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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3701. |
Give the maximum probality of any no. |
| Answer» 1 | |
| 3702. |
Maths Mai chapter wise waitage kya hai ? Kisi ko pata hai ? |
| Answer» Algebra ka sabse jada weightage h | |
| 3703. |
12445*2566666 |
| Answer» 3.1942158e10 | |
| 3704. |
Which chapter is very important for 10th 2018 board |
| Answer» | |
| 3705. |
If one zero of 3x power 2 _ 4x+p is reciprocal to the other then find value of p |
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Answer» 8 P=3 |
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| 3706. |
Sec+tan=p to show sinA psquare -1 upon psquare +1 |
| Answer» | |
| 3707. |
3tan square theta + 4cos square theta + 7 |
| Answer» | |
| 3708. |
Any1 give me blueprint of maths |
| Answer» Check exam pattern here :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 3709. |
Those who have dout in maths can ask me iam mahesh |
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Answer» Sorry it is wrong no 9444657131 |
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| 3710. |
How to find the square root of 1256? Or any square root of an unkNown decimal? |
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Answer» Bcz 6 comes in the lsquare of 4&6 only It\'s either 34 or 36 |
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| 3711. |
99x+101y =499101x+99y=501 |
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Answer» x=3 &y=2 At first add both eq and then subtract both and the result of addition and subtraction ...again add |
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| 3712. |
Solve for X1/(2a+b+2x)=(1/2a)+(1/b)+(1/2x) |
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Answer» I did it yaar. .but I am not getting. . B/2 or -a It\'s esy friend !! Take LCM simply or u can do another thing also ...bring 1/2x to left side then simplify |
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| 3713. |
99x+101y=499101x+99y=501 |
| Answer» x=3 & y=2 | |
| 3714. |
A Cy, a come and a hemisphere are equal base and same hight. Find the ratio of there volume. |
| Answer» {tex}V_1{/tex}(volume of cone) =\xa0{tex}\\frac{1}{3}{/tex}{tex}\\pi{/tex}r2r{tex}V_2{/tex}(volume of hemisphere) =\xa0{tex}\\frac{2}{3}{/tex}{tex}\\pi{/tex}r3\xa0{tex}V_3{/tex}(volume of cylinder) =\xa0{tex}\\pi{/tex}r2{tex}\\cdot{/tex}r{tex}V_1 : V_2 : V_3 ={/tex}\xa0{tex}\\frac{1}{3}{/tex}{tex}\\pi{/tex}r3 :\xa0{tex}\\frac{2}{3}{/tex}{tex}\\pi{/tex}r3 :\xa0{tex}\\pi{/tex}r3 =\xa0{tex}\\frac{1}{3}{/tex}\xa0:\xa0{tex}\\frac{2}{3}{/tex}\xa0: 1{tex}V_1 : V_2 : V_3 = 1 : 2 : 3.{/tex} | |
| 3715. |
Show that 21n can never end with digits0,4,6 and 8 for any natural number n. |
| Answer» The prime factorisation of 21n\xa0= {tex}( 3 \\times 7 ) ^ { n } = 3 ^ { n } \\times 7 ^ { n }{/tex}Since the prime factorisation of given expression i.e., 21n does not contain 2 and 5, therefore, there is no natural number \'n\'\xa0for which 21n\xa0ends with the digits 0, 2, 4, 6 and 8. | |
| 3716. |
Show that 9n cannot end with 2 for any integer n. |
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Answer» Dont be little me mr. DJ Take n = any positive no and show that 2 doesn\'t come at last |
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| 3717. |
What is area theorem and prove and it\'s converse proof |
| Answer» Graph lgega...yha ni hoga | |
| 3718. |
Most important theorem in ch 6 |
| Answer» | |
