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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3751. |
Write a theorem of 10.1 |
| Answer» Bhai book se likh le | |
| 3752. |
if 7x+9y=42 and9x+7y =22find value of x and y |
| Answer» x=-3,y=7 | |
| 3753. |
A number is chosen from 1 to 100 . Find the probability that it is a prime number |
| Answer» {tex}\\frac 14{/tex} | |
| 3754. |
When our examination were held |
| Answer» | |
| 3755. |
Cuboid formula |
| Answer» The volume of a\xa0cuboid\xa0is given by the\xa0formula\xa0V = lwh, andthe surface area of a\xa0cuboid\xa0is given by the\xa0formulaSA = 2lh + 2wh + 2lw where l = length, w = width, and h = height. | |
| 3756. |
Truth or dare??? |
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Answer» Bade ache ache points maar rahe hi bhai....kon hai aap?????? Truth: yahan padhai ke Naam par chatting Hoti haiDare: man karta hai gaaliyan doUmmeed hai koi dare na le |
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| 3757. |
Cos(90-A) |
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Answer» Oh sorry sinA SinA =sec |
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| 3758. |
Show that exactly one of the numbers n, n+2 or n+4 is divisible by 3. |
| Answer» Let n =3kthen n + 2 = 3k + 2and n + 4 = 3k + 4Case 1: When n=3k ,n is divisible by 3 ............(1)n + 2 = 3k + 2or, n + 2 is not divisible by 3n + 4 = 3k + 4= 3(k + 1) + 1or, n + 4 is not divisible by 3Case 2:When n=3k+1, n is not divisible by 3\xa0n + 2 = (3k + 1) + 2=3k + 3 = 3(k + 1){tex} \\Rightarrow{/tex}\xa0n+ 2 is clearly divisible by 3..........................(2)n + 4 = (3k + 1) + 4= 3k + 5= 3(k + 1) + 2{tex}\\Rightarrow{/tex}\xa0n + 4 is not divisible by 3Case 3:When n=3k+2,n is not divisible by 3\xa0n + 2 = (3k + 2) + 2= 3k + 4(n + 2) is not divisible by 3x + 4 = 3k + 6 = 3(k + 2){tex}\\Rightarrow{/tex}\xa0n + 4 is divisible by 3........................(3)Hence, from (1),(2) and (3) it is clear that\xa0exactly one of the numbers n, n + 2, n + 4, is divisible by 3. | |
| 3759. |
Sir in chapter 13 of 10 class in ex 13.4 of 3 question why the area of triangle added in solution |
| Answer» Koi abswer nahi | |
| 3760. |
If the roots of quadratio equation (a-b)x×x+(b-c)X+(c-a)=0 are equal .prove that 2a=b+c |
| Answer» We have (a-b)x2 + (b-c)x + (c-a) = 0Here A\xa0= (a-b), B\xa0= (b-c), C= (c-a){tex}\\therefore D = B^2 - 4AC = (b-c)^2 - 4(a-b) (c-a){/tex}For equal roots, D = 0{tex}\\implies{/tex}(b-c)2 - 4 (a-b) (c-a) = 0b2+c2-2bc -4(ac-a2-bc+ab) =0b2+c2-2bc -4ac+4a2+4bc-4ab=04a2+b2+c2+2bc-4ab-4ac=0(2a-b-c)2=0i.e. 2a-b-c =0Hence, b + c = 2a or 2a = b + c | |
| 3761. |
If the mean =30 And the mode=40 then find the median |
| Answer» 100 | |
| 3762. |
The nth term of an ap is given by a=4n-5 ,then find the sum of first 25 terms of ap |
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Answer» Sorry thats n/2(a+l) 1st yerm term aur kast term nikal la 4n-5ma value put karka than putSn =n/2(2a+(n-1) |
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| 3763. |
Hi girls I am new |
| Answer» | |
| 3764. |
volume of largest circular cone whose edge is 21 |
| Answer» Wrong qstn | |
| 3765. |
What is the formula for section formulae in coordinate geometry |
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Answer» (m1*x2+m2*x1) /m1+m2=x - - - > for y =(m1*y2+m2*y1) /m1+m2. Mx2+nx1/m+n,my2+ny1/m+n |
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| 3766. |
