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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3901. |
Find the 11 term of the last term of the AP 27, 23, 19,.......- 65, |
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Answer» उत्तर है 67 IT IS IN NCERT. |
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| 3902. |
Prove that tan2a-tan2b=sin2a-sin2b÷cos2a cos2b |
| Answer» ki rs7sj | |
| 3903. |
A circle touches all four sides of a quadrilateral ABCD, whose sides are AB=4,BC=7and CD=4.find AD |
| Answer» | |
| 3904. |
Plzz anyone give me datesheet for class 10 board exam |
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Answer» Or u may check on cbse.nic.com 6 march: hindi 8 March :fit12 March; English 16 march:science22 March :sst 28 March; maths m- march 6m- Hindi 8m - FIT, 12m- English, 16m- science 22m- SST and 28m- math I will provide just in 5 min |
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| 3905. |
A.p ex 9.6 |
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| 3906. |
The first term of an ap if Sn=n2+2n is |
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Answer» If we put n=1then we got sn=4 4 |
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| 3907. |
1/secA+1/tanA+1/cosA=1/cosA-1/secA-1/tanA |
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| 3908. |
Disha and mun r u here ?? |
| Answer» Hii pragya | |
| 3909. |
Atooijvjpkbvbm9 |
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Answer» meansss????? What |
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| 3910. |
Jjgionuomhyggouuo0k |
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Answer» ye kon si language h Means??? |
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| 3911. |
llma kha rhta ho delhi m |
| Answer» in okhla | |
| 3912. |
Jo girls brianly aap pr apni id batao |
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Answer» Tujhko kya karna hai be sale Sakshiagarwal1 me nhi hu Mr.rishab Bata du...??? |
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| 3913. |
Plzzzz send all formula together |
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| 3914. |
llma apna number toh do |
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Answer» aap mujhe apna no. De rha h Number dena privacy me khilaf hai. So is app par aesi sharing nahi honi chahiye kuch bhi Mr.yash Ilma ka number Q duuuu 7654908765 |
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| 3915. |
I leave this aap.koi peronalyy chat to. krta nhi yrrr , guch much krte hhhh.....boringggh |
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Answer» Mne who r u piucha h nt how r u. Good u Hlo.who r u Hii jatin Hmmmm to aapko prsnly chat krni h hehehehe Hmmm ohhhh A |
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| 3916. |
Board exam ki datesheet aa gayi hai |
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Answer» Uth gye kyaaa nind se pta lag kya deetsheet aa gyi sukarr hhhh aab pdh lo monikaaa Haa.... Yes aa gayi Ok sorry Yes Aap so rhe ho |
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| 3917. |
Which term of the AP 121,117,113...is it\'s negative term |
| Answer» Here the given AP is :\xa0121,117,113........a=121 and d=117-121 = -4The general term of an AP is given byan\xa0= a+(n-1)dLet nth term is negative{tex}\\Rightarrow{/tex}\xa0a+(n-1)d<0{tex}\\Rightarrow{/tex}\xa0121+(n-1)(-4)<0{tex} \\Rightarrow {/tex}\xa0121-4n+4<0{tex} \\Rightarrow {/tex}\xa0-4n+125 < 0{tex} \\Rightarrow {/tex}\xa0-4n< -125Hence, 4n>125{tex} \\Rightarrow {/tex}\xa0n >{tex}\\frac{{125}}{4}{/tex}So, n > 31.25Hence, the 32nd term is first negative term. | |
| 3918. |
Cubiod has a side 3 at the rate of 2m/sec is |
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| 3919. |
Can y+1 be the remainder on divison of a polynomial p(y) by y-5? Give reason for your ans also |
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| 3920. |
Derive the volume of frustum? |
| Answer» 1/3 pi h (r1^2+r2^2+r1r2) | |
| 3921. |
Find thita when 2cos3thita =1 |
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| 3922. |
what is construction of tangent to a circle. |
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| 3923. |
Can anyone tell final exam datesheet |
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Answer» 06-03-2018~Hindi08-03-2018~Foundation I T12-03-2018~English 16-03-2018~Science 22-03-2018~S. St28-03-2018~Maths02-04-2018~Sanskrit News and updates option me dekh Your city and school name |
