InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40251. |
Area +volume of cone?? |
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Answer» CSA of cone =πrlTSA of cone=πr(r+l)Volume of cone =1/3πr²h Tere papa se puch |
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| 40252. |
If 2 secthita + 3 tan thita =7 then find the value of 2tan thita + 3sec thita |
| Answer» Hopefully 19/4 | |
| 40253. |
If sinthita ×cos thita =12/15 then sum of all possible values of tan thita |
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Answer» Confirm ye answer shi h 25/12 25/12(Anthe2018) |
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| 40254. |
Find the 11th term from the last term (towards the first term)of AP :10,7,4...,-62... |
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Answer» First we have to find the number of terms Firt term(a)=10Common difference(d)=(-3)An=a+(n-1)d-62=10 +(n-1)(-3)-62-10=3-3n-72-3=-3n75=3nn=25Now As we have to find the 11th term from the last therefore First term(a)=(-62)Common difference(d)=(3) Then A11=a+(n-1)d A11 = -62+ (25-1)(3) (n=25) A11= -62 + (24)(3) A11 = -62+72 A11=10 Dhh |
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| 40255. |
In angled ABC, right angled at B, if AB = 12 CM and BC =5 CM, find (1)sinA and tanA |
| Answer» SinA =5/13and tanA=5/12 | |
| 40256. |
What is mode..... |
| Answer» Most occurring number | |
| 40257. |
Sin2thota |
| Answer» | |
| 40258. |
If tanA + secA=p then find the value of cosecA |
| Answer» | |
| 40259. |
Sample question paper maths |
| Answer» Check sample papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 40260. |
Rd solutions |
| Answer» Get RD Sharma solutions with notes :\xa0https://mycbseguide.com/course/cbse-class-10-mathematics/1202/ | |
| 40261. |
123456789-2345789 |
| Answer» Hi Here is your answer 123456789-2345789= 121,111,000I hope its help you ...... | |
| 40262. |
what is secant?with diagram. |
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Answer» thnks Yashashvi Dobhal A line which intersects the circle at 2 different pts The area between the chord and the corresponding arc is called sector |
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| 40263. |
Radius perpendicular to rhe |
| Answer» | |
| 40264. |
Vhdnndgm |
| Answer» | |
| 40265. |
What are tangents |
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Answer» Tangents are the lines drawn from an external point to a circle Tangents are the line segments drawn perpendicular to radius of circle. They only meet at one point on the circle and that point is called the point of contact Tangents are lines touching the cirles externally at only one point |
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| 40266. |
Whatis progression |
| Answer» 2,4,6,8,10........it is a progression .OrWe can say progression is that sequence in which same rule follow in all the terms | |
| 40267. |
Prove 2is rational no. |
| Answer» Let , √2 be a rational number . Then it can be written in the form of a/b where b≠0 and ( a,b are co prime no.s) √2=a/b , now squaring on both sides.. 2= a²/b²... 2b²=a² .. it means a² is divisible by 2 . So a is also divisible by 2. .......... Let , a=2c , now squaring on both sides a²=4 c² putting value of a²... 2b²=4c² --> b²=2c² it means b² is divisible by 2 , so b is also divisible by 2 . Therefore our assumption is wrong . Hence, due to contradiction √2 is an irrational number as it has other common factor other than a and b . Hence, proved that √2 is an irrational number | |
| 40268. |
If ABC is a equilateral triangle AD perpendicular AB. Find ADsquare =3BD square |
| Answer» According to the question,\xa0{tex}\\triangle ABC {/tex}\xa0is an equilateral triangle.In {tex}\\triangle{/tex}ABD, using Pythagoras theorem,{tex}\\Rightarrow{/tex} AB2 = AD2 + BD2{tex}\\Rightarrow{/tex} BC2 = AD2 + BD2, (as AB = BC = CA){tex}\\Rightarrow{/tex} (2 BD)2 = AD2 + BD2, (perpendicular is the median in an equilateral triangle){tex}\\Rightarrow{/tex} 4BD2 - BD2 = AD2{tex}\\therefore{/tex}\xa03BD2 = AD2 | |
| 40269. |
About ex 5.4 |
| Answer» U can get the answers in mycbseguide app | |
| 40270. |
Math is the best |
