulting cuboid=2(lb+bh+hl)=(8*4+4*4+4*8)=32+16+32=64+16Answer=80Cm^2Hence,Total surface area of resulting cuboid is 80cm^2......................................................... |
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| 36599. |
Difference between circumscribed and inscribed |
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Answer» Inscribed means kisi v polygon ke andar Circumscribed is incircirled... |
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| 36600. |
ABC is an isoceles triangle right angle at C.prove that AB^2=2AC^2 |
| Answer» AB²=AC²+BC²(Pythagoras Theorem )AB²=AC²+AC²(AB=BC)AB²=2AC²Hence Proved | |