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| 3924. |
Application of trigonometry |
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Answer» You see in ncert book of maths Hiii renuka |
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| 3925. |
Gdh |
| Answer» Hiii | |
| 3926. |
Do all the questions appear in the board exams are from T.B? |
| Answer» What is T.B | |
| 3927. |
Calculate the no 1 to 100? |
| Answer» 5500 | |
| 3928. |
If sin + 2cos =1 |
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| 3929. |
Why there is only one holiday before ss paper? |
| Answer» haa..yr..it.is.a...big.problem | |
| 3930. |
Show That one and only one out of n,n+3,n+ 6or n+9is divisible by 4where n is any integer. |
| Answer» Refer Monica Capoor\'s book | |
| 3931. |
Find the distance between the points (acos45°,0) and (0, acos45°) |
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Answer» 0.5 unit 555 |
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| 3932. |
All formula of surface area and volume |
| Answer» Refer Monica Capoor\'s book | |
| 3933. |
Hlo guys... |
| Answer» Hallooooooo | |
| 3934. |
Sample paper \'s 5th and 6th question |
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Answer» Subject? ?? Of which subject?? |
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| 3935. |
Evaluate:-Sin18°÷cos72° |
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Answer» 1 1 1 1 1 |
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| 3936. |
Kisi me mujhe yaad kiya kya...??????? |
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Answer» ??? ?? Hello what\'s ur real name...??? me ne* |
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| 3937. |
When did anual exam start |
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Answer» 6 March Board k |
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| 3938. |
Prove(Cos a\\1+sin a)+(1+sin a\\cos a) = 2 sec a |
| Answer» LHS{tex}=\\frac{\\cos A}{1+\\sin A}+\\frac{1+\\sin A}{\\cos A}{/tex}{tex}=\\frac{\\cos ^{2} A+(1+\\sin A)^{2}}{(1+\\sin A) \\cos A}{/tex}{tex}=\\frac{\\cos ^{2} A+\\sin ^{2} A+1+2 \\sin A}{(1+\\sin A) \\cos A}{/tex}{tex}=\\frac{2(1+\\sin A)}{(1+\\sin A) \\cos A}{/tex}{tex}=\\frac{2}{\\cos A}{/tex}\xa0= 2 sec A RHS | |
| 3939. |
How we find roots of quadratic equation |
| Answer» By some methods -1)Factorisation method2)Completing square method 3)Quadratic formula | |
| 3940. |
Hiii koi friend hai online ????????????????? |
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Answer» Abbreviated form of ur name Hii naren Yeah ....? I mean ur school & all From where u r Hii Yes i am. |
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| 3941. |
Ans of questions paper |
| Answer» Of which subject? | |
| 3942. |
1add2 |
| Answer» | |
| 3943. |
If hcf of 65 and 117 is x , will expressible in the form (65m-117),then find value of m |
| Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117{/tex}{tex}13=65m-117{/tex}{tex}65m=130{/tex}m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2\xa0 | |
| 3944. |
Solve for x if x/a+y/b=2 and ax-by=a^2-b^2 |
| Answer» {tex}\\frac { x } { a } + \\frac { y } { b } = 2{/tex}{tex}\\frac { b x + a y } { a b } = 2{/tex}{tex}bx + ay = 2ab{/tex}........(i){tex}ax - by = (a^2\xa0- b^2){/tex}...(ii)Multiplying (i) by b and (ii) by a{tex}b^2x + bay = 2ab^2{/tex}.............(iii){tex}a^2x - bay = a(a^2\xa0- b^2){/tex}........(iv)Adding (iii) and (iv),we get{tex}b^2x + a^2x =\xa02ab^2\xa0+ a^3\xa0- ab^2{/tex}{tex}x(b^2\xa0+ a^2) = 2ab^2\xa0+ a^3\xa0- ab^2{/tex}{tex}x(b^2\xa0+ a^2)\xa0=\xa0ab^2\xa0+ a^3{/tex}{tex}x(b^2\xa0+ a^2)\xa0=a(b^2\xa0+ a^2){/tex}{tex}x = \\frac { a \\left( b ^ { 2 } + a ^ { 2 } \\right) } { \\left( b ^ { 2 } + a ^ { 2 } \\right) } = a{/tex}Putting x = a in (i),we get{tex}b \\times a + a y = 2 a b{/tex}{tex}a y = 2 a b - a b \\Rightarrow a y = a b{/tex}\xa0or y = b{tex}\\therefore{/tex}\xa0solution is x = a, y = b | |
| 3945. |
Cos A =2/5 find value of 4 +4 tan^ A |
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| 3946. |
What is disabled |
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| 3947. |
tuuuhryhf4 |
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| 3948. |
Anyone still awake?? |
| Answer» | |
| 3949. |
Whatsapp users come here |
| Answer» | |
| 3950. |
I man traver 100 km 1 dad |
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Answer» Rub nahi run Rub 1dad inspire you to travel more than 100 km of that man |
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