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Answer» Yes you are right practise hamesa karni chahiye Yes maths is the best subject Agr concept clear hoga nd practice hmesa krte rhnge to sabse jldi banne wala nd sabse asaan subject h maths Kishne kha math best h math jab ati h to best h agar nhi ati to lagta h bakvas h |
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| 40271. |
What is Polynomial ?with example. |
| Answer» An expression which is in the form of a0x²+a2x²+.....+anx² is called polynomialWhere an a...an are real numberExample: 5x+7=0 7x+x²+9=0 | |
| 40272. |
In an AP of n terms if the last term is negative of the first term then the sum of n terms is?? ? |
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Answer» Please give the solution.. Ggdyh Options are.1.n/22.-n3 zero4.n |
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| 40273. |
If tan^4+tan^2=1 show that cos^4+cos^2=1 |
| Answer» | |
| 40274. |
The angle of depression of top & bottom of an |
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Answer» I don t know This ques is not complete |
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| 40275. |
4u squre +8u |
| Answer» 4u square + 8u =04u(u+2)=04u=0,u=0(u+2)=0u=-2.(0,-2) Ans.✔ | |
| 40276. |
Sorry Cos30°+sin30° |
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Answer» sorry √3/2 √3/3 √3/2 √3/2 |
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| 40277. |
Cos30°+Sin23°=? |
| Answer» 1.23 | |
| 40278. |
How to prepare full syllabus in 3months give me subject wise full advice |
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Answer» Built up ur concentraction power Very easy |
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| 40279. |
2:1 |
| Answer» | |
| 40280. |
A circle is inscribed in a square. What is the ratio of the areas of the circle and square |
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Answer» 11:7 or pie :2 Pata nahi??? |
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| 40281. |
2 cubes have there volume in the ratio 1:27 .find the ratio of surface area |
| Answer» 1:9 | |
| 40282. |
( a+b) |
| Answer» | |
| 40283. |
A no x divided by 11,13and17 gives 8,5and3as remainders respectively.find value of x.?? |
| Answer» | |
| 40284. |
There are 2shirts and 3 coats.How can you match them. |
| Answer» | |
| 40285. |
Rd sharma solutions of chapter polynomial |
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Answer» Hi Hyy |
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| 40286. |
Chapter 8 exercise 8.1 |
| Answer» | |
| 40287. |
If cos A=2/5 find the value of 4+4tan2a |
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Answer» 4/625 I dont know |
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| 40288. |
Are there any major changes in Board exams this year ? ? |
| Answer» I don\'t think so !!! | |
| 40289. |
500%80 |
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Answer» 400 500/100×80=400 400 |
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| 40290. |
√x+y=7X+√y=11 |
| Answer» | |
| 40291. |
A cod of a circle of radius 10cm subtant of right angle at the center then the length chord find |
| Answer» 10√2 | |
| 40292. |
SinA+cosA=√2cosA ,prove that cosA-sinA=√2sinA |
| Answer» SinA+cosA=√2cosASinA=√2cosA-cosASinA=(√2-1)cosASinA=(√2-1÷1×√2+1÷√2+1)×cosASinA=(2-1÷√2+1)×cosASinA=cosA÷√2+1(√2-1)×sinA=cosA√2sinA+sinA=cosA√2sinA=cosA-sinA | |
| 40293. |
Sin90° |
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Answer» Aby 1 hota hai re 1 1 1 |
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| 40294. |
How to solve identities easily |
| Answer» Comvert all terms into sin and cos | |
| 40295. |
want to understand completing square method in an easy way |
| Answer» Yea | |
| 40296. |
Exercise 8.4 q.3 1,2 |
| Answer» Ncert book | |
| 40297. |
(1/2+3/3/8/5+11/14+5/2-1/1)÷5/2of5/2of19/7 |
| Answer» | |
| 40298. |
The circumference of two circle are in the ratio 2:3.find the ratio of their areas |
| Answer» 4:9 | |
| 40299. |
If a positive integer \'p\' is divided by 7 ,then find the possible remainders. |
| Answer» 0,1,2,3,4,5,6 | |
| 40300. |
Compute the derivative of i)f(x)=√sec√sinx |
| Answer» | |