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4551.

1/(x-1)(x-2)+1/(x-2)(x-3)=2/3.find for x

Answer»
4552.

From which chapter more questions will come in board examination

Answer»
4553.

If f(x) = x3 + x2 - ax + b is divisible by x2 -x write the value of a and b

Answer» Since f(x) =\xa0x3\xa0+ x2\xa0- ax + b is divisible by (x2\xa0- x), we havex2\xa0- x = 0{tex}\\Rightarrow{/tex}\xa0x(x - 1) = 0{tex}\\Rightarrow{/tex}\xa0x = 0 or x = 1Hence,f(0) = 0{tex}\\Rightarrow{/tex} x3\xa0+ x2\xa0- ax + b = 0{tex}\\Rightarrow{/tex}\xa003\xa0+ 02\xa0- a(0) + b = 0{tex}\\Rightarrow{/tex}\xa0b = 0Also,f(1) = 0{tex}\\Rightarrow{/tex} x3\xa0+ x2\xa0- ax + b = 0{tex}\\Rightarrow{/tex}\xa013\xa0+ 12\xa0- a(1) + 0 = 0{tex}\\Rightarrow{/tex}\xa01 + 1 - a = 0{tex}\\Rightarrow{/tex} 2 - a = 0{tex}\\Rightarrow{/tex}\xa0a = 2Hence , the value of a and b in given polynomial are a = 2 and b = 0.
4554.

Find the value of x if 12th term of the AP is 81 and AP is x-7,x-2,x+3.........find S12 also

Answer»
4555.

2√6x² - 5x - 3√6

Answer» So easy solve by .middle split.......2√6x2 - (9-4)x -3√6 .....solve further....
4556.

Ab is the diameter of the larger semicircle ab=21

Answer»
4557.

Why only maths

Answer» Maths is a good subject.
4558.

2√6x²-5x-3√6

Answer» 3√6/4
4559.

What should be the timings of the examinations held in March of class10th??

Answer» In my opinion it should be 10am to 1 am
TIME OF COMMENCEMENT -10:30 A.M.
4560.

Prove that 1/sec x - tan x - 1/cos x =1/cos x - 1/sec x+ tan x

Answer» To Prove: [1/(secx – tanx)] – [1/cosx] = [1/cosx] - [1/(secx + tanx)]Proof: LHS = [1/(secx – tanx)] – [1/cosx]But [1/cosx] = sec x = [1 ×(secx + tanx)/ (secx - tanx)(secx + tanx)] – [sec x] = [(sec x + tan x) / (sec2x – tan2x)] – [sec x]But (sec2x – tan2x) = 1LHS = sec x + tan x – [sec x] = tan x ………. (1)RHS = [1/cosx] - [1/(secx + tanx)] = [sec x] - [1 ×(secx - tanx)/ (secx + tanx)(secx - tanx)] = [sec x] - [(sec x - tan x) / (sec2x – tan2x)]But (sec2x – tan2x) = 1RHS = [sec x] - [(sec x - tan x)] = tan x …………… (2)As LHS = RHS , Hence Proved
So esy bt likhu kaise
4561.

Where can I find answers of lab manual.

Answer» Guve to me also if u will find ...thanks in advance ?
4562.

if the two zeros of the quadratic polynomial 7x^2-15x-k are reciprocal of each other then find k

Answer» type answer
4563.

Which gas is released when concentrated and dilute hno3 react to zinc????

Answer» I think u r wrong tanu...because I am sure that gas is released. Yeah h2 isn\'t released...
HNO^3 IS NITRIC ACID AND it\'s a strong oxidising agent as soon as the hydrogen gas is produced during the reaction it oxidises it into water. That\'s why NO GAS is released.
Hydrogen..
Come on none have the guys???
4564.

2+2=5?

Answer» 2 +2=5 galti se hota Hai
Ok got it ap fir sa busy ho gaye
What
By mistake
Hiii bff ji
No it is 4
4565.

Maths paper is on which date?

Answer» Ok
????????
28 march 2018
Yes..
What 28 March ???Are u sure
Thanks
28 march
2 8 March
4566.

Find the probability of getting 53 Sundays in a non leap year.

Answer» 1/7
4567.

I want newly launched sampel papers of Cbse board

Answer»
4568.

CosA=3/5 find the value of 4+4tansquareA

Answer» 100/9
cosa= base/hypotenusBase ko 3 man lo and hypo. Ko 5 .P.G.T. lagao Perpendicular = 4 Then apply tan= p/hThen find the value of 4+4sin square theeta
Please tell me kal mera paper hai
100/9
How
100/9
4569.

2√6x² - 5x - 3√6 find the both zeros

Answer»
4570.

Sum of all natural number

Answer» n(n+1)/2
An as there are infinite natural numbers.
-1/12
4571.

