InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40501. |
Area of traingle |
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Answer» Half × base × height =area of triangle Half base ✖ height half base x height |
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| 40502. |
What is the major sector in Circle |
| Answer» If we draw a chord in a circle . The circle is divide into two parts that known as sector . The sector of large area is known as major sector. | |
| 40503. |
X:1/a+b+x = 1/a +1/b +1/x ; a#0, b#0 ; x#0, |
| Answer» we have,\xa0{tex}\\frac{1} {a+b+x}{/tex}=\xa0{tex}\\frac{1}{a}+\\frac{1}{b}+\\frac{1}{x}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{1} {a+b+x}{/tex}\xa0-\xa0{tex}\\frac{1}{x}{/tex}\xa0=\xa0{tex}\\frac{1}{a}{/tex}+\xa0{tex}\\frac{1}{b}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}-\\frac{a+b} {x(a+b+x)}{/tex}\xa0=\xa0{tex}\\frac{a+b}{ab}{/tex}cancel (a+b) from both sides & cross multiply\xa0{tex}\\Rightarrow{/tex}\xa0{tex}-ab =x(x+a+b) {/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + (a+b)x + ab = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(x+a) (x+b) = 0{/tex}{tex}\\therefore{/tex}\xa0{tex}x = -a\\ or\\ -b{/tex} | |
| 40504. |
Solve for x1/a+b+x=1/a+1/b+1/x; a#0,b#0,x#0 |
| Answer» Pls write the ques. with spaces I am unable to read it | |
| 40505. |
if sintheta+2costheta=1prove that 2sin theta -costheta =2 |
| Answer» Given, sin θ + 2 cos θ = 1\xa0On squaring both sides, we get{tex}(sin\\theta+2cos\\theta)^2=1{/tex}{tex}\\Rightarrow sin^2\\theta+4cos^2\\theta+4sin\\theta cos\\theta=1{/tex}⇒ 1 – cos2\xa0θ + 4 (1 – sin2\xa0θ) + 4 sin θ cos θ = 1\xa0{tex}[\\because sin^2\\theta+cos^2\\theta=1]{/tex}⇒ 1 – cos2\xa0θ + 4 – 4 sin2\xa0θ + 4 sin θ cos θ = 1⇒ –cos2\xa0θ – 4 sin2\xa0θ + 4 sin θ cos θ = –4{tex}\\Rightarrow -(cos^2\\theta+4sin^2\\theta-4sin\\theta cos\\theta)=-4{/tex}⇒ cos2\xa0θ + 4 sin2\xa0θ – 4 sin θ cos θ = 4⇒ (cos θ)2\xa0+ (2 sin θ)2\xa0– 2(cos θ) (2 sin θ) = 4⇒ (2 sin θ – cos θ)2\xa0= 22{tex}\\Rightarrow{/tex}2 sin θ – cos θ = 2{tex}{/tex}Hence\xa0proved. | |
| 40506. |
if sin%* |
| Answer» | |
| 40507. |
Write the area of a semi circle of redium R. |
| Answer» 1/2 πr² | |
| 40508. |
Main hu next cbse topper 2019 |
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Answer» Bekhte ha good morning my friend???? subhe subhe ka joke kitna acha hota ha Abe hum kya aram se so rahe hai? Yes ???? ??? what a joke?? Ok bhai topper well done and We\'ll see |
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| 40509. |
To construt a right circular cylinder with given height and circumference |
| Answer» To construct a right circular cylinder with given height and circumference | |
| 40510. |
Prove that √3+√5 is irratinal no |
| Answer» Let us consider\xa0{tex} \\sqrt { 3 } + \\sqrt { 5 }{/tex} is a rational number that can be written as{tex} \\sqrt { 3 } + \\sqrt { 5 }{/tex}\xa0= a{tex} \\Rightarrow \\sqrt { 5 } = a - \\sqrt { 3 }{/tex}Squaring both sides, we get{tex} ( \\sqrt { 5 } ) ^ { 2 } = ( a - \\sqrt { 3 } ) ^ { 2 }{/tex}⇒ 5 = (a)2{tex} + ( \\sqrt { 3 } ) ^ { 2 } - 2 ( a ) ( \\sqrt { 3 } ){/tex}⇒ {tex} 2 a \\sqrt { 3 } {/tex} = a2 + 3 - 5⇒ {tex} 2 a \\sqrt { 3 } {/tex} = a2 - 2{tex} \\Rightarrow \\sqrt { 3 } = \\frac { a ^ { 2 } - 2 } { 2 a }{/tex}As a2\xa0– 2, 2a are integers .So\xa0{tex} \\frac { a ^ { 2 } - 2 } { 2 a }{/tex}\xa0is also rational but\xa0{tex} \\sqrt { 3 }{/tex}\xa0is not rational which contradicts our consideration.Since a rational number cannot be equal to an irrational number . Our assumption that\xa0√3 +\xa0√5 is rational wrong .So,\xa0{tex} \\sqrt { 3 } + \\sqrt { 5 }{/tex}\xa0is irrational. | |
