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| 65851. |
7A housing society used to collect rain water from the root dits building 22mx20m to a cylindrical vessel having diameter ofbase 2m and height 3.5 m and then pumps their water into themain water tank so that all members can use it on a particularday. The rain water collected from the roof just filled thecylindrical vessel, then find the rain fall in centimeter. Whatvalue of housing society is reflected in this question? |
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Answer» Vol. of rain water on roof = vol. of water in cylinder lbh =πr^2h 22*20*h= 22/7*1*1**3.5 h= 22*0.5/22*20 h=0.025m =2.5cm |
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| 65852. |
e is bent in the shape of an equilateral triangle each of whose sides8.8 cm. This wire is rebent to form a circular ring, What is the diameter of the risce of a circle. If each12. A piece of wir |
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| 65853. |
(च) एक वृत्त की एक जीवा की लम्बाई उसकी त्रिज्या केबराबर है । इंस जीवा द्वारा लघु वृत्तखंड में अन्तरित' कोण हैi) 30° (i) 90°(iii) 120° e (1502 |
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| 65854. |
d onlyis theA. 100C. 180B. 1502D. 200 |
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Answer» It shows40 percentage= 40+201 percentage= 60/40100 percentage = (60/40)*100= 600/40= 150 Option-Bplease like the solution 👍 ✔️ |
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| 65855. |
18. Two sides AB & BC and median AM of Δ ABC are respectively equal to sides PQ &QRARONand median PNofΔ PQR. Show that Δ ABM |
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Answer» Since AM & PN is the median of ∆ABC (i)1/2 BC = BM & 1/2QR = QN (AM and PN are median) Now, BC = QR. (given) ⇒ 1/2 BC = 1/2QR (Divide both sides by 2) ⇒ BM = QN In ΔABM and ΔPQN, AM = PN (Given) AB = PQ (Given) BM = QN (Proved above) Therefore, ΔABM ≅ ΔPQN (by SSS congruence rule) ∠B = ∠Q (CPCT) |
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| 65856. |
18. Two sides AB & BC and median AM of Δ ABC are respectively equal to sides PQ &QRΔ PQNand median PN of.Δ PQR. Show that Δ ABM |
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Answer» Since AM & PN is the median of ∆ABC (i)1/2 BC = BM & 1/2QR = QN (AM and PN are median) Now, BC = QR. (given) ⇒ 1/2 BC = 1/2QR (Divide both sides by 2) ⇒ BM = QN In ΔABM and ΔPQN, AM = PN (Given) AB = PQ (Given) BM = QN (Proved above) Therefore, ΔABM ≅ ΔPQN (by SSS congruence rule) ∠B = ∠Q (CPCT) |
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| 65857. |
1. What is the ratio of the areas of a circle and an equilateral triangle whose diameter andrespectively equal?:aside are |
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| 65858. |
18.fwo sides AB & BC and median AM of Δ ABC are respectively equal to sides PQ & QRand median PN of Δ PQR. Show that Δ ABM Δ PQNu |
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| 65859. |
2. Two sides AB, BC and medianAM of one triangle ABC arerespectively equal to sides PQandQR and median PN of APQR (Seefigure). Show that:キBM |
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| 65860. |
[ (नाथ)कक. zu+um+ रद दर -- _ वि (त |
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Answer» (m^2 - n^2) /(m+n)^2 × (m^2 + mn + n^2) /m^3 - n^3 = [(m-n)(m+n)/(m+n)^2] × [(m^2 + mn + n^2)]/[(m-n)(m^2 + mn + n^2)] = (m-n)/(m+n) × 1/(m-n) = 1/(m+n) |
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| 65861. |
7 9 Q e ZU S G/—————j——, 21780 |
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Answer» 25a² - 9b² (5a)² - (3b)² (5a - 3b) ( 5a + 3b) |
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| 65862. |
m ne zu |
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Answer» first changed all the rows to columns in R.H.S.|l m n| = | n l m||e d f| = | f e d||u v w| = |w u v|now,interchange 1st and 2nd column in R.H.S. |l m n| = | l n m||e d f| = | e f d||u v w| = |u w v| now,interchange 2nd and 3rd column in R.H.S. |l m n| = | l m n||e d f| = | e d f||u v w| = |u v w| so L.H.S. = R.H.S.Hence proved. first changed all the rows to columns in R.H.S.|l m n| = | n l m||e d f| = | f e d||u v w| = |w u v|now,interchange 1st and 2nd column in R.H.S. |l m n| = | l n m||e d f| = | e f d||u v w| = |u w v| now,interchange 2nd and 3rd column in R.H.S. |l m n| = | l m n||e d f| = | e d f||u v w| = |u v w| so L.H.S. = R.H.S.Hence proved. |
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| 65863. |
2. Simplify:96x4y3z260xu(a) _4ry3 zu(C) Sa'b' cd(d) 824(b) 16x2 yz |
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Answer» d c c is where |
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| 65864. |
(D). नीचे दिये गये सर्वांगसम त्रिभुजों में सर्वांगसमता का प्रतिबन्ध है-8 cm8 cm3 cm3 cm |
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Answer» kor bhuja man sabhi aaps me purak is liye sarvasngsamhai is the right answer RHS,because angle p&b=90°=RRq=ac=8cm=HRp=AB=3cm=S RHSangle P and B =90°= RRQ=AC=8cm=HRP=AB=3cm=S They are congurrent with SAS Or SSS test. 7.41 is the right answer... |
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| 65865. |
1. The radii of two circles are 19 cm and 9 cm respectively.Find the radius of the circle which has circumference equalto the sum of the circumferences of the two circles. |
