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36651.

Let x-1, x-4 and x-7 are in AP find the value of x

Answer» If x-1, x-4 and x-7 are in APthen x-4 will be average of x-1 and x-7[(x-1)+(x-7)]*1/2=x-42x-1-7=2(x-4)2x-8=2x-82x-2x=-8+80=0Hence there is no solutionStatement in your question is not a question this shows thatx-1, x-4 and x-7 are in AP for all real values of xSo x =.-infinite........-5,-4,-3,-2,-1,0,1,2,3.......................infinite\xa0
36652.

If tan theta (90+theta)=cot theta, find theta

Answer» Ques is wrong
36653.

Decimal expansion of 23/2^3 5^2

Answer» 0.115
0.115
36654.

In a family of 3 children,calculate the probability of atleast one boy?

Answer» 1/3
3 possibilities of one boy, 3 possibilities of 2 boys, 1 possibility of 3 boys
How 7/8
7/8
1/2
36655.

In an AP , if the common different (_4) , and the seventh term (a7) is 4 , then find the first term.

Answer» In this question a7 can be written as a+6d where a is first term and d is common different So a+6d=4a+6(-4)=4a-24=4a=4+24a=28. So first term is 28
36656.

if secA+tanA=p ,then prove that sinA=(p square+1)/(p square-1)

Answer» answer mein sinA=p sq+1/p sq-1 ana ha vo kaise
Multiply, ,(secA-tanA) on both sides... then solve yu will get the value of secA-tanA in terms of p... then solve the given eq. and the value yu have find to get the values of secA and tanA separately in terms of p..... then cosecA=secA/tanA put values..... yu will get cosecA= p²+1/p²-1....now, sinA=1/cosecA..... so, sinA=p sq. -1/p sq. +1
36657.

If tanA =cot (A-18) find A

Answer» A=54
A=54
36658.

Find the length of the tangent CD if ap=3cm and pc=8cm

Answer» This question is not solved without diagram
36659.

Find the largest number of 5 digits when divided by 8 & 9 leave remainder 5

Answer» 99941First subtract 5 from largest number, find the lcm of 8 & 9 divide the remaining by lcm the subtract the remainder from remaining numbet at first
36660.

If sec0 + tan0 =p what is cosec 0*0= theta.

Answer» sec theta+tan theta=p _________(2)sec^2 theta + tan^2 theta=1(sec theta+tan theta)(sec theta - tan theta)= 1sec theta- tan theta=1/sec theta + tan thetasec theta-tan theta=1/p ________(1)(1)+(2)*further you may proceed*
36661.

If S29=99 and S99=29 find S128

Answer» Tnx but S means sum..... Solve it by taking sum of 99 terms..... ?
S29= a + 28d.S99= a + 98d... .a+28d=99.a+98d=29.==> -70d= - 70===> d=1.... a+28d=99==>a= 99-28==> a= 71...S128=a+127d==) 71 + 127===> 198.......?
36662.

Tan1 tan2 tan3 tan4 ...........tan89

Answer» How mr.
1
36663.

all 10 formula list

Answer»
36664.

Prove volume of frustum

Answer» Ya it is really too long aap youtube pr dekh lo
36665.

The largest sphere is curved out of cube of a side 7 cm find the value of the sphere

Answer» 2
36666.

Calculate the area bounded by the line x + y = 10 and both the coordinate axes

Answer»
36667.

X - 2y +

Answer» Siddharth...at 10 we will revise together...if u dont mind...
36668.

Form the polynomial whose zeroes are 3,-1 and -1÷3

Answer»
36669.

Question sahi h sir

Answer»
36670.

Prove the sum of the interior angles of a triangle is 180

Answer» (no. Of side - 2)× 180 is the formula to calculate sum of interior angles of a polygon
36671.

Prove that sin theta cos theta

Answer» What is your question??????sinthita.costhita???
36672.

2+2=? (Only intelligent student can give answer )

Answer» Mai intelligent na hu........... Too bhai ram ram or yaha se nikal
Ans. Is 4
Tenu ni aanda ans. Yaani tu intelligent ni hai..duffer boy!
36673.

How to prove that the centroid of a triangle divides the median in the ratio 2:1??

Answer» \tThe Theorem\xa0D, E, F\xa0are\xa0mid-points of BC, CA, AB.AD, BE and CF are medians.The medians cut each others are\xa0centroid G\xa0.We need to show that:\xa0AG : GD = BG : GE = CG : GF = 2 : 1\xa0\xa0\xa0\xa0\xa0Simple Proof\xa0Reflect the triangle along AC, you can get a diagram below:\xa0\xa0ABCB1 is\xa0a parallelogram.BEB1 is\xa0a straight line . Since CD = AD1 and CD // AD1,\xa0 DCD1A is\xa0a parallelogram. (opposite\xa0sides equal and parallel.)\\\xa0DG // CG1\xa0 Since BD = DC and DG // CG1\\ BG = GG1 (intercept theorem)BG : GG1\xa0= 1 : 1Since GE\xa0= EG1\xa0, BG : GE = 2 : 1.\t
36674.

Px x³ -3x² +5x-3

Answer»
36675.