What is a square +b square

Answer» asq.+bsq.=csq.
Asq+bsq)+2ab
(a+b)²-2ab
4572.

How we find that any no. is a composite number???

Answer» If it has at least 1 factor other than 1 and it self
If any number divided by 1 ,itself and any other factor then it is a composite number. For ex. 9 divisible by 1,3,9
It means 4,6,8,9,10e.t.c are composite numbers because these numbers are not prime numbers
No. that are not prime number are composite no.
4573.

Prove that sin^4 alpha / sin^2 beta + cos^4 / cos^2 beta=1

Answer»
4574.

Friends what is the minimum percentage we should get to take medical stream

Answer» I am not sure
above 60℅ to 70%
It must be more than 85% I think
8.5 cgpa
4575.

Find the area of triangle A(-3,4),B(3,0) and C(5,0)

Answer» By using the formula of a triangle which is used in ch-7 of ncert book.Moreover, it\'s answere is 4 unitsq.
By using the ar of triangle formula
4576.

The product of my age two years ago with my age 3 year hence is 50 .find my present age

Answer» Your present age will be 7yrs
4577.

Find a relation between x and y if the points (x,y),(7,0) are collinear

Answer» Google pa sarch karlo
4578.

Is Using black and blue gel pen in board exam compulsory?

Answer» Gel pen ka koi protocol nahin hai
Use good quality ball pen
Teachers suggested to only use simple blue pens
Mixed reactions! What should i do ?
Yes..
No only blue simple pen allowed
Be use ball pens in board exam...
Noo
I think no cuz gel pen can make your condition worse
4579.

In an equilateral triangle ABC, is drawn perpendicular vto BC meeting BC in D.prove that AD^=3BD^

Answer» What is your answer
4580.

CosA=2/5,then find the value of 4+4tanb*tanb

Answer» 25
4581.

If n=a-1 /a +1 and m=a+1 /a-1, m² +n²-3mn is equal to :

Answer»
4582.

Find the sum of 15th term multipel of 8

Answer» 960
4583.

Solve for quadratic equation by factorisation x-a +x-b = a+b. x-b. X-b. b. a

Answer» We have,{tex}\\frac{{x - a}}{{x - b}} + \\frac{{x - b}}{{x - a}} = \\frac{a}{b} + \\frac{b}{a}{/tex}{tex}\\Rightarrow \\frac{{(x - a)(x - a) + (x - b)(x - b)}}{{(x - b)(x - a)}} = \\frac{{{a^2} + {b^2}}}{{ab}}{/tex}{tex} \\Rightarrow \\frac{{{x^2} + {a^2} - 2ax + {x^2} + {b^2} - 2bx}}{{{x^2} - bx - ax + ab}}{/tex}{tex} = \\frac{{{a^2} + {b^2}}}{{ab}}{/tex}{tex}\\Rightarrow \\frac{{2{x^2} - 2ax - 2bx + {a^2} + {b^2}}}{{{x^2} - bx - ax + ab}} = \\frac{{{a^2} + {b^2}}}{{ab}}{/tex}{tex}\\Rightarrow{/tex}{tex} (2x^2 - 2ax - 2bx + a^2 + b^2)ab = (a^2 + b^2)(x^2 - bx - ax + ab){/tex}{tex}\\Rightarrow{/tex}{tex}2abx^2 - 2a^2bx - 2ab^2x + a^3b + ab^3 = a^2x^2 - a^2bx -a^3x + a^3b + b^2x^2 - b^3x - ab^2x + ab^3{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}2abx^2 - a^2x^2 - a^2bx - ab^2x + a^3x + b^3x - b^2x^2 = 0{/tex}{tex}\\Rightarrow{/tex}{tex}(2ab - a^2 - b^2)x^2 + (-a^2b - ab^2 + a^3 + b^3)x = 0{/tex}{tex}\\Rightarrow{/tex} x[(2ab - a2 - b2)x + (a3 + b3 - a2b - ab2)] = 0{tex}\\Rightarrow{/tex} x = 0 or (2ab - a2 - b2)x + a3 + b3 -a2b - ab2 = 0Now,(2ab - a2 - b2)x + a3 + b3 - a2b - ab2 = 0{tex}\\Rightarrow{/tex} (2ab - a2 - b2)x = a2b + ab2 - a3 - b3{tex}\\Rightarrow{/tex} -(a2 - b2 - 2ab)x = a2b - b3 + ab2 - a3{tex}\\Rightarrow{/tex} -(a - b)2x = b(a2 - b2) + a(b2 - a2){tex}\\Rightarrow{/tex} (a - b)2x = -b(a2 - b2) - a(b2 - a2){tex} \\Rightarrow x = \\frac{{ - b({a^2} - {b^2}) + a({a^2} - {b^2})}}{{{{(a - b)}^2}}}{/tex}{tex}\\Rightarrow x = \\frac{{\\left( {{a^2} - {b^2}} \\right)(a - b)}}{{{{(a - b)}^2}}}{/tex}{tex} \\Rightarrow x = \\frac{{{a^2} - {b^2}}}{{a - b}} = \\frac{{(a - b)(a + b)}}{{(a - b)}}{/tex}{tex}\\Rightarrow{/tex} x = a + b{tex}\\therefore{/tex}\xa0x = 0 or x = a + b
4584.

