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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42151. |
Muje trigonometry identities me solving me problem hoti h |
| Answer» Take easy questions from cbse papers | |
| 42152. |
If alpha and beta are the zeros of polynomial ax2+bx+c,then find 1/alpha2+1/beta2 |
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Answer» B^2-2ac÷c^2 1/α²+ 1/β²=α²+β²/(αβ)²α²+β²=(α+β)²-2αβp(x)=ax²+bx+cα+β=-b/aαβ=c/aPutting values we get= (-b/a)² -2*c/a /c²/a²= b²-2ac/c² |
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| 42153. |
What is the are of frustum |
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Answer» TSA=ΠL(r1+r2)+Πr1²+Πr2² Csa..22/7(r1+r2)l |
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| 42154. |
Muje trigonometry me problem hai plz help me |
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Answer» Take esy scoring questionss Ok Mr saini prove sin30=1/2 using geometry only I am prefect in trigonomentry please ask me questions |
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| 42155. |
Zeroes of tge polynomial x^2-2x-3 |
| Answer» X²-2x-3=0X²-(3-1)x-3=0X²-3x+1x-3=0X(x-3)+1(x-3)=0(X+1)(x-3)=0X=-1,3 | |
| 42156. |
a/x -b/y=0ab*b/x+a*a*b/y=0 |
| Answer» | |
| 42157. |
In D ABC, Right angled at A,it tan C=√3, find the value of sin B cos C + cos B sin C. |
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Answer» A+B+C=180B+C=180-A=180-90=90Now\xa0sin B cos C + cos B sin C.=sin(B+C)= sin 90=1\xa0 1 |
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| 42158. |
Prove that SinA÷1-CosA + tanA÷1+CosA =SecA-CosecA+CotA |
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Answer» Lage paye ne vire? Bs mai vi vdiya hu paii Tu apni bata hum to thik h Hamko ata hi nhi Sabnu boho boho namashkar..kaise ho tussi saare? |
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| 42159. |
Never stop learning, Because life never stops teaching ...? By guys all of you .... ???? |
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Answer» ?? Nice, one....... |
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| 42160. |
If sin¢+cos¢=✓2cos¢Then prove that: cos¢-sin¢=✓2sin¢ |
| Answer» Pehle, cos $ ko l.h.s le ao, take common then root 2 - 1 ko r.h.s le jao, now rationalize the r.h.s term and yu will get the proof...... | |
| 42161. |
If cos+sin=√2cos then prove that cos-sin=√2sin ? |
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Answer» Let θ\xa0= xcos x + sin x = √2 cos xsquaring on both side, we get......cos2x + sin2x + 2cosxsinx = 2cos2x2sinxcosx = 2cos2x - cos2x - sin2x2sinxcosx = cos2x - sin2x2sinxcosx = (cosx+sinx) (cosx - sinx)2sinxcosx = (root2 cosx) (cosx - sinx)2sinxcosx/root2 cosx = cosx - sinx\xa0√2\xa0sinx = cosx - sinx Hey, scroll down ek aisa hi question ka answer dia hai maine |
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| 42162. |
Which book is best for exam preparation of board |
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Answer» NcERT First u get thorough with ncert book then go with some sample papers H.C. verma Ncert krle..agar fer vi paet na bhare ta cbse guide se prepare kr liyo..bahot hai.. You should go with ncert and do 10 past Q papre ok????? |
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| 42163. |
Xsquare-5x+9=0 by splitting middle terms |
| Answer» -9/5 | |
| 42164. |
If the point P(x,y) is equidistant from the points A(a+b,b-a) and B(a-b,a+b).Prove that bx=ay |
| Answer» Distace between the points (x, y) and (a+b, b-a) & (a-b, a+b) is equal\xa0⇒\xa0√{[x - (a + b)]2\xa0+ [y - (b -a)]2} =\xa0√{x - (a - b)]2\xa0+ [y - (a + b)]2}⇒ x2\xa0+ (a + b)2\xa0- 2x(a + b) + y2\xa0+ (b - a)2\xa0- 2y(b - a) = x2\xa0+ (a - b)2\xa0- 2x(a - b) + y2\xa0+ (a + b)2\xa0- 2y(a + b)⇒ -2ax - 2bx - 2by + 2ay = - 2ax + 2bx - 2ay - 2by⇒\xa0ay - bx = bx - ay⇒ 2ay = 2bx⇒ bx = ayHence proved. | |
| 42165. |
