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4 7/11 × x = 38 1/4 51/11 × x = 153/4 x = 33/4 = 8 1/4

(i) ((25)2× 73)/ (83× 7)

Solution:-

83can be written as = (2 × 2 × 2)3

= (23)3

We have,

= ((25)2× 73)/ ((23)3× 7)

= (25 × 2× 73)/ ((23 × 3× 7) … [∵(am)n= amn]

= (210× 73)/ (29× 7)

= (210 – 9× 73 – 1) … [∵am÷ an= am – n]

= 2 × 72

= 2 × 7 × 7

= 98

(ii) (25 × 52× t8)/ (103× t4)

Solution:-

25 can be written as = 5 × 5

= 52

103can be written as = 103

= (5 × 2)3

= 53× 23

We have,

= (52× 52× t8)/ (53× 23× t4)

= (52 + 2× t8)/ (53× 23× t4) … [∵am× an= am + n]

= (54× t8)/ (53× 23× t4)

= (54 – 3× t8 – 4)/ 23… [∵am÷ an= am – n]

= (5 × t4)/ (2 × 2 × 2)

= (5t4)/ 8

(iii) (35× 105× 25)/ (57× 65)

Solution:-

105can be written as = (5 × 2)5

= 55× 25

25 can be written as = 5 × 5

= 52

65can be written as = (2 × 3)5

= 25× 35

Then we have,

= (35× 55× 25× 52)/ (57× 25× 35)

= (35× 55 + 2× 25)/ (57× 25× 35) … [∵am× an= am + n]

= (35× 57× 25)/ (57× 25× 35)

= (35 – 5× 57 – 7× 25 – 5)

= (30× 50× 20) … [∵am÷ an= am – n]

= 1 × 1 × 1

= 1

784.45 is the right answer

5-25+1=266-36+2=3811-121+3=124

5- 25+1-26, 6-36+2-38 ,7-49+3 -52, 8 -64 +4-68 ,9 -81+5 -86 10-100+6 -106 ,11-121+7-128. 128 is the correct answer

Your correct answer is 124

(c) is the right answee

the answer is b as it is simple if you want solution you can tell it in google mike in which my answe is there

B, option is correct answer

Let us assume that the total marks are 100.

Then the average marks obtained by each class A,B,and C is 70,65 and 50.

Then the total marks obtained by students of A,B and C are 70*25, 65*40 and 50*35

So the average of all the classes is,

(70×25+65×40+50×35) / (25+40+35)

So the average of all classes is 61%

There are 3 angles in a triangle A,B,C Hence sum is angle A+angle B+angle C=180°

5/8th of 120l=75litrsshence remaining water is 120-75=45litres.

sum of opposite angle of a cyclic quadrilateral is = 180°

so, y-10 +x+20 = 180=> x+y = 170

and 2x+y = 180-10+ 50 = 220

now subtracting 1 from 2

=> 2x -x = 220 -170 = 50=> x = 50/2 = 25°

and y = 170-25 = 145°

Sin theta= 3/5then cos theta= √(1-9/25= √16/25= 4/5tan theta= sin theta/ cos theta= 3/5/(4/5)= 3/4

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0.5-0.6-0.1 is the answer

how you have done please tell it stepwise

3×3×3×3×3=243×10×10×10×10×10=100000×26=607500000 and ÷607500000=1•••answer=1

x+y=-6; x-y=5/2y=-1; y=-1/2; x=-6-1/2=-12-1/2=-13/2

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can I have it using cross multiplication please

solve by substitution method

by using substitution method

Side of a square = 12 m

Radius of each sector = 12 m

θ = 90°

White part is divided into two parts of equal area.

