InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 39851. |
Find the compound interest of principal 2000 annum 2 rate 5% |
| Answer» 205 | |
| 39852. |
can we write a sin theta equal to cos theta upon cot theta? |
|
Answer» Sin theta -1by cosec theta.. No nahi likh sakte No |
|
| 39853. |
3 + 2 under root 5 is an irrational number |
|
Answer» Yez Yes |
|
| 39854. |
Find the distance of (-4,3) from y axis. |
| Answer» The point on the y-axis is (-4,3){tex}\\therefore {/tex}Distance between (-4,3) and (0,3)d =\xa0{tex}\\sqrt { ( 0 + 4 ) ^ { 2 } + ( 3 - 3 ) ^ { 2 } }{/tex}=\xa0{tex}\\sqrt { 16 + 0 }{/tex}= 4\xa0units | |
| 39855. |
Half yearly hai |
| Answer» Kab hai | |
| 39856. |
He gyes tomarrow my maths paper , mujhe important questios ho to bata dena |
|
Answer» What\'s the portion, my exams are over i will help you. What is your portion I\'ll give u a hint Everything is important. |
|
| 39857. |
If sum and product of zeroes of quadratic polynomial are 8and 12 .find their zeroes |
| Answer» Given that sum and product are8and12Therefore required polynomial is X^2-8x+12Now factorise it you will get x=2,x=6 | |
| 39858. |
If we have to show that it is an AP or not what we have write of difference a2-a1 or t2-t1 |
| Answer» a2--a1 | |
| 39859. |
7 sin square theta + 3 cos square theta |
| Answer» | |
| 39860. |
Arithamatic progression important questions |
| Answer» Practice all questions from ncert book | |
| 39861. |
Which term of AP 3,15,27,39.........will be 120 more than it 21st term |
| Answer» 19 | |
| 39862. |
He bro mera maths paper kal hai .now i am learning important formula\'s. |
|
Answer» Best of luck bhai ? Best of luck |
|
| 39863. |
The product of two numbers is1068 . The first number is 248 . Find second number |
|
Answer» X x Y =1068248 x Y = 1068Y=4.30645161 1068/248= 4.3064 |
|
| 39864. |
What is intergeralisation |
| Answer» | |
| 39865. |
If cos (A +B)=_1 |
| Answer» | |
| 39866. |
692=an(+2= |
| Answer» | |
| 39867. |
If p,q are two consecutive natural number .find HCF of p &q |
| Answer» HCF is 1 | |
| 39868. |
Pythagoras theorem statement or PT ka converse |
| Answer» In a right-angled triangle, “The sum of squares of the lengths of the two sides is equal to the square of the length of the hypotenuse (or the longest side).” | |
| 39869. |
Does the optional exercise questions also can be ask ? |
|
Answer» Only asked in PT Not at all sometime Yes Yes |
|
| 39870. |
If tan (3x + 30degree) =1, then find the value of x. I know but confuse |
|
Answer» Tan (3x + 30°) = 1 The value of tan is 1 when theta is 45 which meansTan45° = 1ThereforeTan (3x + 30°) = Tan45°3x + 30 = 453x = 45-303x = 15x = 15/3x = 5 X=5 |
|
| 39871. |
The 10th and 18th term of AP are 41&73 respiculty find 26th term |
|
Answer» a10 = 41, a18 =73 and a26 =?a10= a + 9d = 41-------(1)a18= a + 17d=73-------(2) (-). (+). (-) ----------------------- -8d = -32 d=4Put d=4 in eqn.(1)a+9d=41 a+9(4)=41 a+36=41 a=5Therefore, a26= a+25d = 5+25(4) = 5+100 a26= 105 a26=105 10th term of AP is 41= a+9d=41---(1)18th term of AP is 73=a+17d=73----(2)Solve (1)&(2);a+9d=41 a+17d=73 ------------------ -8d=-32d=4,substitute d= 4in (1)a+9(4)=41a=5So a26=a+25d =5+100=105 |
|
| 39872. |
Do anyone of you have board question paper of maths of last 5 years?? |
|
Answer» Why Ya Me too Yes Yes I have |
|
| 39873. |
3x_y+4 |
| Answer» | |
| 39874. |
Find a and b if the following have Infinite number solution 2x-3=y, ax+3y=b. |
| Answer» a = -2b = -1 | |
| 39875. |
5-500009 |
|
Answer» -500004 500004 -500004 |
|
| 39876. |
Formula of circle |
| Answer» A=πr2r\tRadius | |
| 39877. |
x-2x-8 |
|
Answer» Middle term split nahi hoga agar x square hua toh easy toh h middle term split kr de??? |
|
| 39878. |
if ax*2 +bx+c=0 is double the other prove that 2ab*2= 9ac*2 |
| Answer» | |
| 39879. |
If the area of triangle is100m represent this in the form of equation |
| Answer» 1/2 x*y=100 | |
| 39880. |
A circular pond of diameter 40m is surrounded by a grass path 5m wide. Find the area of this path. |
|
