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3701.

Give the maximum probality of any no.

Answer» 1
3702.

Maths Mai chapter wise waitage kya hai ? Kisi ko pata hai ?

Answer» Algebra ka sabse jada weightage h
3703.

12445*2566666

Answer» 3.1942158e10
3704.

Which chapter is very important for 10th 2018 board

Answer»
3705.

If one zero of 3x power 2 _ 4x+p is reciprocal to the other then find value of p

Answer» 8
P=3
3706.

Sec+tan=p to show sinA psquare -1 upon psquare +1

Answer»
3707.

3tan square theta + 4cos square theta + 7

Answer»
3708.

Any1 give me blueprint of maths

Answer» Check exam pattern here :\xa0https://mycbseguide.com/cbse-syllabus.html
3709.

Those who have dout in maths can ask me iam mahesh

Answer» Sorry it is wrong no
9444657131
3710.

How to find the square root of 1256? Or any square root of an unkNown decimal?

Answer» Bcz 6 comes in the lsquare of 4&6 only
It\'s either 34 or 36
3711.

99x+101y =499101x+99y=501

Answer» x=3 &y=2
At first add both eq and then subtract both and the result of addition and subtraction ...again add
3712.

Solve for X1/(2a+b+2x)=(1/2a)+(1/b)+(1/2x)

Answer» I did it yaar. .but I am not getting. . B/2 or -a
It\'s esy friend !! Take LCM simply or u can do another thing also ...bring 1/2x to left side then simplify
3713.

99x+101y=499101x+99y=501

Answer» x=3 & y=2
3714.

A Cy, a come and a hemisphere are equal base and same hight. Find the ratio of there volume.

Answer» {tex}V_1{/tex}(volume of cone) =\xa0{tex}\\frac{1}{3}{/tex}{tex}\\pi{/tex}r2r{tex}V_2{/tex}(volume of hemisphere) =\xa0{tex}\\frac{2}{3}{/tex}{tex}\\pi{/tex}r3\xa0{tex}V_3{/tex}(volume of cylinder) =\xa0{tex}\\pi{/tex}r2{tex}\\cdot{/tex}r{tex}V_1 : V_2 : V_3 ={/tex}\xa0{tex}\\frac{1}{3}{/tex}{tex}\\pi{/tex}r3 :\xa0{tex}\\frac{2}{3}{/tex}{tex}\\pi{/tex}r3 :\xa0{tex}\\pi{/tex}r3 =\xa0{tex}\\frac{1}{3}{/tex}\xa0:\xa0{tex}\\frac{2}{3}{/tex}\xa0: 1{tex}V_1 : V_2 : V_3 = 1 : 2 : 3.{/tex}
3715.

Show that 21n can never end with digits0,4,6 and 8 for any natural number n.

Answer» The prime factorisation of 21n\xa0= {tex}( 3 \\times 7 ) ^ { n } = 3 ^ { n } \\times 7 ^ { n }{/tex}Since the prime factorisation of given expression i.e., 21n does not contain 2 and 5, therefore, there is no natural number \'n\'\xa0for which 21n\xa0ends with the digits 0, 2, 4, 6 and 8.
3716.

Show that 9n cannot end with 2 for any integer n.

Answer» Dont be little me mr. DJ
Take n = any positive no and show that 2 doesn\'t come at last
3717.

What is area theorem and prove and it\'s converse proof

Answer» Graph lgega...yha ni hoga
3718.

Most important theorem in ch 6

Answer»
3719.

How to decide which identity be used in some difficult question of trigonometry

Answer»
3720.

If sin A=3\\4 calculate cos A and tan A

Answer» We know that sin A=opp/hyp.........adj=4square-3sq..........which is.....root over 7 (I hope it is correct) cos A=root over 7/4.........tan A=3/root over 7 (tanA=opp/adj & cos A= adj/hyp)
CosA=root7/4&tanA=3/root 7
3721.

The surface area of a sphere is 616 cm. Find its radish.

Answer» 4pie r sq. =616, r sq =616*7/22*4=49,r=7
7 cm
We know that, The surface area of sphere is[ 4pie r square ] Given, sphere =616 r=d/2 =616/2=308,r=308Use formula [4pie r square ]4×22/7 ×308×30888/7×9486488×94864/78348032/7=1192576 aproxmetally I don\'t know this problem are right. So please tum mughe maf kar dena.Thanks
7cm
3722.

5x²+13x+8=0 find the value of x by factorization method..

Answer» X=-1&x=-8/5
3723.

3x-y=39x-3y=9By substitution method

Answer» So easy
3724.

Time table for class 10 cbse tell me

Answer»
3725.

How many rotation in one minute

Answer»
3726.

How many percent of scholarship in rank 17000 in ftre

Answer»
3727.

Cot^2A(secA-1)/1+sinA=sec^2A(1-sinA/1+secA)

Answer»
3728.

Prove that 3+root 5 is irrational

Answer» Let it be rational than 3+√5 =p/q than √5=p/q minus 3 than Lhs is not = to Rhs
Yes
3729.

If pth term and qth term of an AP are a,b,c respectively then show a(q-r),+b(r-p),+c(p-q)=0

Answer» Let the first term and common difference of the AP be A and Dpth term = a ……… (given)= A + (p – 1)D = a\xa0............(1)qth term = b{tex}\\Rightarrow {/tex}\xa0A + (q - 1) D = b ......... (2)rth term = c .......... Given{tex}\\Rightarrow {/tex}\xa0A + (r - 1) D = c ........ (3)Multiplying equations (1), (2) and (3) by q - r, r - p and p - q respecitvely, we geta(q - r) + b(r - p) + c(p - q)= [A + (p - 1) D] (q - r) + [A + (q - 1)D] (r - p) + [A + (r - 1) D] (p - q)]= A [q - r + r - p + p - q] + D [(p - q)\xa0(q - r) + (q\xa0- 1) (r- p) + (r - 1) (p - q)]= A (0) + D(0)= 0
3730.

