InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 43151. |
Chapter 1st exercise 1.1 theorem 1.1 |
| Answer» | |
| 43152. |
Prove that 5 - 2root3 is an irrational number |
| Answer» | |
| 43153. |
(a+b)x+(a-b)y=a^2 +b^2, (a-b)x+(a+b)y=a^2 +b^2 Solve it by substitution method |
| Answer» Very lendhy.. | |
| 43154. |
Tan +cot =5 |
| Answer» | |
| 43155. |
How many terms of the AP: 9,17,25,.....must be taken to give a sum of 636? |
| Answer» Let the number of terms required to make the sum of 636 be n and common difference be d.Given Arithmetic Progression : 9 , 17 , 25 ....First term = a = 9Second term = a + d = 17Common difference = d = a + d - a = 17 - 9 = 8From the indentities of arithmetic progressions, we know : -{tex}S_{n}=\\dfrac{n}{2}\\{2a+(n-1)d\\}, where S_{n} {/tex}is the sum of first term to nth term of the AP, a is the first term, d is the common difference and n is the number of terms of AP.In the given Question, sum of APs is 636.Therefore,\xa0⇒ {tex}636 = \\dfrac{n}{2} \\{2(9) + (n - 1)8 \\} \\\\ \\\\ \\\\ = > 1272 = n(18 + 8n - 8) \\\\ \\\\ = > 1272 = 10n + 8n {}^{2} \\\\ \\\\ = > 636 = 5n + 4n {}^{2}{/tex}\xa0⇒ 4n² + 5n - 636 = 0\xa0⇒ 4n² + ( 53 - 48 )n - 636 = 0\xa0⇒ 4n² + 53n - 48n - 636 = 0\xa0⇒ 4n² - 48n + 53n - 636 = 0\xa0⇒ 4n( n - 12 ) + 53( n - 12 ) = 0\xa0⇒ ( n - 12 )( 4n + 53 ) = 0By Zero Product Rule,\xa0⇒ n - 12 = 0\xa0⇒ n = 12Hence,Number of terms of the AP [ 9 , 17 , 25 ] which are required to make the sum of 636 is 12.\xa0 | |
| 43156. |
How can I get reference book for free in pdf format? |
|
Answer» I can and I have got all of them for free!!!!!!!!!! Oh Sorry!You can\'t get that for free |
|
| 43157. |
Find a relation between x and y if the points (x,y) ,(1,2)and (7,0) are collinear |
| Answer» | |
| 43158. |
In right triangle ABC right angled at B , BE is drawn perpendicular to AC then AE upon AC will be |
| Answer» | |
| 43159. |
Prove that 1 upon route 3 is irrational |
| Answer» | |
| 43160. |
Prove 2+root 3 /5 is a irrational no. , given that root 3 is a irrational no. |
| Answer» Let take 2√ 3/5 is rational no.Then we can write that 2√3/5=r/s where r and s are integers and s not equal to 0. Then r and s has common factor other than 1.=>2√3/5 = a/b=> 2√3=5a/b=>√3=5a/b*1/2=>√3=5a/2b(here 5a and 2b are integers as a and b are the common factor other than 1 so 5a and 2b are also integers)But this contradicts the fact that √3 is irrational .This problem arisen because of our assumption so our assumption is wrong .Hence,we conclude that 2√3/5 is irrational no. | |
| 43161. |
Lateral triangle has two vertices at the points 3 4 - 2 3 find the coordinates of the third vertex |
| Answer» Gsgdhd | |
| 43162. |
Using prime facttorisation find the hcf and lcm of 8,9and25 |
|
Answer» Hcf is 1 and lcm 1800 Hcf is 1 and lcm 1800 |
|
| 43163. |
If tan A = a/b, find the value of sec A |
| Answer» √a²+b²/b | |
| 43164. |
If the sum of the squares of the roots of the equation x2 + 2x – p = 0 is 8, find the value of p. |
| Answer» | |
| 43165. |
I dont understand |
| Answer» What | |
| 43166. |
What us difference between Euclid\'s algorithm and Euclid\'s lemma |
