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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3801. |
When is an equation called an identity prove the trigonometry identity 1+ cot2A = cosec2A |
| Answer» 1+cos2A/sin2A= (sin2A+cos2A)/sin2A=1/sin2A= cosec2A | |
| 3802. |
Show that one and only one out of x,(x+1)and (x+2 ) is divisible by 3 |
| Answer» On dividing n by 3, let q be the quotient and r be the remainder.Then, {tex}n = 3q + r{/tex}, where {tex}0 \\leq r < 3{/tex}{tex}\\Rightarrow\\;n = 3q + r{/tex} , where r = 0,1 or 2{tex}\\Rightarrow{/tex}{tex}n = 3q \\;or \\;n = (3q + 1) \\;or\\; n = (3q + 2){/tex}.Case I If n = 3q then n is clearly divisible by 3.Case II If\xa0{tex}\\;n = (3q + 1)\\; {/tex} then {tex} (n + 2)= (3q + 1 + 2) = (3q + 3) = 3(q + 1){/tex}, which is clearly divisible by 3.In this case, {tex}(n + 2){/tex} is divisible by 3.Case III If n = {tex}(3q + 2){/tex} then {tex}(n + 1) = (3q + 2 + 1) = (3q + 3) = 3(q + 1){/tex}, which is clearly divisible by 3.In this case,{tex} (n + 1){/tex} is divisible by 3.Hence, one and only one out of {tex}n, (n + 1){/tex} and {tex}(n + 2){/tex} is divisible by 3. | |
| 3803. |
From which book the question paper and it\'s language will come |
| Answer» | |
| 3804. |
Angles in alternate segments |
| Answer» | |
| 3805. |
if one zero of the polynomial p (×)=×2-6×2+11×-6is3,find other two zero |
| Answer» The given polynomial f(x)={tex}\\text{x}^3-\\text{6x}^2+\\text{11x-6}{/tex}Since 3 is a zero of p(x), so (x - 3) is a factor of f(x).On dividing f(x) by (x - 3), we get{tex}\\therefore{/tex}\xa0f(x) = (x2\xa0- 3x + 2)(x - 3)= ( x2\xa0- 2x - x + 2)( x - 3)= [x(x - 2) -1(x - 2)](x - 3)= (x - 1)(x - 2)(x - 3)Now f(x)=0 if x - 1 = 0 or x - 2 = 0 or x - 3 = 0{tex}\\Rightarrow{/tex}\xa0x = 1 or x = 2 or x = 3{tex}\\mathrm{Hence}\\;\\mathrm{the}\\;\\mathrm{remainig}\\;\\mathrm{roots}\\;\\;\\mathrm{of}\\;\\mathrm f(\\mathrm x)\\;\\mathrm{are}\\;1\\;\\mathrm{and}\\;2\\;{/tex} | |
| 3806. |
find the eleventh term from the last term27,23,19,....-65 |
| Answer» -25 | |
| 3807. |
{2√56π22/7}521+530-30% |
| Answer» | |
| 3808. |
If m times nth term of an AP is equal to n times the nth term. Find the value of (m+n)the. |
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Answer» Show me the solution Kaisa Nth term equal to mth term hoga to answer. 0 aayga I think ques. Galt h |
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| 3809. |
In a rhombus of side 10 cm one of the diagonal is 12 cm long .find the length of second diagonal |
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Answer» Sorry the other diagonal will be 16 cm 8 cm |
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| 3810. |
Maths guess questions papet |
| Answer» | |
| 3811. |
How many card are there in a dec of card |
| Answer» 52 | |
| 3812. |
SinA+cosA+1÷sinA+cosA-1=??? |
| Answer» cosecA.secA+1 | |
| 3813. |
Proof of theorems of chapter triangles |
| Answer» | |
| 3814. |
If p, q, r, are in A. P. Then find the value of(p+q-r) (q+r-p) |
| Answer» 0 | |
| 3815. |
Father of mathmatics |
| Answer» Maybe Euclid | |
| 3816. |
Prove that√3+√8 is irrational |
| Answer» | |
| 3817. |
Cubic polynomial |
| Answer» The polynomial which have degree 3 is called cubic polynomial | |
| 3818. |
In mathematics, optional exercise is either important or not? |
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Answer» No it\'s not important Most important |
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| 3819. |
Can we multiply sin( 50+1)to sin 40 |
| Answer» | |
| 3820. |
Which is one of the following is polynomial (a)x2-6x+2 (b)5/x2 -3x+1 |
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Answer» I think (a). (a)x2-6x+2. Is the Right answer |
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| 3821. |
Find the co-ordinates of the pointing axis which is nearest to the point (-2,5) |
| Answer» 0,5 | |
| 3822. |