| 3719. |
How to decide which identity be used in some difficult question of trigonometry |
| Answer» | |
| 3720. |
If sin A=3\\4 calculate cos A and tan A |
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Answer» We know that sin A=opp/hyp.........adj=4square-3sq..........which is.....root over 7 (I hope it is correct) cos A=root over 7/4.........tan A=3/root over 7 (tanA=opp/adj & cos A= adj/hyp) CosA=root7/4&tanA=3/root 7 |
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| 3721. |
The surface area of a sphere is 616 cm. Find its radish. |
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Answer» 4pie r sq. =616, r sq =616*7/22*4=49,r=7 7 cm We know that, The surface area of sphere is[ 4pie r square ] Given, sphere =616 r=d/2 =616/2=308,r=308Use formula [4pie r square ]4×22/7 ×308×30888/7×9486488×94864/78348032/7=1192576 aproxmetally I don\'t know this problem are right. So please tum mughe maf kar dena.Thanks 7cm |
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| 3722. |
5x²+13x+8=0 find the value of x by factorization method.. |
| Answer» X=-1&x=-8/5 | |
| 3723. |
3x-y=39x-3y=9By substitution method |
| Answer» So easy | |
| 3724. |
Time table for class 10 cbse tell me |
| Answer» | |
| 3725. |
How many rotation in one minute |
| Answer» | |
| 3726. |
How many percent of scholarship in rank 17000 in ftre |
| Answer» | |
| 3727. |
Cot^2A(secA-1)/1+sinA=sec^2A(1-sinA/1+secA) |
| Answer» | |
| 3728. |
Prove that 3+root 5 is irrational |
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Answer» Let it be rational than 3+√5 =p/q than √5=p/q minus 3 than Lhs is not = to Rhs Yes |
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| 3729. |
If pth term and qth term of an AP are a,b,c respectively then show a(q-r),+b(r-p),+c(p-q)=0 |
| Answer» Let the first term and common difference of the AP be A and Dpth term = a ……… (given)= A + (p – 1)D = a\xa0............(1)qth term = b{tex}\\Rightarrow {/tex}\xa0A + (q - 1) D = b ......... (2)rth term = c .......... Given{tex}\\Rightarrow {/tex}\xa0A + (r - 1) D = c ........ (3)Multiplying equations (1), (2) and (3) by q - r, r - p and p - q respecitvely, we geta(q - r) + b(r - p) + c(p - q)= [A + (p - 1) D] (q - r) + [A + (q - 1)D] (r - p) + [A + (r - 1) D] (p - q)]= A [q - r + r - p + p - q] + D [(p - q)\xa0(q - r) + (q\xa0- 1) (r- p) + (r - 1) (p - q)]= A (0) + D(0)= 0 | |
| 3730. |
If the point of intersection of two ogive is(18,54),then find the value of median |
| Answer» 18 | |
| 3731. |
Don\'t feel fear Kashyap sahab is here |
| Answer» | |
| 3732. |
√alphasquare√beta2√alphasquare infinity times...what is the answer |
| Answer» | |
| 3733. |
Alogritham |
| Answer» | |
| 3734. |
Find the relation between x and y if points (x,y),(1,2) and (7,0) are collinear. |
| Answer» If the given points are collinear, then the area of the triangle with these points as vertices will be zero.{tex}\\therefore{/tex}{tex}\\frac{1}{2}{/tex}[x (2 – 0) + 1 (0 – y) + 7(y –2)] = 0{tex}\\Rightarrow{/tex}{tex}\\frac{1}{2}{/tex}[2x – y + 7y –14] = 0{tex}\\Rightarrow{/tex}{tex}\\frac{1}{2}{/tex}[2x + 6y –14] = 0{tex}\\Rightarrow{/tex} 2x + 6y – 14 = 0{tex}\\Rightarrow{/tex} x + 3y – 7 = 0 .............Dividing throughout by 2This is the required relation between x and y. | |
| 3735. |
Explain why 13233343563715 is a composite number |
| Answer» {tex}13233343563715=5\\times11\\times73\\times10139\\times325079{/tex}.This number is having factors other than 1 and the number itself,therefore it is a composite number. | |