ax+by=cbx+ay=1+cPlz the send the answer quickly |
| Answer» Multiplay eq 1 by a & eq 2 by b and sokve | |
| 3767. |
Why π included in most of the formulas |
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Answer» Pie is equal to circumference divided by diameter. .....So any circular shape has these things. ...So it is included in most formulas where at least one circle is involved so it\'s common for every circle that\'s why taken Pie is the value = circumference / diameter Pie is not a defined value pie is only let |
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| 3768. |
Find the zeroes of polynomial ,p(x)=x2-17x+30 |
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Answer» Xsq - 17x+30Xsq- 15x- 2x + 30X(x-15)-2(x-15)X-15=0X=15X-2=0X=2 i think there should be two x square if it is then the zeroes of the given polynomial is either six or either five by two 15 and 2 2&15 Zeros are 2 and 15 15 , 2 |
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| 3769. |
In this year how much marks will paper come from NCERT of math |
| Answer» The Base of paper will be ncert. .No thing new from outside only questions will be twisted | |
| 3770. |
Ncert chapter 6 |
| Answer» Check NCERT solutions here : https://mycbseguide.com/ncert-solutions.html | |
| 3771. |
Where are ncert solutions in my cbse app |
| Answer» Check NCERT solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 3772. |
18divided5 hours in minute |
| Answer» | |
| 3773. |
How many terms Of sequence 18,16\'14\' should be taken so that their Sum is 0 |
| Answer» 19 | |
| 3774. |
The surface area of the cubeis equal to the surface area of sphere. Find the ratio of their volume?? |
| Answer» | |
| 3775. |
25 paise of 4 rupees |
| Answer» | |
| 3776. |
The ordinate of point on Y-axis is 5 and point B as coordinate (-3,1). Find the length of AB |
| Answer» Here, A\xa0{tex}\\rightarrow{/tex}(0,5) and B{tex}\\rightarrow{/tex}(-3, 1)AB =\xa0{tex}\\sqrt { \\left( x _ { 2 } - x _ { 1 } \\right) ^ { 2 } + \\left( y _ { 2 } - y _ { 1 } \\right) ^ { 2 } }{/tex}{tex}= \\sqrt { ( - 3 - 0 ) ^ { 2 } + ( 1 - 5 ) ^ { 2 } }{/tex}{tex}= \\sqrt { 9 + 16 }{/tex}{tex}= \\sqrt { 25 }{/tex}= 5 units | |
| 3777. |
What is datesheet |
| Answer» | |
| 3778. |
What is rationl number |
| Answer» | |
| 3779. |
What is the formula of step deviation to find mean |
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Answer» A+ {H × Summission fiui / summision fi} So easy ?? |
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| 3780. |
Find two consecutive odd positive integers ,sum of whose square is 290 |
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Answer» X=10,x=-14 x=10 and minus 14 Square of x +square of (x+2)=290 |
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| 3781. |
Find the coordinates of the point on y axis which is nearest to the point(-2,5) |
| Answer» The point on y-axis that is nearest to the point(-2,5) is (0,5). | |
| 3782. |
Cot + cosec -1 ÷ cot-cosec- cosec + 1 = 1+ cos ÷1 +sin |
