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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 63301. |
. Show how v5 can be represented on the number line. |
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Answer» thx |
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| 63302. |
\begin { equation } \begin{array}{c}{\text { Which one of the }} \\ {\text { following is false? }} \\ {\text { (a) The square root of }} \\ {9 \text { is } 3 \text { or }-3} \\ {\text { (b) } \sqrt{9}=3} \\ {\text { (c) }-\sqrt{9}=-3} \\ {\text { (d) } \sqrt{9}=\pm 3}\end{array} \end { equation } |
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Answer» all are true |
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| 63303. |
Show how v5 can be represented on thenumber line. |
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| 63304. |
\left. \begin array l l \text (A) \sqrt 3 & \text (B) \frac 2 3 \\ \text (C) \frac 1 3 & \text (D) \frac 1 \sqrt 3 \end array \right. |
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| 63305. |
. What is the opposite of -3?\begin{array}{ll}{\text { A) } 3} & {\text { C) }-\frac{1}{3}} \\ {\text { (B) } 0} & {\text { (D) } \frac{1}{3}}\end{array} |
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Answer» A) opposite of -3 is 3 |
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| 63306. |
\begin{array} { l } { \text { Simplify the following. } } \\ { \text { a } ( 3 a + b ) ^ { 3 } + ( 3 a - b ) ^ { 3 } } \\ { \text { c } ( 2 x - y ) ^ { 3 } - ( 2 x + y ) ^ { 3 } } \end{array} |
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Answer» 27a^3+27a^2b+9ab^2+b^3+27a^3-27a^2b+9ab^2-b^3=54a^3+18ab^2 8x^3-12x^2y+6xy^2-y^3-8x^3-12x^2y-6xy^2-y^3=-24x^2y-2y^3 |
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| 63307. |
-49*f*m*o*r*text %2B 38*(text*(a*(d*n))) - 100 |
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Answer» sum38+(-49)=-11subtract-11-(-100)=-11+10089 ans if u satisfied with the ans then like or cmmt ✌️ 89 is the answer of the following 89 is the correct answer |
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| 63308. |
a*j - 68*f*m*o*r*text - 30 |
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Answer» -30+6838 the correct answer of the given question 38 is the answer of the quiet -38 is the right answer 38 is the correct answer |
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| 63309. |
49)The range of the function f(x)=f(x)=\frac{1-\tan x}{1+\tan x}R-\{0\} \text { 2) } R |
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Answer» let f(x) = -1so 1 - tanx-------------- = -1 1 + tan(x)1-tanx = -1 -tan(x)2 = 0an absurd resultso(3) option is correct |
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| 63310. |
I. 3. 25 व. 16 : 25 स. 3 : 1660 विद्यार्थियों में से 40 प्रतिशत विद्यार्थियों को विज्ञान विषय रुविकर लगता हैविद्यार्थियों की संख्या बताइये जिन्हें विज्ञान विषय में कम रुचि है।।a Hin |
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| 63311. |
(3/8)/((2*(3/4))) %2B (7/3)/(((2/3)*(text*((2/5)*(f*o))))) - 1/2 |
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Answer» 22/3+2/3 of 11/5+11/8+11/4-3/2 8 of (220+165-240)/28 of (145/2)580 thanks |
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| 63312. |
3*(400/((100*(text*(2*(f*o)))))) %2B 18 - 9 |
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| 63313. |
If the ratio of the areas of two similar triangles is16:25, then the product of the ratios of theircorresponding altitudes and medians is(a) 4:516:25(c) 256 : 625(d) of these |
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Answer» ratio of their corresponding altitudes and medians is 16:25 |
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| 63314. |
C. 40Sd.20%9, What percent of 4/5 is 16/25?a. 100%b. 80%c. 25%d. 60% |
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| 63315. |
1cm'. If the same wire is bent in the formm a circular sheet of radius 14 cm, two circles of radius 3.5 em and8o squares of side 3 cm are removed as shown in the figure. Find thetwarea of the remaining sheet.Mental MATHS |
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Answer» R=14 cmtotal area= πr²=22/7*196=616 cm²r2= 3.5 cmarea of the small circles= 2*πr²=2*12.25*22/7=77 cm²length of rectangle=3breadth=1area =lb=3 cm² area of the small circles+area of rectangle=77+3=80 cm² remaining area=616-80=536 cm² = Area of circular sheet = Pir^2 = 22/7 * 14^2 = 616 cm^2 = Area of the two circles = Pir^2 * 2 = 22/7 * 3.5^2 * 2 = 77 cm^2 = Area of the two squares = a^2 * 2 =3^2 * 2 = 18 cm^2 Total area of squares and circles = 77 + 18 = 95 cm^2. Area of remaining circular sheet = 616-95 = 521 cm^2. find the circumference of the circle whose diameter is 14 centimetre |
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| 63316. |
6. If a number is tripled and the result is increased by 5, we get 50. Find the number |
