This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 65551. |
M is the midpoint of the side DC of a parallelogram ABCD. Line BM intersects seg AC at point L and line AD at point E Prove that, EL = 2BL |
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| 65552. |
(ii) AD is drawn perpendicular to BC, base of anequilateral triangle ABC. Given BC- 10 cm, findthe length of AD, correct to 1 place of decimal.(ICSE) |
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| 65553. |
(2) M is the midpoint of the sideDC of a parallelogramABCD. Line BM intersectsseg AC at point L andline AD at point E.Prove that, EL 2BL |
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Answer» Like my answer if you find it useful |
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| 65554. |
5. In ÎPQR, PQQR15 cm. Find PR(the triangle is right angled at Q) |
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Answer» PR=√(15^2+15^2)=15√2 cm more eassy method |
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| 65555. |
in the given figure, PQR is a right triangle,right-angled at Q. QS isperpendicular to PR. If PQ = 15 cm, QR-8 cm and PR = 17 cm,then find the area of ΔPQR. Also, find the length of QS. |
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| 65556. |
2. In parallelogram PQRS, ZQ (4x 5)° andS (3x 10)o. Calculate : ZQ and ZR. |
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| 65557. |
In Δ ABC, point M is the midpointof side BC.If, AB+AC 290 cm,AM 8 cm, find BC.4. |
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| 65558. |
(2) M is the midpoint of the sideDC of a parallelogramABCD. Line BM intersectsseg AC at point L andline AD at point E.Prove that, EL = 2BL |
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Answer» like my answer if yoy find it useful |
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| 65559. |
16: In the question there are circles. Certain numbers are given inside/outside the circles accordingto a particular rule. In the question one of the circle has a (?) mark inside it. Choose the correctanswer to fill in the space marked (?) from the given alternatives. |
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Answer» third hole m no aye ga=4 third mei ans 16 ayega.reason: in first one 3×5×2×4 ÷10in second one6×2×5×3 ÷ 10and 5×2×2×8 ÷10=16 the answer is 16in third hence 16th third is write answer third holes is 16 in the correct answer 16 is the correct answer 16 is your answer of your ques |
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| 65560. |
In Figure 1, ABC is an isosceles triangle right angled at C withAC 4 cm. Find the length of AB. |
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| 65561. |
3A"If Sin3A- cos CA-26)Les do acute angle.Value of Awheretnthe |
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Answer» sin3A=cos(A-26°)or , cos(90°-3A)=cos(A-26°)or , 90°-3A=A-26°or , A+3A=90°+26°or , 4A=116°or , A=116°/4or , A=29° sin3A= cos(A-20); cos(90-3A)= cos( A-26) 90-3A=A-26; 90+26=4A 116=4A; A=116/4=29 A=29°is is the correct answer for this question a=29 is the right answer for this question |
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| 65562. |
Sin CA+B) = 1Cos (A-B) = 13/2Lind the value ofLA and B |
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Answer» A=60° and B=30° are the values |
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| 65563. |
alue of ate isais:For real a, b, c if a + b + c = ab + bc + ca, then value of value of(B) 2(A) 1(C)3(D) |
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Answer» 0 is the correct answer of the given question |
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| 65564. |
जा 264 ¢ डर byethe melhed of complating fhe Lo |
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Answer» a²x²-3abx+2b²=0or, {(ax)²-2.ax.3b/2+(3b/2)²}+2b²-9b²/4=0or, (ax-3b/2)²+(8b²-9b²)/4=0or, (ax-3b/2)²-(b/2)²=0or, (ax-3b/2+b/2)(ax-3b/2-b/2)=0or, (ax-b)(ax-2b)=0Either, ax-b=0or, ax=bor, x=b/aOr, ax-2b=0or, ax=2bor, x=2b/a∴, the roots of the given equations are: b/a, 2b/a. Ans. |
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| 65565. |
in figure Δ ABC and Δ DEF are such thatAB DE, BC EF, AB | DE and BC || EFShow that(i) ABED is a parallelogram() BEFC is a parallelogramii)ADFC is a parallelogram.19, |
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| 65566. |
In Fig (ii) AD BC and AD II BC.Is AB - DC? Give reasons in support of your answer |
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| 65567. |
