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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42801. |
If I want PCB in 11th so what maths I take Standard or Basic in 10th??? |
| Answer» If you would like to continue with maths for 11th and 12th and furthermore, I would prefer you take standard maths in 10th as it will give a continuity in conceptualisation while you move from 10th to 11th. Else, you are free to take Basic maths. | |
| 42802. |
a2x2-3abx+2b2 =0 |
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| 42803. |
If one of the zeroes of the quadratic polynomial (p – l)x² + px + 1 is -3, then the value of p is |
| Answer» P=4/3 | |
| 42804. |
The nth term of an A.P. is given by an = 3 + 4n. The common difference is |
| Answer» a1=3+4(1)=3+4=7 . a2 =3+4(2)=3+8=11 ..common difference =a2-a1 11-7 =4 . Note -In the place of n substitute the term like 1,2,3.... So on & then find the difference of consecutive term . | |
| 42805. |
The LCM and HCF of two numbers 675 and 45.If one of the number is 135,then find the other number? |
| Answer» We know,Product of two no. = HCF*LCMSo, 135*other no. = 45*675 Other no. = 30,375 / 135Therefore, Other no.= 225 | |
| 42806. |
Use Euclid\'s algorithm to find HCF of 1190 and 1445.Express the HCF in the form 1190m+1445n |
| Answer» | |
| 42807. |
Internal diameter of a hemispherical cup is 7 cm . Find its inner surface area. |
| Answer» Diameter = 7 cm. Therefore, Radius = 7/2 cm.// Thus, inner surface area of a cup = CSA = 2πr^2 = 2 * 22/7 * 7/2 * 7/2 = 77 cm^2// | |
| 42808. |
Find the smallest number which when increased by 3, is divisible by 12,15and 18. |
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Answer» 177 Zero |
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| 42809. |
Ncert exemplar is best or rs Agarwal for maths class 10 plz tell me |
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Answer» NCERT EXEMPLAR Is best and if other than this is RD Sharma Ncert is best... |
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| 42810. |
Oswaal question bank is best or any another |
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| 42811. |
Prove that cube root 6 is irrational. |
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| 42812. |
Find the all zeroes of f(x) : x2 - 2x |
| Answer» Given, f(x) = x^2 - 2x. Therefore, f(x) = 0. x^2 - 2x = 0. x (x - 2) = 0. Thus, zeroes are 0 and 2. | |
| 42813. |
Prove that 2+√3 is an irrational number , given that √3 is irrational number. |
| Answer» Let\'s suppose 2+√3 be rationalSince 2+√3 - 2 also be rational ( difference of two rational number is rational ) Now 2+√3 - 2 = √3 which is rationalBut this contradicts the fact that √3 is irrationalThe contradiction arises by assuming √3 rationalTherefore; 2+√3 is irrationalHence proved . | |
| 42814. |
the product of three consecutive positive integers is divisible by 6 is this statement true or false |
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Answer» The statement is true that the product of any three consecutive positive numbers can be divisible by 6. Yes this is true Yes,For example Let\'s assume the 3 consecutive integers be 2,3,4 2×3×4/6 = 24/6 = 4See its divisible by 6 |
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| 42815. |
Square roit of 16 |
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Answer» 4 4 4 is the correct square root of 16 4 is the square root of 16 256 is the square root of 16 |
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| 42816. |
Define HCF of two positive integers and find the HCF of the following Pairs of number 32 and 54 |
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| 42817. |
If the product of the zeros of x2-3kr+2k2-1. Find the value of k |
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| 42818. |
What is the value of 64 3/2 |
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Answer» 96 96 |
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| 42819. |
Find the zeroes of the polynomial x square +7x-12 . |
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| 42820. |
Find the simplest form of 1095/1168 |
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Answer» 15/16 15/16 15/16 1095/1168= 73*15/73*16So, 73 n 73 gets cancelled and the answer comes out is 15/16. |
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| 42821. |
Prove that ( 3 + 2 ) is irrational |
| Answer» It is not irrational if we add 3+2 we get 5 so 5 is rational | |
| 42822. |
Theta samjhaie |
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| 42823. |
For what value of k( 4 ) is a zero of the polynomial x2- x - ( 2 k - 2 ) |
| Answer» ? | |
| 42824. |
Solve for x, using the quadratic formula: ???^2 − (?^2 + ?^2)? + ?? =0 |
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Answer» abx2−(a2+b2)x+ab=0x=−b±b2−4ac\u200b\u200b/2ax=−(−a2−b2)±(−a2−b2)2−4abab\u200b\u200b/2abx=b/a\u200b , a/b\u200b X=a/b, b/a |
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| 42825. |
Divide using long division method 5x⁴+x²-8x+25 by x-4 |
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| 42826. |
factories 2x2-5x+7 |
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Answer» It cannot be solved by factorisation method 5/2,7/2 |
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| 42827. |
2x²-5x+7 factories |
