InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40051. |
In whixh schhol do you study ....." yogita ingle " ?? |
|
Answer» Jai bharti school EMERALD CONVENT SCHOOL |
|
| 40052. |
Frsd i am students of class 10 how to improve in math plz tell me |
|
Answer» Hi. U solve many and many question in one day . Practise with ncert and examples . Ncert only gave u 70 marks . You take ques. In another Solve only 20 questions daily from maths book u will see ur improvement , its my experience Hi, you can improve in maths by solving more and more questions. U should know all the theorems with their proofs . U should solve all ncert questions and exampler . Even u can take help of ur teacher if u have any doubt. U can even prefer any extra or side book.? I hope it will help u some how. Me same |
|
| 40053. |
>give any two real life examples for congruent shapes |
|
Answer» Our leg and textbook Our hand and text books |
|
| 40054. |
If p is a prime no.,then prove that √p is a irrational no. |
| Answer» Let us assume that rootp is irrational number Therefore rootp =a/ba=b×rootp a is rational number Therefore b×rootp is also rational number But rootp is irrational number Therefore rootp is also irrational number | |
| 40055. |
If rlfkdjck |
|
Answer» Are u a mental What |
|
| 40056. |
Prove that the square of any positive no is of form 5q, 5q +1, 5q +4, for some integar q |
| Answer» This is ncert maths ques.exercise 1.1ques 4 | |
| 40057. |
Sold goods costing amount 12000 to Thakur and co.,issued at 20% above cost less 10%discount |
| Answer» | |
| 40058. |
What passing marks board in2019out of 80 |
|
Answer» 35 Cbse pattern ht chuka h ab scl se kuch mark nhi milega 33% of 80....and one has to get passing marks individually in theory as well as in the 20 marks which we get from our schhol... 33 |
|
| 40059. |
3+ root 5 is irration number |
|
Answer» Yes bro ?? it is proved in the book? Yes because sum of rational and irrational is always irrational. Yes,it is |
|
| 40060. |
Is there anyone who can solve example no.7 of chapter 6 in maths? I did not get it |
|
Answer» Then solve Yes |
|
| 40061. |
The optional exercises are in syllabus 2018 to 2019 |
| Answer» You can check the syllabus :\xa0https://mycbseguide.com/cbse-syllabus.html | |
| 40062. |
Tan thita = 1/√3 then find out the value of 1/1+sin quee thita |
| Answer» Tan ©=1/√3=>©=30°now,1/1+sin^3©=1/1+(1/2)^3=1/1+(1/8)=1/(8+1)/8=1/9/8=8/9 | |
| 40063. |
Find the largest number which devides 615 and 963 leaving remainder 6 in each case. |
|
Answer» I got 70 percent I am in class 11 |
|
| 40064. |
Imp question x class math trignometry |
| Answer» IMP stands for Inhe Mat Padho | |
| 40065. |
Imp question in ch 3 in help book |
| Answer» | |
| 40066. |
The cost of 40 metres of cloth is Rs 200. Find the cost of 50 meters of cloth. NCERT. |
|
Answer» Aanchal equal to should be their (200÷40)×50(5)×50250 250m 250 250m It\'s correct bròooooooooooooo (200÷40)×50=250 |
|
| 40067. |
Find the 9th term from the end of the A.P. 5,9,13,..........185. |
|
Answer» 37 37 37 |
|
| 40068. |
2x-3y=4 and y-4=0 |
|
Answer» y-4=0 then y=4 to the question 2x-3y=4 then 4 value is putup on question 2x=4+3×42x=16 then x= 16/2=8 Ans Oh soory its not 4 its 2 by mistake i wrote it 4 so x=8 Y-4=0Y=4Putting y=4in eqn.i2x-3*4=42x-12=42x=4+12X=16/4=4 |
|
| 40069. |
Ittt7reedgui |
| Answer» | |
| 40070. |
Show that point (6and1) (8and 2) (9and 4) (7and 3) are the vertices of parallelogram |
