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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40351. |
Prove that cos theta - sin theta + 1 / cos theta + sin theta -1 = cosec theta + cot theta |
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| 40352. |
The probability that the month of arpil has exactly 5 monday is |
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Answer» 1/6 5\\30 |
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| 40353. |
Chapter wise distribution of marks |
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Answer» You can find on edudel nic.in Which subject |
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| 40354. |
Solve the equation for x: x+2/x-2-(1-x)/x=17/x |
| Answer» 3 and 6 | |
| 40355. |
In AP, if s6+s7=167 And s10 =235 then find the AP ,where sn denote the sum of its first n term |
| Answer» Sn =\xa0{tex}\\frac{n}{2}{/tex}[2a+(n-1)d]Now, S5+S7=167{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{5}{2}{/tex}[2a+4d]+{tex}\\frac{7}{2}{/tex}[2a+6d]=167{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{{5 \\times 2}}{2}{/tex}[a+2d]+|{tex}\\frac{{7 \\times 2}}{2}{/tex}[a+3d]=167{tex}\\Rightarrow{/tex}\xa05a+10d+7a+21d=167{tex}\\Rightarrow{/tex}\xa012a+31d=167...(i)Also, S10=235{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{{10}}{2}{/tex}[2a+9d]=235{tex}\\Rightarrow{/tex}\xa05[2a+9d]=235{tex}\\Rightarrow{/tex}\xa010a+45d=235{tex}\\Rightarrow{/tex}\xa02a+9d=47...(ii)Multiplying equation (ii) by 6, we get12a+54d=282...(iii)subtracting (i) from (iii), we get\xa023d = 115{tex}\\Rightarrow{/tex}\xa0d = 5{tex}\\Rightarrow{/tex}\xa02a+9(5)=47{tex}\\Rightarrow{/tex}\xa02a = 2{tex}\\Rightarrow{/tex}\xa0a = 1First term = a = 1Second term = a+d=1+5=6Third term = a+2d=1+2(5)=11Thus, the Ap is 1,6,11,... | |
| 40356. |
Find the value of P such that the quadratic equation (p-12)x²-2(p-12)x+2=0 has equal root |
| Answer» Since the equation has equal rootsTherefore D=0 b^2-4ac=0 [2(p-12)]^2 -4*(p-12)(2)=0 4(p-12){(p-12)-2}=0 (p-12)(p-14)=0 p=12 or p=14 | |
| 40357. |
1/(x-1)(x-2)+1/(x-2)(x-3)=2/3 X is not equal to 2&3 |
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| 40358. |
Is there any news about board time table? |
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| 40359. |
Find the nature roots of quadratic equation |
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Answer» D=b²-4ac .........D stand for discriminant# D>0 .....the two roots will be different and real# D= 0..... The two roots will be same # D< 0...... The two roots will be imaginary or say complex.... This is not in your syallbus. You will read this in 11 class b²-4ac |
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| 40360. |
Find the remainder when p (x)=2x2-x-6 is divided by (x-2) |
| Answer» p(x) is not clear to understand | |
| 40361. |
If secA +tanA=p ,then find the value of cosecA.(4 marks) |
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| 40362. |
Trigono6Trigonometry |
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| 40363. |
How many students who study in coaching?️ |
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Answer» Sahi bole bhaii 1000% What 30 gupta Coaching is a waste of time !! 30 |
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| 40364. |
what is eculid\'s devision lemma? |
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Answer» The proven statement use to prove another statement is called Euclid\'s division lemma.... Hahaha |
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| 40365. |
Cos A by 1 + sin a + 1 + sin by cos A is equals to 2 |
| Answer» Cosa/1+sina + 1+sina/cosa=(1-sina)2+(1+sina)/1-sin2a=2(1-sin2a)/(1-sin2a)=2LHS=RHS | |
| 40366. |
Bird. Tub. Base. Is. Not. Added. For. Tsa |
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| 40367. |
Send 2007- 2012 previous qestion papers |
| Answer» Check previous year papers :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 40368. |
If integer chose randomly between 1 to 100 ?find the possibility of number divisible by 8 |