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| 65866. |
L. The radii of two circles are 19 cm and 9 cm respectively.Find the radius of the circle which has circumference equalto the sum of the circumferences of the two circles. |
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| 65867. |
2. Find the radius of the circle in which the length of a chord and its distance from the centre arerespectively equal to(a) 8 cm and 3 cm(b) 12 cm and 9 cm |
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| 65868. |
What is the area of the figure below?10 cm8 cm3 cmcm16 cm |
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| 65869. |
triangle as diameters, prove that thepo10. If cireles are drawn taking two sides of aintersection of these cireles lie on the third side.o right riangles with common hypotenuse ACII. ABC and ADC are twCAD LCBD.12. Prove that a cyclic parallelogram is a rectangleEXERCISE 10.6 (Optionał)Prove that the line ofcentres of two intersecting circles subtends equal angle●two points of intersectione areTwo chords AB and CD of lengths 5 cm and 11 cm respectively of a circleto each other and are on opposite sides of its centre. If the distance beween ACD is 6 cm, find the radius of the circle.The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smcentre?Let the vertex of an angle ABC be located outside a circle and let the sides of thintersect equal chords AD and CE with the circle. Prove that ZABC is equal todifference of the angles subtended by the chords AC and DE at the centre.Prove that the circle drawn with any side of a rhombus as diameter, passesthe point of intersection of its diagonals.at distance 4 cm from the centre, what is the distance of the other chord fABCD is a parallelogram. The circle through A, B and C intersect CD (pronecessary) at E. Prove that AE AD.AC and BD are chords of a circle which bisect each other. Prove that (i) AC anddiameters, (ii) ABCD is a rectangleBisectors of angles A, B and C of a triangle ABC intersect its circumcircle atF respectively, Prove that the angles of the triangle DEF are 9090°-C22 |
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Answer» I dont no |
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| 65870. |
i of two circles are 8 cm and 6 cm respectively. Findradius of the circle having area equal to the sum of theas of the two circles.6 |
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| 65871. |
(b)()Benzoicacidcompletelydimerisesinbenzene.Whatwillbethevapourpressureofasolutioncontaining61gof benzoic acid per 500g benzene when the vapour pressure of pure benzene at the temperature of experiment is66.6 torr? |
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| 65872. |
8.) AB and CD are common tangents to two circles of equal radii. Prove that ABCD |
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Answer» Like my answer if you find it useful! |
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| 65873. |
8 AB and CD are common tangents to two cireles of cqual radi. Prove that AB - CD |
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| 65874. |
Or• Prove that AB=0In figure, common tangents AB and CD to two circles intersect at E. Prove thathot |
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Answer» Tangents to a circle from a common exterior point have equal lengths. As AE and CE are tangents from common point E to the larger circle, AE = CE _______________(1) As BE and DE are tangents from common point E to the smaller circle,BE = DE ______________(2) By adding (1) and (2),AE + BE = CE + DEAB = CD Hence proved |
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| 65875. |
Find the value of1)2% of 1705)8% of80.5 litres:2) 1.5% of3006) 121% of4)1.9% of1200m3) 15% of 30 kg7) 30% of 60hours864808)125%of2.00 days |
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| 65876. |
I. Fill in the blanks with suitable word (s)1. If A = A, then the matrix A is called anSc |
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Answer» the correct answer is sclar matrix matrix.... idempotent .hence it is an example of idempotent it is called as idempotent matrix applicable for an square matrix |
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| 65877. |
ate: cos’30° + sin? 45° - 3—l tan? 60° + cos® 90° |
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| 65878. |
ate or cloth per meter.AB and CD are two common tangents ofcircles in the adjacent diagram. Prove that AB-CD&. |
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Answer» Now produceab and cd to pwe know that length of two tangents drawn from an external point to a circle are equalAP= cp---(1)bp= dp----(2)adding both 1 and 2AP+bp= CP+dpAB = CD |
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| 65879. |
1. In 2007, the population of a town was approximately 35,250. In 2012,the population of the town had decreased to 28,200. Based on a linearmodel, what will be the approximate population of the town in 2014A 31,020B. 26,800c. 25,380D. 15,510 |
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Answer» 31020 |
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| 65880. |
Question 2:Plat the points (u ) given in the following table on the plane,choosing suitable unlts of distanceon the axes-283125 3 17 |