| Answer» According to the property of llgm its opposti sides r equal ...Whi laga do solve ho jayega | |
| 40071. |
Find the of k for which x=1is a root of the equation xsquar+ kx+3=0 Also find other Root |
| Answer» Xsq +kx +3=0Putting the value of x=11+k×1+3=01+1+k+3=04+1+k=0K=-5 | |
| 40072. |
Isme jitna bhi samplw3sample papers hai kya ye sb 2018-19 batch ke liye hai |
| Answer» | |
| 40073. |
Find the sum of all 2 digit odd positive no. |
| Answer» 99/2(2×11+98×2) | |
| 40074. |
Example 14 of ncert class 10 |
|
Answer» Nishant my same qes Yes Chapter no. Bolo na Chapter no |
|
| 40075. |
Someone has maths exam idea please tell me promo code please please |
| Answer» | |
| 40076. |
When datesheet will release |
| Answer» | |
| 40077. |
TSA of hollow cylindar |
| Answer» 2 pie Rh+2pie rh+2pie(R square - r square) | |
| 40078. |
Converse of Pythagoras theorem |
| Answer» | |
| 40079. |
Find a cubic polynomial whose zeroes are 1/2,1,-3 |
| Answer» 2x^3+3x^2-8x+3 | |
| 40080. |
The angles of a quadilateral are in AP whose common difference is 10°. Find the angles |
|
Answer» Thank u yr 75,85,95,105 75,85,95,105By anglesum property |
|
| 40081. |
The length of the side in cm of an equilateral triangle inscribed in a circle of radius 8 cm is |
| Answer» 2*under root 35.60 | |
| 40082. |
In trigonometry who tho solve any equation like sin45+cos29 etc. Plz tell me.. Fastt |
|
Answer» Ask the question i can solve Plzz tell me I can solve |
|
| 40083. |
If midpoint of the line segment joining the points p( 6,b-2 ) and (-2,4) is (2,-3) find the value |
| Answer» According to questionPR = RQ or R is mid-point of PQUsing mid-point formula x\xa0{tex}= \\frac { x _ { 1 } + x _ { 2 } } { 2 }{/tex}\xa0and y\xa0{tex}= \\frac { y _ { 1 } + y _ { 2 } } { 2 }{/tex}{tex}\\frac { b - 2 + 4 } { 2 }{/tex}\xa0= - 3{tex}\\Rightarrow{/tex}\xa0b + 2 = - 6\xa0{tex}\\Rightarrow{/tex}\xa0b = - 8 | |
| 40084. |
Write the nature of the roots of quadratic equation 7x²-4x+³=0 |
| Answer» Root will be real nd distint | |
| 40085. |
Prove that (3+2{5}) is irrational |
| Answer» We will prove this by contradiction.Let us suppose that (3+2 {tex}\\sqrt { 5 }{/tex}) is rational.It means that we have co-prime integers a and b such that{tex}\\frac { a } { b } = 3 + 2 \\sqrt { 5 } \\quad \\frac { a } { b } - 3 = 2 \\sqrt { 5 }{/tex}{tex}\\Rightarrow \\frac{{a - 3b}}{b} = 2{\\sqrt 5 \\,{ \\Rightarrow }}\\frac{{a - 3b}}{{2b}} = \\sqrt 5 {/tex} ....(1)a and b are integers.It means L.H.S of (1) is rational but we know that {tex}\\sqrt { 5 }{/tex} is irrational. It is not possible. Therefore, our supposition is wrong. (3+2 {tex}\\sqrt { 5 }{/tex}) cannot be rational.Hence, (3+2 {tex}\\sqrt { 5 }{/tex}) is irrational. | |
| 40086. |
Find the value of K if the quadratic equation 3x^2-k√3x+4=0 has equal roots |
| Answer» Apply the formula D=bsquare -4ac 0=(-k root 3)square -4 (3)(4)0=3k square -48 48=3k square 48÷3=k square 16 = k square K=4,k=-4 [k will have 2 values because after doing under root we have 2 values] ..I hope it will help you .....☺ | |
| 40087. |
Prove that the ratio of the perimeter of two similar triangles is equal to the corresponding sides |