| Answer» Possibility of getting is 3/18 | |
| 40369. |
Find k if k-3,2k+1,4k+3 are in AP |
| Answer» -4 | |
| 40370. |
Find a,b,and c such that the Nos a,7,6,23,c in AP |
| Answer» {tex}a, 7, b, 23{/tex} and {tex}c{/tex} are in A.P.Let the common difference be d.{tex}a + d = 7{/tex} ....(i){tex}a + 3d = 23{/tex} ....(ii)From (i) and (ii), we get{tex}2d = 16{/tex}{tex}d = 8{/tex}Put d = 8 in (1) we get{tex}a + 8 = 7{/tex}{tex}a = -1{/tex}{tex}b = a + 2d{/tex}{tex}b = - 1{/tex} + 2 {tex}\\times{/tex}\xa08or,{tex} b = - 1 + 16{/tex}or, {tex}b = 15{/tex}{tex}c = a + 4d{/tex}= - 1 + 4 {tex}\\times{/tex}\xa08= - 1 + 32{tex}c = 31{/tex}{tex}\\therefore{/tex}\xa0{tex}a = - 1,b = 15, c =31{/tex} | |
| 40371. |
For what value of p,2p+1,13p ,5p-3 are AP |
| Answer» let the three consecutive terms of AP be {tex}a_1,a_2,a_3{/tex}where\xa0{tex}a_1=(2p+1),a_2=13,a_3=(5p-3){/tex}we know that difference between any two consecutive terms of an AP is equal{tex}\\therefore{a_2} - {a_1} = {a_3} - {a_2}{/tex}{tex} \\Rightarrow 13 - (2p + 1) = (5p - 3) - 13{/tex}{tex} \\Rightarrow 12 - 2p = 5p - 16{/tex}{tex} \\Rightarrow 7p = 28{/tex}{tex} \\Rightarrow p = 4{/tex} | |
| 40372. |
What is nerve cell |
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Answer» rahul it is not maths question . Nerve cell is a long cell which are connected to each other and tranmits electrical signal from one neuron to another |
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| 40373. |
What is the mean of volume |
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Answer» Volume refers to the capacity of body. It means how much body can take inside it. We can say space occupied by any matter in object. |
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| 40374. |
Describe bpt theorem |
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Answer» Seen in your book of ch- 6 BPT(Basic Proportionality Theorem) states that when a line is parallel to third side of a triangle than then line divides other two sides of triangle in same ratio. |
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| 40375. |
If the zeroes of p(x)=x2-p(x+1)-c are alpha and bita then (alpha +1)(bita+1)= |
| Answer» Given, {tex}\\alpha {/tex}\xa0and\xa0{tex}\\beta{/tex} are the zeroes of polynomial\xa0{tex}{x^2} - p(x + 1) + c{/tex}which can be written as\xa0{tex}{x^2} - px + c - p{/tex}So, sum of zeroes,\xa0{tex}\\alpha + \\beta = p{/tex}\xa0{tex}[\\because {/tex}\xa0sum of coefficients =\xa0{tex}\\frac{{ - (coefficient(x))}}{{\\operatorname{co} efficient({x^2})}}{/tex}]and product of zeroes\xa0{tex}\\alpha \\beta = c - p{/tex}\xa0{tex}[\\because {/tex}\xa0product of cofficients=\xa0{tex}\\frac{{constant\\_term}}{{coefficient({x^2})}}{/tex},]Also,\xa0{tex}(\\alpha + 1)(\\beta + 1) = 0{/tex}{tex}\\alpha\\beta + \\alpha + \\beta + 1 = 0{/tex}{tex} \\Rightarrow c - p + p + 1 = 0{/tex}{tex}\\Rightarrow c = - 1{/tex} | |
| 40376. |
Use euclid s algorithem to find hcf of 4052 and 12576 |
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Answer» NCERT textbook ..pg-5 Go gchgchgcjn hovoohlgogo |
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| 40377. |
How to prepare for exams ??? Please help |
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Answer» Thanks Everyday study 4-5 hours and solve previous year questions paper... Study 4 to 6 hours per day without tension. Start studying and nothing else |
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| 40378. |
Tell me this semester syllabus |
| Answer» Check on Google | |
| 40379. |
Is Ncert(Maths) is sufficient for board examOrR.S and R.D ? |
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Answer» Yes but i think rd and exam idea is good for revision... Use NCERT exemplar for practice Ncert is sufficient for board exam.Prepare each questions of ncert only |
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| 40380. |
2+2×78÷9765 |
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Answer» 2.0159754224 (bdmas rules) 2.0159754224 0.0319508449 |
