81279 + Interview Questions in Mathematics QA in Mathematics Page 1228 InterviewSolution

61351.	है 205 1८ 1& 0500 —guig ¢0 “""Oul,s\“ L S 0e
Answer»

Discussion

61352.	AjantaPage NoDatowhen fle) = 48 - 82 +8x+d isdiched by a polynomial glas,we get (21-1) as quotient.and (0+3) as demander. Find
Answer»

Discussion

61353.	Factorise
Answer»

Discussion

61354.	कि.धर श्र) oul or t90h \| 90 h \|) o TAWEVLD TYreq Ry
Answer» Basic Price 12930 Price including VAT 14067.20 VAT % = (14067.20-12930)*100/12930 = 8.79%

Discussion

61355.	Ill th height. Find the cost of painting12.50 per m2the pillar at the rate ofthe curve sunuce area of a right circular cylinderis 44m2 If the radius of the base of theJinder is 0.7 m, find its heightcydiameter of a circular wellis 35m T.
Answer» ryt ans thank you

Discussion

61356.	Find the greatest number that divides 10368, 9504, and 11232 , exactly , leaving no remainders ?
Answer» I think that 2 divide all no

Discussion

61357.	)length-1th12 cm, breadth 8 cm and height-4.5 cm
Answer» thanks

Discussion

61358.	Qi. Find the value of k for which 2x2 kx + k-0 has real and equal roots.02 Ifthe dictn
Answer» If the equation has equal roots, b² - 4ac = 0.b² - 4ac = 0a = 2b = -kc = k (-k)² - 42k = 0k² - 8k = 0k(k - 8) = 0k = 0 and k - 8 = 0k = {0,8} Hence, the values of k are 0 and 8.

61358.

Qi. Find the value of k for which 2x2 kx + k-0 has real and equal roots.02 Ifthe dictn

Answer»

If the equation has equal roots, b² - 4ac = 0.b² - 4ac = 0a = 2b = -kc = k

(-k)² - 4*2*k = 0k² - 8k = 0k(k - 8) = 0k = 0 and k - 8 = 0k = {0,8}

Hence, the values of k are 0 and 8.

Discussion

61359.	3. 6, 12, 21,?, 48(a) 33(c) 40(b) 38(d) 45
Answer» 6 + (2 * 3) = 6 + 6 = 1212 + (3 * 3) = 12 + 9 = 2121 + (4 * 3) = 21 + 12 = 3333 + (5 * 3) = 33 + 15 = 48. So the missing number is 33.

61359.

3. 6, 12, 21,?, 48(a) 33(c) 40(b) 38(d) 45

Answer»

6 + (2 * 3) = 6 + 6 = 1212 + (3 * 3) = 12 + 9 = 2121 + (4 * 3) = 21 + 12 = 3333 + (5 * 3) = 33 + 15 = 48.

So the missing number is 33.

Discussion

61360.	(90 - (48 - 21) + 7
Answer» { 90 - (48-21)} / 7= { 90 - 27 } /7= 63/7= 9. Please hit the like button if this helped you

61360.

(90 - (48 - 21) + 7

Answer»

{ 90 - (48-21)} / 7= { 90 - 27 } /7= 63/7= 9.

Please hit the like button if this helped you

Discussion

61361.	Factorise:
Answer» x³ - 2x² - x + 2 = x² ( x - 2) - ( x - 2) = (x² -1)(x - 2) = ( x - 1) ( x +1) ( x - 2)

61361.

Factorise:

Answer»

x³ - 2x² - x + 2

= x² ( x - 2) - ( x - 2)

= (x² -1)(x - 2)

= ( x - 1) ( x +1) ( x - 2)

Discussion

61362.	2. In Fig. 8.13, find tan P-cot R.12 cm13 cmQi
Answer» using Pythagoras law we got QR² = PR² - PQ² => QR = √ PR² - PQ² => QP = √ ( 13 )² - ( 12 )² => QP = √ 169 - 144 => QP = √25 => QP = 5 .°. tan P = QR/PQ tan P = 5/12 and Cot R = QR/PQ Cot R = 5/12 now tan P - Cot R = 5/12 - 5/12 = 0

61362.

