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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 37851. |
Find the ratio in which the line segment joining the point (-3,10) and (6,-8) is divided by (-1,6) |
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Answer» 2:7 or 7:2 7 : 2 |
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| 37852. |
Tan theta÷1-cot theta + cot theta÷1-tan theta =1+ sec theta cosec theta |
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Answer» Give me full solutions Change both LHS and RHS in form of sin and cos and then solve both LHS and RHS seperatily.. you got it |
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| 37853. |
How many chapters of maths we should study yet |
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Answer» 7 chapters chapter 6 8 chapters 10 chapters |
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| 37854. |
2 tan 30°----------------1+ tan sq. 30° |
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| 37855. |
Prove that√2 is a irrational |
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Answer» See examples of chapter 1 Sorry deep but 4:51 ke bad sidha 5:01 Time ,4:56pm !!! Satig se dekho .Mene nya quesion post kiya h. !! I was typd I am not going to get your question.type karo yarr..... Now , answer me ! See my new question !! Ok i ll type again .New Question !! ?? Nahi yarr kab se dhund dhund ke pagal ho rahe hai ham Aapke pass mera chat nhi pahucha kya .2:44se pehle 2:43 ka chat nhi aaya kya?? Hamare icon me aisa koi chat nahi hai 2:29 ke bad sidha 2:44ka hai.......waisa kya hai chat me bata do aap khud hi .... 2:43 pm ? Hame chat nahi mil raha hai...aap time batao kab ka chat hai Aapne mera vo chat padha kya??? Kyu I want your n**********!! Plz I am here Be online plz !!!??? Hello Hi pk Prefer rs aggarwal..... |
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| 37856. |
√265 - √5. How we will solve it? |
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| 37857. |
P2½ G1 ka ½R h . Solve this puzzle by making a sentence . |
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Answer» Nice ?? Pa dhai gee one ka adha r h ! Padhai ? jeewan ka adhar hai? Hi |
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| 37858. |
(-3,5),(3,1),(0,3),(-1,-4) |
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Answer» Kya find krna hai Find kya krna hai?????? ?? What is the question exactly |
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| 37859. |
If Sn is given find an |
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Answer» Give question to mee .I ll solve it.Fast...... Its too easy. |
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| 37860. |
Hcf of 124098 |
| Answer» Maximum 2 no. Hone chahiye hcf find krne ke liye | |
| 37861. |
Frame a quadratic equation whose only root is -6.. |
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| 37862. |
Why cannot solve elimination method and cross multiplication method |
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Answer» Elimination is easy? but cross multiplication is quite confusing...???? Because it is very complecated ??? |
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| 37863. |
If any one have doubt ask to me |
| Answer» Whai is fragmentation??... | |
| 37864. |
If value of tanA is1/√3 than value of cosA is? A)1/2 b)2√3 c)√3/√2 |
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Answer» Nalayak !! √3/2 hogaaaaa It\'s so easy, chap.... As the value of tan theta\xa0is \'1 upon root 3\' when the theta is 30 degree,i.e, when theta = A = 30 degree and cos A = cos 30 degree = \'1 upon root 2\'. 1/root 2 1/2 |
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| 37865. |
Total written marks = 80 /90 |
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| 37866. |
X^2+3x-(a^2+a-2) |
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| 37867. |
In a triangle vertexes 1,2,3,4,x,y Then prove x+y =3 and area is 6 |
| Answer» It\'s vertices not vertexes!!!? | |
| 37868. |
X square 2 + 6x +6=6 sum 6 find value of k |
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Answer» New Delhi Central board Mtlb In which board or state 10 Where is k in equ.??? Radhe Radhe is question mein hum K nahi pate Hii miss queen Where is k Equation m "k" kha h..?? Where is k? |
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| 37869. |
Basic and standard mathematics sample paper myCBSEguide please give |
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| 37870. |
Alfa upon beata + Beata square upon alfa Find zeros |
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| 37871. |
Solve by completing square:- 2/x2-5/x+2=0 |
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| 37872. |
Rs aggarwal exercise 4a Q.10 |
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Answer» U can prove using bpt first join diagonals and then oblique sides means non parallel sides hence connect them ...Now u have two triangles u can prove by bpt.. Show that the line segment which joins the mid point of the oblique sides of trapezium is parallel to third side. Plz write the question also here plz.. |
