InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 36601. |
The difference of two no.5 and the difference of their reciprocal is 1/10 .find its no. |
| Answer» let no. are x and x+5so 1/x-1/(x+5=1/1010(x+5)-10x=x(x+5)10x+50-10x=x2+5xx2+5x-50=0x2+10x-5x-50=0x(x+10)-5(x+10)=0(x-5)(x+10)=0x=5 or -10so number are 5 and 10 or -10 and -.5 | |
| 36602. |
If sinA=a/b then find the value of cosA in the form of a and b |
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Answer» CosA=1-a/b Khushi is right √(b^2-a^2)/b Using identity... |
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| 36603. |
Important questions of ch heights and distances |
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Answer» The question of cloud and cliff one from RD sharma thank u sister ? Use your ncrt book and keep all the example ans exersice question ............ I think so clouds question. Practice cloud question. |
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| 36604. |
Find a point on y axis that is nearest to A(-2,5) |
| Answer» (0,5) | |
| 36605. |
Determine the ratio in which the line 2x+y_4=0 divides the line segment joins A(2,_2)andB(3,7) |
| Answer» 2:9 | |
| 36606. |
Sin A (1+tanA)+cosA(1+cosA)=secA |
| Answer» | |
| 36607. |
What is a right angle triangle |
| Answer» Triangle in which one angle is 90 degree | |
| 36608. |
SecA +tanA = p. Find the value of - CosecA |
| Answer» CosecA=p^2+1/p^2-1 - 1 | |
| 36609. |
solve for x and y44/x+ y +30/x_y=1055/x+ y+ 40/x_y=13 |
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Answer» solve this complete The x=8 and y=3. Take x+y as v and x-y as u solve and you will get the answer. x=8, y=3 |
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| 36610. |
Find 10 term of an AP -1.0,-1.5,-2.0 |
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Answer» -5.5 -5.5 |
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| 36611. |
Guys tell me briefly that why (5)(7)(11) + (11) is a composite number |
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Answer» Rohit plzz tell its ans briefly it has 2 or more than 2 prime factors Out of knowledge |
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| 36612. |
√x+y=3 and x+√y=6 find x and y |
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Answer» This pair of equation don\'t have any solution. x=3448 |
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| 36613. |
Solve the equation x2 +3x-1734x square |
| Answer» | |
| 36614. |
Find a quadratic polynomial whose zeroes are 1 and-3 |
| Answer» x sq. + 2x - 3..... | |
| 36615. |
What is the ordinate of a point on x axis |
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Answer» 0 is the ordinate of point on X axis. X,0 (x,0) 0,x |
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| 36616. |
Distance formula for...co ordinator |
| Answer» √(x2-x1)^2+(y2-y1)^2 | |
| 36617. |
How to kind valie of k from missising frequency |
| Answer» Complete yur question | |
| 36618. |
Prove that the length of the tangents drawn from an external point to a circle are equal. |
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Answer» Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.To prove: PA = PBConstruction: Join OA, OB, and OP.It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.OAPA and OBPB\xa0... (1)InOPA andOPB:OAP =OBP\xa0(Using (1))OA = OB\xa0(Radii of the same circle)OP = OP\xa0(Common side)Therefore,OPAOPB\xa0(RHS congruency criterion)PA = PB(Corresponding parts of congruent triangles are equal)Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal. See in ncert....yahan par figure draw nahi kr skte.. |
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| 36619. |
Find a relation between x and y when point are collinear |
| Answer» Which points..?? | |
| 36620. |
ncert exampler circle in the given fig. from external point p a tangent pt and a secant ? |
| Answer» | |
| 36621. |
4x-3y-(a-2)=0 |
| Answer» | |
| 36622. |
exercise 12.3 ka8th question plzz |
| Answer» | |
| 36623. |
Show that points are coolinear |
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Answer» Area of 3 points is equal to 0 Ans:- area of triangle in co-ordinate geometry leaving 1/2 Which points????? When the points will be = to 0 |
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| 36624. |
Sin square thitha plus cos four thitha is equal to sin four thitha plus cos square thitha prove that |
| Answer» {tex}\\begin{array}{l}\\sin^4\\theta-\\cos^4\\theta\\\\=(\\sin^2\\theta+\\cos^2\\theta)((\\sin^2\\theta-\\cos^2\\theta)\\\\\\sin^4\\theta-\\cos^4\\theta=\\sin^2\\theta-\\cos^2\\theta\\\\or\\;\\;\\sin^4\\theta+\\cos^2\\theta=\\cos^4\\theta+\\sin^2\\theta\\\\or\\;\\sin^2\\theta+\\cos^4\\theta=\\;\\sin^4\\theta+\\cos^2\\theta\\end{array}{/tex}Hence proved | |
| 36625. |
What is the formula for area of segment of a circle |
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Answer» Thanx usha and simmili both of you Area of required sector-areaof triangle If theta is equal to or less than 90,then area of segment of circle is πr^2theta/360-r^2/2×sin theta............And if theta is greater than 90 then,area of segment of circle is πr^2theta/360-r^2×sin theta/2 ×cos theta/2.........Hope it will help you ???? |
