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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4351. |
Does CGPA pattern is still there or not |
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Answer» Not.... Yaar Not |
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| 4352. |
Find the zeros 25√x+25x+5 |
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| 4353. |
25x^+25x+5 |
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| 4354. |
The length of an arc of a circle of radius 12 cm is 10*22/7. Find the initial angle of this circle |
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Answer» 150 degree 150° |
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| 4355. |
The length of an arc of a circle of radius 12 cm is 10*22/7cm .Find the initial angle of this circle |
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| 4356. |
23+5 |
| Answer» 28. What a difficult question yaar!!!!!!!!!~~~~~ | |
| 4357. |
prove that the line segment joining the points of contact of two |
| Answer» Given: l and m are the tangent to a circle such that l || m, intersecting at A and B respectively.To prove: AB is a diameter of the circle.Proof:A tangent at any point of a circle is perpendicular to the radius through the point of contact.{tex}\\therefore{/tex}\xa0{tex}\\angle X A O = 90 ^ { \\circ }{/tex}and\xa0{tex}\\angle Y B O = 90 ^ { \\circ }{/tex}Since\xa0{tex}\\angle X A O + \\angle Y B O = 180 ^ { \\circ }{/tex}\xa0An angle on the same side of the transversal is 180°.Hence the line AB passes through the centre and is the diameter of the circle. | |
| 4358. |
Trigonometry class |
| Answer» What\'s your question? | |
| 4359. |
sinA - cosA +1 / sinA + cosA - 1= 1 / secA - tanA |
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Answer» So easy I made this.. |
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| 4360. |
Evaluate. Cos45/sec30+cosec30..... (degree on the number)Anybody can answer me |
| Answer» Raiyan itna tough question mat poocho yaar | |
| 4361. |
Lcm of336and54 |
| Answer» 1512 | |
| 4362. |
what is split up for maths board exam for 10th class |
| Answer» | |
| 4363. |
If A,B,C are interior angles of a triangle ABC, then show thatsin(B+C/2)=cosA/2 |
| Answer» So easy...we know that A+B+C = 180..Then A= 180-(B+C)...Put this value in place of A...Then u will find...(Sin B+C) = cos {90-(B+C)}By commentary angles property they are equal.. | |
| 4364. |
Statement of euclid division lemma... |
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Answer» Euclid\'s division lemma,Given positive integers \'a\' and \'b\', their exist two unique integers such that, a = bq+r, where value of \'r\' is 0 | |
| 4365. |
Angle BAC=90* and AD is perpendicular to BC then prove AB.AC = (AD)2 |
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Answer» Hello kiya hua I love you riya Don\'t possible here. |
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| 4366. |
formula of centroids |
| Answer» X1+x2+X3/3.......Y1+y2+y3/3 | |
| 4367. |
2+√3+1/2+√3+1/√3-2 |
| Answer» Will you like to become my friend | |
| 4368. |
Find hcf of 13 41 |
| Answer» Hcf(13,41)=1 | |
| 4369. |
Show that of the numbers n, n+2, and n+4, only one of them is divisible by 3 |
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Answer» It has very long process and by typing it takes more time Sorry this is right Sorry, this is tigh Sorry this questions is wrong |
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| 4370. |
The sum of n terms of an ap is 3n²+5n.find the ap and hence find its 16th terms |
| Answer» Given: Sn\xa0= 3n2\xa0+ 5n{tex}\\therefore{/tex}\xa0S1\xa0= 3(1)2\xa0+ 5(1) = 8{tex}\\Rightarrow{/tex}\xa0a1\xa0= 8 ..(i)S2\xa0= 3(2)2\xa0+ 5(2) = 22{tex}\\Rightarrow{/tex}\xa0a1\xa0+ a2\xa0= 22{tex}\\Rightarrow{/tex}\xa08 + a2\xa0= 22 [using (i)]{tex}\\Rightarrow{/tex}\xa0a2\xa0= 14d = a2\xa0- a1\xa0= 14 - 8 = 6AP is 8, 14, 20, 26, ...Now, a16\xa0= a + 15d= 8 + 15(6) = 98 | |
| 4371. |
Wht is happening guyxz |
| Answer» funn... u tell! | |
| 4372. |
Best CBSE sample paper book |
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Answer» Arihant Evergreen Oswaal |
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| 4373. |
How to find middle term in AP |
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| 4374. |
To prove sin3A = 3sinA - 4sin^3A |
| Answer» Given that x = 30o\xa0we have to verify that sin 3x = 3sin x - 4sin3x.{tex}\\Rightarrow 3 x = 90 ^ { \\circ }{/tex}{tex}\\therefore\\sin 3 x{/tex}{tex}= \\sin 90 ^ { \\circ } = 1{/tex}and, 3sin x - 4sin3x{tex}= 3 \\sin 30 ^ { \\circ } - 4 \\sin ^ { 3 } 30 ^ { \\circ }{/tex}{tex}= 3 \\times \\frac { 1 } { 2 } - 4 \\left( \\frac { 1 } { 2 } \\right) ^ { 3 }{/tex}{tex}= \\frac { 3 } { 2 } - \\frac { 1 } { 2 } = 1{/tex}. | |
| 4375. |
Find all coordinate of the point on y axis which is nearest to the point (-2,5) |
| Answer» The point on y-axis that is nearest to the point(-2,5) is (0,5). | |
