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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42601. |
Express 156 as the product of prime |
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Answer» Okk 2×2×3×13(Take lcm of it ) |
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| 42602. |
For what value of k the equation (k+3)x²-5(5-k)x+1=0 has roots |
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| 42603. |
Use Euclid\'s algorithm to find the HCF of 4052 and 12576. |
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Answer» According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r ≤ b.HCF is the largest number which exactly divides two or more positive integers.Since 12576 > 405212576 = (4052 × 3) + 420420 is a reminder which is not equal to zero (420 ≠ 0).4052 = (420 × 9) + 272271 is a reminder which is not equal to zero (272 ≠ 0).Now consider the new divisor 272 and the new remainder 148.272 = (148 × 1) + 124Now consider the new divisor 148 and the new remainder 124.148 = (124 × 1) + 24Now consider the new divisor 124 and the new remainder 24.124 = (24 × 5) + 4Now consider the new divisor 24 and the new remainder 4.24 = (4 × 6) + 0Reminder = 0Divisor = 4HCF of 12576 and 4052 = 4. 12576=4052×3+420 4052=420×9+272 420=272×1+148 272=148×1+124 148=124×1+24 124=24×5+4 24=4×6+0 HCF of 12576 and 4052 is 4. 12576=4052×3+4204052=420×9+272420=272×1+148272=148×1+124148=124×1+24124=24×5+424=4×6+0HCF of 12576 and 4052 is 4. |
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| 42604. |
Real number formal |
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| 42605. |
4tan²∅ -4/cosø |
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Answer» Ans: -4 Tan²□ +1 = Sec²□And 1/cos□ = sec□So 4( sec²□ - 1) -4sec²□ = -4 |
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| 42606. |
Is exercise 7.3 of coordinate geometry deleted? |
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Answer» Yes Yes Yes Yes Yes |
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| 42607. |
Evaluate: cos theta + sin theta/ cos theta minus sin theta |
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| 42608. |
Draw a line segment of length 7.6 cm and divide it in the ratio 5:8 . Measure the two parts . |
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| 42609. |
Find the zeroes of the quadratic polynomial y^2-3y+2. With the help of the graph. |
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| 42610. |
16/8-5/40×25/100 |
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| 42611. |
Exercise 7.1 |
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| 42612. |
Decimal expanssion |
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| 42613. |
9sec square A -9tan square A = |
| Answer» 9(sec square A - tan square A )=1,sec ^2-tan^2=9. | |
| 42614. |
9sec square A-9tan square A = |
| Answer» -9(sec2 A- tan2 A)-9(-1)=9 | |
| 42615. |
If sin theta + cos theta = p and sec theta + cos theta= q then prove that q(qsquare-1)=2p |
| Answer» Questions galat hai Cos thetha ki place par cosec thetha hoga | |
| 42616. |
Evaluate x+3/x+2- 3x-7/2x-3 =0 |
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| 42617. |
what are formula of all the chapter |
| Answer» What!!! | |
| 42618. |
What is the probability of getting a doublet if 2 dice were thrown simultaneously? |
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Answer» 1/6 6/36=1/2 36 1/6 3/2 |
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| 42619. |
Find the area of the shaded region .if pq=24 cm ,pr =7 cm and 0 is the centre of the circle . |
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Answer» Given,PQ=24cmPR=7cmO is the center of circleTo find shaded regionIn ∆PQRar(PQR)=1/2×PR×PQ1/2×24×7=84cm^2we know that RQ is the hypotenuse of ∆PQR and diameter of the circlethen,To find RQRQ^2=PR^2+PQ^2RQ^2=24^2+7^2RQ^2=576+49RQ^2=625RQ=√625RQ=25cmarea of circle semicircle,1/2πr^21/2π×(24)^2by solving using the value od π we get 6875/28Area of shaded region= Area of semicircle- Area of tirange pqr6875/28-84=4532/28ans where is the figure? |
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| 42620. |
What is clinometer ? |
| Answer» Statistics median | |
| 42621. |
Chapter surface area and volume exercise 13.1 |
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| 42622. |
Find the roots of the following quadratic equation by factorisation method5x^2-14x+6=0 |
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Answer» Real numbers 5x2 - 14x + 6=05x2-5x-6x+65x(x-1)-6(x-1)(x-1)(5x-6)x-1=0 & 5x-6=0x=1 & x=6/5 |
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| 42623. |
write the quadratic polynomial where sum of zero is 3 and product of zero is -4 |
| Answer» x^2−(sum of zeros)x+(product of zeros)Sum of roots = alpha +beta =-b/a=3Product of roots =alpha.beta =c/a= -4So, the Quadratic polynomial is X^2 - (3)x +(-4)=x^2 - 3x -4 | |
