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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 43501. |
Hcf of first facters 20and 30 |
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Answer» It\'s 2 2 |
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| 43502. |
Send maths all chapters formulas |
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| 43503. |
Probability of hitting a ball is 5/7 then what is the probability of not hitting a ball |
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Answer» 2/7 2/7 Probability of hitting the ball = 5/7Probability of not hitting the ball = 1-5/7=2/7 |
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| 43504. |
Find the AP. an=3n-2/2 |
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Answer» What is natural resource a=3 |
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| 43505. |
ABC is an equilateral triangle with AD perpendicular to BC , prove that AD² = 3DC². |
| Answer» Here given triangle ABC must be an equilateral triangle and we have to prove AD2\xa0= 3DC2Solution:Given:\xa0∆ABC is an equilateral, AD ⊥ BC.\xa0\xa0In right ∆ABD,AB2\xa0= BD2\xa0+ AD2⇒ BC2\xa0= BD2\xa0+ AD2 (AB = BC)⇒ (2BD)2\xa0= BD2\xa0+ AD2 \xa0[From (1)]⇒ 4BD2\xa0= BD2\xa0+ AD2⇒ AD2\xa0= 3BD2\xa0= 3DC2 [As BD = DC]Hence proved | |
| 43506. |
2x+3y+9 |
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| 43507. |
sintheta/cosectheta-1+costheta/1+sectheta=sinthetacostheta/(sintheta-costheta) |
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Answer» What ???? |
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| 43508. |
3/2x+5/3y=7 and 9x-10y=14 Following pair of of linear equation are consistent or in consistent? |
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| 43509. |
What is ohms lW |
| Answer» OHM’s law states that under no same temperature,\xa0electric current\xa0flowing through an ideal conductor is\xa0directly proportional to the potential difference\xa0across its ends.V ∝ IV = IR, R – Resistance\tResistance\xa0is a property of conductor to resist flow of charge through it. Its SI unit is\xa0Ohm (Ω).R = V/I, 1 Ohm = 1 Volt/ 1 Ampere | |
| 43510. |
The larger of two supply mentary angles exceeds the smaller by 18 degree. Find them |
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Answer» In two supplementary angles, let one angle be ‘x’. another angle be ‘y’ Sum of these = 180° ∴ x + y = 180 ………… (i) The larger of two supplementary angles exceeds the smaller by 18 degrees. ∴ x-y = 18 ………… (ii) From eqn. (ii), x – y = 18 x = 18 + y Substituting the value of ‘x’ in eqn. (i), x + y = 180 . 18 +y + y = 180 18 + 2y = 180 2y = 180 – 18 2y = 162 ∴ y =\xa016221622 ∴ y = 81 Substituting the value of y’ in x = 18 + y x = 18 + 81 x = 99 ∴ x = 99°, y = 81°.\xa0Orlet the two angle be /x and /yaccording to given condition-/x+/y = 180 ----(1)/x = /y + 18 -----(2)substituting the value of (2) in (1)(1) - /x+/y = 180- (/y+18)+/y = 180- 2/y+ 18 = 180-2/y = 162-/y= 81substituting the value of y in (2)/x=/y+18/x=81+18/x=99 This is question of ncrt book of 3 chapter, exercise-3.3 , question no. 3 |
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| 43511. |
Given that HCF (306,657)=9,LCM(306,657) |
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Answer» 22338 Given that HCF = 9 and the numbers are 306 and 657 .LCM = ?We know that LCM\xa0× HCF = product of two numbers\xa0⇒LCM\xa0× 9 = 306\xa0× 657⇒LCM = 201042/9 = 22338 |
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| 43512. |
If 7 times the 7th term of an AP is equal to 11 times its 11th term , then its 18th term will be |
| Answer» let a = first term and d=common difference.According to question,7a7\xa0= 11 a11=>7(a+6d) = 11(a+10d)=> 7a-11a = 110d-42d=> -4a = 68d=>a = -17d ......(1)Now , a18\xa0= a\xa0+17d\xa0but a = -17 d ..by (1)so\xa0put this\xa0value , we get,a18=-17d +17d =0\xa0Hence proved. | |
| 43513. |
How i get a100% number in board exam ? |
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Answer» ?????? If you give all the answer correct then you can get 100٪ in exam You are non sence |
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| 43514. |
