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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42951. |
If sin 2A=1/2 tan²45. |
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Answer» A =15 A= 15° A=15 ° A= 15° |
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| 42952. |
X2+99x+127 |
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Answer» D = b²-4.a.c = 9801-508 = 9293So , x = {-99(+-)√9293}/2 Ans. 127 ke LCM leke |
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| 42953. |
Xcos A = 8, 15 cosec A = 8 sec A |
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Answer» 1/8 1/8 |
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| 42954. |
The distance between the points (a cos + b sin, 0) and (0, a sin - b cos ), is: |
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Answer» Root of a square + b square Root of a^2 + b^2 |
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| 42955. |
The radius of a circular field is 35cm how many round should be taken round the |
| Answer» 1540/35 m44mIt should take about 44 rounds. | |
| 42956. |
How to find a centroid of triangle? |
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Answer» (x= X1+X2+x3/3) and (y= y1+y2+y3/3) X1+X2+X3/3 H²=b²+p² X1+x2+x3/3 By applying folmula of x1+ x2 +x3 divided by 3 |
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| 42957. |
(Sin Theta + Cos Theta)^2 + (Sin-Cos Theta)^2^1/2 |
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Answer» [(sinA + cosA)**2 + (sinA - cosA)**2] ** 0.5 = [ 2 { (sinA)**2 + (cosA)**2 }] ** 0.5 = (2*1)**0.5 = 2**0.5 Sorry I did a mistake 2 1 Root 2 |
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| 42958. |
If A is acute angle then prove that 1+ cotsq A =cosec o |
| Answer» =1+cossqA/ sinsqA=SinsqA+ cossqA/ sinsqA=1/sinsqA=cosecsq A | |
| 42959. |
3x means |
| Answer» "3x" means => 3 multiplied by x or 3*x | |
| 42960. |
(2-√6)+(6-√2) |
| Answer» 4.13629669 | |
| 42961. |
Is 4.57 bar is an irrational no. |
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Answer» No 4.57 is a rational number Ha No, 4.57 is rational number. |
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| 42962. |
4.57bar is an |
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Answer» 4.57bar is an rational no Is 4.57 bar is an irrational no. 457000 |
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| 42963. |
What is the pass mark for class 10 term 1 exam |
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Answer» 15 16 There is no pass marks such. Term 1 and 2 together 33 marks 30 A |
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| 42964. |
If hcf 39,91=13,then LCM 39,91= |
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Answer» 273 Lcm ×hcf=product of no. 39×91=13×lcmLcm= 273 |
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| 42965. |
Sec⁴-sec² |
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Answer» Sec² I think your question is not complete so please checkout our question . |
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| 42966. |
Are the board copies checked by computer |
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Answer» No No No No No |
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| 42967. |
Quadratic equations : ( x - 2 ) ( x + 1) = (x-1) (x+3) |
| Answer» (x−2)(x+1)=(x−1)(x+3)⟹x 2 +x−2x−2=x 2 +3x−x−3⟹x 2 −x 2 +x−2x−3x+x−2+3=0⟹−3x+1=0 | |
| 42968. |
Is x= -4 a solution of 2x²+5x-3=0 ? |
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Answer» It is not a sol as it is not satisfying the quad.eqn. Ans:-9 9 |
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| 42969. |
Draw a line segmemt of length 8.4 cm and dinde it in ratio 4:7 mesure the two part |
| Answer» | |
| 42970. |
2 cubes each of volume 64cm^3 are joined end to end . Find the surface area of the resulting cuboid |
| Answer» 80cm^3 | |
| 42971. |
tan²A+cot²A+2=secA+cosec²A |
| Answer» bhai term 2 me trigonometry nahi aa rahi .... | |
| 42972. |
Sin A + Cosa= |
| Answer» 1 | |
| 42973. |
3±6 |
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Answer» 3+6=9, 3-6=-3 3+6=9 , 6+3=9 , 3-6=-3 , 6-3=3 3+6=9 , 3-6= -3 |
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| 42974. |
Find the roots of the following quadratic equation2x^2-2√2x+1=0 |
| Answer» a=2, b=2√2, c=1b^2-4ac=8-8=02√2-+√0/4=√2/2x=1/√2Ans=1/√2, 1/√2 | |
| 42975. |
find the sum of the first 22 terms of the AP 2,7 ,12 .....using formula |