2. In Fig. 8.13, find tan P-cot R.12 cm13 cmQi

Answer»

using Pythagoras law we got

QR² = PR² - PQ²

=> QR = √ PR² - PQ²

=> QP = √ ( 13 )² - ( 12 )²

=> QP = √ 169 - 144

=> QP = √25

=> QP = 5

.°. tan P = QR/PQ

tan P = 5/12

and

Cot R = QR/PQ

Cot R = 5/12

now

tan P - Cot R

= 5/12 - 5/12

= 0

Discussion

61363.	Factorise.
Answer» no 4p^2 - 9p^2(2p)^2 - (3p)^2[a^2 - b^2 = (a+b)(a-b)]=>(2p+3p)(2p-3p) using a^-b^=(a-b)(a+b)=(4p-9p)(4p+9q)

61363.

Factorise.

Answer»

no

4p^2 - 9p^2(2p)^2 - (3p)^2[a^2 - b^2 = (a+b)(a-b)]=>(2p+3p)(2p-3p)

using a^-b^=(a-b)(a+b)=(4p-9p)(4p+9q)

Discussion

61364.	(o8t ¢ 7q Yool 1 शध ्g५. अर. (wpe 5 bt 75 &8
Answer»

Discussion

61365.	15 Find out the mode of the following marlobtained by 15 students in a class:Marks : 4, 6, 5, 7,9, 8, 10, 4, 7, 6, 5,9,8, 7,
Answer»

Discussion

61366.	(c) 7515. In the adjoining figure, AOB is a straight line.Ifx y:z 4:5:6, then y-?(a) 60(c) 48°(b) 80°(d) 72°
Answer»

Discussion

61367.	Show that any positive odd integer is in the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.
Answer»

Discussion

61368.	ULUGUShow that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 Where qis some integer131
Answer» Let the integer be 16q+1=61+1=76q+3=61+3=96q+5=6*1+5=11Here 7,9,11 are positive odd integer Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. according to Euclid's division lemmaa=bq+r a=6q+r where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5 but here,a=6q+1 & a=6q+3 & a=6q+5 are odd. Read more on Brainly.in - https://brainly.in/question/2252590#readmore Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. according to Euclid's division lemmaa=bq+r a=6q+r where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5 but here,a=6q+1 & a=6q+3 & a=6q+5 are odd. Read more on Brainly.in - https://brainly.in/question/2252590#readmore

61368.

ULUGUShow that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 Where qis some integer131

Answer»

Let the integer be 16q+1=6*1+1=76q+3=6*1+3=96q+5=6*1+5=11Here 7,9,11 are positive odd integer

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+r

a=6q+r

where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

Read more on Brainly.in - https://brainly.in/question/2252590#readmore

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+r

a=6q+r

where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

Read more on Brainly.in - https://brainly.in/question/2252590#readmore

Discussion

61369.	60 - 48 \div 6 \times 4 + 8
Answer» 60-48÷6x4+860-8x4+860-32+828+836 60-48÷6×4+860-8×4+860-32+828+836 answer

61369.

60 - 48 \div 6 \times 4 + 8

Answer»

60-48÷6x4+860-8x4+860-32+828+836

60-48÷6×4+860-8×4+860-32+828+836 answer

Discussion

61370.	7. Find the greatest number which will divide264 and 168 exactly leaving a remainder of8 in each case.
Answer» 264 -8 =256 & 168- 8 =160256 = (2×2×2×2)×2×2×2×2160 = (2×2×2×2)×2×5 Answer is 2×2×2×2 = 16.

61370.

7. Find the greatest number which will divide264 and 168 exactly leaving a remainder of8 in each case.

Answer»

264 -8 =256 & 168- 8 =160256 = (2×2×2×2)×2×2×2×2160 = (2×2×2×2)×2×5

Answer is 2×2×2×2 = 16.

Discussion

61371.	6 Conto® "Qi 9०S — i——— -
Answer» The cos(10) = sin(90-10) or cos(10) = sin(80) then we have sin(80)/sin(80) = 1 Like my answer if you find it useful!

61371.

6 Conto® "Qi 9०S — i——— -

Answer»

The cos(10) = sin(90-10) or cos(10) = sin(80)

then we have

sin(80)/sin(80) = 1

Like my answer if you find it useful!

Discussion

61372.	_~0=qi+dL+d T: 9५०5
Answer» p²+7p+12p²+4p+3p+12P(P+4) +3(P+4) (P+3) (P+4)

Discussion

61373.	Add:5 3 48 21+28 3 45 8
Answer» 534821+283458 718279 Thanks

61373.

Add:5 3 48 21+28 3 45 8

Answer»

534821+283458 718279

Thanks

Discussion

61374.	QIFind the solution of the equation x-7 = 10.
Answer» x - 7 = 10;x = 10 + 7;x = 17 hit like if you find it useful

61374.