Can any one solve exterior angle thearom created by me ? [Circle] |
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| 43515. |
A tangent to a circle intersect it in _____ point |
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Answer» Only one point 1 1 A tangent to a circle intersect it in only one single point. |
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| 43516. |
SolveX^2 -2x+a^2 -b^2 = 0(\'^\' =square) |
| Answer» X square - 2 X + a square minus b square equal zeroX into x minus 2 into X + (a + b) (a - b)x-2a+2b+2a-2bx not equal to 0 not equal to RHS | |
| 43517. |
The other two zeros of the polynomial x3-8x2+19x-12 if its one zero is x=1. |
| Answer» X=1 is a of P(x)zeroSo x-1 is a factor of P(x)So, P(x)=(x-1)(x2-7x+12)Which is (x-1)(x-3)(x-4)So, other two zeros are 3 &4 | |
| 43518. |
Which topics are removed in chapter 12 Areas related to circles ??? |
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Answer» HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.Deleted syllabus of CBSE Class 10 Mathematics\xa0\xa0D All topics are coming in ch 12 |
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| 43519. |
The decimal form of 129/4×5×555555×7×7777is |
| Answer» 252.81496881 this is the decimal expansion. | |
| 43520. |
Find the distance between M(-7,6) and N(-2,-4). With the graph |
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| 43521. |
If Pth term of an A.P. is c and qth term is d, what is rth term? |
| Answer» rth term will be a+(r-1)e Where e is the common difference and a is 1st term | |
| 43522. |
5ki power x-1 + 5 ki power 1-x = 26 |
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| 43523. |
Reduce into its lowest form 3/15 |
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Answer» 1/5 1/5=0.2 1/5 1/5 |
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| 43524. |
Complete the series : 3,6,24,192,___ |
| Answer» It\'s 3072 as 3*2=6, 6*4=24, 24*8=192,. 192*16=3072 as2*2=4,. 4*2=8,. 8*2=16 | |
| 43525. |
Find the roots by quadratic formula 1) 2x square - 7x+3=0 |
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Answer» 1/2 and 3 2x*2-6x-x+3=0. 2x(x-3)-1(x-3)=0 (2x-1)(x-3)=0. so x=1/2and 3 |
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| 43526. |
Cos 58÷ sin 32 + sin22 ÷ cos 68- cos 38 cosec 52 ÷ tan 18 tan 35 tan 60 x cot 72 cot 55 |
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| 43527. |
Which is the Most important chapter? |
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Answer» Whole ncert is important if u want to score well Quadratic equations Trigonometric portion is quite useful and important as it will be used in further classes too Triangles Trigonometric portion is quite useful and important as it will be used in further classes too |
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| 43528. |
X+2=? |
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Answer» X=-2 x = -2 D |
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| 43529. |
tanA/(1-cotA) +cotA/(1-tanA)= (1+tanA+cotA) plz. gave me a solution plz |
| Answer» tanA/(1–cotA) + cotA(1–tanA) tanA/(1–1/tanA) + 1/tanA(1–tanA) tanA/tanA–1/tanA + 1/tanA(1–tanA)tan²A/tanA–1 + 1/tanA(1–tanA) tan²A/tanA–1 —1/tanA(tanA–1)tan³A–1/tanA(tanA–1)(tanA–1)(tan²A+1+tanA)/tanA(tanA–1)tan²A/tanA + 1/tanA +tanA/tanAtanA + cotA + 11 + tanA + cotA | |
| 43530. |
https://drive.google.com/file/d/1C572cK7gLNe_NvcuYWljc58v6pahP8wO/view?usp=drivesdk |
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| 43531. |
1000 and 20000 ka factor |
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Answer» Factors of 20000 are 1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 80, 100, 125, 160, 200, 250, 400, 500, 625, 800, 1000\xa0... The factors of 1,000. Answer : 1,2,4,5,8,10,20, 25,40,50,100,125,200,250,500,1000 |
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| 43532. |
Find the sum of following A.P(I)2,7,12,...........,to 10 terms |