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| 36626. |
Prove that 1-tan square theta divided by cot square theta -1 is equal to tan square theta.. |
| Answer» Sec^2theta/cosec^2 theta =1/cos^2×sin^2 theta/1=sin^2 theta /cos^2 theta =tan^2 theta.......Hope it will help you ???? | |
| 36627. |
Why we find inner surface area of combine solids like cylender is mounted on hemisphere |
| Answer» If it is asked in question then v hv 2 find yrr.. ? | |
| 36628. |
prove pythagorous |
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Answer» Pythagoras TheoremStatement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.Given: A right triangle ABC right angled at B.To prove: AC2\xa0= AB2\xa0+ BC2Construction: Draw BDACProof :We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.ADBABCSo,(Sides are proportional)Or, AD.AC = AB2\xa0... (1)Also,BDCABCSo,Or, CD. AC = BC2\xa0... (2)Adding (1) and (2),AD. AC + CD. AC = AB2\xa0+ BC2AC (AD + CD) = AB2\xa0+ BC2AC.AC = AB2\xa0+ BC2AC2\xa0= AB2\xa0+ BC2Hence Proved. See textbook |
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| 36629. |
If ABCD is a rhombus then prove that 4AB=AC+ BD |
| Answer» Pl check question | |
| 36630. |
Triangle theorem |
| Answer» | |
| 36631. |
In a ∆ ABC DE||BC such that AD=(4x-3)cm,AE=(8x-7)cm,BD=(3x-1)cm and CE=(5x-3)cm,find the value of x |
| Answer» 1 | |
| 36632. |
How was the paper of info technology?? Kiska bht acha gya?? |
| Answer» | |
| 36633. |
Formula of chapter 13 of class 10 |
| Answer» Ncert me hai...otherwise iss app me chapter 13 k revision notes kholo...vaha mil jyega..apko | |
| 36634. |
सी का वह मान जिसके लिए समीकरण ax2+2bx+c=0 के मूल समान है |
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Answer» इस प्रश्न का उत्तर है- b - √b^2-ac/a or- b + √b^2-ac/a प्रिय शिवम कुशवाहा जी जरा कुछ समय रुक जाए आपका उत्तर मिल जाएगा How mny of yu have completed yur maths full course Write in english |
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| 36635. |
Divide 2x^2 +3x +1 bg x+2 |
| Answer» The quotient is 2x-1 and reminder is 3 | |
| 36636. |
A circle is inscribed in a triangle PQR with PQ=10,QR=8and PR=12 .find the length QM,RN,PL |
| Answer» It is in r.d sharma | |
| 36637. |
All properties of triangle |
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Answer» Nor question It\'s not a satisfactory answer You must remember the basic angle facts such as the sum of the angles on a straight line is 180°, and the properties of alternate and corresponding angles. (b) the exterior angle of a triangle is equal to the sum of the interior opposite angles. Take any triangle ABC. Rules of similarity and congruence r also there in book... |
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| 36638. |
Please help me out....ncert ke page number 269 (statistics ka ex 3 hai) ismai h= 20 kyu liya...????? |
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Answer» C.I different hai so you can solve through assume mean method instead of deviation method by assume mean method u can get answer easily Isme class size same kar lena lower limit mein .5 subtract kar dena aur upper limit mein .5 add kar dena isliye H 40 liya hai Because the distance between classinterval is 20 . h means height so h=20 Shyad misprinted h yha pe 40 aana chahiye |
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| 36639. |
Mean in x and y value |
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Answer» Clear your Question first ?? question clear nhi hai |
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| 36640. |
Hansv |
| Answer» | |
| 36641. |
alpha + beta = |
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Answer» -b/A Gamma -b/a |
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| 36642. |
(1+tan^2A /1+cot^2A)=(1-tan A/1-cotA)^2=tan^2 A |
| Answer» | |
| 36643. |
Paythagoreous threom |
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Answer» (hupotenuse)^2 = ( base)^2 + ( height)^2 AC2 = AB2 + BC2 In a right angled triangle |
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| 36644. |
Triangle ABC is an isoscelen triangle angle A=90 degrees show BC square is equal to 2AB square |
| Answer» \xa0{tex}\\angle A{/tex} =90 and\xa0ABC is an isosceles\xa0triangle then\xa0AB=ACand BC2=AC2+AB2BC2=AB2+AB2BC2=2AB2\xa0\xa0 | |
| 36645. |
In an AP if the common difference =4 and the seventh term is 4 then find the first term |
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Answer» a7= a+(n-2)d , 4= a+(7-2)4 , 4 = a +24 , a=-20 —20 |
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| 36646. |
Value of sin 60° |
| Answer» √3/2 | |
| 36647. |
Kya math ka board ka paper ncert ki optional exercise me se aata hota hai?Pls confirm se hi batana |
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Answer» Uske nicha likha to ha not form examination point of view Yes Ha aata to hai |
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| 36648. |
Please imp question batao. |
| Answer» 9AD²=7AB² wala question | |
| 36649. |
X+y=99Y+x=83 |
| Answer» Q is wrong | |
| 36650. |
Write a rational number between√3 and √5 |
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Answer» How 2 |
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