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| 63317. |
(28 + 7) (26 - 7) |
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| 63318. |
(271) The difference of the speed of a faster car and a slower car is 20 km/hr. If the slower car takes 1 hour more thanthe faster car to travel a distance of 400 km, find speed of bots the cars. |
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Answer» beta khud se karo tabhi tum age badhoge gami nu mathu apni mehnat se karo tabhi safal ban paoge |
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| 63319. |
m—_—“हल, “2Jul ८2 2८728 |
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| 63320. |
5n)%+ (5m+ 4n)? (2) (2x + 7)% - 28 |
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Answer» 1)(4m + 5n)² + (5m + 4n)² 16m² + 25n² + 40mn + 25m²+16n² + 40mn 41m² + 41n² + 80mn |
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| 63321. |
(281) car takes 1 hour less to cover a distance of 200 km, if its speed is increased by 10 km /hr than its usual speed.What is the usual speed of the car? |
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| 63322. |
(text*(((6/7)*(text*(((2/3)*(text*((3/7)*(f*o))))*(o*r))))*(f*o)))/2 |
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Answer» 1-2 1/2 of 6/7=6/14and 2/3 of 3/7=6/21thanks |
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| 63323. |
Express x in terms of y, it is being giventhat 7x-3y = 15. Check if the linerepresented by the equation intersectsthe y-axis at y = -5.(CBSE 2012) |
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Answer» we can represent equation in terms of x in y 7x-3y=15x=(15-3y)/7if it intersect y axis at 5 that means equation must satisfies this ordered pair(0,-5)LHS7(0)-3(-5)15RHS15LHS=RHSthis shows that it intersect at y=-5 |
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| 63324. |
11: A wire is bent into the form of a square of side 27.5 cm. The wire is straightendand bent into the form of a circle. What will be the radius of the circlesformed? |
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| 63325. |
f/((R*(a*(r*(r*(o*(w*(R*(text*((de*(f*(i*(n*(e*(db*y))))))*f(x)))))))))))=-4*x %2B 3 |
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| 63326. |
(2/3)*(text*(3*(f*o))) - 1/3 %2B 1/6 %2B 2/3 |
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Answer» (1/6)+(2/3)-(1/3)+(2/3)×3=(1/6)+(4/6)-(1/3)+(2/3)×3(5/6)-(1/3)+(6/3)=(5/6)+(6/3)-(1/3)=(5+12/6)-(1/3)=(17/6)-(1/3)=17-2/6=15/6ans.if helpful then like it |
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| 63327. |
-9*(-3 %2B 5) %2B 14/(3*(text*(2*(f*o))) - 3 %2B 4) |
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| 63328. |
Ramkali would need ? 1800 for admission fee and books etc.,for her daughter to startgoing to school from next year. She saved 50 in the first month of this year andincreased her monthly saving by 20. After a year,how much money will she save? Willshe be able to fulfil her dream of sending her daughter to school?[CBSE 2005, 2014] |
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| 63329. |
he profits of a firm were 7200 in the year 2014. During the next year, itincreased by 7% and decreased by 5% in the following year. What are theprofits of the firm in the year 2016? |
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| 63330. |
(4/15)*(25/24) %2B (28/16)*(25/35) |
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Answer» 4.5 is the correct answer of the given question 4.5 is the correct answer. 4.5 is right answer Yahi hai Sahi 4.5 is the correct answer |
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| 63331. |
25 21181615(c) 35(d) 27(b) 30(a) 28 |
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Answer» 15 15+1 = 16 16+2 = 18 18+3 = 21 21+4 = 25 25+5 = 30 |
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| 63332. |
Exencise 22a af yau sum a mumiter and muitiply the result byyou getffrom a mumber and multiply the rnesult byyou ger What is the aumber2eneth is 2 m more than swice itsIli, ISE rm Iro |
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Answer» Let the number be nAccording to given condition(n-1/2)1/2 = 1/8n - 1/2 = 1/4n = 3/4 Number is 3/4 |
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| 63333. |
4 k-g) 3 cos A= द है, तो ८४० & का मान है-- 28 |
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Answer» cosA=4/5=base/hypotenuse perpendicular =√(5²-4²)=√(25-16)=√9=3 tanA=perpendicular /base=3/4 |
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| 63334. |
9. The difference of the speed of a faster car and a slower car is 20 km/hr. If theslower car takes 1hour more than the faster car to travel a distance of 400 km,find speed of both the cars |
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| 63335. |
Using the property -k, fill in the blanks :7 28 |
