InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40451. |
My teacher is saying that math ch 13 is not coming in board. Is it right? Please tell. |
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Answer» no it\'s wrong ch-13 will come in board?? No absolutely roungh so you also do ch13 ok dear No absolutely not ???? |
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| 40452. |
Volume and curved surface area of volume are 1650 cubic cm and 660 square cm. Find radius and height |
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| 40453. |
Smallest consecutive no. |
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Answer» Thanks naman gupta 4 |
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| 40454. |
Find roots of quadratic equations by factorisation 2x-x+1/8=0 |
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Answer» 1/2 Please an |
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| 40455. |
What is 1 prime or composite |
| Answer» Which is divisible by 1 or it self | |
| 40456. |
Area related to circle tricks |
| Answer» | |
| 40457. |
How remember the formula of trigonometry |
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Answer» Bhai kuch nahin hai just do 10 questions daily at the beginning you write the formula by seeing the book and after that you it will be remembered Revise daily all formulas Revise all day formulas and put in your study room You have to understand the derivation of the formulae instead of trying to byheart them.These derivations are given in NCERT TB. |
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| 40458. |
Probablity A pack of 52 cardsProbability of spade or an ace |
| Answer» 13/52=1/4 | |
| 40459. |
Find the area of the shaded region PQ=24cm , PR=7cm and O is the centre of the circle |
| Answer» Rq=25 , then area of semi-circle -area of triangle,1÷2×π×rsq,-1÷2 ×b×h, radius =12.5 solve itt ???? | |
| 40460. |
568+568 |
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Answer» Aap 1st ma ho kya ??? 568+568=1136. 1136 |
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| 40461. |
find the 296 term of the series given below .a,bb,ccc,dddd,eeeee |
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| 40462. |
Is RD Sharma best or student advisor? |
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Answer» Rd Sharma RD is best book and it is the best preparation for board exam and other scoring exams.... Rd sharma is best because it have those questions also which came in the board examIt is in very depthIt is best |
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| 40463. |
A+B equal to 0(A&B are possive integer ¬ equal to 0)how |
| Answer» Given, A + B = 0 So, A= -B Or, B= -A If A is positive B is negative If B is positive A is negative So there is no possible value for A and B because it is given that A and B are positive integers. We must also remember that 0 is neither positive nor negative. So, there is no such value for A and B which satisfies the given conditions. | |
| 40464. |
If p(e)=0.05,what is the probability of \'not e\') |
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Answer» Probability is 0.95 P(e)=0.05 P not (e)=1-0.05 =0.95.....:-D 95 There is formula, P(E) + P(E\') = 1 , where E\' means not E .0.05+P(E\') = 1P(E\') = 1-0.05Probability of not E is 0.95 1-0.05=.95 |
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| 40465. |
Class 10 ex 2.3 question1. 2 not understand |
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Answer» Apply long division algorithm Q1 me divide kar ke remainder and quotient nikal na hai or dusre wale me agar completely divide ho jata hai that means remainder is 0 then yes Un Q me apko bus divide Karna hai |
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| 40466. |
3x*x-14x-5=0Solve the equation by factorization |
| Answer» (x-5)(x+1/3) | |
| 40467. |
1÷a+b+x=1÷a+1÷b +1÷c |
| Answer» | |
| 40468. |
Find the distance between the points A(sinQ , 0) and (0,cosQ) |
| Answer» 1 unit | |
| 40469. |
Sin²A.cot²A+cos²A.tan²A=1 |
| Answer» Sin²A.cot²A+cos²A.tan²A=Sin²A.cos²A/sin²A +cos²A.sin²A/cos²A=Cos²A+Sin²A=1Proved | |
| 40470. |
9x+3y+12=018x+6y+24=0 |
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Answer» Infinite solutions as a1/a2=b1/b2=c1/c2 9x+3y+12=0,,,,18x+6y+24,,,,9x+3y+12 (multuply by 2) ,,,,18x+6y+24=0 ,,,{by using elimination method}[From equation 1st nd 2nd]18x+6y+24=018x-6y-24=0Change the sign (+ve to -ve) so the ans is (0) zero!!!.../////......:-) |
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| 40471. |
3x^2+2x+3=0 |
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Answer» Invalid question as discriminant is negative.. Not possible because the d=negative |
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| 40472. |
Find the centre of a circle passing through(5,-8),(2,-9) and (2,1) |
| Answer» 2, -4 | |
| 40473. |
What id maths question paper1 sa1 |
| Answer» It\'s on oye exam app. | |
| 40474. |
What is step deviation? |
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| 40475. |
Sin6A +cos6A=1-3sin\'2Acos\'2A |