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Answer» 2x²-5x+7 2x²-(2+7)x+7 2x²-2x-7x+7 2x(x-1)-7(x-1) (2x-7)(x-1)HOPE IT HELPS U 2x²-5x+72x²-(2+7)x+7 2x²-2x-7x+7 2x(x-1)-7(x-1)(2x-7)(x-1) answer |
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| 42828. |
23+56 |
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Answer» 79 79 79 79 |
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| 42829. |
4-1 |
| Answer» 3 | |
| 42830. |
X-3y=7 3x-3y=15 |
| Answer» Given :\xa0To Find : solve it by cross multiplication methodSolution:Cross multiplication methodEquations :\xa0Comparing the given equationsSo, x = 4 and y = 1 | |
| 42831. |
Show that any positive integer is of the form 3q, 3q+1, 3q+2, where q is some integer |
| Answer» Let p be any positive integer and b = 3. Applying division Lemma with p and b =3 ,we havep = 3q + r, where 0 {tex}\\leq{/tex}\xa0r < 3 and q is some integerSo r=0,1,2If r=0 , p=3qIf r=1, p=3q+1If r=2, p=3q+2Therefore any positive integer is of form 3q,3q+1,3q+2 for some integer q. | |
| 42832. |
(1+1/tan^2A) (1+1/cot^2A) = 1/cos^2-cos^4 |
| Answer» LHS=(1+1/tan²A).(1+1/cot²A)=(1+cot²A).(1+tan²A)=cosec²A.sec²A=1/(sin²A.cos²A)=1/{(1-cos²A)cos²A}=1/(cos²A-cos⁴A) = RHS(Proved) | |
| 42833. |
An army |
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| 42834. |
Give the HCF of 306 and 657 is equal to 9 find LCM of 306 and 657 |
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Answer» We will use the formula to find the LCM of\xa0306 and 657.LCM (a, b) = (a × b) /\xa0HCF (a, b)Given two numbers 306 and 657 and their HCF is 9.To find : LCM(306,657 )using the formula,We haveLCM (306, 657) = (306 × 657) /\xa0HCF (306, 657)= 201042 / 9\xa0= 22338Thus, LCM\xa0of 306 and 657 is 22338 **** up your bur |
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| 42835. |
Explain why ( 17×5×11×3×2+2×11) is a composite number ? |
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Answer» Composite n are the no which r not prime n have factors other than 1So 17*5*11*3*2+2*1 = 5610Factor of 5610= 2,3,5,11,17Therefore it\'s a composite number 11(17×5×11×3×2+2×1)Since the given number has more than two factors it is a composite number |
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| 42836. |
Sin18०/cos72० |
| Answer» Sin(90-72)/Cos 72 Cos72/Cos72 = 1 | |
| 42837. |
Class 10 chapter 1 solution |
| Answer» Euclid division lemma | |
| 42838. |
Monitor oxygen saturtior with a pulse oximanter daily |
| Answer» Please ask question with complete information. | |
| 42839. |
Express the HCF of 468 and 222 as 468x + 222y where x and y are integers. |
| Answer» By Euclid’s division algorithm,HCF of 468 and 222 is468 = (222 x 2) + 24 ----------------------(1)222 = (24 x 9) + 6 ------------------------(2)24 = (6 x 4) + 0 So the HCF of 468 and 222 is 6.Now we have to write 6 as 468x + 222y6 = 222 - (24 x 9) ---------------\xa0[ from (2) ]Now write 24 as (468 – 222 x 2)\xa0--------------\xa0[ from (1) ]⇒ 6\xa0= 222 - {(468 – 222 x 2) x 9 = 222 - {468 x 9 – 222 x 2 x 9} = 222 - (468 x 9) + (222 x 18) = 222 + (222 x 18) - (468 x 9) = 222[1 + 18] – 468 x 9 = 222 x 19 – 468 x 9 = 468 x -9 + 222 x 19So HCF of 468 and 222 is (468 x -9 + 222 x 19) in the form 468x + 222y. | |
| 42840. |
solve the following equation for the value of x and y 1) ax/b - by/a =a+b 2) ax-by =2ab |
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| 42841. |
If one solution of 3x2-8x-(2k+1) is seven times the other, find the value of k |
| Answer» p(x)=3x²-2k+1zeroes=α,7αsum of zeroes= - b/aα+7α= -(2k/3)8α=2k/38α×3=2k24∝=2kk=12∝ (1)product of zeroes= c/a∝×7∝=1/37∝²=1/3∝²=1/(3×7)∝²=1/21∝=±1/√21∵∝=±1/√21∴k=12(±1/√21)k = ±12/√21 | |
| 42842. |
. Prove that 7-2√3 is an irrational number. |
| Answer» Let assume that 7-2root3 be rational and rational numbers are in the form of p/q form.We know that root 3 is irrational and not p/q form. It contradicts the statement that it is irrational as it is p/q form.Subtraction and multiplication of irrational number form irrational number so\xa07-2root3 is irrational. | |
| 42843. |
5+90 |
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Answer» 95 95 |
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| 42844. |
Find the roots of the following |
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| 42845. |
Please send me maths CH 1 PDF rd sharma |
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Answer» Ok https://us04web.zoom.us/j/73719190282?pwd=Z3lEbC9KUDNwOCtqYWxCK2FlL2Yvdz09 |
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| 42846. |
2x^2 + 13x + 20 |
| Answer» 2x² + 8x + 5x + 202x(x+4) +5(x+4)(2x+5)(x+4)X=- 5/2 or -4 | |
| 42847. |
5x+7y=507x+5y=46 Cross-multiplication method |
| Answer» 5(5x+7y=50)7x+5y=46Subtract18x = 204X=204/18X=11.3Y=5(11.3) +7y =5o | |
| 42848. |
Find rational number between 2/5 and 12/25 |
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Answer» 11/25 Put 1/2 (x + y) Ans= 22/50 or 11/25 LCM and make the denominator same and find |
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| 42849. |
The cubic coefficient whose a=5b=2 c=7is |
| Answer» Cubic equation is of the form ax^3 + bx^2 + cx + dThe coefficient of x^3 is a. Here a=5. Hence the cubic coefficient here is 5Hope this helps you... | |
| 42850. |
Why the value of x0=1 |
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