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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 37751. |
Find the rationale number between 3/5and 4/5 |
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Answer» Answer Kya hoga 7/10 7/5 10/15,11/15and many more |
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| 37752. |
x upon a + y upon b = a+b and x upon √a - y upon √b = 2 |
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| 37753. |
A=30 ,verify sin2A= 2tanA/1+tanA×tanA |
| Answer» LHS = RHSHence verified | |
| 37754. |
Pls send the sample paper for the session 19-20 |
| Answer» By download the google than you print this paper☺️☺️ | |
| 37755. |
Solve it by substituting method.. ..Q1. 3x-y=3 9x-3y=9 |
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Answer» See....Y=3x-3 Yeh ha answer Answer galat h 3x-y=3........19x-3y=9..(divided by 3)3x-y=3......23x=3-yX=3-y/3sub X in 13x-y=33(3-y/3)-y=33-y-y=3-2y=3-3y=0sub y in 2\xa03x-y=33x-0=33x=3X=1 |
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| 37756. |
Find the distance between the points P(a+b,a-b) and R(a-b,a+b) |
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| 37757. |
If m times mth term of an A.P is equal to n times nth term of the A.P. Find its (m+n)th term |
| Answer» Thge general nth\xa0term of an AP is a + (n -1)d.\xa0From the given conditions,\xa0m (a + (m-1)d) = n( a + (n-1)d)=> am + m2d - md = an + n2d - nd=> a(m-n) + (m+n)(m-n)d - (m-n)d = 0=> (m-n) ( a + (m+n-1)d ) = 0\xa0Rejecting the non-trivial case of m=n, we assume that m and n are different.=> ( a + (m + n - 1)d ) = 0\xa0The LHS of this equation denotes the (m+n)th\xa0term of the AP, which is Zero. | |
| 37758. |
Which chapters are included in basic maths |
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Answer» All chapters All chapters.... But basic maths means that the toughness will be less.... And you can\'t take maths for further studies..... All ncert chapter |
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| 37759. |
An elec |
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| 37760. |
1 Terms of an ap is 5 find the 32th term |
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Answer» Common difference kitna hai Oye D |
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| 37761. |
I should consult only ncert for maths borad exam 2020 only ncert not other books |
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Answer» No in previous 10years mostly question come from rs but after 2 years allquestion from ncert Welcome and best of luck for boards tere ko bhi aur mere ko bhi Thanks for teliing so i should consult exemplar and ncert rathar than rd No If u want to score more than 80 than u have to follow reference books like rs or rd.If u want my suggestion than rs is best for boards along with ncert book and exemplar |
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| 37762. |
Line and angle |
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| 37763. |
Five year hence the age of jacob will be three times that ohG sin |
| Answer» \xa0Let x (in years) be the present age of Jacob\'s son\xa0and y (in years) be the present age of Jacob. 5 years hence, it has relation:(y + 5) = 3(x + 5)or, y + 5 = 3x + 153x + 15 - y - 5 = 0or, 3 x - y + 10 = 0 .......(i)5 years ago, it has relation(y - 5) = 7(x - 5)y - 5 = 7x - 35or, 7x - 35 - y + 5 = 0or, 7 x - y - 3 0 = 0 ....(ii)From eqn. (i), y = 3x + 10 ....(iii)On substituting the value of y in eqn. (ii), we get7x-(3x + 10) - 30 = 07x - 3x - 10 - 30 = 0or, 4x - 40 = 0or, 4x = 40x=10On substituting x = 10 in eqn. (iii),{tex}y = 3 \\times 10 + 10{/tex}y = 30 + 10{tex}\\therefore {/tex}\xa0y = 40Hence, the present age of Jacob = 40 years and son\'s age = 10 years | |
| 37764. |
Find the value of p and q 2p, 2p+q, p+4q ,35 are in A.P |
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| 37765. |
What is standard math or basic math ?? |
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Answer» This is two type of maths exam.?? In standrad maths you can mathematics in class XI but you cannot take biology. In basic maths you cannot take mathematics in class XI but can pursue commerce or humanities stream. In basic maths question paper will be easy than standard. In standrad 40% questions will come from out of syllabus and 20% from syllabus. If you want to take maths in class XI you have to sit for compermental exam meant for standard mathematics. |