| 40511. |
Find the middle term of the following ap -6 ,-2,2,......58 |
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Answer» 6, 10, 14, 18, 22, 26, 30, 34, 38, 42, 46, 50, 54 ,58 6 |
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| 40512. |
In a triangle angle PQR = 90° and QS is perpendicular to PR.Prove that RQsquare /PQ square = RS/PS |
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Answer» Please solve this question n if u had solve then send it to me on my whatsapp or in this cbse guide app Bh |
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| 40513. |
Quadratic equations exercises completely |
| Answer» | |
| 40514. |
If a=—1.25,d=—0.25 write first 4terms of AP |
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Answer» And i am also sorryfor telling that the anwer is -1.75 but finally at end my anwer is also -2.0?? By mistake my answer is worng sorry the answer is -2.0 and by the help of formula. T4 =a+(n-1)d , by putting the valve =-1.25+(4-1)-0.25=-1.25+{3×(-.25)}=-1.25-.75=-2.0 ans But my answer is -1.50 -0.50 |
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| 40515. |
Find the missing term 2,0,9,3,28,8,?A)23 B)65 C)52 D)63 |
| Answer» | |
| 40516. |
67584/21 कब=22528/7 |
| Answer» This number has been divided by 3. | |
| 40517. |
Theorem 1.3 |
| Answer» | |
| 40518. |
Prove:-Sec sq.+ cosec sq.=sec sq.-cosec sq. |
| Answer» L.H.S= 1/cos sq. + 1/sin sq.= (Sin sq. + Cos sq.)/(cos sq. × sin sq.)=1/(cos sq. × sin sq.)= Sec sq. Cosec sq = R.H.S | |
| 40519. |
7-6√5 prove that its irrational |
| Answer» Let 7-6√5 as rational. It can be expressed in the form of p/q where p and q are co prime integers.7-6√5=p/q6√5=7-p/q√5=7q-p/6Now since p and q are integers.So RHS is rational so LHS is also rationalBut we know that √5 is irrational This contradiction arises due to our incorrect assumption. This shows our assumption is wrong.So 7-6√5 is irrational. Hence proved :-) | |
| 40520. |
How do I develop the ability of solving questions mentally? |
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Answer» By practice the sample papers and Last year\'s board papers because much questions are from their By practice, if you want marks first understand NCERT question than extra Using mind |
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| 40521. |
3727 _72727₹2737| [email\xa0protected]₹&3+₹₹3737₹ |
| Answer» Eygf | |
| 40522. |
If cosecA = 2, find the value of 1÷ tanA+sinA÷1+cosA |
| Answer» | |
| 40523. |
12+18 |
| Answer» It\'s 30. Don\'t ask such silly questions. | |
| 40524. |
Abcd is ractangle find the area |
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Answer» Ab×ac AB×Ac |
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| 40525. |
ABCD is rectangle in which angle E =angle F then prove that AD/AE =AB/AF |
| Answer» | |
| 40526. |
the median of the distrudation is14.4 find x and y if sum of frequency is 20 |
| Answer» Give me all other frequencies and c.i. | |
| 40527. |
How to escape from classtests..? ? |
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Answer» For doing fun What and for what? |
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| 40528. |
A cubical block of 7cm surmounted by a hemisphere, find the total surface area of solid |
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Answer» TSA= 5a×a+CSA of hemisphere +a×a-22/7×7×7 Srry above answer is incorrectCorrect answer is:TSA of solid= 5a²+CSA of Hemisphere =5×7×7+2×22/7+7/2×7/2 =265+77 =342 cm² Apply formula of TSA of cube=6a²TSA of cubical block= 6×7×7=294 cm²That\'s all.. |