| 3736. |
Science ke ppr ke liye carbon and compound.....herdity and evolution kaise kiya |
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Answer» That is most inporatant sis and in chemistry prepare nomenclature and IUPAC names. Vo to aata hain bro...uske illava Prepare monohybrid and dihybrid cross for heredity and evolution. |
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| 3737. |
2 X + 3 y |
| Answer» | |
| 3738. |
The tangent at any point of a circle is perpendicular to the radius through the point of contact |
| Answer» GIVEN\xa0: A circle C (0, r) and a tangent AB at a point P.TO PROVE :\xa0{tex}O P \\perp A B{/tex}CONSTRUCTION Take any point Q, other than P, on the tangent AB. Join OQ. Suppose OQ meets the circle at R.PROOF\xa0: We know that among all line segments joining the point O to a point on AB, the shortest one is perpendicular to AB.To prove that {tex}O P \\perp A B{/tex}, it is sufficient to prove that OP is shorter than any other segment joining O to any point of AB.Clearly,\xa0{tex}OP = OR{/tex}Now,\xa0{tex}OQ = OR + RQ{/tex}{tex}\\Rightarrow \\quad O Q > O R{/tex}{tex}\\Rightarrow \\quad O Q > O P \\quad [ \\because O P = O R ]{/tex}{tex}\\Rightarrow \\quad O P < O Q{/tex}{tex}\\therefore{/tex}\xa0{tex}O P \\perp A B{/tex} | |
| 3739. |
Wrote 23.426 in p/q |
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Answer» good 23426/1000 |
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| 3740. |
When will board datesheet release? |
| Answer» | |
| 3741. |
SinA - CosA = 1/2 then find the value of sinA.cosA |
| Answer» | |
| 3742. |
hey hello guys ..?? |
| Answer» | |
| 3743. |
The area of three adjacent faces of cuboid are x,y& z if it\'s volume is v then show that v^2=xyz |
| Answer» Let the length, breadth and height of the cuboid be l, b and h units respectively.x = lb, y\xa0= bh, z\xa0= hl∴ xyz\xa0= (lb) (bh) (hl) = l2b2h2 . . . (1)Again v = lbh∴ v2 = (lbh)2 = l2b2h2 . . . (2)From (1) and (2)v2 = xyz | |
| 3744. |
When we will get time table of class 10 board exams |
| Answer» I think on 10 of this month as it was announced | |
| 3745. |
Determine whether 50cm,80cm,100cm can be a the sides of a right angle or not |
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Answer» No because it does not satisfy Pythagores Theorem No |
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| 3746. |
Mathematics formula for class 10 for all xhapter |
| Answer» Check revision notes here :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 3747. |
Find value of @ for which (@ - 12)x2+(@-12)x+2=0 has equal zeroes and ........ @= alpha |
| Answer» We have, (k- 12 )x2 + 2(k - 12)x + 2 = 0.\xa0a = k - 12,b = 2(k - 12) and c = 2.The given equation will have equal roots, if{tex}\\therefore{/tex}\xa0D = b2 - 4ac = 0{tex}\\Rightarrow{/tex}\xa04(k\xa0- 12)2 - 4 (k - 12){tex}\\times{/tex} 2 = 0{tex}\\Rightarrow{/tex}4(k- 12) [(k\xa0- 12) - 2]\xa0= 0{tex}\\Rightarrow{/tex}4(k\xa0- 12)(k\xa0- 14) = 0{tex}\\Rightarrow{/tex}4(k\xa0- 12) (k - 14) = 0 {tex}\\Rightarrow{/tex}\xa0k - 12 = 0 or, k - 14 = 0 {tex}\\Rightarrow{/tex}\xa0k\xa0= 12 or, k = 14 | |
| 3748. |
4u-5y |
| Answer» | |
| 3749. |
Solve Under root x+y=11 and x+under root y=7 |
| Answer» | |
| 3750. |
(a-b)x+(a+b)y=a*a-b*B-2ab |
| Answer» x = a + b{tex}\\therefore{/tex} (a - b)(a + b) + (a + b)y = a2 - b2 - 2aba2 - b2 + (a + b)y = a2 - b2 - 2ab{tex}y = \\frac{{ - 2ab}}{{a + b}}{/tex} | |