| Answer» Lemma is a proven statement used for proving another statement while algorithm is a series of well defined steps which gives a procedure for solving a type of a problem.Euclid\'s division lemma: For given any positive integers a and b there exist unique integers q and r satisfying a = bq + r, 0 ≤ r < b.Euclid\'s division algorithm is used for finding the Highest Common Factor of two numbers where in we apply the statement of Euclid\'s division lemma. | |
| 43167. |
3x+2y=5; 2x_3y=7 |
| Answer» Solve 3x + 2y = 5 and 2x - 3y = 7 by elimination methodSOLUTION :-3x + 2y = 5 ...... (1)2x - 3y = 7 ....... (2)We multiply eq (1) with 2 and eq (2) with 3eq (1) x 2 => 6x + 4y = 10 ...... (3)eq (2) x 3 => 6x - 9y = 21 ...... (4)eq (3) - eq (4) by elimination method6x + 4y - 6x + 9y = 10 - 2113y = -11y = -11/13substitute the value of y in any of the equation to get the value of x{ I\'m substituting it in eq (1) }3x + 2(-11/13) = 53x - 22/13 = 53x = 5 + 22/133x = 87/13x = 87/39x = 29/13 | |
| 43168. |
Find the volume of sphere whose radius is 0.63 m |
|
Answer» Thanks gaurav Radius of the sphere(r) = 0.63 mVolume of the sphere = 4/3πr³= (4/3 × 22/7 × 0.63 × 0.63 × 0.63)\xa0= 4×22×.09×.21× 0.63= 1.0478 m³ 1.047m³ |
|
| 43169. |
I am not able to understand how to simplify the LHS according to RHS using trignometric identities |
| Answer» First convert into sin and cos then solve it ok☺️ | |
| 43170. |
Prove that 2+root 3 is irrational |
| Answer» Yes | |
| 43171. |
Z^2+1/z^2-1=0 |
|
Answer» Tum math ki all chapter complete kr li ho kya Jswgsjsj |
|
| 43172. |
Find the zeroes of the follo |
| Answer» Wing aage | |
| 43173. |
X/6+y/15=4, x/3-y/12=19/4 |
| Answer» Solution krna h | |
| 43174. |
simplify each of the following 2/3+(-5)/12+4/99- |
| Answer» | |
| 43175. |
add 7/9 and 4/9 |
|
Answer» 11/9 7/9+4/9=11/9 |
|
| 43176. |
the area of triangle 1,-1 -4,6 ,-3,-5 |
| Answer» | |
| 43177. |
Cobstruct the abgle of the measurement 90° |
|
Answer» step 1 take a line segment name itstep 2 take a compass draw semicircle on itstep 3 divide that semicircle in 3 equal parthence is divided into three equal partfrom middle part do half of that by an Arc join the ark to the line segment Euisiehbeuudhehbdjejf |
|
| 43178. |
Express the trignometric ratio sinA , secA, and tanA in terms of cotA |
|
Answer» 1.TanA=1/cotA2. sinA÷cosA=TanA SinA×1/cosA=1/cotA SinA×1/sin(90-A)=1/cotA SinA/sin(90-A)=1/cotA3. secA=1/cosA SecA=1/cotA×sinA [cosA/sinA=cotA] SecA×sinA=1/cotA Sec×cos(90-A)=1/cotA SecA×1/sec(90-A)=1/cotA SecA/sec(90-A)=1/cotA [ i ] sinA in terms of cotA :sinA = 1 / cosecA We know that: cosec²A = 1 + cot²AsinA = 1 / √1 + cot²A[ ii ] secA in terms of cotA :We know that: 1 + tan²A = sec²AsecA = 1 + tan²AsecA = 1 + 1 / cot²AsecA = √(cot²A + 1 ) /cotA[ iii ] tanA in terms of cotA :tanA = 1 / cotAI hope it will help you? |
|
| 43179. |
What is a sector? |
| Answer» Sector is an area bounded by two radius and an arc. | |
| 43180. |
Finda point on the y-axis which is equidistant fromthe points A(6,5) andB(-4,3). |
| Answer» | |
| 43181. |
x^2+25x-600 factorisation? |
| Answer» X²-15x+40x-600 => x(x-15)+40(x-15) => (x+40)(x-15) => x=-40 or 15. | |
| 43182. |
How can i score 100% marks in cbse board 2020-21 |
|
Answer» Study well focus on study you will acchive ?% Aise phone chala ke to nahi aayenge,Haa bas sapno mein aa sakte h Sapne dekho |
