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75 x 60 ÷ 15

Using BODMAS rule first we do division and then multiplication

75 x (60÷15)= 75 x 4= 300 ans

Area of equilateral Δ=(√3/4)*a²=(√3/4)*30*30 cm²=225√3 cm²

P(E)=0.13P(E bar)=1-0.13=0.87

Let A(0,-1) , B(2,1) ,C(0,3) are vertices of the

Triangle.

D , E , F are midpoints of BC , CA and AB.

*************************************************

The midpoint of the line segment joining

the points (x1,y1) and (x2 , y2 ) is P( x , y ).

x = ( x1 + x2 )/2 ;

y = ( y1 + y2 )/2

*************************************************

Now ,

i ) mid point of B(2,1) , C(0,3) is D( x , y )

x = ( 2 + 0 )/2 = 1

y = ( 1 + 3 )/2 = 2

D = ( 1 , 2 )

Similarly ,

ii ) mid point of C( 0,3) , A(0,-1) = E( 0,1)

iii ) mid point of A(0,-1), B(2,1) = F(1,0)

*************************************************The area of the triangle formed by the

vertices ( x1,y1 ), ( x2, y2 ) , ( x3 , y3 ) is

1/2|x1 ( y2 - y3 )+x2( y3 - y1 ) +x3( y2 - y1) |

*********************************************

iv ) Area of the triangle A( 0, -1), B( 2 , 1 )

C( 0 ,3 ) is

1/2|0( 1 - 3 ) + 2( 3 + 1 ) + 0 ( -1-1 ) |

= 1/2 | 8 |

= 4 sq units

v ) Area of the triangle D( 1,2 ) , E( 0 , 1 ),

and F( 1 , 0 ) is

1/2 | 1( 1 - 0 ) + 0( 0 - 2 ) + 1( 2 - 1 ) |

= 1/2 | 2 |

= 1 sq units

vi )

ratio = ( area ∆ABC )/( area ∆DEF )

= 4/1

= 4 : 1

P(E bar)=1-P(E)=1-0.68=0.32

We know

P(E) + P(E') = 1

P(E') = 1 - 0.68 = 0.32

sorry by mistake post

replace p → k

secx+tanx=k

[1/cosx+sinx/cosx]=k

(1+sinx)/cosx=k

(1+sinx)=kcosx

(1+sinx)²=k²cos²k

1+2sinx+sin²x=k²(1-sin²x)

1+2sinx+sin²x=k²-k²sin²x

(k²+1)sin²x+2sinx+1-k²=0

use the quadratic formula to solve:

sinx=t

(k²+1)t²+2t+1-k²=0

-2±√(2)²-4(k²+1)(1-k²) / 2k²+2

-2±√4k⁴/ 2k²+2 =>-2±2k² / 2k²+2 =>-1±k² / k²+1 =>

-1-k² / k²+1 or -1+k² / k²+1

In conclusion sinx=t =>sinx= (k²-1)/(k²+1)

Given roots are 3p-2q,3q-2phence sum of roots=p+qproduct of roots=13pq-6(p^2+q^2)so eqn is x^2+(p+q)x+13pq-6(p^2+q^2)...................(1)also given 3p^2=5p+2..........(2) and 3q^2=5q+2..............(3)by subtracting 3 from 2 we get p+q=5/3By adding 2 and 3 we get p^2+q^2=37/9so pq=(p+q)^2-(p^2+q^²)=-6/9 = -2/3

1

2

Let side of equilateral triangle be x

Perimeter = 3x = 30

x = 10 cm

So, Area of equilateral triangle

= √3/4 × side²

= √3/4 × 10²

= 25√3 cm²

National Rural Employment Guarantee Act (NREGA) 2005:100 days assured employment every year to every rural household in 200 districts later extended to 600 districts.One third jobs reserved for women.The central government’s National Employment Guarantee Funds.And state government’s State Employment Guarantee Funds for implementation of the scheme.Under the programme if an applicant is not provided employment within fifteen days s/he will be entitled to a daily unemployment allowance.

Narega” has drawn rural women into the labor market in numbers never seen before. At the time of its inauguration, program rules required that at least one out of three workers employed would have to be female. The motivation was simple: Men in India’s workforce vastly outnumber women. Data shows a steady rise in women’s participation over the years. Women now comprise over half the program’s workforce, and accounted for over 55 percent of person-days worked in 2015-16.