QIFind the solution of the equation x-7 = 10.

Answer»

x - 7 = 10;x = 10 + 7;x = 17

hit like if you find it useful

Discussion

61375.	J JU.PIINu OUL Th Height of tower and width of canal.Centre of a circle is (2x, X-7). Find the value of x if the circle passes through A (11, -9) and diameter ofcircle is 10v2 cm.A vessetin the for28.23.
Answer» Radius = 10√2/2 = 5√2unitscentre = (2x-1,x-7)point on circle = (11,-9) distance between centre and a point on circle = RadiusDistance between (2x-1,x-7)&(11,-9) = 5√2(11-2x+1)^2+(-9-x+7)^2= 50(12-2x)^2+(-2-x)^2= 50 2.4 and 8

61375.

J JU.PIINu OUL Th Height of tower and width of canal.Centre of a circle is (2x, X-7). Find the value of x if the circle passes through A (11, -9) and diameter ofcircle is 10v2 cm.A vessetin the for28.23.

Answer»

Radius = 10√2/2 = 5√2unitscentre = (2x-1,x-7)point on circle = (11,-9)

distance between centre and a point on circle = RadiusDistance between (2x-1,x-7)&(11,-9) = 5√2(11-2x+1)^2+(-9-x+7)^2= 50(12-2x)^2+(-2-x)^2= 50

2.4 and 8

Discussion

61376.	Factorise: 15xy-6x +5y-2.
Answer»

Discussion

61377.	15 xy - 6x + 5y - 2
Answer»

Discussion

61378.	6x+5y=7x+3 y+1
Answer» 6x + 5y = 7x + 3y + 1 5y - 3y = 7x - 6x + 1 2y = x + 1

61378.

6x+5y=7x+3 y+1

Answer»

6x + 5y = 7x + 3y + 1

5y - 3y = 7x - 6x + 1

2y = x + 1

Discussion

61379.	43. If-15/ =25, then find the value ofx.15 (3)(a) x = 7575(b) x 8(c) x 6(d) x 5
Answer»

Discussion

61380.	16. If x-4--/15), find the value of x + 1
Answer»

Discussion

61381.	15) Find using algebraic identity (x+1)?
Answer» (x+1)(x+1)^2(x+1)(x^2+1+2x)x^3+x+2x^2+x^2+1+2xx^3+3x^2+3x+1

Discussion

61382.	In Δ ABC (Figure 3), AD丄BC. Prove thatAC2 = AB2 + BC2-2BOx BDB D
Answer» In the right angle triangle ABD, we have AD² = AB² - BD²In the right angle triangle ACD we have AD² = AC² - CD² So AC² - CD² = AB² - BD² => AC² = AB² + CD² - BD² => = AB² + (CD + BD)* (CD - BD ) = AB² + BC * [(BC - BD) - BD] = AB² + BC * [ BC - 2 BD ] = AB² +BC² - 2 BC * BD

61382.

In Δ ABC (Figure 3), AD丄BC. Prove thatAC2 = AB2 + BC2-2BOx BDB D

Answer»

In the right angle triangle ABD, we have AD² = AB² - BD²In the right angle triangle ACD we have AD² = AC² - CD²

So AC² - CD² = AB² - BD² => AC² = AB² + CD² - BD² => = AB² + (CD + BD)* (CD - BD ) = AB² + BC * [(BC - BD) - BD] = AB² + BC * [ BC - 2 BD ] = AB² +BC² - 2 BC * BD

Discussion

61383.	(1) Write the following statements in conditional form.Every rectangle is a parallelogram.
Answer»

Discussion

61384.	७४ ४ ६ Db 2k i S BR kB) hlﬁ 19% %38 \| डर 128 1» ])3पर्ः 1% %CI1 ‘"‘
Answer»

Discussion

61385.	Show that in a quadrilateral ABCD, AB + BC CD +AD> AC+ BD
Answer»

Discussion

61386.	3. In the adjoining figure, AD = BC and BD = AC. Provethat ZADB = ZBCA.
Answer» AD=BCBD=ABAB=ABand,

Discussion

61387.	168 8 121) 1322) 1443) 1284) 162
Answer» in first figure 678/2=168logic is multiplied all sides and divide by 2same way in second figure answer is 1246/2=144

Discussion

61388.	QI 1) Shiv sold his dining table at a loss of 20%. If he had sold for rs800 more, he wouldhave made a profit of 5%. Find the cost price.
Answer» Let the cost price be Rs x. According to question, selling price = CP-20% of CP= 0.8x SP+ 800= CP + 5%of CP 0.8x+800=x+0.05x 1.05x-0.8x=800 0.25x= 800 x=3200 Hence, the cost price is Rs 3,200. thanks I can't understand it

61388.