(i) AB-BC, BD(ii) AC-BC. DC(iii) AD-BD. CD |
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Answer» Sorry for the inconvinience! we are currently answering only for the questions posted in english! |
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| 65568. |
इज 6 डे. 2Vhed oo fhe IR RN BUNTS \‘%१७५6 |
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Answer» Effectsof AirPollution. High levels of airpollutioncan cause an increased risk of heart attack, wheezing, coughing, and breathing problems, and irritation of the eyes, nose, and throat. Airpollutioncan also cause worsening of existing heart problems, asthma, and other lung complications. Noise pollution can causehypertension, highstresslevels, tinnitus,hearing loss,sleep disturbances, and other harmful effects. Sound becomes unwanted when it either interferes with normal activities such as sleeping, conversation, or disrupts or diminishes one's quality of life. |
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| 65569. |
6०. From Fhe Sum 7 b+ 3n andl पड izAllbiocl e M,,J है ८. न |
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| 65570. |
tures, Calculatz fhe aa ofuthe page, Jf eachpicture measwing 9 cM |
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Answer» The page is a rectangle where l=8 b=6 Area = l×b =8cm×6 cm =48 sq cm |
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| 65571. |
In A PQR, If PQ > PR and bisectors of ZQ and ZRintersect at S. Show that SQ > SR. |
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| 65572. |
Dateeid- Point el theomen |
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| 65573. |
18. The vertices of an AABC are A(5, 5), B(1, 5) and C9, 1). A line is drawn to intersect sides ABand AC at P and Q respectively, such that AP=AQ-3.AB AC 4Find the length of the line segment PQ |
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| 65574. |
1! OR -fe 1 S adve for xiz s = T4+ 7,[a #0,b-# 0,x 2 0x #â(a +b)] |
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Answer» thanx |
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| 65575. |
cb = 125then findatb =4thevalueCa-6) |
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Answer» 5^3= 125a= 5b= 3a-b= 2 |
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| 65576. |
17.In Figure, DE || BC. if AD =DB = -2, AE = x + 2 and EC = - 1. find the value of x. 111 |
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Answer» I will answer in 12 hours. I am busy now |
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| 65577. |
45. In the following figure, AD 5.6 cm, ADh1cm, AB = 8.4 cm and EC = (x-1)Given that DE || BC.(x+1)AC |
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Answer» excellent |
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| 65578. |
%f(x) = 3x2-x-ad f(1) = 4, dif(x) |
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Answer» f(x) = Integration of f'(x) = 3x³/3 +2*2/x² +c = x³+4/x² +c now putting f(1) = 4 , we get f(1) = 4 = (1)³+4/(1)²+c=> 4 = 5+c => c = 4-5 = -1 so, the function is f(x)= x³+4/x²-1 |
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| 65579. |
D (3x-1) cm c1. In the figure, ABCD is a parallelogram in whichDC II AB, AD II BC, and DC (3x -1) cm, CB 5(y-1) cm,BA (x+7) cm and AD (2y +1) cm.Find x, y, and the perimeter of the parallelogram.A(x+7) cm |
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| 65580. |
CB[CB2. Find the zeros of the polynomial x +x-plp+ 1). |
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Answer» x² + x - p(p+1) = x² + (p +1)x - px - p(p +1) = x(x + p + 1) - p(x + p + 1) = (x + p + 1)(x - p)To find the zeroes, equate the factors to zero. x + p + 1 = 0=> x = -p -1 x - p = 0=> x = p Therefore, zeroes are -p -1, p |
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| 65581. |
40QT4 in Fig 6. 36 Qs PRthar A POS-4 TOR事1sides PR and QR of |
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Answer» the photo is not well cropped. |
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| 65582. |
In the given figure, the line segment PQ isparallel to AC of AABC and it divides thetriangle into two parts of equal area, Find25.the ratio AA: |
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| 65583. |
Practice set 2.2- 17, PS 13,11,PR-1',In Î PQRfind QR., point S is the midpoint of side QR.If PQ |
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| 65584. |
Ifanangle of a parallelogram is two-third of its adjacent angle, find the angles of fheparallelogram |