Ex-3.4.1 is creating confusion in solving.How to solve it? |
| Answer» Thanks | |
| 42166. |
The fourth term of an AP is zero.prove that the 25th term of an AP is three times its 11th term. |
| Answer» | |
| 42167. |
what is graphical method? |
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Answer» maine to ye aise he pooch tha for frns presenting any equations on graph |
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| 42168. |
CosA-sinA+1/cosA+sinA-1=cosecA+cotAProve. |
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| 42169. |
Find probability if a leap year is selected randomly will contain 53 thursday |
| Answer» 1/7 Ans | |
| 42170. |
How to draw a more than type ogive |
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Answer» First find out c.f. for more than type ogive in decending order. And then draw the graph and graph u will draw will be from higher to lower . |
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| 42171. |
How to draw a less than type ogive |
| Answer» | |
| 42172. |
Hello friends.... Chai pe lo !!!!!!???? |
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Answer» Ap bana ke doge kya??? I don\'t drink chai. I like coffee |
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| 42173. |
Can be use 1/2r^2SIN THETA FOR AREA OF TRIANGLE |
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Answer» Why Noooooo |
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| 42174. |
If (a-b), a and (a+b) are zeros of the polynomial 2x³-6x²+5x-7, write the value of a? |
| Answer» I think a=1. | |
| 42175. |
Two congruent cubes are joined end to end whose side is a cm then its total surface area is??? |
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Answer» 10a² cm Its ncert question......check it in this app |
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| 42176. |
Average marks of 18 girls and 12 boys are 30 and 38 then average marks of whole class??? |
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Answer» 33.2 33.2...... |
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| 42177. |
If cos ×=cos 40°*sin50°+sin40°*cos50°,then find the value of × |
| Answer» x=0° | |
| 42178. |
Can anyone prove that √7 is irrational number? |
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Answer» Let √7 be a rational number say p/q where q is not equal to zero and p and q are coprime.√7=p/qSq. Both side7=p²/q²,7q²=p²--------(1)7q² is divisible by 7,p² is divisible by 7,p is divisible by 7, Let p=7a,Putting the value in equation 1.7q²=(7a)²7q²=49a²q²=7a²7a²is divisible by 7q² is divisible by 7q is divisible by 7Both p and q have common factor 7.Therefore our supposition is wrong.√7 is irrational. Mujhe solution chahiye yess nhi Yes Bt solution kaise dun??? Kya rohit ji.... prove ho gya....mera to |
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| 42179. |
Exercise 3.6 question 1 (3) |
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Answer» I solve it ...My answer is x= 1/5 and y= -2??? For board Take 1÷x= N and y= M....Solve from elimination method then u will get x and y |
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| 42180. |
If 8tanx=5 then find the value of sinx-cosx |
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Answer» Tan x = 15/8Height =15Adjacent = 8Hypotenuse =17Sin = 15/17Cos = 8/17Sinx - cosx = 15/17 - 8/17= 15-8/17=7/17 8tanx°=5 Tanx=5/8=perpendicular/base Hypotnuse=√89 Sinx-cosx=5/√89-8/√89=-3/√89 |
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| 42181. |
A number X is choosen at random from the numbers -2,-1,0,1,2. Then the probability that x^2 |
| Answer» P(E)=3/5 | |
| 42182. |
If A+B =90 and secA =2/3, then find the value of cosec B |
| Answer» | |
| 42183. |
Calculate total resistance in which R1=6 R2 =7 R3 = 8 R4 =9 |
| Answer» 30 | |
| 42184. |
Trigonmetry exercise 8.1 9th question |