Factorize:

x²-3x+2x²-2x-1x+2x(x-2)-1(x-2)(x-2)(x-1)Therefore,(x-2)(x-1)are the factors.

i) (x-2)x-2=0x=2So,p(x)=2p(x)=2x⁴-5x³+2x²-x+2p(2)=2(2)⁴-5(2)³+2(2)²-2+2=32-40+8= -40+40=0Hence,it proves that (x-2) is a factor .

ii) (x-1)x-1=0x=1So,p(x)=1p(x)=2x⁴-5x³+2x²-x+2p(1)=2(1)⁴-5(1)³+2(1)²-1+2=2-5+2-1+2=6-6=0Hence,it proves that (x-1) is a factor.

Thus 2x⁴-5x³+2x²-x+2 is divisible by x²-3x+2

Hydrochloric acid is secreted by the parietal cells present in stomach and it serves the following functions:

The pH ofgastric acid is normally around 1.5-3.5; as a result, stomach is the most acidic area in our body due to presence of hydrochloric acid.

Hydrochloric acid denatures proteins by basically cleaving the bonds and “melting” the proteins. Hydrochloric acid also activates pepsin, via its conversion from a substance called pepsinogen. The function of Pepsin is to mainly digest the protein we eat.

HCl acts as an antiseptic in the stomach too, by killing the microorganisms that exist in the food we eat. Hydrochloric acid also assists in the prevention of food fermentation which may occur in the dark, moist environment of the stomach. This hence prevents food-poisoning and occurrence of yeast, bacterial, viral, parasitic, and protozoa infections.

HCl is also essential in the breakdown of various vital nutrients. It allows for the digestion and absorption of the trace minerals zinc, iron, copper, magnesium, calcium, selenium, and vitamins B12 and vitamin B3.

thnx

two angles are 30 and 120the other angle will be180- (120+30)=180-150=30°hence as 2 angles are equal it will.be an iscoeles triangle

so which type of triangle it will be ??

(1) yes it is equal.please like my answer

1) CD and PS are equal .Because both triangles are congruent by SSS test2) areas of both triangles are same /equal

(I) a king of red colour

Number of favourable outcomes i.e. ‘a king of red colour’ is 2 out of 52 cards.

Therefore, probability of getting ‘a king of red colour’

P1= Number of favorable outcomes /Total number of possible outcome

= 2/52= 1/26

(ii) Total number of face card out of 52 cards = 3 times 4 = 12

p2 = 12/52 = 3/13

(iii) Cards of diamonds and hearts are red cards.

Number of face card in diamonds (king, queen and jack or knaves) = 3

Number of face card in hearts (king, queen and jack or knaves) = 3

Therefore, total number of red face card out of 52 cards = 3 + 3 = 6

Therefore, probability of getting ‘a red face card = 6/52 = 3/26

(4)the jack of heartsp4 = 1/52

(5)a spadep5 = 13/52= 1/4

(6)the queen of diamondsp6 = 1/52

ABC is right angled triangle

AB² + BC² = AC²

20² + 21² = AC²

AC² = 400 + 441 = 841

AC² = 841 = 29²

AC = 29

So, Perimeter of triangle

20 + 21 + 29

= 41 +29

= 70

which question bro.

Given:∠ABC = 90° &∠AMP = 90°(i) In ΔABC and ΔAMP, we have

∠A = ∠A (common angle)

∠ABC = ∠AMP = 90° (each 90°)

∴ ΔABC ~ ΔAMP (By AA similarity criterion)

(ii) As, ΔABC ~ ΔAMP (By AA similarity criterion)

If two triangles are similar then the corresponding sides are equal,

Hence, CA/PA = BC/MP

Geometric mean= (2x6x8x24)^4= (2x2x3x2x2x2x2x2x2x3)^4= 4sqroot(3)= 4x1.73= 6.92

No option is correct

We know,Product of numbers (a * b) = LCM(a, b) * HCF(a, b)

Therefore,12*16 = 48*HCFHCF = 12*16/48HCF = 12/3 = 4

(a) is correct option

In2 triangle ABC, we have

BP= BQ = 3cm

AP= AR = 4cm

( tangents drawn from an external point to the circle are equal).

So, RC = AC-AR

=11-4=7cm

Hence RC= CQ= 7 cm

Then, BC= BQ+QC

7+3=10cm

thanks

Distance Travelled= 5km Cost for 1km= 10 rs. Cost for rest 4 km = 3*4= 12rs. Total Cost=10+12= 22 rs.