If the point of intersection of two ogive is(18,54),then find the value of median

Answer» 18
3731.

Don\'t feel fear Kashyap sahab is here

Answer»
3732.

√alphasquare√beta2√alphasquare infinity times...what is the answer

Answer»
3733.

Alogritham

Answer»
3734.

Find the relation between x and y if points (x,y),(1,2) and (7,0) are collinear.

Answer» If the given points are collinear, then the area of the triangle with these points as vertices will be zero.{tex}\\therefore{/tex}{tex}\\frac{1}{2}{/tex}[x (2 – 0) + 1 (0 – y) + 7(y –2)] = 0{tex}\\Rightarrow{/tex}{tex}\\frac{1}{2}{/tex}[2x – y + 7y –14] = 0{tex}\\Rightarrow{/tex}{tex}\\frac{1}{2}{/tex}[2x + 6y –14] = 0{tex}\\Rightarrow{/tex} 2x + 6y – 14 = 0{tex}\\Rightarrow{/tex} x + 3y – 7 = 0 .............Dividing throughout by 2This is the required relation between x and y.
3735.

Explain why 13233343563715 is a composite number

Answer» {tex}13233343563715=5\\times11\\times73\\times10139\\times325079{/tex}.This number is having factors other than 1 and the number itself,therefore it is a composite number.
3736.

Science ke ppr ke liye carbon and compound.....herdity and evolution kaise kiya

Answer» That is most inporatant sis and in chemistry prepare nomenclature and IUPAC names.
Vo to aata hain bro...uske illava
Prepare monohybrid and dihybrid cross for heredity and evolution.
3737.

2 X + 3 y

Answer»
3738.

The tangent at any point of a circle is perpendicular to the radius through the point of contact

Answer» GIVEN\xa0: A circle C (0, r) and a tangent AB at a point P.TO PROVE :\xa0{tex}O P \\perp A B{/tex}CONSTRUCTION Take any point Q, other than P, on the tangent AB. Join OQ. Suppose OQ meets the circle at R.PROOF\xa0: We know that among all line segments joining the point O to a point on AB, the shortest one is perpendicular to AB.To prove that {tex}O P \\perp A B{/tex}, it is sufficient to prove that OP is shorter than any other segment joining O to any point of AB.Clearly,\xa0{tex}OP = OR{/tex}Now,\xa0{tex}OQ = OR + RQ{/tex}{tex}\\Rightarrow \\quad O Q > O R{/tex}{tex}\\Rightarrow \\quad O Q > O P \\quad [ \\because O P = O R ]{/tex}{tex}\\Rightarrow \\quad O P < O Q{/tex}{tex}\\therefore{/tex}\xa0{tex}O P \\perp A B{/tex}
3739.

Wrote 23.426 in p/q

Answer» good
23426/1000
3740.

When will board datesheet release?

Answer»
3741.

SinA - CosA = 1/2 then find the value of sinA.cosA

Answer»
3742.

hey hello guys ..??

Answer»
3743.

The area of three adjacent faces of cuboid are x,y& z if it\'s volume is v then show that v^2=xyz

Answer» Let the length, breadth and height of the cuboid be l, b and h units respectively.x = lb, y\xa0= bh, z\xa0= hl∴ xyz\xa0= (lb) (bh) (hl) = l2b2h2 . . . (1)Again v = lbh∴ v2 = (lbh)2 = l2b2h2 . . . (2)From (1) and (2)v2 = xyz
3744.

When we will get time table of class 10 board exams

Answer» I think on 10 of this month as it was announced
3745.

Determine whether 50cm,80cm,100cm can be a the sides of a right angle or not

Answer» No because it does not satisfy Pythagores Theorem
No
3746.

Mathematics formula for class 10 for all xhapter

Answer» Check revision notes here :\xa0https://mycbseguide.com/cbse-revision-notes.html
3747.

Find value of @ for which (@ - 12)x2+(@-12)x+2=0 has equal zeroes and ........ @= alpha

Answer» We have, (k- 12 )x2 + 2(k - 12)x + 2 = 0.\xa0a = k - 12,b = 2(k - 12) and c = 2.The given equation will have equal roots, if{tex}\\therefore{/tex}\xa0D = b2 - 4ac = 0{tex}\\Rightarrow{/tex}\xa04(k\xa0- 12)2 - 4 (k - 12){tex}\\times{/tex} 2 = 0{tex}\\Rightarrow{/tex}4(k- 12) [(k\xa0- 12) - 2]\xa0= 0{tex}\\Rightarrow{/tex}4(k\xa0- 12)(k\xa0- 14) = 0{tex}\\Rightarrow{/tex}4(k\xa0- 12) (k - 14) = 0 {tex}\\Rightarrow{/tex}\xa0k - 12 = 0 or, k - 14 = 0 {tex}\\Rightarrow{/tex}\xa0k\xa0= 12 or, k = 14
3748.

4u-5y

Answer»
3749.

Solve Under root x+y=11 and x+under root y=7

Answer»
3750.

(a-b)x+(a+b)y=a*a-b*B-2ab

Answer» x = a + b{tex}\\therefore{/tex} (a - b)(a + b) + (a + b)y = a2 - b2 - 2aba2 - b2 + (a + b)y = a2 - b2 - 2ab{tex}y = \\frac{{ - 2ab}}{{a + b}}{/tex}