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42851.

The area of triangle formed by x+3y= 6 , 2x-3y=12 and the y-axis is

Answer»
42852.

2x-y=4,3y-x=3.Also,find the coordinates of the points where these lines interact the 2 axes

Answer»
42853.

Sin¶=√3÷2, find the value of all t- ratios of ¶

Answer» Sin 60°=√3/2 therefore ¶=60°Cos60°=1/2Tan60°=√3Cosec60°=2/√3Sec60°=2Cot60°=1/√3
Sin 60° = Root 3/ 2 , so , theta = 60°
42854.

(-5,7) (3,-1)

Answer»
42855.

Find a quadratic polynomial whose zeros are -9 and -1/9

Answer» Your answer is ( 9xpower2+80x-1)
42856.

What is 2 raise to power 100

Answer» 1267650600228229401496703205376
2×2^99
42857.

2y+12y-432=0 factor

Answer» 2y²+36y-24y-432=02y(y+18)-24(y+18)=0(Y+18) (2y-24) =0Y=-18 or y =12
30.85
42858.

The difference between two numbers is 26 one number is three times the other. Find it.

Answer» 13 and 39
Let the large number be XLet the small number be YAccording to the question,=》X–Y=26 =》X=26+YTHEN,X=13YPutting the value of X we get =》26=3Y–Y =》26=2Y=》13=YSo the value of x=3YPutting the value of Y we get =》X=3×13 =》X=39HENCE,THE NUMBERS ARE 13 and 39
42859.

Prove that 10+5√3 is irrational

Answer»
42860.

Kisi ke pas 10th ki ml aggarwal book hai Kya ka math ki

Answer» Solution hai
Yes hai
Yes hai
Code 041 APC
Anyone tell me
42861.

33x² - 267x + 252 =0 Solve this equation in detail

Answer» 33x2-267x+252= 3(11x2-89x-84)=0=11x2-89x+84=11x2-77x-12x+84=11(x-7) -12(x-7)=(11x-12)(x-7) =12/11,7
X=12/11 , X=7
42862.

If sin A=3/4,calculate cos A and tan A

Answer» √7/4 , 3/√7
42863.

Find tan 15degree tan60 degree tan 75 degree

Answer» Tan 15° = (90°-75°)Cot =cot 75° = 1/tan 75° So, Tan 15° = 1 / Tan 75°.....[1] Tan 60° = √3According to question :-= Tan 15° * Tan 60° * Tan 75°= 1/Tan 75 ° * Tan 75° * Tan 60°= 1 * √3= √3 Answer :- √3
Hello
42864.

Solve for x and y by elimination method :4x-3y=7x+2y=3

Answer» (x, y) =(5/2, 1)
42865.

P(x)= 3x^4+5x^3-7x^3-2x+2,g(x)=x^2+3x+1

Answer»
42866.

2x2+3X+1=0

Answer» Given\xa02x2+3x+1=0On comparing this equation with\xa0ax2\xa0+ bx + c = 0, where\xa0a = 2, b = 3, c = 1∴\xa0b2\xa0− 4ac = (5)2\xa0− 4 × 2 × 1= 9 − 8= 1x = −b±b2−4ac\u200b\u200b / 2a= −3±1\u200b\u200b /\xa02×2x = −3+1 / 4\u200b\xa0or\xa0x = −3−1\u200b / 4x = −2 / 4\u200b\xa0or\xa0x = −4\u200b / 4x = −1/2\u200b\xa0or\xa0x = −1
42867.

Solution for 9x²+14x-8 using completing square method

Answer» Solution for 9x^2-14x-8=0 equation:Simplifying9x2 + -14x + -8 = 0Reorder the terms:-8 + -14x + 9x2 = 0Solving-8 + -14x + 9x2 = 0Solving for variable \'x\'.Factor a trinomial.(-4 + -9x)(2 + -1x) = 0Subproblem 1Set the factor \'(-4 + -9x)\' equal to zero and attempt to solve:Simplifying-4 + -9x = 0Solving-4 + -9x = 0Move all terms containing x to the left, all other terms to the right.Add \'4\' to each side of the equation.-4 + 4 + -9x = 0 + 4Combine like terms: -4 + 4 = 00 + -9x = 0 + 4-9x = 0 + 4Combine like terms: 0 + 4 = 4-9x = 4Divide each side by \'-9\'.x = -0.4444444444Simplifyingx = -0.4444444444Subproblem 2Set the factor \'(2 + -1x)\' equal to zero and attempt to solve:Simplifying2 + -1x = 0Solving2 + -1x = 0Move all terms containing x to the left, all other terms to the right.Add \'-2\' to each side of the equation.2 + -2 + -1x = 0 + -2Combine like terms: 2 + -2 = 00 + -1x = 0 + -2-1x = 0 + -2Combine like terms: 0 + -2 = -2-1x = -2Divide each side by \'-1\'.x = 2Simplifyingx = 2Solutionx = {-0.4444444444, 2}
42868.

X + x =

Answer» 2x
2x
2x
2x
2x
42869.

.If (α β ) are the zeroes of the quadratic polynomial ax²+bx+c then α +β =....