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Answer» 1199 Answer will be 1199 |
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| 42976. |
In the equation x+y=10 , if x=6 then find the value of y |
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Answer» Y is 4 y=10-6=4Therefore y=4 |
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| 42977. |
Find Median:02Class 35-45 45-55 55-65 65-75 75-85 85-95F238665 |
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| 42978. |
∆BAT-∆ACB |
| Answer» | |
| 42979. |
Is this to make more than 4 tangets on circle |
| Answer» Hlo | |
| 42980. |
From Quadratic equations ..16x -10/x = 27 |
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Answer» 16x-10/x=2716x^2-10/x=2716x^2-10=27x16x^2-27x-10=016x^2-32x+5x-10=016x[x-2] +5[x-2]=0[16x+5] [x-2]=0 16x+5=0 OR x-2=016x=-5 x=2x=-5/16 Take \'x\' as LCMand proceed your steps. you\'ll get an quadratic equation. |
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| 42981. |
Slove the equation |
| Answer» | |
| 42982. |
How many tengents in a circle |
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Answer» Infinite. Infinite Infinite Infinite |
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| 42983. |
ad=3cm ,db=6cm, ae=2cm,ec=? |
| Answer» | |
| 42984. |
. If the seventh term of an A.P. is 1/9 and its ninth term is 1/7, find its 63rd term. |
| Answer» | |
| 42985. |
Find the mean of 1,2,3,.....n |
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Answer» 1+2+3=66÷3=2 1+2+3/36/3=2 2 |
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| 42986. |
Bpt theorem easy |
| Answer» | |
| 42987. |
If the 7th times the 7th term of an AP is equal to 11th times of 11th term then find its 15th term.. |
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Answer» 7(a+6d)=11(a+10d)7a+42d=11a+110d 0 =11a- 7a+110d-42d 0 = 4a+ 68d 0 = 4(a+17d) 0 = a+ 17 d ( as 4 goes to LSH and 0/4=0) 0 = a18Please check question properly 7(a+6d) =11(a+10d) 7a+42d = 11a+110d0 = 11a-7a+110d-42d0 = 4a+68d-68d=4a-68d/4=a-17d=aa 18= a+17da 18=-17d+17da 18 = 0Therefore the answer is 0 and please see the question properly it\'s not 15th term it\'s 18th term |
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| 42988. |
25+28+31......100 |
| Answer» a=25 ,d=28-25=3,an=100an=a+(n-1)d100=25+(n-1)3100=25+3n-3100=25-3+3n100=22+3n100-22=3n78=3nn=78/3n=26 answer | |
| 42989. |
Ex 5.1 |
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Answer» First question 5.1 part 4 full |
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| 42990. |
How we can solve cubic equations ? |
| Answer» | |
| 42991. |
Tips to became a topper from average student |
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Answer» Self study After school and before Coaching Kitna bhi padh le vro top to sharma uncle ka beta ji karega.... |
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| 42992. |
The required solution of 4x2 – 25x = 0 are |
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Answer» Ok thanks 4x^2 - 25x = 0x(4x - 25 = 0)4x - 25 = 0/x4x - 25 = 04x = 25x = 25/4 = 6.24 |
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| 42993. |
Find the product of the roots of 1upon under root 6 x square minus 3x minus 1 upon underoot 2 |
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| 42994. |
What is the formula of mode and median |
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Answer» I+ (n/2-cf/f )/f Mode=l+(f1-fo/2f1-fo-f2)h |
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| 42995. |
Whole root 100-1000+12313-34674×1247÷154346= |
| Answer» Bro what a nice questionTook me 1 hour to do it Finally got.....INVALID INPUT?? | |
| 42996. |
Give detail Project |
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Answer» Cgjgjkggkj diff official usual XP zip zip zip xp do xp zip xp xp GP xp xp xp ?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️?️ Hi |
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| 42997. |
find the degree of polynomial 2x+5-(x²+2x-5) |
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Answer» 3 2 It is 3 because when we multiply x² by 2x it becomes 2x³ 3 2 |
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| 42998. |
Polynomial of 2x+3x=0 |
| Answer» 2x+3x=05x=0X=-5 | |
| 42999. |
Class 10 page no 12 |
| Answer» | |
| 43000. |
Find Factors using Factorisation.(i) 5²-25-399(ii) 5k²-30k-360(iii) 5x²+35xy-600y² |
| Answer» | |