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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42701. |
Find a quadratic polynomial the sum of whose zeros is 4 and one zero is 5 |
| Answer» =k{x² – (sum of zeroes)x + (Product of zeroes)}=k{x² – 4x + 5}ANS:- x² – 4x + 5 | |
| 42702. |
Find the point on x-axis which is equidistant from the points (2,-2) and (-4,2) |
| Answer» Let the point A(2,-2), B(-4,2) and (x,0) is equidistant from point P and Q.Now, using distance formula to find PA and AQ in both conditions PA=PB PA²=PB² (x-2)²+(0+2)² =(x+4)²+(0-2)² X²+4-4x+4=x²+16+8x+4 -4x+4=8x+16 X=-1Now, P(-1,0) | |
| 42703. |
form a quadratic polynomial whose zeroes are 3/5 and −1/2. |
| Answer» Sum of zeroes = 3/5+(-1/2)= 1/10Product of zeroes = 3/5*(-1/2) = -3/10 Quadratic polynomial = k( x^2-(sum of zeroes)x+product of zeroes) = k( x^2-1/10x+(-3/5)) = k(x^2-1/10x-3/5)Let k = 10 10(x^2-1/10x-3/5)Therefore, the quadratic polynomial is 10x^2-x-6 | |
| 42704. |
Find a quadratic polynomial whose zeroes are √5 +√2, √5-√2 |
| Answer» X²-2√2x+3 | |
| 42705. |
The length of the minute hand of a clock is 14cm. Find the area swept by the minute hand in 5 min |
| Answer» Area swept by minute hand is 51.3333cm | |
| 42706. |
Ex 8.4 question no. 5 |
| Answer» | |
| 42707. |
Circle chapter top 100 questions |
| Answer» Important 2 Marks Questions for Class 10 Maths Board are as follows-Question 1-\xa0Find the value of k for which the roots of the quadratic equation\xa02x2+kx+8=0, will have equal value.Question 2-\xa0Determine the AP whose third term is 5 and seventh term is 9.Question 3-\xa0If any point is equidistant from the points (a+b, b-a) and (a-b, a+b), prove that bx = ay.Question 4-\xa0If the line segment joining the points A(2,1) and B (5,-8) is trisected at the points P and Q, find the coordinates of P.Question 5-\xa0If, from an external point P of a circle with centre O, two tangents PA and PB are drawn such that\xa0∠BPA=120, then show that OP = 2PA.Question 6-\xa0Prove that the tangent drawn to a circle at the end points of a diameter are parallel to each other.Question 7-\xa0Find the value of p for which the numbers 2p-1, 3p+1, 11 are in A.P. Hence find the numbers.Question 8-\xa0Find the coordinates of the points of trisection of the line segment joining the points A (7,-2) and B (1,-5).Question 9-\xa0Find the coordinates of the point on x-axis, which is equidistant from the points (-2,5) and (2,-3).Question 10-\xa0A circle touches all the four sides of a quadrilateral ABCD. Prove thatAB + CD = BC + DAQuestion 11-\xa0Which term of the A.P. 8, 14, 20, 26, …….. Will be 72 more than its 41st term?Question 12-\xa0A line intersect the y-axis at the points P and Q respectively. If (2,-5) is the midpoint of PQ, then find the coordinates of P and Q.Question 13-\xa0Solve for x:\xa043–√x2+5x−23–√=0Question 14-\xa0Prove that the perpendicular drawn from the point of contact to the tnagent, passes through the centre of the circle.Question 15-\xa0Show that in two concentric circle, is bisected at the point of contact.Question 16-\xa0Find the ratio in which the point (-3,k) divides the line segment joining the points (-5,-4) and (-2,3). Hence find the value of k.Question 17-\xa0If the nth term of an A.P. is given by tn= 3n + 4, find the common difference of the A.P. and the sum of its first five terms.Question 18- In the figure below, the radius of incircle of\xa0ΔABC\xa0of area 84 cm2 is 4 cm and the lengths of the segment AP and BP into which side AB is divided by the point of contact are 6 cm and 8 cm. Find the lengths of the sides AC and BC. | |
| 42708. |
O is the center of circle of radius 5cm T is a point |