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Answer» Given a/b = ak/bk Then, In this ratio k = 45/7 = 5*4/7*4 = 20/28 In this ratio k = 75/7 = 5*7/7*7 = 35/49 |
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| 63336. |
3. Two wire circles of diameters 28 cm and 35 cm are cut and then joined to form a big circle of radiusk cm. Find the value of k. |
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Answer» Find the circumference of the circle with diameter 28 cm: Circumference = πD = π(28) = 28π cm Find the circumference of the circle with diameter 35 cm: Circumference = πD = π(35) = 35π cm Find the Circumference of the big circle: Total length = 28π + 35π = 63π cm Find the Diameter: Diameter = Circumference ÷π = 63π ÷ π = 63 cm Find the radius: Radius = Diameter ÷2 = 63 ÷2 = 31.5 cm Answer: The radius, k , is 31.5 cm |
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| 63337. |
k.9. Find the point at which the line 7x + 4y = 28 intersects the x-axis |
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| 63338. |
-5/7 %2B (-2)/((6*(text*(f*(r*(m*o)))))) |
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| 63339. |
(2/5)*(3*(3/4)) %2B 108/((36*(text*((f*o)/3)))) |
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| 63340. |
20r + (ι + β)),284)Find the non-zero value of k, for which the quadratic equeaequal roots. Hence, find the roots of the equation.tion ka1-2 (k - 1)arehasof5. If 9th term of an AP is zero, provethat its 29th term is double the 19th ternm. |
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Answer» thanks |
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| 63341. |
Triangle XY Z is similar to trlangle PQRSolve for n.153530284/L12k R |
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| 63342. |
43. If k 28 + 16/3, then what will be the value of\begin{array}{ll}{\frac{2+\sqrt{3}}{2}} & {\text { B. } \frac{2-\sqrt{3}}{2}} \\ {\frac{3+\sqrt{3}}{2}} & {\text { D. } \frac{3-\sqrt{3}}{2}}\end{array} |
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| 63343. |
2. A car travel 432 km in 48 ( of petrol. How far would is travel in 28 ?t of 10 k sugar? |
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Answer» It is given that it travel252 km HIT THE LIKE BUTTON IF YOU ARE SATISFIED |
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| 63344. |
AnsWer the followings. (3 marks each)Write relation between mean, median and mode of the data. If mean andmode of some data is 23 and 20 then find median of data.151 |
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| 63345. |
Date12 The Value ฤ. 6J6J6Jl6 |
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Answer» 36✓6. . 36√6 sure this answer is correct 36/6 is the correct answer |
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| 63346. |
4币(2+V3) TarT (2-3)큠게丽titt14.-az TT (2.d-9d + 5z? + 3x _ I) ah àFind all zeroes of the polynomial (2x4 -9x3 5x2 3x 1) if two of its zeroes are(2+3) and (2-V3). |
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| 63347. |
4. How are clouds formed?5. List any three human activitiesthat you think would lead to airpollution. |
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Answer» 4. During day time, on being heated, a large amount of water evaporates from variouswater bodies and goes into the air. .A part of this water vapour also reaches theatmosphere through biological activities such as transpiration and respiration. .Thiscauses the air in the atmosphere to heat up. When this heated air rises, it expandsand cools, which results in the condensation of water vapour forming water droplets..The presence of dust and other suspended particles in air also facilitates the processof condensation. The formation of water droplets leads to the formation of clouds. 5. .Burning of fossil fuels such as coal and petroleum.Industrialization.Deforestation |
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| 63348. |
\frac 5 \operatorname sin ^ 2 30 ^ \circ %2B \operatorname cos ^ 2 45 ^ \circ %2B 4 \operatorname tan ^ 2 60 ^ \circ 2 \operatorname sin 30 ^ \circ \operatorname cos 60 ^ \circ %2B \operatorname tan 45 ^ \circ |
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| 63349. |
( \operatorname { tan } 15 ^ { \circ } \times \operatorname { tan } 45 ^ { \circ } \times \operatorname { tan } 60 ^ { \circ } \times \operatorname { tan } 75 ^ { \circ } ) |
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Answer» tan15°= cot75°so it becomes =(cot75°×tan45°×tan60°×tan75°)::(cota × tana =1)= (1×1×root3)= root3 |
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| 63350. |
((7/5)*(text*((f*o)*(4/9 %2B 2/3))))/((4*(2/3))) |
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Answer» 7/5 of (4+6/9)÷14/3= 7/5 of 10/9×3/14= 7/5 of 10/42= 7/22 plz accept as best 7/22 is the correct answer of the given question 7/22 is right answer of this question. please like my answer |
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