QI 1) Shiv sold his dining table at a loss of 20%. If he had sold for rs800 more, he wouldhave made a profit of 5%. Find the cost price.

Answer»

Let the cost price be Rs x.

According to question,

selling price = CP-20% of CP= 0.8x

SP+ 800= CP + 5%of CP

0.8x+800=x+0.05x

1.05x-0.8x=800

0.25x= 800

x=3200

Hence, the cost price is Rs 3,200.

thanks

I can't understand it

Discussion

61389.	60482856.3?472114128(A) 8(C) 4(B) 2(D) 7
Answer» A is the right answer..

Discussion

61390.	Show that any positive odd integer is of the form 6q-+ 1, or 6q3,or 6q+ 5, where gissome integer1, or 6q+3, or 64+ 5, where qi
Answer»

Discussion

61391.	\| 20 anid Qi
Answer» 26+91=117. 26-91=-65

Discussion

61392.	the point (3, 8)Find the centre and the radius of the circle 2x+ 2y-6x 2y -270.
Answer»

Discussion

61393.	subtract the sum of x²-5xy+2y²and y²-3x² from the sum of 6x²-8xy-y² and 2xy-2y²-x²
Answer»

Discussion

61394.	(j) 5x-y=9(ii) 6x-2y = 10(iii) 2x +2y=4
Answer» 5x - y = 9 => y = 5x - 9 6x - 2y = 10 => 2y = 6x - 10 => y = 3x - 5 2x + y/2 = 4 => 4x + y = 8 => y = 8 - 4x

61394.

(j) 5x-y=9(ii) 6x-2y = 10(iii) 2x +2y=4

Answer»

5x - y = 9 => y = 5x - 9

6x - 2y = 10 => 2y = 6x - 10 => y = 3x - 5

2x + y/2 = 4 => 4x + y = 8 => y = 8 - 4x

Discussion

61395.	(3x+5y)(6x-2y)
Answer» 18x^2-6xy+30xy-10y^2will be the answer

Discussion

61396.	Find the perimeter of the following rectangle?6x + y\|3x-2y
Answer» The perimeter of rectangle is 18x-2y Your correct answer for this question is 18x-2y Your correct answer is Rs 18x-2y Perimeter = 2 ( L + B ) = 2 ( 6x + y + 3x - 2y ) = 2 ( 6x + 3x + y - 2y ) = 2 ( 9x + y ) = 18x + yperimeter of the figure is 18x - y 2(6x + y + 3x - 2y)2(9x - y)18x - 2y ans 18x-2y is right answer the perimeter of rectangle is 18 x - 2y Correct answer 18x-2y the perimeter is 18x-2y 2(6x+y+3x-2y)2(9x-y)18x-2x is the answer 2 (6x+y +3x-2y) 2 (9x-y) = 18x-2y Perimeter of rectangle=2(l+b)2(6x+y+3x-2y)2(9x-y)2×9x-y18x-2y Perimeter of rectangle =2×(l+b)2×(6x+y+3x-y)2×(9x-y)18x-2y The perimeter of the rectangle is 18x- 2y 2(6x+y+3x-2y)2(6x+3x+y-2y)2(9x-y)18x-y perimeter of rectangle=2(l+ b) =2[(6x+y)+(3x-2y)]=(12x+2y)+(6x-4y)=(12x+6x)+(2y-4y)=18x -2y 2×(l+B)=2(6x + y +3x- 2y)=2×(9x - y)= 18x - 2y Perimeter of rectangle=2(l+b)= 2{(6x+y)+(3x-2y)}=2(6x+y+3x-2y)=2(9x-y)=18x-2y perimeter = 2(l+b)=2(6x+y+3x-2y)=2(6x+3x+y-2y)=2(9x-y)=18x-y my answer is right perimeter of rectangle=2(l+b)2(6x+y+3x-2y)12x+2y+6x-4y18x-2y the perimeter of a rectangle is calculated by Farmula 2( l+b ) where l is given by 6x+yand b is given by 3x+y Now perimeter = 2( 6x+y+3x-2y )= 18x - 2y the perimeter of a rectangle is calculated by Farmula 2( l+b ) where l is given by 6x+yand b is given by 3x-2y Now perimeter = 2 ( l+b ) = 2[ (6x+y)+(3x-2y)] = 2(9x-y) = 18x-2y p=2×(l+b)2(6x+y+3x-2y)2(9x-y)18x-2y 2( 6x+y + 3x -2y)=2(6x+3x + y-2y)=2(9x -y)=18x -2y is the perimeter of the given rectangle.