| 42624. |
Write the prime factor of 186 |
| Answer» I don\'t know ?? | |
| 42625. |
Cosec 4theta =2/√3 , find value of theta |
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Answer» Theta is 15 Theta =π/12 theta=15 |
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| 42626. |
Express 130 as the product of primes. |
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Answer» 2×5×13 2×5×13 2×5×13 2×5×13 2×5×13 |
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| 42627. |
solve 3x^2+5x+2=0 by factoring method |
| Answer» Please answee | |
| 42628. |
Kya is mein maths hindi mei nahi h kya |
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Answer» Ok No |
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| 42629. |
Write the value of 9+9 tan²A. |
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Answer» 9(1+tan^2 A) = 9 (sec^2A) 9(1+tan^2 A)= 9sec^2A 9secsquare |
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| 42630. |
Define to Pythagoras theorem |
| Answer» a theorem attributed to Pythagoras that the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides. | |
| 42631. |
Find hcf and lcm for 377,435&667 |
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| 42632. |
if sin square a=cos(a-6) |
| Answer» 6.25 | |
| 42633. |
गुड मोर्र्निंग |
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| 42634. |
Kx(x-2)+6 |
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Answer» Kx^2-2kx+6 Kx^2+2kx+6 Kx^2+2k+6 |
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| 42635. |
How to solve a quadratic equation with Completing square method ?? |
| Answer» It was not going to come in exam it is in reduction portion | |
| 42636. |
If sin theta equal to cos theta than find the value of theta |
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Answer» 45° If sin theta is equal to cos theta than the value of theta is 45° sin theta is equal to cos theta only for 1 value of theta and that is 45 degree ..so theta is equal to 45 degree 45° Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficient.(i) x²+7x+12 |
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| 42637. |
Find the root of the quadratic equation root 2x²+7x+5 root 2=0 by factorisation |
| Answer» = 2x^2 + 7x + 5 root 2= 2x^2 + 2x + 5root 2x + 5 root 2here factors are 2x and 5 root 2x= 2x( x + 1) + 5 root 2( x + 1) = (2x + 5root2) and (x+1) there fore x = -5 root 2 upon 2 i.e. - 5 upon root 2 or -1 | |
| 42638. |
For what value of k, the equation have equal roots 9x²+6kx+4=0 |
| Answer» 2,-2 | |
| 42639. |
Solve the pair of linear equation 2x - 3y=1,3x-4y=1 |
| Answer» Given equations :- 2x-3y=1 x = (1+3y)/23{(1+3y)/2} -4y = 1 (3+9y) / 2 -4 y = 13+9y-8y=23 + y = 2 Y = -2X = (1+3×-2) /2 =-5/2 | |
| 42640. |
Prove that ✓6 is irrational |
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| 42641. |
Find a quadratic polynomial whose zeroes are 2 and -5. |
| Answer» Sum of the zeroes =2 ...........Product of the zeroes = -5...............x2-(sum of the zeroes)x+(product of the zeroes).............x2-(2)x+(-5)............x2-2x-5 | |
| 42642. |
Zeroes of p(x) = x^2 - 2x - 3 are (a) 1, -3 (b) 3, -1 (c) -3, -1 (d) 1, 3 |
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Answer» 3 , -1 Ya exactly, I am getting the same answer. But in the book the answer is written as (a) 1, -3 b) 3, -1 |
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| 42643. |
When b²-4ac=0, then the quadratic equation ax²+bx+c=0 will have ____ roots. |
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Answer» Equal and real roots Two real and equal roots Equal roots Equal roots Two real and equal roots |
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| 42644. |
2A= cot(A-18°),2A=acute angle |
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| 42645. |
25x^2+30x+7=0 find the roots of these equations by quadratic formula |
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Answer» -30+√200/50 and -30-√200/50 x(-3+√2)/5 or x(-3-√2)/5 |
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| 42646. |
Determine k for 2xsquare+Kx+6=0 x=-2 |
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Answer» ➡️2x²+kx+6=0➡️2(-2)²+k(-2)+6=0➡️2(4)+k(-2)+6=0➡️8+k(-2)+6=0➡️K(-2)+14=0➡️K(-2)=-14 ➡️K=-14/-2➡️K=7Therefore, k=7 7 |
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| 42647. |
Therom 1.2 |
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| 42648. |
We have to do the solutions the the MCQs in maths exam? Or only answer is sufficient? |
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Answer» Solutions will give you full marks of questions while direct answers will just half marks H |
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| 42649. |
If mean is 56 find p. CI =0-20,20-40,40-60,60-80,80-100,100-120. F =16,11,25,P,12,10 |
| Answer» P=16 | |
| 42650. |
Find the x, (k-1) x^2+kx+1 |
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