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Answer» Thanks a=2,,,,,,,,,,,, d=5 ..................................... l=a+(n-1) d ====....... 2+(10-1) 5======= .. 2+9×5====....2+45=47 .,...................................... Sn=n/2×(a+l) ====10/2*[2+47]========5*49=====245 Common difference =7-2=5First term(a)=2An=10S=n/2[2a+(n-1)dS=10/2{2(2)+(10- 1)5S=5{4+9(5)}S=5{4+45}S=5(49)S=245 a=2 d =5 n=10Sn=?Sn=n/2 [2a+(n-1)*d]Sn=10/2[2*2+(10-1)*5)]Sn=5[4+9*5]Sn=5[4+45]Sn=5[49]Sn=245. |
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| 43533. |
How many natural numbers between 5 and 995 are divisible by 6? |
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Answer» 165 Sorry I don\'t know |
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| 43534. |
The mid points of line segment joining (2a,4)and (-2,3b)is (1,2a+1),the value of a and b is |
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| 43535. |
Prove that sec ^theta-sin ^theta/tan ^theta= 1+cot^theta-cos^theta |
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| 43536. |
Write the sum of exponents of prime factors in the prime factorisation of 250. |
| Answer» Prime factors are those prime numbers which constitute to the formation of a number by multiplication of smaller prime numbers.Now, let us first take the prime factors of the number 250, we getNow the prime factor grouped together can be written as\xa0Hence, the exponents for 2 and 5 are 1 and 3 respectively; therefore the sum of the exponent isHence, the sum of exponents of prime factors in the prime factorization of 250 = 4. | |
| 43537. |
The larger of two supplementary angles exceeds the smaller by 20 degrees. Find the angles. |
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Answer» let the two angle be /x and /yaccording to given condition-/x+/y = 180 ----(1)/x = /y + 18 -----(2)substituting the value of (2) in (1)(1) - /x+/y = 180- (/y+18)+/y = 180- 2/y+ 18 = 180-2/y = 162-/y= 81substituting the value of y in (2)/x=/y+18/x=81+18/x=99 Larger angle will be 110 degrees n the other smaller angle be 180 -110 i.s 70 degrees.Hope u found it helpfull ? Sorry by mistake jaldi send ho gaya X + X+20 = 180......... 2x+20==180.......2x==180+20==160............ X==160/2=80 |
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| 43538. |
(6,5) (3,2)find distance between them |
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Answer» √(6-3)^2+(5-2)^2 =3√2 3√2 |
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| 43539. |
Class 10 maths board question paper 2020 |
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| 43540. |
Solve the equation x³‐3 |
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| 43541. |
8.4 ex solutions |
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| 43542. |
If sin 0=5/13 then cos 0 |
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| 43543. |
The addition of a rational no and an irrational no is equal to |
| Answer» Jldi btao | |
| 43544. |
Exercise 3.2 class 10 questions number 1 ka both parts ???? |
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| 43545. |
Formula for Sn |
| Answer» sn=n/2+(2a+(n-1)d | |
| 43546. |
What is deleted in mathematics |
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Answer» In arithmetic progression, application in solving daily life problems based on sum to n term. In quadratic equations,Situational questions are not CBSE board exams |
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| 43547. |
Ncert solutions for 3.2 exercise class 10 |
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| 43548. |
(4-x) (3+1)=2-3x |
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Answer» X=2 (4-x)(3+1)=2-3x(4-x)4=2-3x16-4x=2-3x-4x-3x=2-16-7x=-147x=14X=14/7X=2Answer completed |
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| 43549. |
Find the zeros of the polynomial 6?2 − 3 − 7? and verify the relationship between the zeros and |
| Answer» =6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 or ⇒3x+1=0⇒x=3/2 or ⇒ x= - 1/3α=3/2 ,β= - 1/3⇒α+β= -b/a⇒3/2+(-1/3)= - (-3)/6⇒3/2-1/3=1/2⇒7/6 =1/2\xa0⇒αβ=c/a\xa0⇒\xa03/2(-1/3)= -7/6⇒-1/2= -7/6\xa0⇒1/2=7/6 | |
| 43550. |
If p and q is a zero of x²+5x+12.find tha value of p.q= |
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Answer» 12 product of zeros =constant term /cofficient of x2=12/1. |
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