|
| 43183. |
If the third and the ninth terms of an AP are 4 and –8 respectively, which term of this AP is zero? |
| Answer» given 3rd term = 4i.e, a+2d=4 ---- 1and 9th term = -8i.e., a+8d=-8 ------------- 2by by subtacting 1 and 2 we get, a+2d = 4 a+8d = -8 - - + ---------------- -6d = 12 ---------------so, d = -12/6 d = -2substitute it in (1) we get,\xa0a+2(-2) = 4a = 4+4 =8a=8\ufeff\ufeffhere we get a=82nd term = a+d = 8+(-2) = 8-2 = 63d term = a+2d = 8+2(-2) = 8-4 = 44th term = a+3d = 8+2(-3) = 8-6 = 25th term = a+4d = 8+2(-4) = 8-8 =06th term = a+5d =8+5(-2) = 8-10 = -2 .......so the series we got is 8,6,4,2,0,-2.....here we get zero at 5th placeso, 5th number in the series is 0.\xa0 | |
| 43184. |
How I got notes of trigonometry on this application |
|
Answer» Open the app click on maths subject then the content are shown click on the chapter which u want to study then on the top the ncert revision note are shown or ncert solution are shown click on ncert revision notes then the notes are appear.ok then u can study ??? Please tell me someone |
|
| 43185. |
All trigonometry ratio and identity? |
|
Answer» How Then got it in this app I want trigonometry notes What are u trying to ask . Please answer this question anyone please |
|
| 43186. |
How many pairs of positive integer x,y exist such that H.C.F(x,y)+L.C.M(x,y) |
| Answer» | |
| 43187. |
A=4,n=7,d=4 the an is |
|
Answer» 28 an = a + ( n - 1 ) d an = 4 + 6 ( 4 )an = 4 + 24an = 28 Formula of nth term =\xa0Where n is the no. of termd is the common differencea is the first termSubstitute the given values :Hence the value of a is 28. |
|
| 43188. |
In traingle pqr right angle atq PQ=3 and PR=6 determine angle QPR and angle PRQ |
| Answer» ∆PQR is a right angle triangleby Pythagoras theorem(PR)^2=(PQ)^2+(QR)^26^2=3^2+((QR)^236=9+(QR)^236-9=(QR)^2(QR)^2=27QR=✓9×3QR=3✓2AngleQPR =60° because side opposite to P is ✓3/2 times the hypo(PR)Angle PRQ=30° because side opposite to R is 1/2 of the hypo(PR) | |
| 43189. |
2x+5x-6x |
|
Answer» X only Pura question kya hai?? |
|
| 43190. |
30 rs is 1000g . what is the gram if rs 20? |
|
Answer» In rs 30,gram=1000.In rs 1,gram=1000/30.In rs 20,gram=33.33×20=666.66. 500g |
|
| 43191. |
The pair of linear equation2x-5y=3 and 2y-5x-8=0have |
| Answer» Unique solution | |
| 43192. |
Can two numbers have 18 as their HCF and 3800 as their LCM ? Give reason |
| Answer» | |
| 43193. |
Find the LCM of 9/10+7/15 |
| Answer» 9/10+7/1527/30+14/3041/30Such a silly question | |
| 43194. |
Solve graphically4x-5y-20=0 and 3x+5y-15=0 |
| Answer» | |
| 43195. |
Ifp(E)=0.05,what is the probabilityof\'notE\'? |
|
Answer» We know,P(E) + P( not E) = 1here, P(E) = 0.050.05 + P(not E) = 1P(not E) = 1 -0.05 = 0.95 It\'s p(E\') = 0.95 I am here is a good name Are u ishika |
|
| 43196. |
What is bharat |
|
Answer» Is anyone Diya here? I am here only Hello kya tum ho |
|
| 43197. |
What is the exact definition of pythogoras |
|
Answer» What do u say We will change the mnames of ours |
|
| 43198. |
How to solve7x+2y=8, 3/5x+2y=9 by cross multiplication method |
| Answer» | |
| 43199. |
Find the H.C.F of 233,56 |
|
Answer» 1 As,233>53 |
|
| 43200. |
Draw the graph of the linear equation 3=2x+y |
| Answer» | |