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| 40476. |
Express the trigonometric ratios sinA secA tanA in terms of cotA |
| Answer» For sin A,By using identity {tex}cosec ^ { 2 } A - \\cot ^ { 2 } A = 1 \\Rightarrow \\cos e c ^ { 2 } A = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\frac { 1 } { \\sin ^ { 2 } A } = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\sin A = \\frac { 1 } { \\sqrt { 1 + \\cot ^ { 2 } A } }{/tex}For secA,\xa0By using identity {tex}\\sec ^ { 2 } A - \\tan ^ { 2 } A = 1 \\Rightarrow \\sec ^ { 2 } A = 1 + \\tan ^ { 2 } A{/tex}{tex}\\Rightarrow \\sec ^ { 2 } A = 1 + \\frac { 1 } { \\cot ^ { 2 } A } = \\frac { \\cot ^ { 2 } A + 1 } { \\cot ^ { 2 } A } \\Rightarrow \\sec ^ { 2 } A = \\frac { 1 + \\cot ^ { 2 } A } { \\cot ^ { 2 } A }{/tex}{tex}\\Rightarrow \\sec A = \\frac { \\sqrt { 1 + \\cot ^ { 2 } A } } { \\cot A }{/tex}For tanA,{tex}\\tan A = \\frac { 1 } { \\cot A }{/tex} | |
| 40477. |
7x-4y=2,x+2y=16 |
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Answer» 7x - 4y = 2 .......... (i)x + 2y = 16......... (ii)multiply (ii) by 22x + 4y = 32....... (iii)Add (i) and (iii)9x = 34x = 34/9Put in (ii)x + 2y = 1634/9 + 2y = 162y = 16 - 34/92y = 110/9y = 55/9 x=34/9 And y=110/9 |
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| 40478. |
Find the value of k if the quadratic equation 3x^2 -k√3x+4 =0 has equal roots |
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Answer» The value of k=4 The value of k = 4 |
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| 40479. |
Bj |
| Answer» | |
| 40480. |
10 reappearcompartment private Ka paper kab hoga form to fill ho Gaye |
| Answer» Kyon sa paper | |
| 40481. |
Sin60 Cos30+ sin30 cos60 Evaluate |
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Answer» 1 Sin 60 =root 3 upon 2 ,cos30=root 3upon 2 + sin 30=1upon 2 ,cos 60=1 upon 2 and solve it Sin(90-30) cos30+ sin30 cos(90-30). Cos30 cos30 +sin 30 sin30. Cos²30 + sin²30. =1 |
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| 40482. |
(1+2)(1+2) |
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Answer» 9 9 Answer is 9 =(1+2)(1+2)=(3)(3)=3×3=9 9 |
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| 40483. |
Tan 15=? |
| Answer» Let tan(15°) = tan(45°-30°) We know that tan(A - B) = (tanA - tanB) /(1 + tan A tan B) ⇒tan(45°-30°) = (tan45°- tan30°)/(1+tan45°tan30°) = {1- (1/√3)} / {1+(1/√3)} ∴ tan15° = (√3 - 1) / (√3 + 1) | |
| 40484. |
In fig OAB is quadrant of radius 7 . Find the shaded region |
| Answer» 77/2 | |
| 40485. |
Property of all shape |
| Answer» | |
| 40486. |
If the sum of first m terms of AP is 2m*m + 3m , then what is its second term? |
| Answer» Second term is 9.....first term = sum of 1 term....then second term would = sum of 2 terms minus 1st term | |
| 40487. |
Is 70% in maths come from ncert book only |
| Answer» 100% maths come from ncert only the values are changed. | |
| 40488. |
(cosec A-cot A) ²=1-cos A\\1+cos A |
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| 40489. |
Surface area and volume all formulas |
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| 40490. |
SinA + tanA=p find the value of cosecA |
| Answer» 1/p-tanA | |
| 40491. |
196 or 38220 |
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Answer» 195 is an HCF of 196 or 38220 196 is HCF of 196 n 38220 Hcf kya What is your question Pls be specific What do you want |
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| 40492. |
Area of frustum |
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Answer» T S A-πl(R+r)+πr2+πR2 Dujgr I |
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| 40493. |
What is the area of rectangle |
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Answer» Length ×breath Area of rectangle is length *breadth L×b Area of rectangle=length*breadth |
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| 40494. |
Who invent alpha and bita |
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Answer» Alpha is the first letter of Greek alphabet. In the system of Greek numerals,it has a value of 1. α Is a alpha β is a bita |
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| 40495. |
Prove that √3+2√5is irrational no |
| Answer» We know that√3 is irrationalLet√5 be rational√5=p/qSq. Both side5=p2/q25q2=p2If p divides p then it must divide p2This contadicts tthe fact that√5 is irrational | |
| 40496. |
How sin90° will be formed |
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| 40497. |
Sin×sin+cos×cos=1 prove it |
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Answer» Sin✖sin+Cos Cos✖=1 because Sin2+Cos2=1 and formula is sin2+ cos2 =1 Hence proved that sin✖sin + cos✖cos =1. Wrong answer? p/h*p/h+b/h*b/h=P2/h2+b2/h2=(P2+b2)/h2=H2/h2=1 |
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| 40498. |
E a dice is thrown randomly on time what are the chances of coming code number ward number |
| Answer» 1/6 | |
| 40499. |
Find value without using trignometry table cot40+ cosec40° |
| Answer» 2.598 | |
| 40500. |
56m भुजा abcd इसकी कयारियाँ ज्ञात करे |
| Answer» what mean of क्यारियाँ | |