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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 39101. |
Find the value of theta if 2 Sin 2 theta equal to root 3 |
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Answer» 2sin 2theta=√3 sin 2theta=√3/2 sin 60° 2theta=60° theta=60°/2=30°ans Theta=60 Sin 60 |
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| 39102. |
For which value of k will the following pair of linear equations have no solution? |
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| 39103. |
Kisi circle ka cumfrance 8PAI hai to area |
| Answer» {tex}\\text {Circumferece of circle = 8}\\pi{/tex}{tex}\\text {Also, circumference of circle = 2} \\pi \\text {r}{/tex}{tex}\\therefore 2\\pi r=8\\pi{/tex}{tex}\\Rightarrow r=4{/tex}{tex}\\text {Area of circle = }\\pi r^2{/tex}{tex}\\Rightarrow \\text {Area of circle =} \\pi (4)^2=16\\pi \\text { sq.units}{/tex} | |
| 39104. |
Sir please give me this year class 10th syllabus 2018-19 |
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| 39105. |
x+3y=10 -2x+5y=13 |
| Answer» The value of x=1 y=3 | |
| 39106. |
2x+8x=12 by elimination method |
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Answer» Where is another one Where is second equation It is only one equation |
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| 39107. |
2x 3y=5 |
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| 39108. |
How to learn trignometric identities |
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| 39109. |
Mean by |
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| 39110. |
Find the roots of the equaxtion x-1/x=1 by factorisation |
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| 39111. |
Dfvc |
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| 39112. |
{4x-3}\\{2x+1} -10 {2x+1}\\{4x-3} =3 |
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| 39113. |
example 8.4 5th sum |
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| 39114. |
What is cos67 - sin 23 ans |
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Answer» cos67-sin23cos67 - cos(90 - 23) = cos67 - cos67= 0 Thanks |
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| 39115. |
What is the prime factor of 146 |
| Answer» 146 is a composite number. Factor pairs: 146 = 1 x 146 or 2 x 73. Factors of 146: 1, 2, 73. Prime factorization: 146 = 2 x 73. | |
| 39116. |
How to solve completing method |
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Answer» Step 4 : now for the value of x Step3: add (1/2×coefficient of x) to both RHS and LHS Step1: arrange them in their standard form Step2: coefficient of x² should be 1(if any other then divide by its coefficient to all term s of equation |
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| 39117. |
Find the smallest number which when increase by 17 excatly divisible by both 520 and 468 |
| Answer» The smallest number divisible by 520 and 468 = LCM(520,468)Prime factors of 520 and 468 are :520 = 23{tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa013468 = 2 {tex}\\times{/tex}\xa02 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa013Hence LCM(520,468) = 23{tex}\\times{/tex}\xa032 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa013 = 8\xa0{tex}\\times{/tex}\xa09{tex}\\times{/tex}5{tex}\\times{/tex}13 = 4680Now the smallest number which when increased by 17 is exactly divisible by both 520 and 468.=LCM(520,468)-17=4680-17=4663 | |
| 39118. |
Ad |
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| 39119. |
Prove that (Sin x+***) ^2+(cos x+cosec X) ^2 =(1+sec) xcosecx |
| Answer» LHS =(sin A + sec A)2 + (cos A + cosec A)2{tex}= \\left( \\sin A + \\frac { 1 } { \\cos A } \\right) ^ { 2 } + \\left( \\cos A + \\frac { 1 } { \\sin A } \\right) ^ { 2 }{/tex}{tex}= \\sin ^ { 2 } A + \\frac { 1 } { \\cos ^ { 2 } A } + 2 \\frac { \\sin A } { \\cos A } + \\cos ^ { 2 } A{/tex}{tex}+ \\frac { 1 } { \\sin ^ { 2 } A } + 2 \\frac { \\cos A } { \\sin A }{/tex}= {tex}sin^2A+cos^2A{/tex} +\xa0{tex}\\frac { 1 } { \\sin ^ { 2 } A } + \\frac { 1 } { \\cos ^ { 2 } A }{/tex}{tex}+ 2 \\left( \\frac { \\sin A } { \\cos A } + \\frac { \\cos A } { \\sin A } \\right){/tex}= 1 +\xa0{tex}\\frac { \\sin ^ { 2 } A + \\cos ^ { 2 } A } { \\sin ^ { 2 } A \\cos ^ { 2 } A } + 2 \\left( \\frac { \\sin ^ { 2 } A + \\cos ^ { 2 } A } { \\sin A \\cos A } \\right){/tex}= 1 +\xa0{tex}\\frac { 1 } { \\sin ^ { 2 } A \\cos ^ { 2 } A } + \\frac { 2 } { \\sin A \\cos A }{/tex}=\xa0{tex}\\left( 1 + \\frac { 1 } { \\sin A \\cos A } \\right) ^ { 2 }{/tex}= {tex}(1+secAcosecA)^2{/tex}=RHS | |