| Answer» Given\xa0{tex}\\triangle A B C{/tex}\xa0and\xa0{tex}\\triangle PQR{/tex}\xa0in Which BC= a, CA = b, AB = c and QR = p, RP = q, PQ = r.Also, {tex}\\triangle A B C \\sim \\triangle P Q R{/tex}To Prove\xa0{tex}\\frac { a } { p } = \\frac { b } { q } = \\frac { c } { r }{/tex}{tex}= \\frac { a + b + c } { p + q + r }{/tex}Proof Since\xa0{tex}\\triangle ABC{/tex}\xa0and\xa0{tex}\\triangle PQR{/tex}\xa0are similar, therefore their corresponding sides are proportional.{tex}\\therefore \\quad \\frac { a } { p } = \\frac { b } { q } = \\frac { c } { r } = k{/tex}\xa0(say) ...(i){tex}\\Rightarrow \\quad a = k p , b = k q{/tex}\xa0and\xa0{tex}c = k r{/tex}{tex}\\therefore \\quad \\frac { \\text { perimeter of } \\triangle A B C } { \\text { perimeter of } \\triangle P Q R }{/tex}{tex}= \\frac { a + b + c } { p + q + r }{/tex}{tex}= \\frac { k p + k q + k r } { p + q + r }{/tex}{tex}= \\frac { k ( p + q + r ) } { ( p + q + r ) } = k{/tex}\xa0...(ii)From (i) and (ii), we get{tex}\\frac { a } { p } = \\frac { b } { q } = \\frac { c } { r }{/tex}{tex}= \\frac { a + b + c } { p + q + r }{/tex}{tex}= \\frac { \\text { perimeter of } \\triangle A B C } { \\text { perimeter of } \\triangle P Q R }{/tex}\xa0[each equal to k]. | |
| 40088. |
sum of spheres |
| Answer» | |
| 40089. |
How i can learn all values of trigonometric ratios easily? |
|
Answer» I know a trick it is easy to do Sakshi By applying the trickkkkk Please write the triginometry ratio every time when doing sum |
|
| 40090. |
X²-(√2+1)x +√2=0 solve the equation by method of completing the square |
| Answer» | |
| 40091. |
Prove that Tan A÷1+sec A - tan A ÷1-sec A =2cosecA |
| Answer» LHS =\xa0{tex}\\frac{\\tan A}{\\sec A-1}+\\frac{\\tan A}{\\sec A+1}{/tex}{tex}=\\frac{\\tan A(\\sec A+1)+\\tan A(\\sec A-1)}{(\\sec A-1)(\\sec A+1)}{/tex}{tex}=\\frac{\\tan A \\cdot \\sec A+\\tan A+\\tan A \\sec A-\\tan A}{\\sec ^{2} A-1}{/tex}{tex}=\\frac{2 \\tan A \\sec A}{\\tan ^{2} A}{/tex}\xa0[{tex}\\because{/tex}\xa0{tex}(sec^2\\theta - 1) = tan^2\\theta\xa0{/tex}]{tex}=\\frac{2 \\sec A}{\\tan A}{/tex}{tex}=\\frac{2 \\frac{1}{\\cos A}}{\\frac{\\sin A}{\\cos A}}{/tex}{tex}=2 \\times \\frac{1}{\\cos A} \\times \\frac{\\cos A}{\\sin A}{/tex}{tex}=\\frac{2}{\\sin \\mathrm{A}}{/tex}{tex}= 2 cosec\\ A{/tex} = RHS | |
| 40092. |
What us square root of 3 |
|
Answer» 1.732 is square root of 3 Since the number 3 is not a perfect square hence the root for 3 isn\'t a whole numberIt is root (3) or approximately equal to 1.7302Hope it will help you. |
|
| 40093. |
It is given that the difference between the zeros of 4x^2-8kx+9 is 4 and k>0 then k = ? |
| Answer» Let, the two zeroes of the polynomial f(x) = 4x2 - 8kx - 9 be α and -α.Comparing f(x) = 4x2\xa0- 8kx - 9 with ax2+bx+c we geta = 4; b = -8k and c = -9.Sum of the zeroes = α + (-α) ={tex}-\\frac ba=\\;-\\frac{-8k}4 {/tex}0 = 2kk = 0 | |
| 40094. |
6a+3=9 |
|
Answer» 6a+3=96a=9-36a=6a=1 6a+3=96a=9-36a=6a=6÷6a=1 a=1 a=1 |
|
| 40095. |
a-3 |
| Answer» Means | |
| 40096. |
If the product of zeros of the polynomial ax sq. -5x-6 is 4 ,find the value of a |
| Answer» Here, Product of zeroes=4 c/a = 4 -6/a = 4 (c=-6) a = -6/4 a = -3/2 (Ans). | |
| 40097. |
What is euclid\'s division algorithm |
|
Answer» Again and again use of division lemma till the ans not come Again and again use of division lemma a=bq+r{where o<=r The euclid\'s division algorithm:-a=bq+r(where 0≤r |
|
| 40098. |
1+2+3+4+5+6+8+8+8+8+95+68+668-58 |
| Answer» 826 | |
| 40099. |
If 2cos thita=underroot3, find the value of 2cos thita+1/2cos thita-1 |
| Answer» Underroot3+1/Underroot3 -13+1-underroot3/underroot34-underroot3/underroot3 × underroot3 /underroot3 1/3 Answer | |
| 40100. |
If tan theta +1upon tan theta = 2 then find tan^2theta +1 upon tan^2 theta |
| Answer» 2 | |