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| 37873. |
Which is greater 1.6 or 1.62 |
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Answer» 1.62 is greater than 1.60 1.62 1.62 1.62 is greater as there is one more digit after point 1.62 |
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| 37874. |
If ad=4x-3 ae=8×-7 bd=3×-3 ce=5×-3 find value of x |
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| 37875. |
Find the roots of 3x square - 2√6 X + 2=0 |
| Answer» b^2-4ac = (-2√6)^2-4×3×2 =4×6-24=24-24 = 0 roots are real and equal | |
| 37876. |
The 17th term of an AP exceeds its 10th term by 7.find the common difference. (True) (false) |
| Answer» a17 = a10 + 7a+16d = a + 9d + 7 16d-9d = 77d = 7d = 7Common difference is 7 | |
| 37877. |
Sin theta ×sin theta /cosec theta |
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Answer» Sin×Sin=sin square= 1-cos square/cosec. Cosec=1/sin hence sin(1-cos square) apply identity a2-b2 Sin(1+cos)(1-cos) I think answer is cosec theta as Sin=1/cosec and vice versa ATQ Sin theta × sin/cosec=> Sin theta × cosec theta / sin theta=> Sin theta wil be cancelled=> Cosec thetaHence the answer is cosec theta |
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| 37878. |
5597+3= |
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Answer» 5600 5600 5600 5600 |
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| 37879. |
Sec+tan=p prove that sin=[(p)2-1][(p)2+1] |
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| 37880. |
What types of questions will come in basic mathematics for class 10 |
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Answer» Best support in ncert exam in board 80/question come in ncert book or 20/ question come in RS agrwal Ncert From NCERT |
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| 37881. |
Plzzz.. help me frnds x²-2ax+a² |
| Answer» (x-a)^2 | |
| 37882. |
x²-2ax+a² |
| Answer» Zeroes of Sum=2aZeroes of products=a^2 | |
| 37883. |
in figure 4.145 pa qb perpendicular to ac prove that 1/x+1/z=1/y |
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| 37884. |
Find the 11th term from the last term of AP 27,23,19,.....,-65 |
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Answer» 27 , 23 , 19 ,...., - 65 is an A.Pa = 27 ,common difference = a2 - a1d = 23 - 27 = - 4Rewrite the A..P,- 65, - 61, - 57, ... 19, 23, 27here,first term = a = - 65common difference = a2 - a1d = - 61 - ( - 65 )d = -61 + 65d = 4n = 11nth term = an = a + ( n - 1 )da11 = -65 + ( 11 - 1 ) 4= -65 + ( 10 {tex}\\times{/tex} 4 )= -65 + 40= -25Therefore,required 11th term= a11 = - 25 -65,-61,-57.....27a=-65.d=4N=11An=a +(n-1)dA11=-65+(11-1)4-65+40=-2511th term is -25 |
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| 37885. |
How to practice and learn in4 days |
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Answer» To focus on tarket to achieve goal But what???? |
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| 37886. |
Pythageorus theorm?? |
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Answer» The square of base and perpendicular is equal to the square of hypoteneuse side is called Pythagoras theorem (Hypotenuse)^2 = (Base)^2 + (Height)^2 It is only used on right angled triangleHypotenuse² =AB² + BC² |
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| 37887. |
Why there is no sample papers of new pattern of 2020 |
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| 37888. |
If the average of 11,12,13,14and x is 13 then find the value of d |
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| 37889. |
V^2 + 4√3v - 15 middle term splitup the equation. |
| Answer» (V-√3) (2V + 5√3 | |
| 37890. |
2x+80x+77y=0 |
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| 37891. |
D e parallel to BC and BD is equal to CE prove that ABC is an isosceles triangle |
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| 37892. |
A natural number when increased by 84 equals 160 times its reciprocal. Find the number |
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| 37893. |
Do factor xsquare-3x-2 give solution |
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| 37894. |
Queen ji tell the name |
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Answer» Who is sumit mis suhana Amira or aap ki nazar me koi aap jasi achi larki ho to jrror btana Ya from one week |
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| 37895. |
If the sum of the zeroes of the polynomial f(x) =2x³-3kx²+4x-5 is 6, then find the value of k. |
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| 37896. |
How to derive section formula |
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| 37897. |
I need format of lesson plan of class 10th maths 2019-20 |
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| 37898. |
Pls answer |
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| 37899. |
Every even integer is on the form of ? |
| Answer» 2n. ; Where n is a natural number | |
| 37900. |
If sin3a=cos(A-26)where 3A is acute angle find value of A |
| Answer» 29 | |