Answer» Sorry I thought that 40m is radius.R=20 and r= 25 Given :diameter of the circular pond is 40mtherefore the radius =40/2=20mthe width of the grass path=5mtherefore the radius of the outer circle =25mArea of the pond={tex}\\frac{22}7\\times20\\times20{/tex} =1256m2Area of the outer circle={tex}\\frac{22}7\\times25\\times25{/tex} =1964.28m2Area of the grass path =Area of the outer circle -Area of the pond =1964.28-1256 =708.28m2 Area of Path=π(R²-r²), where R= 40+5=45 and r=40 |
|
| 39881. |
4×3 |
|
Answer» 12 ?? 4 × 3 = 12 12 12 |
|
| 39882. |
If Cos (A+B) =0 .than what is the value of sin (A+B). |
|
Answer» 0 0 |
|
| 39883. |
_5(+6)_5(+9)+56 |
|
Answer» - 30 - 45 + 56. = - 75 + 56. =. -19 _19 |
|
| 39884. |
What is difference between transitive and asymmetric representation of sets? |
| Answer» | |
| 39885. |
If the point p(x,y)is equidistant from the point a(1,5) and b(5,1)then prove that x=y |
| Answer» Given , point P(x,y) is equidistant from points L(5,1) = (x1, y1) and M(-1,5)= (x2, y2).So, PL = PM{tex}\\Rightarrow PL^2=PM^2{/tex} [On squaring both sides]{tex}\\Rightarrow\\left(\\sqrt{{(x_\\;\\;-x_1)}^2+\\;(y\\;-y_1)^2}\\right)^2\\;=\\;\\left(\\sqrt{{(x\\;-x_2)}^2+\\;(y\\;\\;-y_2)^2}\\right)^2{/tex}{tex}\\Rightarrow (x-5)^2+(y-1)^2=(x+1)^2+(y-5)^2{/tex} [Using distance formula]⇒ x2 - 10x + 25 + y2 - 2y + 1 = x2 + 2x + 1 + y2 - 10y + 25⇒ - 10x - 2y + 26 = 2x - 10y + 26⇒ -10x - 2x = - 10y + 2y⇒ - 12 x = - 8y{tex}\\Rightarrow 3x=2y{/tex} | |
| 39886. |
Cosecx - cotx=1/4 then find the value of cosecx +cotx |
| Answer» | |
| 39887. |
Bracket Y minus 20 degree and Y + 30 degree |
| Answer» Y2 + 30y -20y -600 | |
| 39888. |
(y-20) degree and () |
| Answer» | |
| 39889. |
1/a+b+x=1/a+1/b+1/c |
| Answer» Given,{tex}\\frac { 1 } { ( a + b + x ) } = \\frac { 1 } { a } + \\frac { 1 } { b } + \\frac { 1 } { x }{/tex}{tex}\\Rightarrow \\quad \\frac { 1 } { ( a + b + x ) } - \\frac { 1 } { x } = \\frac { 1 } { a } + \\frac { 1 } { b } \\Rightarrow \\frac { x - ( a + b + x ) } { x ( a + b + x ) } = \\frac { b + a } { a b }{/tex}{tex}\\Rightarrow \\quad \\frac { - ( a + b ) } { x ( a + b + x ) } = \\frac { ( a + b ) } { a b }{/tex}On dividing both sides by (a+b){tex}\\Rightarrow \\quad \\frac { - 1 } { x ( a + b + x ) } = \\frac { 1 } { a b }{/tex}Now cross multiply{tex}\\Rightarrow{/tex}\xa0x(a + b + x) = -ab\xa0{tex}\\Rightarrow{/tex}\xa0x2 + ax + bx + ab = 0{tex}\\Rightarrow{/tex}\xa0x(x +a) + b(x +a) = 0{tex}\\Rightarrow{/tex}\xa0(x\xa0+ a) (x + b) = 0{tex}\\Rightarrow{/tex}\xa0x + a = 0 or x + b = 0{tex}\\Rightarrow{/tex}\xa0x = -a or x = -b.Therefore, -a and -b\xa0are the roots of the equation. | |
| 39890. |
Completing 4x+3x+2. 4xsquare hai |
| Answer» | |
| 39891. |
Find the roots of the eqution 1/x+4 -1/x-7=11/30,xnot equal to -4,7 |
| Answer» Roots are 2 and 1 | |
| 39892. |
What COLLARYin triangles |
|
Answer» colloary means that a given statement is proved Corollary means the final result or "परिणाम" |
|
| 39893. |
Ax +bx+c=0. Find the quadratic equation |
|
Answer» Wrong question Lanear equation |
|
| 39894. |
Who invent zero(0) |
|
Answer» Maina nahi kiya . Arrayabhat Aryabhat invented zero Arrayabhatt |
|
| 39895. |
Why maths in hindi mai kyu nhi h ab hum kaha sai padae kare |
| Answer» English me bhi ki ja sakti h .main bhi hindi medium me hi hu juber khan ?? | |
| 39896. |
Find the value of p for which the linear pair has infinite solution : 12x+14y=0; 36x+py=0. |
|
Answer» Why did you say sorry divya... sorry p=42 when it have no solution(parralel) p have no value if you take infinitive many solution if you take one soluton then p=42 |
|
| 39897. |
1+cotA÷secA =sinA×sinA÷1-cosAProve the above equation |
| Answer» | |
| 39898. |
-3x4-7x+5 ÷ x2+5 |
| Answer» | |
| 39899. |
If sinA =3/4 ,then calculate the value of cosA and tanA |
|
Answer» Here tan A =3 and cosA =4 COt 7 t an 7 |
|
| 39900. |
show that cube of any positive integer is of the form 4m,4m+1 or 4m+8,for some integer m. |
| Answer» a=bq×rA=4q×r (where q is any poistive no.) 0<=r>4r=0,1,2,3Put r in a=bq+r(4q+0)cube=64q^3=4(16q^3)=4m(m=16q^3)(4q+1)cubeDo like (4q+0)cube | |