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| 65881. |
iist ladiait4. Find the area of the region bounded by the ellipse1.16 9 |
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| 65882. |
m 9.2)sides)1D and E are points on sides AB and AC respectively of Δ ABC such thatar(DBQ- ar (ERC). Prove that DE I BC. |
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| 65883. |
If A = {4(n-1); ne and B = {41 - 4n: ne N}where N is the set of natural numbers, then whichone is true?(1) ACB(2) BCA(3) AB=A (4) AUB=B |
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Answer» B is a proper subset of A |
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| 65884. |
1SCUOLPel leue.9. The cost of 2 meters of rope is 375 2. Findcost of cloth per metre. |
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| 65885. |
the-tenhe-ä¸0(2/3)haduilllLcy ne |
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Answer» thanking you sir |
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| 65886. |
100 oranges are bought at the rate atRs.375 and sold at the rate of 60 perdozen. Then percentage of profit is |
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| 65887. |
100 oranges are bought at the rRs.375 and sold at the rate of 60 perate atdozen. Then percentage of profit is |
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Answer» CP=375SP is 60 per dozen so 5 per piece so SP=500so profit=(500-375)/375*100=33.33% |
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| 65888. |
A space of 3 m x 1.5 m is cut for a door froma wooden wall of dimension 14 m x 8 m.5.An iron plate needs to be fixed all around thewooden wall to protect it from moisture. Findthe length of the iron plateFind the cost of polishing the wall at the rateof 375 per sq mA.B |
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| 65889. |
3. Robert mowed of his lawn beforedinner and 5 of it after dinner. Whatfraction of the lawn did he mow? |
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Answer» 2/5 multiple 1/5 jsksbdksfjosvrkehddkwnke For this add both the fractionshence2/5+1/5=3/5th of lawn was mowed. |
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| 65890. |
along the inside edge of the plot. Find the area of the path. A lawn is 80 m long and 30 m wide. Through the centre of the lawn paihs each 2 mwide, run at right angles. Find the anea of the remaining portion of the lawnthe fellowinfields of eiven dimension: |
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Answer» Outer Area =l*b=80*30=2400m^2Inner length =(80-2-2)=(80-4)=76mInner Breadth =(30-2-2)=(30-4)=26m Inner Area =l*b=76*26=1976m^2 Area of remaining portion =2400-1976Area of remaining portion =424m^2 Like my answer if you find it useful! |
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| 65891. |
Find the area of the region bounded bythe parabola y2=4x and its latusrectum |
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| 65892. |
nbe hree times old as she was 9 years ago. How old is sheA town's population increased by 1200 people, and then this new population decreased11% The town now had 32 less people than it did before the 1200 increase. Find the |
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Answer» Thanks |
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| 65893. |
5. By selling an article for 74550, Tony incurs a loss of 9%, what percent would hegain or lose by selling it for 4825? |
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Answer» thankyou for the answer |
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| 65894. |
SOLVED EXAMPLESEXAMPLE 1 A vertical pole stands on the level ground. From a point nthe ground, 25 m away from the foot of the pole, the angle ofelevation of its fop is found to be 60°. Find the height of the poleTake 3-1.732 |
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Answer» thank bro |
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| 65895. |
Three years ago. Beeru purchased a buffalo from Surjeet for 1100discharge his debt nowear the ddebto.the rate of interest being 10% per annum, compounded a |
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| 65896. |
48. The number of diagonals in a polygon of 7 sies is |
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Answer» thanks for raising the doubt with us The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon = 7*4/2= 14 |
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| 65897. |
5. The perimeter of a triangular field is 540 m, and its sides are in the rau25: 17:12. Find the area of the field. Also, find the cost of ploughing thefield at 40 per 100 m 2. |
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| 65898. |
right circular cylinder is 3 metre height and the circumference of its base is 22 metre find its curved surface area |
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Answer» CSA= 2πrh= now |
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| 65899. |
1 do es ,L'/ “कह B|| Ex Qe 15i ) exe |
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| 65900. |
25The base of a triangular field is twice its attende.& the cost of plangtrungat the rate ofthe fieldis 213,500, won the baseE 375 per 100mand the[aus. 1200m, 600malte mode of the field au. |
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