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| 40529. |
Proof the triangle therom 6.1,6.2,6.3 ,6.4,6.5 of class 10 |
| Answer» | |
| 40530. |
√sec2α+cosec2α=tanα+cotα |
| Answer» | |
| 40531. |
Sporti material chapter 10 circle. Question 25 ,and 28 answer plzz |
| Answer» | |
| 40532. |
Kkm |
| Answer» Whatdo you mean? | |
| 40533. |
What is frequency distribution table |
| Answer» The table in which such a distribution of frequencies is given is called the frequency distribution table.The number of times a particular observation occurs in a given data is called its\xa0frequency of an observationThe tabular arrangement of data showing the frequency of each observation using tally marks or by condensing the data into classes or groups is called frequency distribution. | |
| 40534. |
What is the relations between mean, median mode |
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Answer» How you can say this explain it?????? Empirical relation between mean, median and mode:Mode = 3 median - 2 mean. |
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| 40535. |
In some application of trigometry 1st ex 3 question for ABC ? how AC will get 3m |
| Answer» | |
| 40536. |
The value of (-18)+(-6)×2-{(-4)×(-3)-6(3-(7-9))} |
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Answer» Tha corract answar is 60 I think it\'s -60 |
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| 40537. |
All questions in 10th board exam is ncert or not |
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Answer» may be.... ???? |
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| 40538. |
(a-b)x + (a+b)y = a2 - 2ab - b2 , (a+b)x (a+b)y = a2 +b2. Solve for x and y |
| Answer» x = a + b{tex}\\therefore{/tex} (a - b)(a + b) + (a + b)y = a2 - b2 - 2aba2 - b2 + (a + b)y = a2 - b2 - 2ab{tex}y = \\frac{{ - 2ab}}{{a + b}}{/tex} | |
| 40539. |
Name the angle formed in a minor segment |
| Answer» an obtuse angle | |
| 40540. |
2x+2y-23 |
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Answer» Plzz tell us whole question.. What u want to ask in this question. Plzzz ask in detail.. |
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| 40541. |
If Sin theta = cos(theta-6degree) find value of theta |
| Answer» | |
| 40542. |
Nikhil |
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Answer» Same here also hii nikhil? Hi nikhil |
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| 40543. |
Surface area ànd volume of all shapes |
| Answer» Please give a proper shape | |
| 40544. |
If sin(A-B) = 1/2 & cos(A-B) = 1/2 then find A and B |
| Answer» A = 45 and B = 15 | |
| 40545. |
SecA+tanA=x then SecA=? |
| Answer» secA =x- tanA | |
| 40546. |
Construct an isosceles triangle whose base is 7cm and the sum of one equal side and altitude is 13cm |
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Answer» Theory poocho nn Bhai isme tmhe construct krke koi kaise dega |
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| 40547. |
Find the two roots of equations (x+1)(x-2)+x=0 |
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Answer» Ohi tera wala yaar!!!!! When it is very simple y dont tell the answer?? Is it +√2 & -√2 ???? |
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| 40548. |
Quadrantic polynomials whose sum and product of its zeroes are 4 and 1 |
| Answer» Xsquare -4x+1 | |
| 40549. |
Bpt theorm of unit 6 |
| Answer» | |
| 40550. |
In adjacent figure AC is diameter of the circle and AT is tangent at A find the value of x |
| Answer» 65° | |