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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42751. |
In ex 1.1 q5 why b is taken as 3 not 9? |
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| 42752. |
Prove that Root3 is irrational number |
| Answer» If possible let √3 is a rational number Let √3 =a/b {a and b is co- prime number} = b√3 =a [ squaring both side][ b√3]²=[a]²= 3b²=a²................. (1) 3 is divides a²Their for 3 divides a Let a= 3c [ c is positive integer]Putting a=3c in equation (1) # 3b²= (3c) ² # 3b² = 9c² # b²= 3c² 3 is divides b²Their for 3 divides b 3 is common factor of A and B But It contradict the fact a and b are co-prime number So our assumlat is wrong Their for √ 3 is an irrational number. .......... Aakash Anand ? | |
| 42753. |
1/2(2x+3y)+ 12/7(3x-2y)=1/2; 7/2x+3y. + 2/3x-2y =2 |
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| 42754. |
find the indicated terms of the sequence whose nth terms are ( n -1 )( 2 - n )( 3 - n ) ; a1,a2,a3 |
| Answer» Here we have, an = (n - 1)(2 - n)(3 - n)Put n = 1a1\xa0= 1(1 - 1)(2 - 1)(2 - 2)(3 + 2) = 0Put n = 2a2\xa0= 2(2 - 1) (2 - 2)(3 + 2) = 0Put n = 3a3\xa0= 3(3 - 1)(2 - 3)(3 + 3) =\xa03 (2) (-1) (6) =\xa036 | |
| 42755. |
(1/2x)+(1/3y)=2(1/3x)+(1/2y)=13/6Solve this equation by eliminating method |
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Answer» Let 1/x=a,1/y=b,1a/2+1b/3=2(1a/3)+(1b/2)=13/6, Let 1/x=a,1/y=b,1a/2+1b/3=2(1a/3)+(1b/2)=13/6 Let 1/x be a and 1/y be b.a/2 + b/3 = 2 and a/3 + b/2 = 13/6.Now take LCM.3a/6 + 2b/6 = 2 and 2a/6 + 3b/6 = 13/6.Send the denominator to RHS.3a + 2b = 12 and 2a + 3b = 13.Multiplying eq 1 by 2 and eq 2 by 1 .We get 6a + 4b = 24 and 6a + 9b = 39.Now you can eliminate. |
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| 42756. |
Find the largest number which divides 438 and 606 leaving remainders 6 in each case. |
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Answer» 24 24 24 |
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| 42757. |
What are golden quadrilateral super highways |
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Answer» The answer isGolden quadrilateral superhighway is a one of the major highway in India.It links four mega cities of India which are Delhi-Kolkata-Chennai-Mumbai.It has installed because of reducing time between mega cities.And the it has 2 corridors which has from Gujarat to Assam.And Kashmir to kanyakumari.That\'s it GQSH are maintained by NHAI(National highway authority of India).It is linked by 4 major states such as Chennai-Mumbai-Delhi- Kolkata. It reduces traffic. |
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| 42758. |
Find the remainder when px³+x²+7x+2 |
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| 42759. |
What is the perimeter of the square |
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Answer» Perimeter of square=(4×side) 4 × side Perimeter of square (p)=4×side 4a 4a |
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| 42760. |
3/x-1/y+9=0,2/x+3/y=5 find x and y |
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Answer» Thanks x=-1/2. y=1/3 |
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| 42761. |
Our cbse class 10 exams have been cancelled so on what basis we got our result |
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Answer» Prebords Decide by CBSE after few days objective criteria? |
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| 42762. |
Bodmass |
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Answer» In BODMAS :B = BracketO = OfD = DivisionM = MultiplicationA = AdditionS = Subtraction Noice ? |
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| 42763. |
Cbse board exam of class 10 was cancelled due to covid 19........... |
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Answer» Very bad Everything happens for a reason... Haan toh naacho ab ?? Re bidu Maja aa gaya |
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| 42764. |
Chapter - 1Proof √5 is irrational number |
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| 42765. |
3x +2x =5x |
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Answer» Lollllllll Hjkd |
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| 42766. |
X square -3x - 10 =0 |
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Answer» Please like ,share and subscribe my video on YouTube. https://youtu.be/crGyWC-oxjc x = 5, -2. |
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| 42767. |
find theZero of the the polynomial if any-x²-2x+3 |
| Answer» - (x^2 + 2x - 3) = 0. (S = 2, P = -3, No :- 3, -1).x^2 + 3x - x - 3 = 0. x (x + 3) - (x + 3) = 0.(x - 1) (x + 3) = 0.x = 1 or -3// | |
| 42768. |
Show that any positive integer is of the form 3q or 3q+1 or 3q+2 for some integer q. |
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Answer» Let any positive integer be q. If divide q by 3 we get the remainders 0,1,2 which can be written as 3q, 3q+1, 3q+2 for some integer q. Hence any positive integer is of the form 3q or 3q+1 or 3q+2. I don\'t NO WkwjensnsnjeiA3b6b |
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| 42769. |
Cos theta - sin theta = |
| Answer» cos theta - sin theta = √sin^2 theta + cos^2 theta - 2 sin theta cos theta = √1 - 2 sin theta cos theta// | |
| 42770. |
If a IA |
| Answer» Iska Matlab?? | |
| 42771. |
For a natural number n, the number 6n will always end in the digit. |
| Answer» 6. Eg :- 6^2 = 36, 6^3 = 216, etc. | |
| 42772. |
Please give me notes of mathematics |
| Answer» Chapter? | |
| 42773. |
L.C.M OF 7060 |