| Answer» Is not a full question | |
| 42709. |
In what ratio does the line x-y-2=0 divides the line segment joining (3, -1) and (8,9) ? |
| Answer» The answer is 2:3.... | |
| 42710. |
For what last value of \'n\' natural number is divisible by 9 |
| Answer» | |
| 42711. |
What is infinity +1 and infinity -1 |
| Answer» | |
| 42712. |
Does 22:3 and 33:24 proportion? |
| Answer» No these are not proportion. | |
| 42713. |
Solve - If sin( X+Y ) = cos( X−Y ) = 1, find the value of X and Y |
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Answer» Are you on ig plzz tell your name my name is samjoshi Hi Sin(x+y)=1 and cos(x-y) =1 from here put value of sin 90 =1 and cos 0=1 and add both equations , answer is x,=45 and y=45 degree |
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| 42714. |
prove the identity - (tan θ + secθ -1 ) / (tanθ - secθ +1) = (1+ sinθ) / cosθ |
| Answer» This is 3 step method first divide this values that are in upon like tan as cos or something and cross multiply than re arange it as you divided | |
| 42715. |
In a rhombus of side 10cm, one of the diagonal is 12cm long. Find the lengthof the second diagonal |
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Answer» Hii The length of other diagonal is 16 cm |
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| 42716. |
Basic Sample paper solve |
| Answer» Ya I have | |
| 42717. |
Write a negative integer and a positive integer whose difference is -3. |
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Answer» -8+5=-3 2-5=-3 -14-11=-3 (3 – 6) = (–3) |
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| 42718. |
Check whether the following are quadratic equation :16x^2-3= (2x+5)(5x-3) |
| Answer» 16x^2-3=10x^2-6x+25x-1516x^2-3-10x^2+15=19x6x^2+12-19x=06x^2-19x+12=0It is in ax^2+bx+c=0 formTherefore it is a quadratic equationHope this is helpful for you ??Thank u ?? | |
| 42719. |
IF x/3 +y/4 = 6 and x/6 + y/2 = 6 find the value of 3y _ 2x and x/y + 1/2 |
| Answer» x/3 + y/4=6Taking LCM4x + 3y = 72........(1) x/3 + y/4 = 6Taking LCM1x + 3y= 36.......(2) By elimination method. 4x + 3y = 72- - -1x + 3y = 36---------------------3x= 36X= 12 From eqn 23y = 36-12Y = 8Apply x and you value•3y-2x = 24-24=0•x/y + 1/2 = 12/8 + 1/2 = 12/8+4/8 = 16/8 = 2 | |
| 42720. |
Find the nature of the roots of the quadratic equation 2/x^2-5/x+2= 0 and solve it |
| Answer» The nature of the roots be real and distinct.. and roots be 2 , 1/2 .. | |
| 42721. |
(tan theta)/(1 - cot theta) + (cot theta)/(1 - tan theta) = 1 + sec theta*cosec theta |
| Answer» | |
| 42722. |
Formula of circular ring. Can one explain me? |
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Answer» Area=π®^2 ... Circumstance=2π® Area or perimeter How? Some question papers are locked please open all paper |
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| 42723. |
₹225 का 45% कितना होगा |
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Answer» 101.2 225×45÷100 101.25 225*45/100 101.25 bro |
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| 42724. |
Probability of 53 Saturday in non leap year |
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Answer» 1/7 1/7 |
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| 42725. |
State whether |
| Answer» Garbh nirdhan ki Vidya samjhaie | |
| 42726. |
if alfa+beta is the zero of polynomial then find 3x+x-4 |
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Answer» First of all go and make your question correct. Btw your question is wrong ➖ 1/4 |
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| 42727. |
The mean and median of a certain are 14 and 15 respectively.find the value of mode ? |
