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ears. eyes. bnose. elbow. feet. arms. nose.

EARSFEETELBOWARMSEYESNOSELEGS

EARS, FEET, ELBOW, ARMS, EYES, NOSE, LEGS

Ear ;hand nought lips foot head

(i) ∠ACB = ∠ACD ∠BAC = ∠DAC AC = AC(ii) Yes, the triangles are congruent.

Red=2Blue=3Green=4Total=9Probability of blue balloon=3/9=1/3Probability of not green=(9-4)/9=5/9

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angle 1 = angle 2

angle 2 = angle 3

So, angle 1 = angle 3

First Axiom: Things which are equal to the same thing are also equal to one another.

1)Circle has no sides 2)No a circle is not a polygon as it has no sides.

HCF of two prime numbers is always (1)

HCF of two prime number is 0.

HCF of any two prime number is always 1

HCF of two prime no is always 1

HCF of two prime no is always 1

it will be always 1 and LCM Will be a*b

HCF of two prime no is always 1

let ABCD be a quadrilateralwhere A(4,3);B(6,4)C(5,6) and D(3,5) are co ordinatesnow by section formula√((4-6)2+(3-4)2)=√((-2)2+(-1)2)=4+1=5.......(i)√((6-5)2+(4-6)2)=√((-1)2+(-2)2)=1+4=5......(ii)

⇒From (i)&(ii)we get AB = BC....(iii)similarly by section fomula AC=BD....(iv)So,we get that two adjacent sids are equal and two diagonals are equalHence, ABCD is a squareso points A,B,C,D are the angular points of a square.(Hence prooved)

bhai ni Samjh aya

Prime number : The natural numbers, which is divisible by 1 and the number itself is called a prime number.

List of prime numbers : 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47 and so on.

Now, 32 is an even number. We need to find 32 as the sum of two prime numbers.

The two possibilities arise :

i) 13 + 19 = 32

ii) 3 + 29 = 32

the two possibilities are 13+19=32,3+29=32

The reaction between barium hydroxide and ammonium chloride is an endothermic reaction. Heat is absorbed during endothermic reaction, fall in temperature is observed.Ba(OH)2 +2NH4Cl → BaCl2 +2NH4OHThis reaction is called double displacement reaction

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She has to Divide in 4 parts so24.16/4= 6.04each one will get 6.04

-S^5 t^3 u^ 3 is the correct answer of the given

5040 iska answer Hai Ab Mujhe like karo

Sn = n/2 (2a + (n-1)d) = 15/2 ( 2 + 14(2)) = 15(1+14) = 225

Sum of first 2019 even numbers:-a=2d=2n=2019∴S₂₀₁₉=(2019/2)[(2×2)+(2018×2)]=4078380

1st 10 even numbers are 2,4,6,8,10

Mean:-

Mean = Sum of all observations / Total no.of observations

Mean = 2+4+6+8+1+12+14+16+18+20/10

Mean = 110/10

Mean = 11

wrong

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17/6 = 1/2 + 7d17/6-1/2 = 7d7/3 = 7dd = 1/3

a4 = 1/2 + 3*1/3= 1/2 + 1= 3/2

lffgh

The region between a chord andeither of its arcs is called a segment the circle.

Angles in the same segment of a circle areequal.

For chord CD,

We know, that Angles in same segment are equal.∠CBD =∠CAD ∠CAD =70°

∠BAD =∠BAC +∠CAD =30° + 70° = 100°

∠BCD+∠BAD=180°

(Opposite angles of a cyclic quadrilateral)

∠BCD + 100° = 180°

∠BCD =180° - 100°

∠BCD=80°

In ΔABC

AB = BC (given)

∠BCA =∠CAB(Angles opposite to equal sides of a triangle)

∠BCA =30°

also, ∠BCD = 80°

∠BCA +∠ACD =80°

30° + ∠ACD = 80°∠ACD =50°

∠ECD =50°

Hence,∠BCD =80° & ∠ECD =50°

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Mean of first 20 positive numbers = sum of all observation upon total number of observation.

2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40/20 = 21

answer is 21

46 010 is the correct answer of your question.

Statement : Equal chords of a circle subtend equal angles at the centre.

Given : AB and CD are chords of a circle with centre O, such that AB = CD.

To prove : ∠AOC = ∠COD

Proof :In ΔAOB and ΔCOD,AO = CO [radii of same circle]BO = DO [radii of same circle]AB = CD [given]

ΔAOB ≅ ΔCOD [SSS]∠AOB = ∠COD [C. P. C. T]

Hence, Equal chords of a circle subtend equal angles at the centre.

Given a circle with centre O and chords AB = CDDraw OP⊥ AB and OQ⊥ CDHence AP = BP = (1/2)AB and CQ = QD = (1/2)CDAlso ∠OPA = 90° and ∠OQC = 90°Since AB = CD⇒ (1/2) AB = (1/2) CD⇒AP = CQIn Δ’s OPA and OQC,∠OPA = ∠OQC = 90°AP = CQ (proved)OA = OC (Radii)∴ ΔOPA ≅ ΔOQC (By RHS congruence criterion)Hence OP = OQ (CPCT)

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(e). Is right answer

(e) is the right answer of this question

Sum of first 2019 even numbers:-a=2d=2n=2019∴S₂₀₁₉=(2019/2)[(2×2)+(2018×2)]=4078380

यूएचएचबीबीजेकेआईयूइजभूजमोक

7 ka answer nehi Yaya hai

Given : In a circle C(O,r), chord AB = chord CD.

To Prove :∠AOB =∠COD.

Proof : In△AOB and△COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

Chord AB = Chord CD [given]

⇒△AOB≅△COD [by SSS congruence axiom]

⇒∠AOB =∠COD. [c.p.c.t.]

Point A lies in the y axis ( x = 0)

Point C is int the x axis ( y = 0 )

Point B and D are in the line x = 2 . ( hence it is parallel to y axis .

The diagonal AC intersects the parallel lines x = 0 and x = 2

Hence the angle it makes with the y axis is the angle θ ,(the angle between the diagonals )

AC cuts the y axis at y = 2 and x axis at x = 4

hence tan θ = 4/2 = 2