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| 37766. |
But i m 100% sure that i have 2choose medical strem |
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Answer» Then you can choose standard as well as basic ??????????? If u want to choose medical stream then u will have to choose basic |
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| 37767. |
What is mathe |
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Answer» गणित एक विषय है जो हम रोज पढ़ते हैं।( Maths is a subject which we study everyday) Maths is a subject |
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| 37768. |
What is math |
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Answer» ????????????? Maths is a subject aap nhi jante the kya. Ye subject ke sath sath ek. Musibat bhi hai. I don\'t like maths. Maths ek subject h, yeh kesa ajeeb sa question h?? It is a subject....a subject in which u solve problems of the questions |
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| 37769. |
Rs Aggarwal class10 exercise 11c |
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| 37770. |
Proof √9 is irrational ? |
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Answer» Root 9 to irrational ho hi nhi skta to ans mei ye ayega ki its a rational no. Prove krdo by pythagours theorem that root 9 is rational no. Root 9 rational hai bhai...3 ka square hai kaha irrational prove karne chale ho |
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| 37771. |
3x_5y=09x=2y+7 |
| Answer» \tBy Elimination method,\tThe given system of equations is :\t3 x - 5 y - 4 = 0............(1)\t9 x = 2 y + 7\t9 x - 2 y - 7 = 0.............(2)\tMultiplying equation (1) by 3, we get\t9 x - 15 y - 12 = 0.............(3)\tSubtracting equation (3) from equation (2) , we get\t13 y + 5 = 0\t{tex}\\Rightarrow \\quad 13 y = - 5 \\Rightarrow y = \\frac { - 5 } { 13 }{/tex}\tSubstituting this value of y in equation (1), we get{tex}3 x - 5 \\left( \\frac { - 5 } { 13 } \\right) - 4 = 0{/tex}\t{tex}\\Rightarrow \\quad 3 x + \\frac { 25 } { 13 } - 4 = 0 \\Rightarrow 3 x - \\frac { 27 } { 13 } = 0{/tex}\t{tex}\\Rightarrow \\quad 3 x = \\frac { 27 } { 13 } \\Rightarrow x = \\frac { 9 } { 13 }{/tex}\tSo, the solution of the given system of equation is{tex}x = \\frac { 9 } { 13 } , y = \\frac { - 5 } { 13 }{/tex}\tBy Substitution method:\tThe given system of equation is:\t3 x - 5 y - 4 = 0.............(1)\t9 x = 2 y + 7...................(2)\tFrom equation (2),\t{tex}x = \\frac { 2 y + 7 } { 9 }{/tex}..................(3)\tSubstituting this value of x in equation(1), we get\t{tex}3 \\left( \\frac { 2 y + 7 } { 9 } \\right) - 5 y - 4 = 0{/tex}\t{tex}\\Rightarrow \\quad \\frac { 2 y + 7 } { 3 } - 5 y - 4 = 0{/tex}\t{tex}\\Rightarrow \\quad 2 y + 7 - 15 y - 12 = 0{/tex}\t{tex}\\Rightarrow{/tex}\xa0-13y - 5 = 0{tex}\\Rightarrow{/tex}\xa013y = -5\t{tex}\\Rightarrow \\quad y = \\frac { - 5 } { 13 }{/tex}\tSubstituting this value of y in equation(3), we get\t{tex}x = \\frac { 2 \\left( \\frac { - 5 } { 13 } \\right) + 7 } { 9 } = \\frac { - \\frac { 10 } { 13 } + 7 } { 9 } = \\frac { - 10 + 91 } { 117 } = \\frac { 81 } { 117 } = \\frac { 9 } { 13 }{/tex}\u200b\u200b\u200b\u200b | |
| 37772. |
Maths ka two part ho gya hai kya |
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Answer» Hnji Basic and standard ?? Basic and Sandard Yeah |
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| 37773. |
How many solutions do a linear eqation in two variable have? |
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Answer» Its infinite because if u keep on changing the numbers you will be getting different answers. Infinite Infinite Infinite solutions. Infinite..... ? |
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| 37774. |
Prove and state Pythagoras theorem |
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| 37775. |
How many of students are taking Basics for class 10 |
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Answer» Show that any positive odd integers is of the form 6q + 160 + 360 + 5 Where Q is some integer You are from which school? |
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| 37776. |
Agar mujhe 11 me bio lena h to kya mai 10 me standard maths le skte hu |