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Answer» 12 3 median = mode+ 2 mean(3)15=mode+ (2)1445 = mode+ 2845-28= mode17= mode |
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| 42728. |
find the nature of roots of quadratic equation 3x2-√7x+1=0 |
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Answer» Here, Discriminant is less than zero so it has imaginary roots.. 0 The given equation has real and unequal distinct roots The nature of the roots is Irrational |
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| 42729. |
write a quadratic equation with two different real roots |
| Answer» x² + 5x + 6 | |
| 42730. |
Find the coordination of the points where the line 5x-4y+20=0 intersect the y-axis |
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Answer» Write full answer (5,0) At (5,0) the equation is intersects y axis ??? ???????? ?? ?????????? ? ???? ??(5,0) |
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| 42731. |
1/(1+sin theta)+1/(1-sin theta) |
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Answer» 2sec0(theta) 2sectheta |
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| 42732. |
From the following frequency distribution prepare the more than o give |
| Answer» | |
| 42733. |
Do all question in basic math paper come from NCERT #manav |
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Answer» The paper of basic n standard either will come from NCERT or from exemplar. So we just need to do 2 things that is to solve exemplar n NCERT. Yes ,I would suggest that before solving the exercises ,just once solve the examples questions given before every exercises of NCERT .NCERT exercises +NCERT examples questions are enough for maths basic. |
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| 42734. |
Find the rational number between√2and√7 |
| Answer» | |
| 42735. |
If x=2sin2Ɵ and y=2cos2Ɵ+1, then find x+y. |
| Answer» | |
| 42736. |
d = √a^2+4a^2+9a^2+a^2 |
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Answer» /,-_)@+$&@)@/@)}©™©]©™©°€°£}¢\\∆€¶~×π|π`ש Jgydy |
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| 42737. |
Tan thita is equal to 11 |
| Answer» Not poss | |
| 42738. |
if secA - tanA =x |
| Answer» | |
| 42739. |
If cosec theta plus cot theta is equal to x.Then find cosec theta and cot theta |
| Answer» 1+cos theta / sin theta | |
| 42740. |
In the given figure, DE || BC, AD = 2 cm, BD = 2.5 cm, AE = 3.2 cm and DE =4 cm.Find AC and BC. |
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Answer» AD/BD = AE/EC ....... AD/(AD+BD) = DE / BC. Use these formulas. (ΔADE ~ ΔABC) AC =7.2 Where is the figure? |
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| 42741. |
if 5 is rational and -root3 is irrational then what is 5+foot 3 |
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Answer» Irrational Hey |
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| 42742. |
26 by 6 in decimals expission |
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Answer» 4.333333............. non terminating repeating 4.333333333.......... 4.333333333It means non terminating repeating decimal expansion.. |
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| 42743. |
26 by 6 in decimals expulsion |
| Answer» 4.33333333333.......... | |
| 42744. |
Find the roots of the quadratic equation 3x² - 2√6x + 2 = 0 |
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Answer» Thanks 3x2 - 2√6x +2 =0 =) (√3x)^2 - 2×√3x ×√2 + (√2)^2 = 0 =) (√3x - √2)^2 =0So √3x -√2 =0=)x = √2/√3 |
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| 42745. |
Prove that 2-√3/2 is irrational number. |