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| 40381. |
(1/x*1)*(2/x*2)#4/x*4 |
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| 40382. |
Which term of the sequence 114,109,104.....is the first negative term? |
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Answer» I thought it\'s answer should be 24th term as it\'s 1stnegative which is -1 104 B hmm 109 |
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| 40383. |
Prove theorem 10. 2 |
| Answer» NCERT CH-10 PG.NO.-211 | |
| 40384. |
On simplification whether 2 root 45 +3 root20 gives irrational or rational number |
| Answer» It is an irrational no. as2√45=6√5 and3√20=6√5 6√5+6√5=12√5Which is an irrational no.Hence it is an irrational no. | |
| 40385. |
If . 1/a+b+x = 1/ a+ 1/ b+ 1/ c Then find the value of \'x\'... |
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Answer» How X= -b , -a |
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| 40386. |
a-a |
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Answer» A is vovel 0 ? 0 |
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| 40387. |
Please tell me the cut off marks for Bihar in NTSE stage 1. |
| Answer» Between 160 and 170 | |
| 40388. |
If secA+tanA=p, then find the value of cosecA |
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Answer» Arrange krlena ache se smjhke bnana secA+tanA=p ----------- (i)‘.\' sec²A-tan²A=1(secA+tanA)(secA-tanA)=1secA-tanA = 1/p ------------- (ii)Subtracting eqn ii from IWe get,2tanA= p-1/ptanA = (p²-1)/2pcotA = 2p/(p²-1)Nowcosec²A-cot²A = 1cosec²A=1+cot²Acosec²A=1+[2p/(p²-1)]²cosec²A= 1+4p²/(p²-1)²cosec²A= (p²)² - 2p²- 1- 4p²/(p²-1)²cosec²A= (p²)² + 2p²+1/(p²-1)²cosec²A= (p²+1)² / (p²-1)²cosecA= (p²+1)/p²-1) secA+tanA=p ----------------------------(1)∵, sec²A-tan²A=1or, (secA+tanA)(secA-tanA)=1or, secA-tanA=1/p -----------------------(2)Subtracting (2) from (1) we get,2tanA=p-1/por, tanA=(p²-1)/2p∴, cotA=2p/(p²-1)Now, cosec²A-cot²A=1or, cosec²A=1+cot²Aor, cosec²A=1+{2p/(p²-1)}²or, cosec²A=1+4p²/(p²-1)²or, cosec²A=(p⁴-2p²+1+4p²)/(p²-1)²or, cosec²A=(p⁴+2p²+1)/(p²-1)²or, cosec²A=(p²+1)²/(p²-1)²or, cosecA=(p²+1)/(p²-1) |
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| 40389. |
Can two numbers have 18 as their HCF and 380 as their LCM ? Give reason |
| Answer» No because HCF must be the factor of LCM. | |
| 40390. |
I want ot this subject in Hindi medium |
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| 40391. |
What is the formula of area of quadrilateral in coordinate geometry |
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Answer» Tell me first which type of quadrilateral? Mera answer kahan hai ? |
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| 40392. |
Write the formula of:1.Mean2.Median3.Mode |
| Answer» Refer to ncert book ch statistics | |
| 40393. |
x/x-1-x-1/x=34/15 |
| Answer» Refer to the maths NCERT book ch polynomials | |
| 40394. |
Exercise 11.1 quetion6 |
| Answer» You can find c using asp 180-45-105=c C=30 now draw the triangle | |
| 40395. |
the area of |
| Answer» Area of what ?? | |
| 40396. |
In maths also most of the questions will come from ncert book in board exam |
| Answer» yep | |
| 40397. |
Find the value of k, for which one root of the quadratic equation kx^2-14x+8=0is 2 |
| Answer» If 2 is one of the root of given quadratic equation then we can write k(2)^2-14(2)+8=0 or, 4k-28+8=0 or, 4k-20=0 or, 4k=20 or, k=5 (answer) | |
| 40398. |
2 digit ka yog 15 hai 1 digit dushre ka 1/2 hai tho digit qatt kare |
| Answer» Let the digits be x and y........yog means addition so x+y=15----------(1)➡➡➡➡1 digit dusre ka half so let x=y/2 (or u can put y=x/2)➡➡➡➡➡put in eqn (1)....y=10...x=5? | |
| 40399. |
What are the important chapters in maths and how can i solve maths. |
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| 40400. |
Preboard kon se book se bante hai |
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Answer» Satish kumar NCERT ?? NCERT ! Mujhe bhi bata dei agar pata chale to |
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