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Answer» This is a wrong question ? LCM (60, 70) = 420. L.c.m of 7060 |
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| 42774. |
Sum of two natural numbers is 25 and their difference is 7 find the numbers |
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Answer» x=17 and y=8 16 and 9 |
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| 42775. |
7. If a = 3.5, d = 0, n = 105 then find value of n th term of AP |
| Answer» Since d = 0, n th term will always be 3.5. | |
| 42776. |
Cos=12/15 |
| Answer» sin A = 9/15. cos A = 12/15. tan A = 9/12. sec A = 15/12. cosec A = 15/9. cot A = 12/9. | |
| 42777. |
Find all the zeroes of the polynomial 8x4+8x3 -18x2-20x-5 if two of it\'s zeroes are √5/2 and √5/2 |
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Answer» p (x) = 8x^4 + 8x^3 - 18x^2 - 20x - 5. g (x) = (x + √5/2) (x - √5/2) = x^2 - 5/4. Now, on doing p(x) /g(x), we get quotient = q(x). Factorize q(x) to get the two other zeroes. 33 |
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| 42778. |
(5+6+3-2-5) |
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Answer» 21 7 will be the answer Do you really belong to class 10? |
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| 42779. |
Define potential difference... |
| Answer» Potential difference between two points is defined as the amount of work done in moving a unit charge from one point to another ie, V = W/Q. (where V is the potential difference, W is the work done and Q is the charge) | |
| 42780. |
If cos A is =12/5 then find the value of sin A + cos A |
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Answer» cot A = 12/5. Third side = √12^2 + 5^2 = √144 + 25 = √169 = 13// Therefore, sin A + cos A = 5/13 + 12/13 = 17/13// Sjgdfmjt |
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| 42781. |
290000÷557896=? |
| Answer» 0.51981014382 | |
| 42782. |
Divide the polynomial p(x) = x³-4x+6 by the 2-x² |
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Answer» The answer is wrong given by u 2-x^2√x^3-4x+6\\-x -x^3+2x ____________ -2x+6Quotient= -xRemainder= 6-2x |
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| 42783. |
find which are surds or not root 27× root 3 |
| Answer» √27 * √3 = 3√3 * √3 = 3 * 3 = 9.// Both are surds. | |
| 42784. |
Root 100 × root 2 find it surds or not with explanation |
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Answer» 10√2 √100 * √2 = 10 * √2 = 10√2.//. |
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| 42785. |
Q1. Prove that there is no natural number for which 12h ends with the digit zero. |
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| 42786. |
Find the HCF of1008 and 1080 by prime Factoriston method |
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Answer» Answer: 72 1008 = 2*2*2*2*3*3*71080=2*2*2*3*3*3*5hcf is common factors of both the numbershcf(1008,1080) = 2*2*2*3*3=72 |
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| 42787. |
What is the hcf of 13 and 72 by Euclid\'s theorem |
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Answer» Using Euclid\'s Division Lemma a=bq+r Where, 0<_ r The HCF (72, 13) by Euclid\'s algorithm/theorem is:a = bq + r (0<_r |
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| 42788. |
Find the zero |
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| 42789. |
What is the formula of sum |
| Answer» Sn=n/2{a+a+(n-1)d} | |
| 42790. |
32(57)√45 |
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Answer» 1824√45 1824/45 1824√45 1824✓45 |
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| 42791. |
2x +4y=10 |
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Answer» Yes 2x+4y-10X=2, y=4, -10 Y=2 X=1 |
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| 42792. |
Find all the zeroes of the polynomial 2x4 + 7x – 19x2 – 14x + 30, if two of its zeroes are √2, -√2 |
| Answer» 2x⁴+7x-19x²-14x+30 | |
| 42793. |
Can x^2 -1 be the quotienr on division of x^6 - 2x^3 + x - 1 by a polynomial in x of degree 5 |
| Answer» Hi | |
| 42794. |
Find the H.C.F of 36 , 96 and 120 by Euclid\'s division lemma |
| Answer» Euclid\'s division algorithm is to compute the highest common factor (HCF) of two or three given positive integers.Euclid\'s division lemma states that for any two positive integers say a and b there exists two unique whole number say q and r , such that ,a =b q+r , where 0 ‹ r ‹b.Solution : on applying Euclid\'s division lemma for 36 and 96 96 = 36 ×2 +24Here , remainder = 24≠0 So take new dividend as 36 and divisor as 24.36=24×1+12Here,the remainder=12≠0So,take new dividend as 24 and divisor as 12.24=12×10+0Here,the Remainder=0 and the last divisor is 12 .So, HCF of 36 and 96 is 12.On applying Euclid\'s division lemma for 12 and 120 120=12×10+0Here remainder=0So ,HCF of 36,96 and 120 = 12. | |
| 42795. |
Find the zeroes of 3x²+x-1 and verify their relationship. |
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| 42796. |
find the hcf of 8(x² - 4) ; 12(x³ + 8) and 36(x² - 3x - 10) |
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| 42797. |
Find the zeroes x^2-3 |
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Answer» √3 ans. X = √3 , x = -√3 X=0 |
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| 42798. |
Cos48. -sin42. |
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Answer» Answer is 0 The answer is 0 The answer is 0.276377208 |
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| 42799. |
Exercise 3.2 all answer |
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| 42800. |
(A+b)^× |
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