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Answer» Yes, you can take. But if you sure that you won\'t take maths in 11 then its better to opt for basic maths as it will be easier than standard and can also increase your percentage. yes Yes you can take but if you don\'t want to persue maths then you should take basic maths as it is much easier than standard |
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| 37777. |
exercise 3.3 question no. 1 all examples |
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| 37778. |
Give me a solution of converse of B.P.T and converse of phythagoras theorem |
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Answer» In nhi on google☺️☺️☺️ Check on teachoo website in Google |
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| 37779. |
Find the perpendicular distance of A(6,4) from the x-axis. |
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Answer» Q. Find the Perpendicular Distance Of A(6,4) from the\xa0X-axis\xa0????Shreya Aapne http://clay6.com se copy toh kar liya lekin Question theek se read naheen kiya......Haina Miss Darshini....Jaisa kee Aapne likha hai :- Consider a Point P(x,y) on the coordinate plane Perpendicular distance of the point P(x,y) from the x axis=ordinate of the point P(x,y)=y Perpendicular distance of the point P(x,y) from the y axis=ordinate of the point P(x,y)=x Perpendicular distance from y-axis = x coordinate of the point Given x coordinate of point is 6, Therefore, perpendicular distance of point A(6,4) from y-axis is 6......toh word language toh lagvag theek hai lekin ending galat hai......\xa0I\'m also not going to write by myself but, I\'ll include some of the changes that in my view\'re necessary.......Consider a point A(x,y) on the coordinate plane.Perpendicular distance of the point A(x,y) from the x axis=ordinate of the point A(x,y)=y. [Since, An ordered pair contains abscissa (value of x) and ordinate (value of y) respectively]Perpendicular distance of the point A(x,y) from the y axis=abscissa\xa0of the point A(x,y)=x.\xa0Perpendicular distance from x-axis = y\xa0coordinate of the point Given y\xa0coordinate of point is 4, Therefore, perpendicular distance of point A(6,4) from x-axis is 4. That\'s it.... :) Sorry, For showing Off.... But As I\'ve heard that peoples learn from their mistakes, so I hope you too\'ll do the same..... :) Once again, Sorry.... Consider a Point P(x,y) on the coordinate planePerpendicular distance of the point P(x,y) from the x axis=ordinate of the point P(x,y)=yPerpendicular distance of the point P(x,y) from the y axis=ordinate of the point P(x,y)=xPerpendicular distance from y-axis = x coordinate of the point Given x coordinate of point is 6, Therefore, perpendicular distance of point A(6,4) from y-axis is 6 Aap abhi tak padh rahe ho |
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| 37780. |
Hi how to get above 70% in maths half early exam |
| Answer» Just see the videos from youtube from which chap. which are the main questions And then prepare it very well Tab aa jaege 70%se uppar | |
| 37781. |
In the following AP, find the missing term in the box 2, ,26 |
| Answer» The missing term of box is 14 | |
| 37782. |
Is there any additional content in standard maths? |
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Answer» No there is no additional content. The previous year\'s difficulty level was a standard. No Yes , in the standard maths the weightage of refrences is much more than NCERT |
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| 37783. |
Aagr. 10th me basic maths le to commerce nhi milegi kya....? |
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Answer» You could opt for commerce but without maths Thik hai yogesh Ji meri aoukat basic ki hai . Aur aapki aoukat kiski hai.. ????? If you want to cop with maths in commerce you should choose standard but if you only want to take commerce than you can choose basic maths. Tumhari aoukat basic ki hi hai Milega lekin extra subject maths nhi le sakte |
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| 37784. |
When we choose basic maths to. 11th.me kon kon se subjects le sakte hai. |
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Answer» Yogesh Ji aap stupid Ho kya.... ????? You can choose any subject except maths Aou kesi ho jane men Really commerce nhi milegi bins maths wali. Arts and biology |
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| 37785. |