61396.

Find the perimeter of the following rectangle?6x + y|3x-2y

Answer»

The perimeter of rectangle is 18x-2y

Your correct answer for this question is 18x-2y

Your correct answer is Rs 18x-2y

Perimeter = 2 ( L + B ) = 2 ( 6x + y + 3x - 2y ) = 2 ( 6x + 3x + y - 2y ) = 2 ( 9x + y ) = 18x + yperimeter of the figure is 18x - y

2(6x + y + 3x - 2y)2(9x - y)18x - 2y ans

18x-2y is right answer

the perimeter of rectangle is 18 x - 2y

Correct answer 18x-2y

the perimeter is 18x-2y

2(6x+y+3x-2y)2(9x-y)18x-2x is the answer

2 (6x+y +3x-2y) 2 (9x-y) = 18x-2y

Perimeter of rectangle=2(l+b)2(6x+y+3x-2y)2(9x-y)2×9x-y18x-2y

Perimeter of rectangle =2×(l+b)2×(6x+y+3x-y)2×(9x-y)18x-2y

The perimeter of the rectangle is 18x- 2y

2(6x+y+3x-2y)2(6x+3x+y-2y)2(9x-y)18x-y

perimeter of rectangle=2(l+ b) =2[(6x+y)+(3x-2y)]=(12x+2y)+(6x-4y)=(12x+6x)+(2y-4y)=18x -2y

2×(l+B)=2(6x + y +3x- 2y)=2×(9x - y)= 18x - 2y

Perimeter of rectangle=2(l+b)= 2{(6x+y)+(3x-2y)}=2(6x+y+3x-2y)=2(9x-y)=18x-2y

perimeter = 2(l+b)=2(6x+y+3x-2y)=2(6x+3x+y-2y)=2(9x-y)=18x-y

my answer is right

perimeter of rectangle=2(l+b)2(6x+y+3x-2y)12x+2y+6x-4y18x-2y

the perimeter of a rectangle is calculated by Farmula 2( l+b )

where l is given by 6x+yand b is given by 3x+y

Now perimeter = 2( 6x+y+3x-2y )= 18x - 2y

the perimeter of a rectangle is calculated by Farmula

2( l+b )

where l is given by 6x+yand b is given by 3x-2y

Now perimeter = 2 ( l+b ) = 2[ (6x+y)+(3x-2y)] = 2(9x-y) = 18x-2y

p=2×(l+b)2(6x+y+3x-2y)2(9x-y)18x-2y

2( 6x+y + 3x -2y)=2(6x+3x + y-2y)=2(9x -y)=18x -2y is the perimeter of the given rectangle.

Discussion

61397.	3x+2y-5=0. 6x-5y-1=0
Answer» 3x+2y=5; 6x-5y=1; 2(3x+2y=5)=6x+4y=10; 6x-5y=1/y=9; ; 3x+2(9)=5; 3x+18=5; 3x=5-18=-13, x=-13/3 (3x+2y=5)2=6x+4y=10; 6x-5y=1/9y=9; y =1; 6x-5(1)=1; 6x=1+5=6; x=6/6=1

61397.

3x+2y-5=0. 6x-5y-1=0

Answer»

3x+2y=5; 6x-5y=1; 2(3x+2y=5)=6x+4y=10; 6x-5y=1/y=9; ; 3x+2(9)=5; 3x+18=5; 3x=5-18=-13, x=-13/3

(3x+2y=5)2=6x+4y=10; 6x-5y=1/9y=9; y =1; 6x-5(1)=1; 6x=1+5=6; x=6/6=1

Discussion

61398.	6x+2y=75x+3y=15find x and y.
Answer» x=9 8y=4 50

Discussion

61399.	Find the perimeter of the following rectangle?6x + y3x-2y
Answer» Perimeter of rectangle = 2(l+b) = 2 (( 6x + y) + (3x - 2y)) = 2 (9x - y) = 18x - 2y

61399.