| 4376. |
Find the probability of getting , a non face card , a spade from well shuffled cards of 52 |
| Answer» Total number of cards = 52Number of face cards = 12{tex}\\therefore{/tex}No. of non-face cards = 52 - 12 = 40P(non-face card) =\xa0{tex}\\frac { 40 } { 52 } = \\frac { 10 } { 13 }{/tex} | |
| 4377. |
Tan 27 tan 7 |
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| 4378. |
What is the probability that an ordinary year has 53 Sunday |
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Answer» In ordinary year there are 365 days . So probability is 1/365 . May it help you 1 by 7 2/7 |
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| 4379. |
1 is composite no. OR prime no. |
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Answer» No composite no prime Nothing from both 1 is natural number it is neither composite nor prime Composite |
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| 4380. |
(x + x2) tan x |
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| 4381. |
ABC is an isosceles triangle in which AB=AC and D is a point on BC . Prove that ABsq-ADsq=BD.CD |
| Answer» I prove it. | |
| 4382. |
Tra |
| Answer» ? | |
| 4383. |
Lemna |
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Answer» HJ se kah rhi hoon Koi yahan no. Mat daalna tumhare saath saath hum bhi band ho jayenge Kya aap whatsapp pr aa sakte hian A statement which is proved Lema |
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| 4384. |
The 7th term of an ap is 32 and its 13 term is 62 find the AP |
| Answer» a+6d=32a+12d=62Now solve it a=2,d=5 ayaga | |
| 4385. |
Theorem of ulternate segment angle in CH circle |
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Answer» Haha..yes it\'s too long to be decribed Too long |
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| 4386. |
Sin theta + cos theta is equal to 1 |
| Answer» No, sin square theta+cos square theta =1 | |
| 4387. |
If one zeros of quadratic polynomial 2*²–(3α+1)-× -9 is negetive of other. Find value of α |
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| 4388. |
Sin^6+cos^6=1-3sin^2+cos^2 |
| Answer» We have,LHS = sin6A + cos6A{tex}\\Rightarrow{/tex}\xa0LHS = (sin2A)3 + (cos2A)3{tex}\\Rightarrow{/tex}\xa0LHS = (sin2A + cos2A) { (sin2A)2 + (cos2A)2 - sin2A cos2A)} [{tex} \\because{/tex}\xa0a3 + b3 = (a + b) (a2 - ab + b2)]{tex} \\Rightarrow{/tex}\xa0LHS = {(sin2A)2+(cos2A)2 + 2sin2A cos2A - 2 sin2A cos2A - sin2A cos2A}{tex} \\Rightarrow{/tex} LHS = {(sin2A + cos2A)2 - 3sin2A cos2A } = 1 - 3sin2A cos2A = RHS. | |
| 4389. |
Thals theorem explan it |
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Answer» Thanku A line drawan parallel to the third side of a triangle divides the two sides in the same ratio |
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| 4390. |
Find k the sum & product of the roots of quadratic equation kx2-4x+4k=0 are equal |
| Answer» K=1 and sum of roots=\'4\' and product of roots=\'4\' | |
| 4391. |
Find the area of abc if A (2,3) B (4,5) and C(6,-3) |
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Answer» 10 unit square Use the formula given in NCERT maths ch-7 ar. Of triangle Apply area formula |
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| 4392. |
9 ×9 |
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Answer» Mujhe nhi aata 81 81 ( eighty one ) |
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| 4393. |
Provide that root is an irrational number. |
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| 4394. |
SecA +tanA then find the value of sinA/cosA |
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Answer» And sinA /cosA =tanA Please write full question |
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| 4395. |
Is NCERT is enough for this 2018 board exam |
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Answer» Yes First complete ncert and then the new sample papers Only do ncert I think sbse pehle ncert book s padhni chahiye phir jaakar extra books padhni chahiye I don\'t think so.. |
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| 4396. |
If P(2,1) Q(4,2) R(5,4) S(3,3) Are the vertices of a quadrilateral PQRS. Find its area |
| Answer» It\'s so easy | |
| 4397. |
Find n , if n-2 , 4n-1 and 5n+2 are in AP |
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Answer» Sorry man n=1 4n-1-(n-2)=5n+2-(4n-1)4n-1-n+2=5n+2-4n+13n+1=n+32n=2So,n=1 n=1 N=2 |
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| 4398. |
TrianglePQR is right angled at Q.QX |
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| 4399. |
5+1= |
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Answer» 6 6?? |
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| 4400. |
4xsquare+1x-0 please factorise this |
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Answer» X=0 or X=-1/4 4x2+1x-04x2+1x=0X (4x+1)=04x+1=0×X4x+1=0X=-1/4Here x2 means x square.?? X=-1/4 |
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