(a-b)x+(a+b)y=2a×a-2b×b(a+b)(x+y)=4abFind the value of x by cross multiplication method

Answer»
4585.

If Alpha and beta are the roots of the 2x2+5x_4=0 find the value of Alpha 3+ beta 3

Answer»
4586.

Pythagoras theorem proof

Answer» Se* see
U can se it in mathematics ncert
Not possible here ....but easiest ?
4587.

What is diameter of radius ?? Without Google be honest

Answer» 2r
twice
Don\'t know
Twice of it ( 2r )
2r
2r
2r
Give ans
4588.

2chairs and3 tablescost RS5650,whereasv3chairs and 2tables cost rupee 7,500

Answer» Chair= 2240Table cloth= 390
4589.

find next term.. 1 1 2 6 .... (any genius present?)

Answer» So simple... ???
Firstly we multiply one from one then answer came one, then we multiply one from two then answer came two, then we multiply two from three we get six then lastly we multiply six from four and we get final answer 24
Okk I will tell How it is 24
The answer is 24
59 ?
Aur solution bhi
Yees jaldi se
if 24 how.. tell the basic idea behind
24 hi hoga
My final ans 24...
can I say the answer?
1 answer h ya bas 1 hi Banda sahi h????
Who???
Vrna 25 ydi alag way se dekhe toh
question is complete and correct
Must be 24 ...?? Multication ..
24
I think question is not complete
one is right
1 1 2 7??
Is it 24 or 25 ??.. ab jyada nhi matha lgana chta .. kl english ka hai...
no.. wrong
41???
Rahul 31??
Ap nhi mental ability hai..
This is not in A.P.
31??
Are question pura do
no
16?
4590.

If p(E)= 0.05 what is probability of not E

Answer» 1-0.05
19/20
.95
4591.

I have get my roll no. So how can I find center of examination

Answer» Skul will tell u.... Ur center
4592.

If 2sin²A- cos²A=2 , find the value of A

Answer» Value of A is 90degree
4593.

1+cot square A/1+cosec squareA = cosecA

Answer» 1/sin square A +1
?
4594.

a+b=0, prove that a=-b

Answer» Kya mazak h....???
What ??????
Already proved yrr...
Already proved !!
4595.

Find area of shadded region in AC. =24cm bc=10cm.

Answer»
4596.

Write the following in decimal form and say what kind of decimal expansion each has: 1/11

Answer» 0.09090909090909
Terminating expansion
4597.

If 15cot P=8 ,then find sin P and sec P

Answer» Check ncert examples from this chapter
Take cot P = 8/15 and cot P = b/p so b = 8 and p = 15 then by Pythagoras theorem bsquare + psquare = hsquare hence b and p is given therefore find h.... Then sin P = p/h and sec P = h/b put the value of p, h and h,b respectively and find the solution..
???
Very easy
4598.

√5+√5=?

Answer» 2√5
4599.

Solve for x: (4x-3/2x+1)-10(2x+1/4x-3)-3

Answer» Take 4x-3/2x+1 =p ....so 2x+1/4x-3 = 1/p.....hence the eqns are..p-10/p-3 = p2-10-3p....solve it then put the value of p in 4x-3/2x+1
4600.

Cos A =7/25 .Find tan A +cot A

Answer» cos A\xa0{tex}=\\frac{7}{25}{/tex}\xa0We know that sin2 A + cos2 A = 1{tex}\\Rightarrow{/tex}\xa0sin2\xa0A = 1 - cos2\xa0A{tex}\\Rightarrow{/tex}\xa0sin2\xa0A = 1\xa0{tex}-\\frac{49}{625}=\\frac{576}{625}{/tex}\xa0sin A\xa0{tex}=\\sqrt{\\frac{576}{625}}=\\frac{24}{25}{/tex}Now tan A\xa0{tex}=\\frac{\\sin A}{\\cos A}=\\frac{24 / 25}{7 / 25}{/tex}{tex}=\\frac{24}{7}{/tex}and cot A\xa0{tex}=\\frac{1}{\\tan A}=\\frac{7}{24}{/tex}{tex}\\therefore{/tex}\xa0tan A + cot A\xa0{tex}=\\frac{24}{7}+\\frac{7}{24}{/tex}{tex}=\\frac{625}{168}{/tex}