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| 65585. |
152EXERCISE 6,6 (Optional)*PQSR PR1. In Fig 656, PSIS the bisector ofQPR ofAPQR. Prove that e=Fig. 6.56Fig. 6.57 |
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| 65586. |
८... «1... तरल लाल19-30 - (12 श (8= ) f) | |
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Answer» 19-[30-{12+(8-3)}]=19-[30-{12+5}]=19-[30-17]=19-13 =6 |
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| 65587. |
Draw a line segment PQ 4.8 cm.Construct the perpendicular bisector of PQ. |
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| 65588. |
If x men working x hours a day for x days canproduce x articles, then the number of articlesproduced by y men working y hours a day for ydays is : |
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Answer» x men work x four for x days= x units1 man working 1 hour for 1 day=x/(x*x*x)=1/(x*x)thereforey men working 1 hour for 1 day=y/(x*x)y men working y hours for 1 day= y*y/(x*x)y men working for y hours for y days= (y*y*y)/(x*x) |
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| 65589. |
in triangle abc PQ is a line segment intersecting a b at p and ac at q such that segment PQ is parallel to segment bc if PQ divides triangle ABC into 2 equal parts means equal in area find BP / a b |
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| 65590. |
समाकरण. g"[ R 22“ - ५.52 + 1 न |
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Answer» D= b^2-4ac(-√5)^2-4 = 5-4= 1इस समीकरण के दो भिन्न वास्तविक मूल होंगेक्योंकि यहां पर डी का मान जीरो से बड़ा है |
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| 65591. |
.State True or False. Give reason also."If a number of circles touch a given line segmentPQ at a point A, then their centre lie on theperpendicular bisector of PQ". |
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| 65592. |
State True or False. Give reason also."If a number of circles touch a given line segmentPQ at a point A, then their centre lie on theperpendicular bisector of PQ". |
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| 65593. |
22. Solve for r: -INr+0.1.21xAD |
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Answer» 3 and 4/3 is the correct answer me to 3 and 4/3 is the correct answer 3 and 4/3 is the correct answer 2350 is the correct answer 3 4/3 the best answer me |
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| 65594. |
4. State True or False. Give reason also."If a number of circles touch a given line segmentPQ at a point A, then their centre lie on theperpendicular bisector of PQ". |
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| 65595. |
7,Draw a line segment PQ-6cm and divide it in the ratio of 3:2. |
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Answer» Draw a line segment of 6 cmthen Take 3 cm and then 2cm |
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| 65596. |
3. Compute the mean of the following data1-3123-55-77-9Frea2719[CB4 Find fhe mean of the f |
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| 65597. |
Which is greater- Speed of 24 km/h or 12.8 m/s and by how much?Note you can compare them in any units. |
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Answer» speed in( km/h) = 18/5 times speed in (m/s) so 24km/h in m/s = 24*(5/18) = 20/3 m/s. = 6.67m/s therefore 12.8 m/s is greater than 6.7 m/s by 4.1m/s. |
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| 65598. |
h Using determinants find the value of k, if the area of AABC is 3 sq, units where AE (1,3),B (0, 0) C (k, 0). |
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| 65599. |
Explain the working of sonar. |
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Answer» Please like the solution 👍 ✔️ Sonaris simply making use of an echo. When an animal or machine makes a noise, it sends sound waves into the environment around it. Those waves bounce off nearby objects, and some of them reflect back to the object that made the noise. |
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| 65600. |
Lesson 6 HA STORY OF UNITSName Haley Grisnud âĄDate __1. Label the place value chart. Use place value disks to find the sum or difference. Wstandard form on the line.5001009 Gon000) 300100,000 less than five hundred sixty thousand, three hundred thirteen is1 L a | the 17h | h.b. Ten thousand more than 300,000+ 90,000 + 5,000 + 40 isC. 447,077 isthan 347,077. |
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Answer» b.405,040 is the answer. |
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