Area of part 1 = Area of square ABCD - Area of sector BAPC

Area of part 1= (Side)² - (πr²θ)/360°

= (12)² - (3.14 × 12 × 12 × 90°/360°)

= 144 - (3.14 × 3 × 12)

= 144 - 3.14 × 36

= 144 - 113.04

Area of part 1 = 30.96 m²

Area of Part 1= Area of part 2 = 30.96 m²

Total Area of white part = 2× 30.96 = 61.92 m²

Cost of covering 1m² area by silver foil = ₹100

Cost of covering 61.92 m² area by silver foil = ₹(61.92 × 100) = ₹ 6192

Hence , the Cost of covering by silver foil = ₹ 6192 .

sec theta + tan theta =xSo 1/cos theta + sin theta/cos theta =xSo cos theta =( 1+sin theta) /xHence sec theta = 1/cos theta =x/(1+sin theta)

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how

which question to answer

36x2-12xy+y2

Final result :

(6x - y)2

(6x-y)²

correct answer for this question

Sec 41× sin(90-41) + cos(90-41)× cosec41 - 2 / 3^1/2 × tan (90-70)× 3^1/2 × tan 70 - 3(1/2 -1)=( sec 41× cos 41 )+( sin 41× cosec 41 )-(2× cot70 × tan70) -3(-1/2)= 1 + 1 - 2 + 3/2= 3/2.

Sin(90-x)= cos xCos(90-x) = sin xTan(90-x)= cot xCotx × tanx =1Sin × cosec=1Cos × sec=1

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P(A)=2^n is the formula for the number of elements of a power set of given set

Given :-

49x - 57y = 172 ........(i), and

57x-49y=252.............(ii)

Adding (i) and (ii), we get

106x - 106y = 424

=> x - y = 4 .................(iii)

Now substracting (i) and (ii), we get

-8x - 8y = -80

=> x + y = 10 ...............(iv)

Adding (iii) and (iv), we get

2x = 14

=> x = 7

putting the value of x in question (iii), we get

y = 3

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In ∆ABE and ∆ACE AB = ACABE = ACF ( AB=AC so angle B = angle C)angle A = angle A so by ASA rule ∆ABE and ∆ACE both are congurent.So by CPCT BE = CF

In ∆ABE and ∆ACE AB = ACABE = ACF ( AB=AC so angle B = angle C)angle A = angle A so by ASA rule ∆ABE and ∆ACE both are congurent.So by CPCT BE = CF

Mass (solute) = 40 gram

Mass (solvent) = 320 gram

Mass (solution) = Mass (solute) + Mass (solvent)

= 40 gram + 320 gram

= 360 gram

∴ Mass % (solution) = [ Mass (solute)/Mass (solvent)]× 100

= [40/360]× 100

= 11.1 %

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36x²-84x+49(6x)²-2(6)(7)x+(7)²(a-b)²=(6x-7)²

So it is square of 6x-7

Given:cost of chair=Rs1485cost of 469 chairs=469×1485=Rs .696,465

Cost of 1 chair =rs1485Cost of 469 chairs=rs1485*469=rs696,465

7L is 7000ml 8L 122ml is 8000+122ml =8122ml8122/7000= 1.16ml

Mass (solute) = 40 gram

Mass (solvent) = 320 gram

Mass (solution) = Mass (solute) + Mass (solvent)

= 40 gram + 320 gram

= 360 gram

∴ Mass % (solution) = [ Mass (solute)/Mass (solvent)]× 100

= [40/360]× 100

= 11.1 %

Radius (r1) of 1stcircle = 19 cm

Radius (r2) or 2ndcircle = 9 cm

Let the radius of 3rdcircle ber.

Circumference of 1stcircle = 2πr1= 2π (19) = 38π

Circumference of 2ndcircle = 2πr2= 2π (9) = 18π

Circumference of 3rdcircle = 2πr

Given that,

Circumference of 3rdcircle = Circumference of 1stcircle + Circumference of 2ndcircle

2πr= 38π + 18π = 56π

→ r = 28 cm

The answer to this question is 28. so easy

the answer to this question is actually 28cm. don't forget the units