| 39120. |
Ghhydga |
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| 39121. |
Find the product zero of the polynomial p(x)=ax^3+bx^2+cx+d |
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| 39122. |
Ncert. Solution of. All chapter answer key |
| Answer» Check NCERT solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 39123. |
solution of rs agarwal ch-1to ch-3 |
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| 39124. |
Find the zeros of the polynomial x square minus root 2 x minus 12 |
| Answer» 3 root 2 and minus 2 root 2 | |
| 39125. |
What is a Ecluid division lemma |
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Answer» a = bq + r It is a proven statement given by Euclid a=bq+r 0 |
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| 39126. |
Exercise 4.1 question no 2(3,4) with explain |
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| 39127. |
Smallest unit |
| Answer» 0 | |
| 39128. |
The comman differance of an AP in which a18 -a32 ?? |
| Answer» I think question is wrong | |
| 39129. |
Cross multipicatioon |
| Answer» Cross multiplication is a method for solving pair of linear equation in two variable.Formula is :-X/(b1c2-c1b2)=y/(c1a2-a1c2)=1(a1b2-b1a2) | |
| 39130. |
Chapter 5 exercise 5.2 ka 20th question |
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| 39131. |
Sina+sin2a |
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Answer» SinA + sin2A=Sin3A Or SinA + (sinA)^2Then,=sinA(1+sinA) Check the question carefully I think the question is wrong....check the question and repost it |
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| 39132. |
Find Two small HCF numbers of two equilateral triangles |
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| 39133. |
7x square +3x -4 =0 |
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Answer» Sorry x= -1 X=1 and x=4/7 7x^2+3x-4=07x^2+7x-4x-4=07x(x+1)-4(x+1)=0(7x-4)(x+1)=0x=4/7 nd x =-1 |
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| 39134. |
Can we have any n\xa0E\xa0N, where 7n\xa0end with the digit zero\xa0 |
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| 39135. |
Find the value of x for which x² +(k-1) x + k² - 16 is exactly divisible by x-3 |
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| 39136. |
x squre + 1/x square +x-1/x-4=0 |
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| 39137. |
Ex 2.4 question no 4 |
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| 39138. |
In Euclids division Lenna a=bq+r where a greater than r,\'b is greter than r |
| Answer» Both a and B are greater than r | |
| 39139. |
Its true that CBSE declare that board exam will head in feb |
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Answer» I think it will be from feb ending I don\'t think so It\'s true? |
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| 39140. |
For which values of p does the pair of equation given below has unique solution 4x+pu+8=0 2x+2y+2=0 |
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Answer» I think we doesn\'t get unique solution The pair of equations has unique solution only when the value of P is 8 |
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| 39141. |
Find median45,67,12,34,98,7,88,66,88, |
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Answer» 66 66 |
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| 39142. |
0\\0+2(90) |
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Answer» The number is infinite Infanite |
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| 39143. |
Compartment exam sample papers |
| Answer» Check sample papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 39144. |
Q 4 |
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| 39145. |
sin60+cos60×sin30 |
| Answer» Sin60+cos60×sin30.=Sin60=√3/2 Cos60=1/2 Sin30=1/2.So, √3/2+1/2×1/2 =√3/2+1/4 =(2√3+1)/4.ans. | |
| 39146. |
The values of k for which the quadratic equation x2-2kx+5k=0 has equal roots,are |
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| 39147. |
Sum of arithmetic progression find d=? |
| Answer» you have not written question properly so this is my answer to you | |
| 39148. |
What is pusay |
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| 39149. |
Re agrawal questions |
| Answer» Aapko konse ques chahiye?? | |
| 39150. |
(2-^3) |
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