| Answer» We have,L.H.S. =\xa0{tex}\\frac { ( \\cot \\theta + cosec \\theta ) - 1 } { ( \\cot \\theta - cosec \\theta + 1 ) }{/tex}{tex}= \\frac { ( cosec \\theta + \\cot \\theta ) - \\left( cosec ^ { 2 } \\theta - \\cot ^ { 2 } \\theta \\right) } { ( \\cot \\theta - cosec \\theta + 1 ) }{/tex}\xa0[{tex}\\because{/tex} 1 = cosec2{tex}\\theta{/tex} - cot2{tex}\\theta{/tex}]{tex}= \\frac { ( cosec \\theta + \\cot \\theta ) [ 1 - ( cosec \\theta - \\cot \\theta ) ] } { ( \\cot \\theta - cosec \\theta + 1 ) }{/tex}{tex}= \\frac { ( cosec \\theta + \\cot \\theta ) ( \\cot \\theta - cosec \\theta + 1 ) } { ( \\cot \\theta - cosec \\theta + 1 ) }{/tex}{tex}= ( cosec \\theta + \\cot \\theta ) = \\left( \\frac { 1 } { \\sin \\theta } + \\frac { \\cos \\theta } { \\sin \\theta } \\right) = \\frac { 1 + \\cos \\theta } { \\sin \\theta }{/tex}= R.H.S.Hence,\xa0{tex}\\frac { \\cot \\theta + \\ cosec \\theta - 1 } { \\cot \\theta - \\ cosec \\theta + 1 } = \\frac { 1 + \\cos \\theta } { \\sin \\theta }{/tex}. | |
| 3783. |
How can we prove root 2 irrational |
| Answer» | |
| 3784. |
When will the datesheet for class 10 release ? |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3785. |
Equal roots means |
| Answer» D = 0 | |
| 3786. |
Value of2+4= |
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Answer» 6 6 |
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| 3787. |
If x+y=7 then xy= |
| Answer» | |
| 3788. |
If p,q are zeroes of polynomials 2x\'2-x+3,find the value of p\'2 and q\'2 |
| Answer» we have f(x) = 2x2\xa0- 7x +3{tex}\\Rightarrow{/tex}\xa0Sum of roots = p + q =\xa0{tex}- \\frac { \\text { Coefficient of } x } { \\text { Coefficient of } x ^ { 2 } }{/tex}=\xa0{tex}- \\left( \\frac { - 7 } { 2 } \\right) = \\frac { 7 } { 2 }{/tex}{tex}\\Rightarrow{/tex}\xa0Product of roots = pq =\xa0{tex}{/tex}{tex}\\frac { \\text { Constant term } } { \\text { Coefficient of } x ^ { 2 } } = \\frac { 3 } { 2 }{/tex}Since, {tex}(p+q)^2{/tex}\xa0= p2\xa0+ q2\xa0+ 2pq{tex}\\Rightarrow{/tex}\xa0p2\xa0+ q2\xa0= (p + q)2\xa0- 2pq{tex}= \\left( \\frac { 7 } { 2 } \\right) ^ { 2 } - 3 = \\frac { 49 } { 4 } - \\frac { 3 } { 1 } = \\frac { 37 } { 4 }{/tex}Hence, the value of {tex}p^2+q^2{/tex}=\xa0{tex}\\frac{37}{4}{/tex} | |
| 3789. |
Find circumference of circle whose diameter is 55cm |
| Answer» 2×22/7×55/2 | |
| 3790. |
A+B=12 A×B=32 A-B=? |
| Answer» 4 | |
| 3791. |
The sum of first n terms of an AP is given by Sn=2n+3n find the sixteenth term of AP |
| Answer» | |
| 3792. |
Derivation of distant formula (coordinate geometry |
| Answer» | |
| 3793. |
When date sheet of class will declare |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3794. |
the flood |
| Answer» | |
| 3795. |
if x/7=y/11=z/13=2x-3y+z/m then value of m is |
| Answer» | |
| 3796. |
Blue print of 2018 of 10 class |
| Answer» It is a property which resest the flow of current through a conductor. | |
| 3797. |
What is gama |
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Answer» Nutron particles Raduation.. very harmful.. change AGTC content in dna |
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| 3798. |
If tan 2A=cot B prove that A+B=90* |
| Answer» | |
| 3799. |
Find the probability of having 53 fridays in a year |
| Answer» A leap year has =366 days=52\xa0weeks + 2 extra\xa0daysSo total outcomes will be [(Mon, Tue),(Tue, Wed),(Wed, Thu),(Thu, Fri),(Fri, Sat),(Sat, Sun),(Sun, Mon)]=7So Friday can fall on any one of the 2 extra days i.e,(Thu, Fri),(Fri, Sat) hence total no of Fridays will become 53{tex}Proabibilty\\;of\\;the\\;event=\\frac{Number\\;of\\;favourble\\;outcomes}{Total\\;number\\;of\\;possible\\;outcomes}{/tex}The probability of getting 53 Fridays in a leap year ={tex}2 \\over 7{/tex} | |
| 3800. |
What is mean? |
| Answer» Mean is determined by adding all the data points in a population and then dividing the total by the number of points. | |