Find the perimeter of the following rectangle?6x + y3x-2y

Answer»

Perimeter of rectangle = 2(l+b)

= 2 (( 6x + y) + (3x - 2y))

= 2 (9x - y)

= 18x - 2y

Discussion

61400.	2xIn figure, ABCD is a trapezium of area 24.5 sq. cm. In it, ADIl BC ,LDAB = 90° , ADBC3.4 cm. If ABE is a quadrant of a circle, find the area of the shaded region.Ar
Answer»

Discussion

Explore topic-wise InterviewSolutions in .

है 205 1८ 1&amp; 0500 —guig ¢0 “""Oul,s\“ L S 0e

AjantaPage NoDatowhen fle) = 48 - 82 +8x+d isdiched by a polynomial glas,we get (21-1) as quotient.and (0+3) as demander. Find

Factorise

कि.धर श्र) oul or t90h | 90 h |) o TAWEVLD TYreq Ry

Ill th height. Find the cost of painting12.50 per m2the pillar at the rate ofthe curve sunuce area of a right circular cylinderis 44m2 If the radius of the base of theJinder is 0.7 m, find its heightcydiameter of a circular wellis 35m T.

Find the greatest number that divides 10368, 9504, and 11232 , exactly , leaving no remainders ?

)length-1th12 cm, breadth 8 cm and height-4.5 cm

Qi. Find the value of k for which 2x2 kx + k-0 has real and equal roots.02 Ifthe dictn

3. 6, 12, 21,?, 48(a) 33(c) 40(b) 38(d) 45

(90 - (48 - 21) + 7

Factorise:

2. In Fig. 8.13, find tan P-cot R.12 cm13 cmQi

Factorise.

(o8t ¢ 7q Yool 1 शध ्g५. अर. (wpe 5 bt 75 &amp;8

15 Find out the mode of the following marlobtained by 15 students in a class:Marks : 4, 6, 5, 7,9, 8, 10, 4, 7, 6, 5,9,8, 7,

(c) 7515. In the adjoining figure, AOB is a straight line.Ifx y:z 4:5:6, then y-?(a) 60(c) 48°(b) 80°(d) 72°

Show that any positive odd integer is in the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.

ULUGUShow that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 Where qis some integer131

60 - 48 \div 6 \times 4 + 8

7. Find the greatest number which will divide264 and 168 exactly leaving a remainder of8 in each case.

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Add:5 3 48 21+28 3 45 8

QIFind the solution of the equation x-7 = 10.

J JU.PIINu OUL Th Height of tower and width of canal.Centre of a circle is (2x, X-7). Find the value of x if the circle passes through A (11, -9) and diameter ofcircle is 10v2 cm.A vessetin the for28.23.

Factorise: 15xy-6x +5y-2.

15 xy - 6x + 5y - 2

6x+5y=7x+3 y+1

43. If-15/ =25, then find the value ofx.15 (3)(a) x = 7575(b) x 8(c) x 6(d) x 5

16. If x-4--/15), find the value of x + 1

15) Find using algebraic identity (x+1)?

In Δ ABC (Figure 3), AD丄BC. Prove thatAC2 = AB2 + BC2-2BOx BDB D

(1) Write the following statements in conditional form.Every rectangle is a parallelogram.

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Show that in a quadrilateral ABCD, AB + BC CD +AD&gt; AC+ BD

3. In the adjoining figure, AD = BC and BD = AC. Provethat ZADB = ZBCA.

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QI 1) Shiv sold his dining table at a loss of 20%. If he had sold for rs800 more, he wouldhave made a profit of 5%. Find the cost price.

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Show that any positive odd integer is of the form 6q-+ 1, or 6q3,or 6q+ 5, where gissome integer1, or 6q+3, or 64+ 5, where qi

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the point (3, 8)Find the centre and the radius of the circle 2x+ 2y-6x 2y -270.

subtract the sum of x²-5xy+2y²and y²-3x² from the sum of 6x²-8xy-y² and 2xy-2y²-x²

(j) 5x-y=9(ii) 6x-2y = 10(iii) 2x +2y=4

(3x+5y)(6x-2y)

Find the perimeter of the following rectangle?6x + y|3x-2y

3x+2y-5=0. 6x-5y-1=0

6x+2y=75x+3y=15find x and y.

Find the perimeter of the following rectangle?6x + y3x-2y

2xIn figure, ABCD is a trapezium of area 24.5 sq. cm. In it, ADIl BC ,LDAB = 90° , ADBC3.4 cm. If ABE is a quadrant of a circle, find the area of the shaded region.Ar

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Show that in a quadrilateral ABCD, AB + BC CD +AD> AC+ BD