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Answer» Show that every positive integer is of the form 9q,and that every positive odd integer is of the form 9q,9q+1,9q+8,where q is some integer This contradicts the fact that root3 is irrational number.. Since contradiction has arisen in our assumption. Therefore we conclude that given number is also a irrational number |
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| 42746. |
A boat goes 16km upstream and 24km downstream |
| Answer» Please ask question with complete information. | |
| 42747. |
What are logarithms explain with example problems |
| Answer» Logarithms are another way of thinking about exponents.For example, we know that 2 raised to the 4th\xa0power equals 16. This is expressed by the exponential equation 24 = 16. | |
| 42748. |
S7 term is 49 and that of S17 is 289 then find nth term? |
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Answer» 2n-1 Dont know |
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| 42749. |
what is Thales theorem..pls give provement |
| Answer» If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio.ConstructionJoin the vertex B of {tex}\\triangle{/tex}ABC to Q and the vertex C to P to form the lines BQ and CP and then drop a perpendicular QN to the side AB and also draw PM{tex}\\perp{/tex}AC as shown in the given figure.ProofNow the area of\xa0{tex}\\triangle{/tex}APQ =\xa0{tex}\\frac {1}{2}{/tex}\xa0{tex}\\times{/tex}\xa0AP\xa0{tex}\\times{/tex}\xa0QN (Since, area of a triangle =\xa0{tex}\\frac {1}{2}{/tex}\xa0{tex}\\times{/tex}\xa0Base\xa0{tex}\\times{/tex}\xa0Height)Similarly, area of\xa0{tex}\\triangle{/tex}PBQ =\xa0{tex}\\frac {1}{2}{/tex}\xa0{tex}\\times{/tex}\xa0PB\xa0{tex}\\times{/tex}\xa0QNarea of\xa0{tex}\\triangle{/tex}APQ =\xa0{tex}\\frac {1}{2}{/tex}\xa0{tex}\\times{/tex}\xa0AQ\xa0{tex}\\times{/tex}\xa0PMAlso, area of\xa0{tex}\\triangle{/tex}QCP =\xa0{tex}\\frac {1}{2}{/tex}\xa0{tex}\\times{/tex}\xa0QC\xa0{tex}\\times{/tex}\xa0PM ...(i)Now, if\xa0we find the ratio of the area of triangles {tex}\\triangle{/tex}APQand {tex}\\triangle{/tex}PBQ, we have{tex}\\frac{\\text { area of } \\Delta A P Q}{\\text { area of } \\Delta P B Q}{/tex}\xa0=\xa0{tex}\\frac{\\frac{1}{2} \\times A P \\times Q N}{\\frac{1}{2} \\times P B \\times Q N}=\\frac{A P}{P B}{/tex}Similarly,\xa0{tex}\\frac{\\text { area of } \\Delta A P Q}{\\text { area of } \\Delta Q C P}{/tex}\xa0=\xa0{tex}\\frac{\\frac{1}{2} \\times A Q \\times P M}{\\frac{1}{2} \\times Q C \\times P M}=\\frac{A Q}{Q C}{/tex}\xa0...(ii)According to the property of triangles, the triangles drawn between the same parallel lines and on the same base have equal areas.Therefore, we can say that {tex}\\triangle{/tex}PBQ and {tex}\\triangle{/tex}QCP have the same area.area of {tex}\\triangle{/tex}PBQ = area of {tex}\\triangle{/tex}QCP ...(iii)Therefore, from the equations (i), (ii) and (iii) we can say that,{tex}\\frac{{AP}}{{PB}} = \\frac{{AQ}}{{QC}}{/tex}Also, {tex}\\triangle{/tex}ABC and {tex}\\triangle{/tex}APQ fulfil the conditions for similar triangles, as stated above. Thus, we can say that {tex}\\triangle{/tex}ABC\xa0{tex} \\sim {/tex}\xa0{tex}\\triangle{/tex}APQ.The MidPoint theorem is a special case of the basic proportionality theorem.According to mid-point theorem, a line drawn joining the midpoints of the two sides of a triangle is parallel to the third side. | |
| 42750. |
It is important that we will also solved the case based and McQs Question.... |
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Answer» Anybody else who answered me......By the way...... Exam was cancelled due to covid 19...?? Thanks btane ke liye No not that important..... Only the Correct option is enough Not important |
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