Find the probabiliy that a non leap year chosen at random has 52 sundays53 sundays |
| Answer» Answer By :- SyedaA non-leap year has 365 daysA year has 52 weeks. Hence there will be 52 Sundays for sure.52 weeks = 52 x 7 = 364 days .365– 364 = 1day extra.In a non-leap year there will be 52 Sundays and 1day will be left.This 1 day can be\xa0Sunday, Monday,\xa0Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.Of these total 7 outcomes, the favourable outcomes are 1.Hence the probability of getting 53 sundays = 1 / 7.∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7. | |
| 37786. |
write the formula of area of triangle if vertices are given |
| Answer» 1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)} | |
| 37787. |
Question paper pattern |
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Answer» Vvvv easy...bhai tu chill kar!! Mcq type Go to CBSE website , pattern is given there !!! Not provided yet by CBSE. |
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| 37788. |
Statistics chapter |
| Answer» Full chapter 3 formula pr depend h 1. Mean = €fx÷€f 2. Median = l + { h× n/2- cf÷ f}3. Mode = l + (f1 - f0÷2f1 - f0 - f2)× h | |
| 37789. |
Standard and basic sample paper |
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Answer» ??? U r in 12th class?? Which stream u choose in 11th??? |
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| 37790. |
7th chapter is difficult |
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Answer» Mere tution. Me aaja harmail cheema....mere sir bht achhe se padhate h... No Jisko nii aata....wo pagal hoga No. It is very easy. |
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| 37791. |
For what value of n,the nth term of the A.P is 63,65,66,...........&3,10,17,.........are equal? |
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Answer» ans. n=13 An 1= an2 |
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| 37792. |
2+2%2 |
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Answer» 3 3 3 3 by BODMAS |
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| 37793. |
Prove that 5-3/7 root 3 is an irrational number |
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Answer» Bhai net pr dhundhne pr jada achhe answers mil jaate h...faltu ka time barbad Thank you Solve kar ka batayo Let 5-3/7√3 be rational.Therefore its simplest form will be p/q.Now,5-3/7√3=p/q3/7√3=5-p/q3/7√3=5q-p/q√3= 7(5q-p)/qHere,7,5,p,q are rational numbers.Therefore, √3 will be also a rational no.But this contradicts the fact that √3 is irrational, and this contradiction arises by assuming 5-3/7√3 as rational.Hence 5-3/7√3 is irrational. No it is no an irrational number |
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| 37794. |
Mathmatics main kaise man lagye |
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Answer» Yha koi baba nii h....to srry...yha puchhne se achha..padh le...to man lg jaega.????? ? Group study se ? |
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| 37795. |
How you find roots of any eqation |
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Answer» Joy shukla is foolish Completing square method is deleted from cbse...nonsense... Either by mid term splitting or quadratic formula or completing sq method |
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| 37796. |
Is standard paper of maths is tough than previous maths papers?isn\'t itOr it is of same level? |
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Answer» See...this is the first time that maths paper has been divided into standard and basic...so exactly no one knows that standard will be tougher or not....no doubt that it will be a level higher than basic one...but exactly no one knows ..! Yes |
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| 37797. |
Find the value of sin 45 geometrical method |
| Answer» In a Rt. angle Triangle,Let the side be "a"By Pythogorus theroma2 + a2 = h2h = a√2Sin(45°) = a/a√2 = 1/√2 | |
| 37798. |
ABC is a triangle, right angled at C and AC = root 3 BC. Prove that angle ABC=60 degree |
| Answer» Given,AC = √3 BCLet < ABC = @ then,Tan @ = perp./ base= AC / BC= √3 BC/ BC= √3\xa0So,\xa0@ = 60° | |
| 37799. |
How we will find these answers is that chapter Because in they ask Solve it or prove it |
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| 37800. |
PROVE ME HOW 1 UPON 2 ROTT IS IRATIONAL |
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