When was class 10 board examination date sheet will be declared |
| Answer» You can check the datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3823. |
Date sheet 10 th 2018 |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3824. |
2_5/555664+558,75-668 |
| Answer» | |
| 3825. |
Pre board me agar pas nahi ho to board ka roll no nahi melta, answer plz |
| Answer» Good joke ? | |
| 3826. |
4-2=??? |
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Answer» 6-4 2 |
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| 3827. |
What do you think abt ur preparation for board exam? |
| Answer» C CBSE question paper of last date 2017 | |
| 3828. |
x datesheet 2018 |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 3829. |
Show that diagonal of trapezium divide each other proportionally |
| Answer» Construction needed !! Use Thales theorem , prove by drawing one parallel line passes through the intersection of two diagonals ...and then try by using thales | |
| 3830. |
Imp ques in triangles class 10 |
| Answer» | |
| 3831. |
From which month exam are starting |
| Answer» 5 mar | |
| 3832. |
1)sin6A+cos6A=1-3sin2a.cos2a2)5tan-4=a find the value of 5sina-4cosa÷5sina+4cosa |
| Answer» | |
| 3833. |
If a number is divided by 5 then write all the possible remainders |
| Answer» 0, 1,2,3,4 | |
| 3834. |
CH 10 |
| Answer» | |
| 3835. |
Ex 13.3 |
| Answer» | |
| 3836. |
Geometrically find out the value of cos 30 and cot 60 |
| Answer» Cos30=root3/2 , cot60=1/root3 | |
| 3837. |
2sin^2A-cos^2A=2 . Then find A |
| Answer» | |
| 3838. |
Modal papra |
| Answer» | |
| 3839. |
Prove that angle between alternate chorder areally equal |
| Answer» | |
| 3840. |
At which point a tangent is perpendicular to the radius? |
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Answer» Oooo At any point of contact. |
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| 3841. |
How to score 70 marks out of 80 in class 10 math which book should I follow |
| Answer» Ncert +rd sharma+reliable | |
| 3842. |
IF sec alpha =5/4 then evaluate tan alpha /(1+tan square alpha |
| Answer» We have,{tex} \\sec \\alpha = \\frac { \\text { Hypotenuse } } { \\text { Base } } = \\frac { 5 } { 4 }{/tex}So,Let us draw a right triangle ABC, {tex}\\angle B=90^\\circ{/tex}\xa0such thathypotenuse = AC = 5 units, Base = AB = 4 units, and{tex}\\angle B A C{/tex}= {tex}\\alpha{/tex}.Applying Pythagoras theorem in\xa0{tex}\\Delta{/tex}ABC, we get{tex}A C ^ { 2 } = A B ^ { 2 } + B C ^ { 2 }{/tex}{tex}\\Rightarrow \\quad 5 ^ { 2 } = 4 ^ { 2 } + B C ^ { 2 }{/tex}{tex}\\Rightarrow \\quad B C ^ { 2 } = 5 ^ { 2 } - 4 ^ { 2 } = 9{/tex}{tex}\\Rightarrow \\quad B C = \\sqrt { 9 } = 3{/tex}{tex}\\therefore \\quad \\tan \\alpha = \\frac { B C } { A B } = \\frac { 3 } { 4 }{/tex}Now, we have,\xa0{tex}\\frac { 1 - \\tan \\alpha } { 1 + \\tan \\alpha } = \\frac { 1 - \\frac { 3 } { 4 } } { 1 + \\frac { 3 } { 4 } } = \\frac { \\frac { 1 } { 4 } } { \\frac { 7 } { 4 } } = \\frac { 1 } { 7 }{/tex}therefore,\xa0{tex}\\frac{1-\\tan\\alpha}{1+\\tan\\alpha}=\\frac17{/tex} | |
| 3843. |
Will today the board datesheet will be released? |
| Answer» | |
| 3844. |
What is the area of parallelogram? |
| Answer» | |
| 3845. |
Anyone knows when will date sheet comes |
| Answer» I think 5 march | |
| 3846. |
marking shecme not avilabe for all chapter |
| Answer» | |
| 3847. |
Find the value of x in this equation "4x +6 = 59". |
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Answer» 53/4 13.25 |
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| 3848. |
Kis kisko maths accha lagta hai..... |
| Answer» | |
| 3849. |
Meri chats kaha gayab ho gyi |
| Answer» | |
| 3850. |
How to take l.c.m |
| Answer» Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3s, and 21 has one 7, so we multiply 3 two times, and 7 once. This gives us 63, the smallest number that can be divided evenly by 3, 9, and 21. | |