Answer» α +β= -b/a = bx/ax² = b/ax
42870.

8x+5y=11,x+y=4

Answer» X=-3 and Y=7
Our value is xX -3 and y is 7
First multiply by 5 in equation second then we get 5 x + 5 Y = 20 now put the elimination method subtract equation first from second then we get - 3 x = 9 therefore the value of x is -3 put the value of x in second equation then we get the value of Y = 7
42871.

find the sum of APs

Answer» Ap kha h
42872.

What is the basis of Euclid division algorithm

Answer» a=bq+r
A is equal to B Q plus R
a=bq+r, where r is equal or greater than 0 and smaller than b
a = bq +r (0<_r
42873.

Find k so that the quadratic equation (k+1)x square-2(k+1)x+1=0, has equal roots.

Answer» k=3
42874.

15674+54456

Answer» 15674 + 54456 = 70130
70130
70130
70130
70130
42875.

If alpha and beta are the zeros of the polynomial x^2 -4 root 3 +3 find alpha ^2 +beta ^2 +alphabeta

Answer»
42876.

Why circumference of circle is 2×pai×radius ?

Answer» π\xa0is defined to be the ratio of the circumference of a circle over its diameter (or 2 times its radius).This ratio is a constant since all circles are geometrically similar and linear proportions between any similar geometric figures are constant.If you were looking for how the value of the ratio\xa0π\xa0is calculated or how we know that the same ratio applies to the area of a circle, then those are different questions. (Ask if either of these are what you were looking for).
42877.

From which book we have to study maths class 10 to score 100 in mcq paper tell me

Answer» Ncert
NCERT ,rd Sharma ,rs Aggarwal , NCERT exampler, etc.
Solve more and get more means marks
NcertRead the concepts carefully
Ncert exampler
42878.

3x+60y=3900

Answer» Eska factorisation nahi hoga agar esko shridharacharya rule se kare to nahi aa raha hai
42879.

Find all the zero\'s of the polynomial x³+10x²-9x-4 if one of its zero is one

Answer»
42880.

The roots of quadratic equation 7x2+x-1=0

Answer» 2,13/7
42881.

Value of π=??

Answer» 22/7 or 3.14
But π≠22/7 but it is appropriate value.
22/7
3.14
22/7
42882.

The fourth term of an A.P is 0 . Prove that it 25th term is triple it\'s 11th term ???

Answer» Search in goggle
Put appropriate question
Hii
42883.

How we can easily assume the value for x in linear equations for drawing graph of smaller units?

Answer»
42884.

Which of the following number have terminating decimal 16/225,5/18,2/21,7/250

Answer» 7/250 with division of 2 × 5^3 which is sign of terminating decimal
16/225
16/225
42885.

If cot = 15/8, then evaluate (2+2sin)(1-sin)/(1+cos)(2-2cos)

Answer» 15/under root 32
(2+2 sin A) (1-sin A)/(1+cos A) (2-2 cos A)= 2(1+sin A) (1-sin A)/2(1+cos A) (1-cos A)= (1-sin2A)/(1-cos2A)= cos2A/sin2A= cot2A= 225/64
42886.

If in triangle abc right angled at b , sinC = a²-b² / a²+b², then cosC equals to Plz help...

Answer»
42887.

The expression of the Polynomial represented by the graph is

Answer»
42888.

if x =2^3 3 5 ^2 ,y=2^2 3^3

Answer» Your questions is not clear
42889.

Solve by elimination method√5x - √7y = 0√7x - √3y = 0Find the value of x and y

Answer» First of all we will squaring all the terms = (√5x)² - (√7y)²=0 ,(√7x)² - (√3y)²=0After that is becomes = 5x–7y=0 -this will be equation 17x–3y = 0 -this will bhi equation 2We multiply equation 1 from 7 and equation 2 from 5 Then it eq 1×7 subtract eq 2×5Eq 1- +35x – 49y = 0Eq 2- ± 35x ± 15y = 0 ————————— 0 34y = 0Y = 34Now we put the value of \'y\' in eq 15x–7y = 05x–7×34 = 05x–238 = 0X = 238/5X = 47.6Y = 34
42890.

If DE//BC,find x

Answer»
42891.

If De parallel BC is equals to 1.5 cm equals to 3 cm = 21 CM then find BC

Answer»
42892.

943-514

Answer» 429
429
42893.

Chapter triangle exercise 6.2 question no. 9 class 10th

Answer» Ftyhb
42894.

(-3) -(-2) -(-3) +9-10+12=

Answer» 13
13
-3+2+3+9-10+12. = 2-1+12 =13
4 is the answer
13
42895.

Solve the quadratic equations by factorisation method:x\'2-9=0(1)

Answer»
42896.

Find the coordinates of the point which divides the join of (-1,7)and(4,-3) in the ratio 2:3

Answer» Coordinates (1,3)
Coordinates- (1,3)
42897.

Half-year try

Answer»
42898.

15/1600

Answer» 0.009375
0.234375
42899.

cos^4(theth) =(a^2 -1)/(a^2 +1) find the value of sec( theta) + tan(theta)

Answer»
42900.

Ex

Answer» Exercise