| Answer» 9. In\xa0ABC right angles at B, if\xa0\xa0find value of:(i)\xa0(ii)\xa0Ans.\xa0Consider a triangle ABC in which\xa0B =\xa0.Let BC =\xa0\xa0and AB =\xa0Then, using Pythagoras theorem,AC =\xa0=\xa0=\xa0\xa0=\xa0\xa0=\xa0For\xa0C, Base = BC, Perpendicular = AB and Hypotenuse = AC(i)\xa0\xa0=\xa0=\xa0\xa0= 1(ii)\xa0\xa0=\xa0=\xa0 | |
| 42185. |
If the numbers a,b,c,d,e form an AP, then the value of a-4b+6c-4d+e is |
| Answer» Assume a=1, b =2, c=3, d=4 ,e=5 and substitute and then solve.? | |
| 42186. |
How many three digit numbers are divisible by 7 |
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Answer» Three digit number are100 to 999105,112,119.......994Ans:128 128 By Euclid divisor lemma -:999 / 7= 142*7+5Here999 is a divident 7 is quoent 142 is divisor 5 is reminder So 7 number is 999-5= 994 (You know that higest nois 3 digit is 999 ) 128 The first 3-digit number which is divisible by 7 is 105The last 3-digit number which is divisible by 7 is 994The list of 3-digit numbers divisible by 7 are105, 112, 119,…..994 which forms an A.PConsider a formulaT(n) = a + (n – 1)dWherea = 105d = 7T(n) = 994994 = 105 + (n – 1)7889 = 7n – 77n = 896n = 128∴ There are 128 3-digits number which are divisible by 7 |
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| 42187. |
show that the points a(0,0),b(3,0),c(4,1) and d(1,1) form a parallelogram |
| Answer» By using distance formula√( X2 -X1)² + (Y2 -Y1)² | |
| 42188. |
Compute the value of mode for the following frequency distribution |
| Answer» | |
| 42189. |
How to prepare for maths quiz |
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Answer» Your basic concept must be clear, then u prepare for maths quiz U must know the basics |
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| 42190. |
5x-7/2x+1=7x+2/7x-5 Find: x |
| Answer» 150 | |
| 42191. |
+91 90488 80890 |
| Answer» | |
| 42192. |
If cosec theta= 5 by 4 find cot theta |
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Answer» 5/4 I don\'t know tanvi 3/4 3/4 3/4 |
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| 42193. |
Some basic knowledge about polynomial |
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Answer» Polynomial is algebraic expression with non negative integral power In polynomials variable should be whole number. Variable should not be in fraction , not in root and variable should not be negative.it should always be a positive number. I want to know about polynomials |
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| 42194. |
A train travels a distance of 480km at a uniform speed. If the speed had been 8 km/hr less |
| Answer» Let the original speed of the train be x km/hourDistance traveled by the train = 480 kmHence, the original speed of the train is 40 km/hour | |
| 42195. |
Honda route 5 phone number |
| Answer» What?? | |
| 42196. |
If x=asin theta and y=btan theta ,then prove that a^2/x^2- b^2/y^2 |
| Answer» I don\'t know | |
| 42197. |
What is an identity |
| Answer» in maths , an identity is an relating mathematical expression which proves expression A and expression B equal . With the help of an identity , we can prove A&B expression equal and we can also find values of terms and let\'s(let x=, lety= etc) in these 2 expressions (expression A and expression B).examples:-(a+b)^2 =a^2+b^2+ 2ab(a+b) (a-b) = a^2-b^2(a-b)^2= a^2+ b^2 -2abHope it\'s usefull | |
| 42198. |
Find the point on x axis which is equidistant from (2,\t-5)and (-2,9) |
| Answer» 7 | |
| 42199. |
Is periodic test marks will be added in CBSE results according to revised syllabus? |
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Answer» A die is thrown once.Find the probability of getting 1. a prime number Yes it is included |
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| 42200. |
Prove that one and Only one out of n,n+2 and n+4 is divisible by 3 ,where n is any positive integer |
| Answer» | |