How many terms of the sequence 18,16,14........ should be taken so that their sum is zero

Answer» We know that\xa0sum = n/2(2a + (n-1) d) 0 = n/2(2 * 18 + (n - 1) * (-2)) 0 = n/2(36-2n+2) 0 = 38n - 2n^2 2n^2 - 38n = 0 2n(n-19) = 0 n - 19 = 0 n = 19.
Ans is 19 term
19
36676.

Then find of A.P last value

Answer»
36677.

Sample paper 2017-2018 (last year) ?????

Answer» Do you want it
36678.

A bicycle wheel makes 5000 revolution on moving 11 km. Find the diameter of the wheel?

Answer» Distance covered in 5000 revolutions = 11 km = 11,000 m = 11,00,000 cm Distance covered in 1revolution = 11,00,000 / 5000 = 220 cm Distance covered in 1 revolution = Circumference of the wheel of the bicycle Let the radius of the wheel be \'r\' cm. ⇒ 2 x 22/7 x r = 220 ⇒ r = 220 x 7/22 x 1/2 ⇒ r = 35 cm Hence, the diameter of the wheel is 70 cm.All the Best??for ur exams @diti
36679.

If both ogives intersect at x,y what is median

Answer» The median will be x. samyukta sis ye 0 nahi hogi
Median will be y
0
36680.

Find the sum of first 8 multiples of 3.

Answer» Ap will be 3,6,9...So, sum of first 8 multiples = 8/2*[2(3) + 7(3)] = 4(6 + 21) =108
36681.

Theorm10.2

Answer»
36682.

Please someone answer my question below

Answer»
36683.

Formula\'s

Answer»
36684.

A kite is flying 165 m long .The thread makes angle of 30°

Answer» height of the kite from ground is 55root3 mlength of the thread is 110root3 m
SO.....Complete your question......
36685.

Describe the formula Sn-(Sn-1)

Answer»
36686.

The mean of the following data is 7.5. Find the value of P.x=3, 5, 7, 9, 11, 13f=6, 8, 15, P, 8, 4

Answer» Σfi = 41+p\xa0Σfixi = 303+9pMean = Σfixi / Σfi7.5 = (303+9p) / (41 +p)7.5(41 +p) = 303 +9p307.5 +7.5 p = 303 +9p307.5 - 303 = 9p - 7.5 p4.5 = 1.5 pp = 4.5 / 1.5 = 3P = 3Hence, the value of p is 3.
36687.

If secQ +tanQ =p , then find the value of cosecQ

Answer» Sec + tan= p -(1)Sec^2 - tan^2 = 1So. (Sec+ tan)( sec- tan) = 1 Put sec+tan= P. ,so u will getSec - tan =1/p-(2) Adding eq. 1 and 2 u get Sec + tan + sec - tan= p + 1/p2sec = p^ 2 + 1/ p- (3)Subtracting eq. 1 and 2 U get 2 tan = p^ 2 - 1 / p-(4) Take ratio of eq 3 and eq 4So sec/ tan = p^2 +1 / p^2-1 = cosecA = p^2+1 / p^2-1 Hope u understand otherwise contact me 6265790757
36688.

Find the sum of all natural no from 1to 100

Answer» Too simple yaarA.p. is in form of 1,2,3....100 where d is 1 Here last term (l) is 100a=1N=100Sum of all natural number =n÷2×(a+l)100÷2×(1+100)50×101=5050
5050
5050
36689.

If the value of sin theta / sec theta + tan theta - 1 + cos theta/ cosec theta + cot theta -1

Answer»
36690.

If x=3 is one root of the quadratic equation x²-2kx-6=0, then find the value of k.

Answer» I/2
9-6k-6=03-6k=0-6k=-3K=1/2
36691.

The lengthsside of the diagonals of a rhombus are 30cm and 40cm Findin the sideof of theof rhombus

Answer» Answer is 25 cm by Pythagoras theorem
36692.

Given that 1+sinΦ+cosΦ=1Then prove that 2sinΦ-cosΦ=2

Answer»
36693.

tanA=CotB ,prove that A+B =90

Answer» TanA= CotB , TanA= Tan(90-B) , A=90-B , A+B=90
Tan A = tan ( 90-B ). = A = 90- B ......... = A+ B = 90
36694.

tanA = cot B

Answer» Then A+B=90
There is something missing..plz check it again
Incomplete question
36695.

What is the trick behind atleast and atmost in case of probability

Answer» please see byjus application for thisit is told very nice there
36696.

If x = 0 y=..?

Answer»
36697.

Sin @[email\xa0protected]

Answer» That\'s sin square A + cos square A is equals to 1
1 maybe
36698.

Cosecsquarethita minus cotsquarerhita

Answer» 1
1+cot^2theta =cosec^2theta1=cosec^2theta - cot^2theta So the value is 1
1
Minus1
36699.

What is composit no.

Answer» Composite numbers are the numbers which has the factor other than 1 and itself
Composite numbers are the numbers having more than two factors.....Ex. 4, 6, 8, 9 etc...
The number having more tha 2 factors are called composite no.
36700.

X minus 3 is root equations s2k X - 6 - 0 is a value of the k

Answer» If x-3=0X=3Then 2kx-6=02k(3)-6=06k-6=06k=6K=6/6K=1
K=0